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BH3 Molecule

Method:B3LYP

Basis set:6-21G (d,p)

        Item               Value     Threshold  Converged?
Maximum Force            0.000070     0.000450     YES
RMS     Force            0.000039     0.000300     YES
Maximum Displacement     0.000356     0.001800     YES
RMS     Displacement     0.000214     0.001200     YES

Media: File:BY416 BH3 FREQ.LOG

Low frequencies ---   -0.6727   -0.3834   -0.0055   12.9097   16.4795   16.4932
Low frequencies --- 1163.0392 1213.2115 1213.2142


BH3


IR

wavenumber (cm-1) Intensity (arbitrary units) symmetry IR active? type
1164 92 A2" yes out-of-plane bend
1214 14 E' slight bend
1214 14 E' slight bend
2580 0 A1' no symmetric stretch
2713 126 E' yes asymmetric stretch
2713 126 E' yes asymmetric stretch


There are 6 vibrations of BH3, as seen in the table. These do not show up in the IR spectrum because there are two pairs which are degenerate (of the same energy). These degenerate pairs are only seen once in the IR spectrum. Furthermore, for a vibration to be IR active it must have a change in the dipole moment. The A1 symmetric stretch does not invlve an overall change in the dipole moment. Therefore it is not seen in the IR spectrum.

MO diagram

(MO diagram for BH3, Lecture 4 Tutorial Problem Model Answers, P. Hunt, [1], accessed 22/05/18)

The LCAO AOs are similar to the computed MOs. There are areas of electron density and no electron density (nodes) seen in both. This shows that qualitative MO theory is useful as its accuracy is high.

Ng611 (talk) 19:17, 4 June 2018 (BST) Ate there any differences at all that you can see (there actually are some!). Otherwise, good analysis.

NH3 Molecule

Method:B3LYP

Basis set:6-21G (d,p)

   Item               Value     Threshold  Converged?
Maximum Force            0.000006     0.000450     YES
RMS     Force            0.000004     0.000300     YES
Maximum Displacement     0.000012     0.001800     YES
RMS     Displacement     0.000008     0.001200     YES

Media: File:BY416 NH3 OPTIMISATION.LOG

Ng611 (talk) 19:18, 4 June 2018 (BST) This should be a frequency log file here.

Low frequencies ---   -8.5646   -8.5588   -0.0044    0.0454    0.1784   26.4183
Low frequencies --- 1089.7603 1694.1865 1694.1865
NH3 molecule

NH3BH3

Method:B3LYP

Basis set:6-21G (d,p)

   Item               Value     Threshold  Converged?
Maximum Force            0.000122     0.000450     YES
RMS     Force            0.000058     0.000300     YES
Maximum Displacement     0.000513     0.001800     YES
RMS     Displacement     0.000296     0.001200     YES


Media: File:BY416 NH3BH3 OPT.LOG


Ng611 (talk) 19:18, 4 June 2018 (BST) ... And here.

Low frequencies ---  -13.6017   -0.0013   -0.0007   -0.0003   19.4531   43.3457
Low frequencies ---  266.2693  632.1302  638.2535


NH3BH3 molecule

Energy Calculations:

E(BH3)= -26.61532364 a.u

E(NH3)= -56.55776873 a.u

E(NH3BH3)= -83.22468893 a.u

Association energy, deltaJ : E(NH3BH3) - [E(NH3)+E(BH3)] = -0.05159656 a.u

-0.05159656 x 2625.5 = -135.4667683 kJ/mol

The energy calculation shows that the B-N bond is weak. The bond enthalpy is +135 kJ/mol. This is lower than other organic bonds.[2]

Ng611 (talk) 19:19, 4 June 2018 (BST) The final value should be reported to the nearest kj/mol

BBr3

Method:B3LYP

Basis: 6-31G (d,p) for B, LanL2DZ (pseudo-potential) for Br

  Item               Value     Threshold  Converged?
Maximum Force            0.000023     0.000450     YES
RMS     Force            0.000014     0.000300     YES
Maximum Displacement     0.000118     0.001800     YES
RMS     Displacement     0.000069     0.001200     YES

DOI:10042/202469

File:By416 bbr3 freq3.log

Low frequencies ---   -3.1706   -0.0002   -0.0001    0.0000    1.6540    3.3467
Low frequencies ---  155.8924  155.9627  267.7046
BBr3 molecule

Project : Aromaticity

Benzene

Method:B3LYP

Basis set:6-21G (d,p)


        Item               Value     Threshold  Converged?
Maximum Force            0.000198     0.000450     YES
RMS     Force            0.000082     0.000300     YES
Maximum Displacement     0.000849     0.001800     YES
RMS     Displacement     0.000305     0.001200     YES

File:BENZENE FREQ BY416.LOG

Low frequencies ---  -11.6728   -0.0010   -0.0008    0.0003    6.6686   15.6846
Low frequencies ---  414.0392  414.6031  621.0860

Benzene

Charge distribution:

Charges:

Carbon = -0.239

Hydrogen = 0.239

Discussion:

In benzene, every carbon atom has the same electronegativity, therefore has the same charge. The same applies to the hydrogen atoms. The hydrogen atoms have the same magnitude of charge as carbon, but the opposite sign.

Borazine

Method:B3LYP

Basis set:6-21G (d,p)

[[File:Borazine opt2 by416.PNG]

       Item               Value     Threshold  Converged?
Maximum Force            0.000073     0.000450     YES
RMS     Force            0.000026     0.000300     YES
Maximum Displacement     0.000298     0.001800     YES
RMS     Displacement     0.000106     0.001200     YES

File:BORAZINE FREQ2 BY416.LOG

Low frequencies ---  -15.3480  -15.3480  -12.7393   -0.0158   -0.0107   -0.0107
Low frequencies ---  288.9049  288.9049  403.7235

Borazine

Charge distribution:

Charges:

Nitrogen= -1.102

Hydrogen atoms bonded to Nitrogen= 0.432

Boron= 0.747

Hydrogen atoms bonded to Boron= -0.077


Discussion:

Nitrogen is much more electronegative than boron and hydrogen. Therefore, it pulls electron density from orbitals of B and H, towards itself. As a result the hydrogen atoms bonded to nitrogen have a positive charge because electron density has been pulled away. On the other hand, boron is less electronegative than nitrogen so does not pull as much electron density towards itself. Therefore, it has a less negative charge and its electron density is dispersed on the hydrogen. Hence the hydrogen atoms bonded to boron are more negative than the hydrogen atoms bonded to nitrogen.

Charge Comparison

Borazine has N - H bonds which are more polar than benzene and B - H bonds which are less polar than benzene. This is because nitrogen is more electronegative than carbon. Hence creating bonds with a greater charge difference/ more polar. Boron is less electronegative than carbon therefore there is lower charge difference between B-H than C-H.

Ng611 (talk) 19:21, 4 June 2018 (BST) Good discussion of the effects of electronegativity on the overall charge distribution. What do the partial charges sum to, and is there any difference in partial charge for atoms related by symmetry?

MO Comparisons

1.

Benzene: ]

Borazine:

These MO diagrams represent p orbitals. 3 p orbitals are in the same phase on either side (the grouping of electron density). The phases are distinguished by colour. In between the areas of electron density, there are nodes where the likelihood of finding an electron is 0. For benzene, the electron density is distributed evenly among the p orbtials in the same phase. This is because all the carbons in benzene are of the same electronegativity. However, for borazine, the electron distribution is gravitated towards the nitrogen atoms (blue atoms). This is because nitrogen is much more electronegative than boron, as discussed before when considering charge density.

Ng611 (talk) 19:24, 4 June 2018 (BST) Which p-orbtials are responsible for the overall MO here? A comment about the symmetry of the orbitals and the symmetry of the molecule here would also be useful.

2.

Benzene:

Borazine:

This example is also looking at p orbitals. As mentioned in the other examples, the distribution is more equal in benzene than borazine. In borazine, the orbitals are skewed because of the different electronegativities. The distribution is even in benzene because the electronegativies are the same.


3.

Benzene:

Borazine:

This example also looks at P orbitals, here all the p orbitals are in the same phase. Only the above place is showing in the pictures, there is also an orbital underneath. The image was taken like this to see the distribution of one orbital. In this case the electron density is distributed equally among the benzene. This is because of the equal electronegativty of the carbons. In borazine, however, the spread of electron density is less equal. The nitrogen atoms have more electron density surrounding them, because of their higher electronegativity.

Aromaticity

For a molecule to be aromatic it needs to obey certain rules. These rules include: being cyclic, planar. all the atoms being conjugated and obeying the 4n+2 rule. The 4n+2 rule, also known as huckle's rule, states that for a molecule to be aromatic it must have the right number of pi electrons. This right number is 4n+2, which is the mathematical shorthand for the series: 2,6,10,14,18... where n must be an integer. Therefore, for the molecule to be aromatic it must have pi electrons that equal to a number in that series. For example, even though clyclooctatetraene is cyclic, conjugated and planar it is not aromatic as it has 8 pi electrons.

The basic conceptions of aromaticity are a simplified version of the MOs. For example, the idea of conjugation is rigid as it assigns electrons to certain bonds. However, as shown in the MO diagrams, the electrons can be found anywhere in the orbital. Furthermore, the idea of aromaticity originated from benzene. The rules assigned, also based from benzene/aromatic compounds, do not apply in some cases. For example benzene is not planar in certain conditions. The idea of aromaticity can also be applied to compounds which are not the conventional aromatic compounds. Some examples include polyhedral boranes, metallobenzenes and fullerenes.

Ng611 (talk) 19:27, 4 June 2018 (BST) This is a promising paragraph. You should go into far more detail though regarding these concepts of aromaticity. For example, what new concepts of aromaticity have arising to explain aromaticity in the compounds you mention. What experiments can be performed to see whether aromaticity is actually occuring?

The Pz orbitals are not conjugated in the pi system therefore they cannot be considered when looking at aromaticity. The orbitals are not conjugated because their orientation/angle is not at the correction orientation to allow the pi orbitals to create a conjugated system. Therefore, it is not a good description for aromaticity.

[3]

Ng611 (talk) 19:27, 4 June 2018 (BST) A good report overall. You let yourself down slightly in the final section (the discussion on aromaticity) and in uploading the wrong data for two of your calculations. Otherwise, this was a good piece of work overall. Well done.