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NH3 optimization

Summary Details

calculation method: RB3LYP

basis set: 6-31G(d,p)

final energy: -56.55776873 au

RMS gradient: 0.00000485 au

point group: C3V

optimized N-H bond length: 1.01798 A

optimized bong angle: 105.74115


The charge on the Nitrogen atom is -1.125 and the charge on the hydrogen atom is 0.375. As the nitrogen atom is much more electronegative than the hydrogen atoms it pulls electron density towards itself therefore you'd expect it to have a negative charge while the hydrogen's would be electron deficient and so positively charged

Item Table

          Item            Value      Threshold  Converged?
 Maximum Force            0.000004     0.000450     YES
 RMS     Force            0.000004     0.000300     YES
 Maximum Displacement     0.000072     0.001800     YES
 RMS     Displacement     0.000035     0.001200     YES

Link to data:media:NH3_OPT_01386810.LOG

NH3 Dynamic Image

NH

Link to file:(File:NH3 OPT 01386810.LOG)

NH3 Vibration Data

no negative frequencies shown therefore the optimization worked

Analysis Questions&Answers

how many modes do you expect from the 3N-6 rule?

3(4)-6= 6 therefore you'd expect 6 modes

which modes are degenerate?

modes 2 and 3 have the same energy and modes 5 and 6 have the same energy

which modes are "bending" vibrations and which are "bond stretch" vibrations?

1,2 and 3 are bending while 4,5 and 6 are stretching

which mode is highly symmetric?

mode 4

one mode is known as the "umbrella" mode, which one is this?

mode 1

how many bands would you expect to see in an experimental spectrum of gaseous ammonia?

2 bands would be expected in an experimental spectrum of ammonia which would be for modes 1 & 2/3. 2 & 3 have the same energy so have the same band. The rest of the modes are not IR active as there is no net change in dipole moment during vibrations

N2 optimization

Summary Details

calculation method: RB3LYP

basis set: 6-31G(d,p)

final energy: -109.52412868 au

RMS gradient: 0.00000060 au

Point Group: D∞h

optimized N-N bond length: 1.10550 A optimized bong angle: 180

Item Table

          Item             Value     Threshold  Converged?
 Maximum Force            0.000001     0.000450     YES
 RMS     Force            0.000001     0.000300     YES
 Maximum Displacement     0.000000     0.001800     YES
 RMS     Displacement     0.000000     0.001200     YES

Link to data:media:N2 OPT.LOG

N2 Dynamic Image

N

Link to file:(File:N2 OPT.LOG)

N2 Vibration Data

no negative frequencies shown therefore the optimization worked. For this molecule there is no change in dipole moment as electronegativites of atom within the molecule are the same and so intensity for peak is very small and the peak would be seen on a spectrum

H2 optimization

Summary Details

calculation method: RB3LYP

basis set: 6-31G(d,p)

final energy: -1.17853936 au

RMS gradient: 0.00000017 au

point group: D∞h

optimized H-H bond length: 0.74279 A optimized bong angle: 180

Item Table

         Item              Value     Threshold  Converged?
 Maximum Force            0.000000     0.000450     YES
 RMS     Force            0.000000     0.000300     YES
 Maximum Displacement     0.000000     0.001800     YES
 RMS     Displacement     0.000001     0.001200     YES


Link to data:media:H2 OPT.LOG

H2 Dynamic Image

H

Link to file:(File:H2 OPT.LOG)

H2 Vibration Data

no negative frequencies shown therefore the optimization worked. For this molecule there is no change in dipole moment as electronegativites of atom within the molecule are the same and so intensity for peak is very small and the peak would be seen on a spectrum

Haber-Bosch Process Analysis

below is the energy values used to determine the energy for the reaction of N2 + 3H2 -> 2NH3

   E(NH3)= -56.55776873
   2*E(NH3)= -113.11553746
   E(N2)= -109.52412868
   E(H2)= -1.17853936
   3*E(H2)= -3.53561808
   ΔE=2*E(NH3)-[E(N2)+3*E(H2)]= -0.05579070= -146.48 kJ mol-1

The negative value for ΔE suggests that this reaction is exothermic therefore this means that the product is lower in energy than the products so ammonia is more stable than the reactants

S2 optimization

Summary Details

calculation method: RB3LYP

basis set: 6-31G(d,p)

final energy: -796.32599779 au

RMS gradient: 0.00000372 au

point group: D∞h

optimized S-S bond length: 1.92943 A

optimized bong angle: 180

Charges on both S atoms are 0 as they are the same atom and have the same electronegativity values so both pull electron density towards each other the same amount

Item Table

         Item              Value     Threshold  Converged?
 Maximum Force            0.000006     0.000450     YES
 RMS     Force            0.000006     0.000300     YES
 Maximum Displacement     0.000011     0.001800     YES
 RMS     Displacement     0.000016     0.001200     YES


Link to data:media:S2 OPT 2.LOG

S2 Dynamic Image

S

Link to file:(File:S2 OPT 2.LOG)

S2 Vibration Data

no negative frequencies shown therefore the optimization worked. For this molecule there is no change in dipole moment as electronegativites of atom within the molecule are the same and so intensity for peak is very small and the peak would be seen on a spectrum

Molecular Orbital Analysis

These two images above show both the bonding (2σg) and anti-bonding (2σu*) molecular orbitals formed when the 2s atomic orbitals on both sulfur atoms combine. As shown in the image these orbitals are low in energy relative to the orbitals and because they are so low in energy they dont contribute much to chemical bonding. The bonding orbital is lower in energy than the anti-bonding orbital (0.0001au difference between them) and both molecular orbitals are fully occupied by electrons . Also shown in the image is the energies for the 1s molecular orbitals which i much lower in energy than the 2s orbitals and are also not involved in chemical bonding.


These two images above show both the HOMO (highest occupied molecular orbital) and LUMO (lowest unoccupied molecular orbital, meaning its unfilled) which are formed through the combination of the 3p atomic orbitals on both sulfur atoms and have the label 3πg* (two p orbitals on one atom combine with another two from the other atom orthogonal to the inter nuclear axis in the formation of these MOs). These molecular orbitals are involved in chemical bonding and are very similar in energy. The label of these orbitals shown depends on which p-orbitals were involved in there formation. Both the HOMO and LUMO are anti-bonding orbitals and because the HOMO is an anti-bonding interaction this makes the corresponding bond very reactive

This image shows the molecular orbital 3πu meaning that this is the bonding orbital (meaning that the 3p orbitals which combined to form this were in phase) which corresponds to the HOMO and LUMO as for . This molecular orbital is relatively high in energy and is filled with electrons