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Tty115

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Tty115

NH3

Summary

Molecule: NH3

Calculation Method: RB3LYP

Basis set: 6-31G(d,p)

RMS Gradient: 0.05399560 a.u.

Point Group: C3V

        Item               Value     Threshold  Converged?
 Maximum Force            0.000004     0.000450     YES
 RMS     Force            0.000004     0.000300     YES
 Maximum Displacement     0.000072     0.001800     YES
 RMS     Displacement     0.000035     0.001200     YES

NH3 molecule

The optimisation file is linked to NH3 Molecule


Vibration modes of optimised NH3

how many modes do you expect from the 3N-6 rule? 6

which modes are degenerate (ie have the same energy)? 2,3 and 5,6

which modes are "bending" vibrations and which are "bond stretch" vibrations? Vibration modes 1,2,3 are "bending" vibrations and modes 4,5,6 are "bond stretch" vibrations

which mode is highly symmetric? Vibration modes 1 and 4.

one mode is known as the "umbrella" mode, which one is this? Vibration mode 1

how many bands would you expect to see in an experimental spectrum of gaseous ammonia? 2 Bands. There are 4 degenerate modes giving four different peaks. But modes 4,5,6 have intensities too low therefore two of the peaks would not appear on the spectrum, hence only 2 bands would be seen.

Charges on NH3

Charge Distribution

N-Atom: -1.125C

H-Atom: 0.375C

We'd expect the N atom to be negative as it is more electronegative than H, and therefore H should be positive.

N2 optimisation

Summary

Molecule: N2

Calculation Method: RB3LYP

Basis set: 6-31G(d,p)

RMS Gradient:0.02473091 a.u.

Point Group: D*H


         Item               Value     Threshold  Converged?
 Maximum Force            0.000001     0.000450     YES
 RMS     Force            0.000001     0.000300     YES
 Maximum Displacement     0.000000     0.001800     YES
 RMS     Displacement     0.000000     0.001200     YES

N2 molecule

The optimisation file is linked to N2 Molecule

Vibration modes of N2

How many modes do you expect from the 3N-5 rule? N=2, therefore 1 mode

Which modes are degenerate (ie have the same energy)? Only one mode therefore no degenerate modes

Which modes are "bending" vibrations and which are "bond stretch" vibrations?Mode 1 is a stretching mode.

Which mode is highly symmetric? Mode 1

How many bands would you expect to see in an experimental spectrum? 0 due to no change in dipole moment.

Charge Distribution

N-Atom: 0.000C

N-Atom: 0.000C

Neutral charge expected on both atoms as there is no difference in electronegativity.

H2 optimisation

Summary

Molecule: H2

Calculation Method: RB3LYP

Basis set: 6-31G(d,p)

RMS Gradient:0.09719500

Point Group: D*H


         Item               Value     Threshold  Converged?
 Maximum Force            0.000000     0.000450     YES
 RMS     Force            0.000000     0.000300     YES
 Maximum Displacement     0.000000     0.001800     YES
 RMS     Displacement     0.000001     0.001200     YES

H2 molecule

The optimisation file is linked to H2 Molecule

Vibration modes of H2


How many modes do you expect from the 3N-5 rule? N=2, therefore 1 mode

Which modes are degenerate (ie have the same energy)? Only one mode therefore no degenerate modes

Which modes are "bending" vibrations and which are "bond stretch" vibrations?Mode 1 is a stretching mode.

Which mode is highly symmetric? Mode 1

How many bands would you expect to see in an experimental spectrum? 0 due to no change in dipole moment.

Charge distribution

H-Atom: 0.000C

H-Atom: 0.000C

Neutral charge expected on both atoms as there is no difference in electronegativity.

Haber-Bosch Reaction Energy Calculation

Energy for the reaction of N2 + 3H2 -> 2NH3 can be determined:

E(NH3)=-56.55776873 a.u.

2*E(NH3)= -113.11553746 a.u.

E(N2)= -109.52412868 a.u.

E(H2)= -1.17853936 a.u.

3*E(H2)= -3.47784060 a.u.

ΔE=2*E(NH3)-[E(N2)+3*E(H2)]= -0.0557907 a.u.

ΔE = -146.48 kJ/mol

Therefore the energy for converting hydrogen and nitrogen gas into ammonia gas is -146.48 kJ/mol. Reaction is exothermic meaning the product is more stable as it is lower in energy therefore the ammonia product is more stable.

Literature value of the Haber-Bosch Reaction is -92.44 kJ/mol. [1]

  1. Max Appl "Ammonia" in Ullmann's Encyclopedia of Industrial Chemistry 2006 Wiley-VCH, Weinheim. doi:10.1002/14356007.a02_143.pub2

ClF

Summary

Molecule: ClF

Calculation Method: RB3lYP

Basis Set: 6-31G(d,p)

RMS Gradient: 0.03767912

Point Group: C*V

         Item               Value     Threshold  Converged?
 Maximum Force            0.000246     0.000450     YES
 RMS     Force            0.000246     0.000300     YES
 Maximum Displacement     0.000433     0.001800     YES
 RMS     Displacement     0.000613     0.001200     YES
ClF molecule

The optimisation file is linked to ClF Molecule

Vibration Modes

Vibration modes of ClF

How many modes do you expect from the 3N-5 rule? N=2, therefore 1 mode.

Which modes are degenerate (ie have the same energy)? Only 1 mode therefore no degenerate modes.

Which modes are "bending" vibrations and which are "bond stretch" vibrations? Mode 1 is stretching.

Which mode is highly symmetric? 1

How many bands would you expect to see in an experimental spectrum of gaseous ClF? 1

Charge Distribution

Cl-Atom : 0.309C

F-Atom : -0.309C

We would expect too see a negative charge on F as it is more electronegative than Cl

Charge distribution of ClF


Energy for the reaction of Cl2 + F2 → 2ClF

E(Cl2) = -920.34853296 a.u.

E(F2) = -199.42620785 a.u.

E(ClF) = -559.94269578 a.u.

2×E(ClF) = -1119.885392 a.u.

ΔE = [2×E(ClF)]-[E(Cl2) + E(F2)]

ΔE = -0.11065119 a.u.

ΔE = -290.51 kJ/mol

The reaction is exothermic meaning the product ClF is more stable as it is lower in energy, therefore the equation favours the ClF product.

Molecule Orbitals

Electronic configuration of Cl: 1s22s22p63s23p5

Electronic configuration of F: 1s22s22p5

The first six occupied orbitals are all Atomic orbitals(AO), Orbitals 4,5 and 6 all have energies of around -7.30 a.u., relatively deep in energy.

2p AOs of Cl in ClF

and therefore they must be 2p orbitals in Cl, as there are three of them and they don't contribute to Molecular orbitals, as shown on the right.








The diagrams below shows the 7th and 8th MO that are occupied; these represent the 3s-2s sigma occupied MO(-1.21864 a.u.) and 3s-2s sigma antibonding occupied MO(-0.83311 a.u.) respectively.The occupied antibonding orbital is higher in energy

3s-2s sigma MO
3s-2s sigma* MO






The diagrams below show the 3p-2p MOs in ClF that are all occupied. There are two different energies, showing that there are two different types of interaction, sigma and pi. 3p-2p sigma MO has energy of -0.52314 a.u. while the two degenerate 3p-2p pi MOs have energies of -0.46713 a.u.

3p-2p sigma occupied MO
3p-2p pi occupied MO
3p-2p pi occupied MO



























The diagram on the right shows the 3p-2p sigma antibonding unoccupied MO in ClF. It has an energy value(-0.12150a.u. )higher than both 2p-3p sigma bonding(-0.52314 a.u.) and 3p-2p pi antibonding(-0.32855 a.u.). It is also the LUMO of ClF.

3p-2p sigma antibonding unoccupied MO