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RichardZhang

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Borane

Optimization of Borane(3-21G)

Optimization of Borane(6-31G)

The optimisation file is linked to here

Ng611 (talk) 19:29, 4 June 2018 (BST) You mean 'frequency file' (you've uploaded the frequency file, which is correct, but not labelled it as such).

BH3
Vibrational Information
Mode Vibration Intensity Symmetry IR Active Type
1 1163 93 A2' Yes out-of-plane bend
2 1213 14 E' Yes bend
3 1213 14 E' Yes bend
4 2582 0 A1' No symmetric stretch
5 2715 126 E' Yes asymmetric stretch
6 2715 126 E' Yes asymmetric stretch
The IR spectrum of Ammonia borane


There are less than six peaks in the spectrum even though there are obvious six vibrations. This is because the translation modes are degenerate each other, such as mode 2 and mod 3, mode 5 and mode 6. In addition, the vibration mode 4 is IR inactive, which therefore also missed in the IR spectrum.

The molecular orbital of Borane

No obvious differences can be observed between the real and LCAO MOs, which means that the qualitative MO theory is quite accurate.

Association energy calculation

Optimization of Ammonia(6-31G)

1.RB3LYP/6-31G:

The optimisation file is linked to here


Ammonia
Vibrational Information
Mode Vibration Intensity Symmetry IR Active Type
1 1694 145 A Yes out-of-plane bend
2 1694 13 E Yes bend
3 1694 13 E Yes bend
4 3461 1 A1 No symmetric stretch
5 3589 0 E No asymmetric stretch
6 3589 0 E No asymmetric stretch
The IR spectrum of Ammonia

Optimization of Ammonia Borane(6-31G)

1.RB3LYP/6-31G:

The optimisation file is linked to here

Ng611 (talk) 19:32, 4 June 2018 (BST) Remember to upload the correct file! We're looking for frequency log files.

Ammonia Borane

Calculation process

E(NH3)=-56.55776863 a.u ≈ -1.48492x10^5 kJ/mol

E(BH3)=-26.61532360 a.u ≈ -6.9879x10^4 kJ/mol

E(NH3BH3)=-83.22469012 a.u ≈ -2.18506x10^5 kJ/mol

ΔE = E(NH3BH3)-[E(BH3)+E(NH3)] = -2.18506x10^5+(6.9879x10^4+1.48492x10^5) ≈ -135 kJ/mol

The value of association energy is a negative value and much smaller than the carbon carbon single bond(around 300 kJ/mol) and carbon-carbon double bond(around 600 kJ/mol). Therefore, the B-N dative bond is relatively weak.

Ng611 (talk) 19:31, 4 June 2018 (BST) Remember to cite your bond values (ideally from a textbook, databook, or paper).

Borone tribromide

Optimization of borone tribromide(GEN)

1. RB3LYP/GEN:

The optimisation file is linked to here

Boron tribromide
Vibrational Information
Mode Vibration Intensity Symmetry IR Active Type
1 156 145 E' NO asymmetric stretch
2 156 13 E' NO asymmetric stretch
3 268 13 A1' NO symmetric stretch
4 378 1 A2 Yes out-of-plane bend
5 763 0 E' Yes bend
6 763 0 E' Yes bend
The IR spectrum of Borone tribromide

The pps-optimisation of BBr3: DOI:10042/202437

The pps-frequency of BBr3: DOI:10042/202439

Project of aromaticity

Optimization of Benzene

1.RB3YLP/6-31G:

The optimisation file is linked to here

Ng611 (talk) 19:34, 4 June 2018 (BST) Again, remember to upload frequency lof files.

Benzene
The IR spectrum of Benzene

Optimization of Borazine

1.RB3YLP/6-31G:

The optimisation file is linked to here

Borazine
The IR spectrum of Borazine

The Natural Bond Orbital analysis

The charge diagram of Benzene
The charge diagram of Borazine
The atoms in benzene
Atom Charge/a.u Electronegativity
c -0.239 2.5
H 0.239 2.2
The atoms in borazine
Atom Charge/a.u Electronegativity
B 0.747 2.0
N -1.102 3.04
H-N 0.432 2.2
H-B -0.077 2.2

According to the diagrams and tables shown above, it is obvious that the charge density in the benzene is evenly distributed. In addition, the charge of the hydrogen is 0.239 a.u and the charge of the carbon is -0.239, which is a big difference. This is mainly because of the electronegativity difference between H(2.2) and C(2.5). As carbon is more electronegative than hydrogen, it will attracts the charges toward itself, which therefore becomes more negative in charge density than hydrogen. For borazine, the distribution of charge density is more complex. The nitrogen is a strong electron withdrawing group as the electronegativity of N is around 3.04 which is much larger than the electronegativity of hydrogen(2.2)and boron(2.0). Therefore, it will pulls the charge density towards itself and away from the boron and hydrogen.


Ng611 (talk) 19:35, 4 June 2018 (BST) Good discussion of the effects of electronegativity on the overall charge distribution. What do the partial charges sum to, and is there any difference in partial charge for atoms related by symmetry?

The MOs of Benzene and Borazine
MOs of Benzene MOs of Borazine Describtion
These Molecular orbitals are MO no.14 for benzene and MO no.15 for Borazine. Both orbitals are the anti-bonding sigma orbitals. The orbital energy of benzene is -0.43854, which is almost the same as the energy of borazine(-0.43197). Based on the diagram, it is clear that the molecular orbital of benzene is more symmetric than that of borazine. This is because the nitrogen in the borazine is more electronegative and it pulls the electron density away from the borons and hydrogens.
Both orbitals are the no.21 MOs in benzene and borazine and they are both anti-bonding pi orbitals. The MO of benzene is more symmeric than the MO of borazine. The energy of benzene orbital is -0.24691, which is less negative than the energy of borazine(-0.2759). Moreover, it is clear to see that the upper portion of MO in the borazine is smaller than the lower part. This is because the higher electronegativity nitrogens withdraw the charge density toward their part.
Both orbitals are the no.24 MOs in benzene and borazine and they are both bonding sigma orbitals. The orbital energy of benzene is 0.09117 and the orbital energy of borazine is 0.08953. The MO of benzene is more symmetric than that of borazine. This is because the large electronegativity of nitrogens withdraw electron density from hydrogen and boron and distored the structure of the molecular orbital.

Ng611 (talk) 19:41, 4 June 2018 (BST) Well done for comparing the correct MOs by shape and not energtic ordering (which is not necessarily reliable). I would include a brief discussion of the overall symmetry of the molecule to improve this section further. Perhaps also consider dicussing the constituent AOs that form the MOs and the overall symmetry of the MO. I'm also not sure your discussion of MO 24 is particularly useful as it's quite high in energy.


The aromaticity is applied in the organic chemistry to descirbe a cyclic, flat molecule with a ring of resonance bonds. These bonds induces more stability other types of structure or arrangements of atoms. In terms of the electronic nature of the molecule, aromaticity describes a conjugated system often made of alternating single and double bonds in a ring. This configuration allows for the electrons in the molecule's pi system to be delocalized around the ring, increasing the molecule's stability.

Ng611 (talk) 19:41, 4 June 2018 (BST) Not nearly enough discussion here. You should include some thoughts on how the modern conceptual model of aromaticity differs from Huckel's model to improve the section.

Ng611 (talk) 19:41, 4 June 2018 (BST) An adequate report. Your discussion on aromaticity was missing a great deal of detail, and you missed out on easy marks by uploading the wrong log files. However, your calculations were accurately and correctly performed -- some additional discussion and analysis would have made this into a truly excellent piece of work.