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Rep:Mod:RumanAhmedsNH3Stuff

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NH3

Molecule

Optimised Ammonia

Molecule Information

Molecule Name: Ammonia

Calculation Method: RB3LYP

Basis Set: 6-31G(d.p)

Final Energy: E(RB3LYP) = -56.55776873 au

RMS Gradient: 0.00000485 au

Point Group: C3v

Bond Length: 1.01798 +- 0.01A

Bond Angle: 105.741 +- 1°

The optimisation file can be accessed by clicking here


Item               Value     Threshold  Converged?
 Maximum Force            0.000004     0.000450     YES
 RMS     Force            0.000004     0.000300     YES
 Maximum Displacement     0.000072     0.001800     YES
 RMS     Displacement     0.000035     0.001200     YES
 Predicted change in Energy=-5.986274D-10
 Optimization completed.
    -- Stationary point found.

Vibrations

Wavenumber Symmetry Intensity (au)
1090 A1 145
1694 E 14
1694 E 14
3461 A1 1
3590 E 0
3590 E 0

Questions on Vibrations

1) Modes expected from 3N-6 rule: 3*4-6=6

2) Degenerate Modes: Modes with wavenumbers 1694cm-1 and modes with wavenumbers 3590cm-1

3) Bending Vibrations: 1090cm-1 and 1694cm-1 Bond Stretches: 3461cm-1 and 3590cm-1

4) Highly Symmetric Modes: 3461cm-1 and 1090cm-1

5) Umbrella Mode: 1090cm-1

6) 2 bands

Charge Analysis

Charge on each H: +0.375

Charge on N: -1.125

Overall Charge on Ammonia: 0

The expected charge values for each Hydrogen would be above 0 and below +1, and each Hydrogen would have the same charge value. The expected charge value on the Nitrogen would be -3 multiplied by the charge value of 1 Hydrogen, below 0 and above -3. This is because the N-H bond is polar, due to the Nitrogen being highly electronegative when compared to Hydrogen, so electron density in the N-H bond is withdrawn by the Nitrogen. Because the electron density isn't fully withdrawn, the charge values on each Hydrogen would be greater than 0, but less than 1. And the charge value of the Nitrogen would be -3 multiplied by the charge on a single Hydrogen atom in the molecule.


N2

Molecule

Optimised Nitrogen

Molecule Information

Molecule Name: Nitrogen

Calculation Method: RB3LYP

Basis Set: 6-31G(d.p)

Final Energy: E(RB3LYP) = -109.52412868 au

RMS Gradient: 0.02473091 au

Point Group: DinfH

Bond Length: 1.10550 +- 0.01A

Bond Angle: There is no bond angle because it is a diatomic molecule.

The optimisation file can be accessed by clicking here


         Item               Value     Threshold  Converged?
 Maximum Force            0.000001     0.000450     YES
 RMS     Force            0.000001     0.000300     YES
 Maximum Displacement     0.000000     0.001800     YES
 RMS     Displacement     0.000000     0.001200     YES
 Predicted change in Energy=-3.401012D-13
 Optimization completed.
    -- Stationary point found.

Vibrations

Wavenumber Symmetry Intensity (au) !
2457 SSG 0

N2 has a single band and is IR inactive.

Charge Analysis

Charge on each Nitrogen atom: 0

Overall Charge on N2: 0

Expected charge on each Nitrogen: 0

Expected charge across entire molecule: 0

The two atoms in N2 are the same; both are Nitrogen. Because of this, they have equal electronegativities and the bond will not be polar.

H2

Molecule

Optimised Hydrogen

Molecule Information

Molecule Name: Hydrogen

Calculation Method: RB3LYP

Basis Set: 6-31G(d.p)

Final Energy: E(RB3LYP) = -1.17853936 au

RMS Gradient: 0.00000017 au

Point Group: DinfH

Bond Length: 0.74279 +- 0.01A

Bond Angle: There is no bond angle because it is a diatomic molecule.

The optimisation file can be accessed by clicking here


         Item               Value     Threshold  Converged?
 Maximum Force            0.000000     0.000450     YES
 RMS     Force            0.000000     0.000300     YES
 Maximum Displacement     0.000000     0.001800     YES
 RMS     Displacement     0.000001     0.001200     YES
 Predicted change in Energy=-1.164080D-13
 Optimization completed.
    -- Stationary point found.

Vibrations

Wavenumber Symmetry Intensity (au) !
4466 SSG 0

H2 has a single band and is IR inactive.

Charge Analysis

Charge on each Hydrogen atom: 0

Overall Charge on H2: 0

Expected charge on each Hydrogen: 0

Expected charge across entire molecule: 0

The two atoms in H2 are the same; both are Hydrogen. Because of this, they have equal electronegativities and the bond will not be polar.

ConQuest/CCDC

Unique Identifier for complex: GIKGOW01

Link to complex: this is the link

H-H bond in complex: 0.9080 A

Difference in bond lengths: H-H bond in complex is 0.16521 A longer.

The H-H bond in the metal complex is longer due to the Rhenium bonded to one of the Hydrogens in the H-H bond. The Re-H bond withdraws electron density from the H-H bond, weakening the bond. The weakening of the bond causes the bond to elongate.

Energies

E(NH3)= -56.5577687 au

2*E(NH3)= -113.1155375 au

E(N2)= -109.5241287 au

E(H2)= -1.1785394 au

3*E(H2)= -3.5356181 au

ΔE=2*E(NH3)-[E(N2)+3*E(H2)]= -0.0557907 au

                          = -146.4784829 KJ/mol (au value multiplied by 2625.5)

All values are to 7 dp

The value for ΔE is highly negative, indicating that the reaction is highly exothermic, so energy is released. Therefore, the Ammonia gas is ~146.5 KJ/mol more stable than the reactants.

CO

Molecule

Optimised Carbon Monoxide

Molecule Information

Molecule Name: Carbon Monoxide

Calculation Method: RB3LYP

Basis Set: 6-31G(d.p)

Final Energy: E(RB3LYP) = -113.30945313 au

RMS Gradient: 0.00010485 au

Point Group: C*v

Bond Length: 1.13786 +- 0.01A

Bond Angle: There is no bond angle because it is a diatomic molecule.

The optimisation file can be accessed by clicking here


         Item               Value     Threshold  Converged?
 Maximum Force            0.000182     0.000450     YES
 RMS     Force            0.000182     0.000300     YES
 Maximum Displacement     0.000072     0.001800     YES
 RMS     Displacement     0.000101     0.001200     YES
 Predicted change in Energy=-1.301714D-08
 Optimization completed.
    -- Stationary point found.

Vibrations

Wavenumber Symmetry Intensity (au) !
2210 SG 70

CO has a single band and is IR active.

Charge Analysis

Charge on Carbon: +0.506

Charge on Oxygen: -0.506

Overall Charge on Carbon Monoxide: 0

Expected charge on Carbon: 0 < Q1 < +1

Expected charge on Oxygen: -Q1 ( -1 < Q2 < 0)

Expected charge across entire molecule: 0

Oxygen has a higher electronegativity than carbon, so electrons within the C-O triple bond will be withdrawn by the oxygen, causing the Carbon to be slightly positively charged, and the Oxygen to become slightly negatively charged.

Molecular Orbital Information

HOMO

This is the HOMO of Carbon Monoxide. It shows mainly p orbital character. It is an occupied antibonding orbital with sigma* interactions, mainly contributed to by the 2pz orbitals from both Carbon and Oxygen.

LUMO

This is the LUMO of Carbon Monoxide. It shows mainly p orbital character. It is an unoccupied antibonding pi* orbital, and is mainly contributed to by the 2px orbital from Carbon and the 2px orbital from Oxygen, both of which are out of phase. The 2px orbital from Oxygen is very bloated, which could be due to s interactions with the 2px orbital, making it larger than a typical p orbital.

6th MO

This is the 6th Molecular Orbital in Carbon Monoxide. It shows p orbital character. It is an occupied bonding pi orbital, and is contributed to by the 2py orbitals from both Carbon and Oxygen, both of which are in phase.

1st MO

This is the 1st Molecular Orbital of Carbon Monoxide. It shows s orbital character. It is occupied, and it's very deep in energy, therefore it cannot take part in bonding. It is almost solely contributed to by the 1s orbital from Oxygen.

4th MO

This is the 4th Molecular Orbital of Carbon Monoxide. It shows mainly s character. It is an occupied bonding orbital, and is mainly contributed to by the 2s orbital of Carbon and the 2s orbital of Oxygen, however there is a significant amount of contribution from the 2px orbitals of both Carbon and Oxygen too.

Marking

Note: All grades and comments are provisional and subject to change until your grades are officially returned via blackboard. Please do not contact anyone about anything to do with the marking of this lab until you have received your grade from blackboard.

Wiki structure and presentation 1/1

Is your wiki page clear and easy to follow, with consistent formatting?

YES

Do you effectively use tables, figures and subheadings to communicate your work?

YES

NH3 1/1

Have you completed the calculation and given a link to the file?

YES

Have you included summary and item tables in your wiki?

YES

Have you included a 3d jmol file or an image of the finished structure?

YES

Have you included the bond lengths and angles asked for?

YES

Have you included the “display vibrations” table?

YES

Have you added a table to your wiki listing the wavenumber and intensity of each vibration?

YES

Did you do the optional extra of adding images of the vibrations?

YES

Have you included answers to the questions about vibrations and charges in the lab script?

YES

N2 and H2 0.5/0.5

Have you completed the calculations and included all relevant information? (summary, item table, structural information, jmol image, vibrations and charges)

YES

Crystal structure comparison 0.5/0.5

Have you included a link to a structure from the CCDC that includes a coordinated N2 or H2 molecule?

YES

Have you compared your optimised bond distance to the crystal structure bond distance?

YES

Haber-Bosch reaction energy calculation 1/1

Have you correctly calculated the energies asked for? ΔE=2*E(NH3)-[E(N2)+3*E(H2)]

YES

Have you reported your answers to the correct number of decimal places?

YES

Do your energies have the correct +/- sign?

YES

Have you answered the question, Identify which is more stable the gaseous reactants or the ammonia product?

YES

Your choice of small molecule 4/5

Have you completed the calculation and included all relevant information?

YES

Have you added information about MOs and charges on atoms?

YES, overall good explanations. Some of your MO explanations are incorrect however, for example for MO4 I don't see any p character on the carbon atom. Also the carbon is the grey atom and the oxygen the red one, you seen to have mixed them up in some calculations.

Independence 0/1

If you have finished everything else and have spare time in the lab you could: Check one of your results against the literature, or Do an extra calculation on another small molecule, or Do some deeper analysis on your results so far

No independent work found.