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NH3 Molecule

Calculation Method; RB3LYP

Basis Set; 6-31G(d,p)

Final Energy - E(RB3LYP); -56.55776873 au

RMS Gradient; 0.00000485

Point Group; C3V

Optimized N-H bond length; 1.01798 A

Optimized H-N-H bond angle; 105.741°

         Item               Value     Threshold  Converged?
 Maximum Force            0.000004     0.000450     YES
 RMS     Force            0.000004     0.000300     YES
 Maximum Displacement     0.000072     0.001800     YES
 RMS     Displacement     0.000035     0.001200     YES
NH3 Optimized Molecule

File:EBR NH3 OPT POP.LOG

Vibrations

There are 6 vibrational modes observed, as expected from the 3N-6 rule because we have 4 atoms and; 3(4)-6=6. There are 2 pairs of degenerate modes; 2&3 and 5&6 (from the table above). It can also be seen that 1, 2, & 3 are bending vibrations and 4, 5, & 6 are stretching vibrations. The stretching vibration 4 is highly symmetric and bending vibration 1 is known as the "umbrella mode". In an experimental spectrum of gaseous ammonia, 3 bands would be expected to be seen due to the 2 pairs each only showing 1 band between the pair (2), and the highly symmetric mode, 4, not showing a band in the IR spectrum due to this symmetry and then the final mode, 1, showing another band (1).

Charges

Charge on N atom; -1.125

Charge on H atoms; 0.375

These charges are as would be expected due to nitrogen being the more electronegative atom of the two.

N2 Molecule

Calculation Method; RB3LYP

Basis Set; 6-31G(d,p)

Final Energy - E(RB3LYP); -109.52412868 au

RMS Gradient; 0.00000060

Point Group; Dinfh

Optimized N-N bond length; 1.10550 A

         Item               Value     Threshold  Converged?
 Maximum Force            0.000001     0.000450     YES
 RMS     Force            0.000001     0.000300     YES
 Maximum Displacement     0.000000     0.001800     YES
 RMS     Displacement     0.000000     0.001200     YES


N2 Optimized Molecule


File:EBR N2 OPT POP.LOG

Vibrations

There is only one stretching vibrational mode observed in N2 and, due to the symmetry of the molecule, it is not seen in the IR spectrum. Only one is expected, due to the 3N-5 rule of 2-atom molecules.

Charges

Charge on N atom; 0.00

As expected, there is no charge on either N atom as they are equivalent and so there is no overall net charge.

H2 Molecule

Calculation Method; RB3LYP

Basis Set; 6-31G(d,p)

Final Energy - E(RB3LYP); -1.17853936 au

RMS Gradient; 0.00000017

Point Group; Dinfh

Optimized H-H bond length; 0.74279 A

         Item               Value     Threshold  Converged?
 Maximum Force            0.000000     0.000450     YES
 RMS     Force            0.000000     0.000300     YES
 Maximum Displacement     0.000000     0.001800     YES
 RMS     Displacement     0.000001     0.001200     YES


H2 Optimized Molecule


File:EBR H2 OPT POP.LOG

Vibrations

There is only one stretching vibrational mode observed in H2 as expected, from the 3N-5 rule of 2-atom molecules. Again, due to the symmetry of the molecule, the vibration is also not seen in the IR spectrum.

Charges

Charge on H atom; 0.00

As expected, there is no charge on either of the H atoms as they are equivalent to each other and so there is no overall net charge.

The Haber-Bosch Process

Ammonia can be synthesized in a reaction known as the Haber-Bosch process where gaseous hydrogen and nitrogen are reacted together to form ammonia. it is a reversible process with specific conditions to ensure a good yield and rate of reaction of the product, ammonia.

                N2 + 3H2 --> 2NH3

E(NH3)= -56.55776873

2*E(NH3)= -113.11553746

E(N2)= -109.52412868

E(H2)= -1.17853936

3*E(H2)= -3.53561808

ΔE=2*E(NH3)-[E(N2)+3*E(H2)]= -0.0557907 au = -146.48 kJ/mol

This value of -146.48 kJ/mol is much higher than that of literature values around -45.7 kJ/mol [1]

Ammonia, the product, is more stable; as indicated by the negative energy change so the products are obviously of lower energy and most stable.

C=O Molecule

Calculation Method; RB3LYP

Basis Set; 6-31G(d,p)

Final Energy - E(RB3LYP); -113.30945314 au

RMS Gradient; 0.00001828

Point Group; Cinfv

Optimized C=O bond length; 1.13793 A

         Item               Value     Threshold  Converged?
 Maximum Force            0.000032     0.000450     YES
 RMS     Force            0.000032     0.000300     YES
 Maximum Displacement     0.000012     0.001800     YES
 RMS     Displacement     0.000018     0.001200     YES
C=O Optimized Molecule

File:EBR CO OPT POP.LOG

Vibrations

There is only one vibration seen in the molecule of C=O- a stretch of the double bond.

Charges

Charge on C atom; 0.506

Charge on O atoms; -0.506

The charges on the two atoms and equal but opposite; as expected on a 2 atom molecule with no net charge. Also, as expected, the oxygen is the atom with the negative charge; it is the more electronegative charge so is the atom most able to attract the electrons in the bond.

Molecular Orbitals

Molecular Orbital 1

Molecular Orbital 2

Molecular orbitals 1 and 2 show the bonding and antibonding orbitals of the two 1s AO's. they are very deep in energy at -19.25805 and -10.30433, respectively, this is much deeper than the valence MO's and thus we know that they do not take part in the chemical bonding of the molecule.

Molecular Orbital 3; This is the highest occupied molecular orbital (HOMO), formed from the mixing of 2s and 2p orbitals of the carbon and oxygen. It is a bonding orbital (5σ).

Molecular Orbital 4; This is the lowest unoccupied molecular orbital (LUMO), it is the corresponding antibonding orbital (2π) to the MO below (1π).

Molecular Orbital 5; This is the bonding orbital formed from the two 2p AO's. It is the first π MO to occur in the molecule of C=O.

Formation of C=O

One way to synthesise C=O is from the reaction of carbon dioxide, CO2, with hydrogen gas to form C=O and water.


                CO2 (g) + H2(g) --> CO(g) + H2O(g)


CO2

Calculation Method; RB3LYP

Basis Set; 6-31G(d,p)

Final Energy - E(RB3LYP); -188.58093945 au

RMS Gradient; 0.00001154

Point Group; Dinfh

Optimized C-O bond length; 1.16915 A

Optimized O-C-O bond angle; 180°

         Item               Value     Threshold  Converged?
Maximum Force            0.000024     0.000450     YES
RMS     Force            0.000017     0.000300     YES
Maximum Displacement     0.000021     0.001800     YES
RMS     Displacement     0.000015     0.001200     YES
CO2 Optimized Molecule

File:EBR CO2 OPT POP.LOG


H2O

Calculation Method; RB3LYP

Basis Set; 6-31G(d,p)

Final Energy - E(RB3LYP); -76.41973740 au

RMS Gradient; 0.00006276

Point Group; C2V

Optimized O-H bond length; 0.96522 A

Optimized H-O-H bond angle; 103.745°

       Item               Value     Threshold  Converged?
Maximum Force            0.000099     0.000450     YES
RMS     Force            0.000081     0.000300     YES
Maximum Displacement     0.000115     0.001800     YES
RMS     Displacement     0.000120     0.001200     YES
H2O Optimized Molecule

File:EBR H2O OPT POP.LOG


CO2 (g) + H2(g) --> CO(g) + H2O(g)

E(CO)= -113.30945314

E(H2O)= -76.41973740

E(CO2)= -188.58093945

E(H2)= -1.17853936

ΔE= [E(CO)+E(H20)]-[E(CO2)+E(H2)]= 0.03028827 au = 79.52 kJ/mol

This value of 79.52 kJ/mol is higher than that of the literature value of 41 kJ/mol[2], this may be due to approximations used in Gaussian leading to this error.

H2CO Molecule

Calculation Method; RB3LYP

Basis Set; 6-31G(d,p)

Final Energy - E(RB3LYP); -114.50319933 au

RMS Gradient; 0.00007386

Point Group; CS

Optimized C=O bond length; 1.20676 A

Optimized C-H bond length; 1.11056 A

         Item               Value     Threshold  Converged?
 Maximum Force            0.000197     0.000450     YES
 RMS     Force            0.000085     0.000300     YES
 Maximum Displacement     0.000232     0.001800     YES
 RMS     Displacement     0.000149     0.001200     YES
HC=O Optimized Molecule

File:EBR H2CO OPT POP.LOG

Vibrations

There are 6 non degenerate vibrational modes of H2CO.

Charges

Charge on C atom; 0.221

Charge on O atom; -0.494

Charge on H atoms; 0.137

These charges are as would be expect because the O atom is the most electonegative however the C=O bond is not as polar as the C=O bond in the C=O molecule above due to the hydrogen's also having a positive electronegativity.

Preparation of Formaldehyde

H2CO can be prepared via the dehydrogenation of methane, CH3OH.

              CH3OH --> CH2O + H2


CH3OH


Calculation Method; RB3LYP

Basis Set; 6-31G(d,p)

Final Energy - E(RB3LYP); -115.72396437 au

RMS Gradient; 0.00001494

Point Group; C1

Optimized C-O bond length; 1.41811 A

Optimized C-H bond length; 1.09302 A

Optimized O-H bond length; 0.96520 A

          Item               Value     Threshold  Converged?
 Maximum Force            0.000038     0.000450     YES
 RMS     Force            0.000020     0.000300     YES
 Maximum Displacement     0.000507     0.001800     YES
 RMS     Displacement     0.000240     0.001200     YES
HCOH Optimized Molecule

File:EBR H3COH OPT POP.LOG


CH3OH --> CH2O + H2

E(CH2O)= -114.50319933

E(H2)= -1.17853936

E(CH3OH)= -115.72396437

ΔE= [E(CH2O)+E(H2)]-[E(CH3OH)]= 0.04222568 au = 110.86 kJ/mol

The value of 110.86 kJ/mol is slightly higher than the literature value of 84 kJ/mol [3] but it much closer than other enthalpies calculated above using Gaussian.

References

  1. Modak, J. M. (2002). Haber Process for Ammonia Synthesis. Resonance.
  2. Higman, C., & van der Burgt, M. (2003). Gassification.
  3. REUS, G., DISTELDORF, W., OTTO GAMER, A., & HILT, A. (n.d.). Formaldehyde. Ullmann's Encyclopedia of Industrial Chemistry.