Jump to content

Rep:Mod:01381641

From ChemWiki

Optimisation of an NH3 Molecule

Summary

Calculation Method: RB3LYP

Basis Set: 6-31G(d,p)

Final Energy, E:-56.55776873

Point Group: C3v

RMS gradient: 0.00000485

Optimisation Output


         Item                Value     Threshold  Converged?
 Maximum Force            0.000004     0.000450     YES
 RMS     Force            0.000004     0.000300     YES
 Maximum Displacement     0.000072     0.001800     YES
 RMS     Displacement     0.000035     0.001200     YES


File:SHAZEEN PHUNT NH3 OPTF POP.LOG

Ammonia

N-H Bond Length - 1.01798 au

H-N-H Bond Angle - 105.7o

From the valence shell electron repulsion theory, a bond angle of around 107o would be expected so the angle of 105.7 is a good output after optimisation as it is close.

Ensuring optimisation has completed correctly

No negative frequencies present so optimisation completed correctly.

Analysis

Modes expected from the 3N-6 rule: 6

Degenerate Modes: 2 & 3, 5 & 6

'Bending' Vibrations Modes: 1, 2, 3

'Stretching' Vibrations Modes: 4, 5, 6

Highly Symmetric Mode: 4

'Umbrella' Mode: 1

Symmetric Stretch: 4

There would be 2 bands expected in an experimental spectrum of gaseous ammonia which would be for modes 1 & 2/3. Modes 2 and 3 are degenerate so would have the same band. The rest of the modes would not be seen as the intensity is too low. This is because the vibrations do not cause a change in dipole moment hence are not infrared active.

Charge on N-atom: -1.125 Charge on H-atom: 0.375

As nitrogen is more electronegative than hydrogen, it would draw most of the electron density towards itself giving itself a negative charge compared to hydrogen which would have a positive charge.

Optimisation of an N2

Summary

Calculation Method: RB3LYP

Basis Set: 6-31G(d,p)

Total Energy: -109.52412868 a.u.

RMS Gradient: 0.00000060 a.u.

Point Group: D∞h

Optimisation Output


         Item                Value     Threshold  Converged?
 Maximum Force            0.000001     0.000450     YES
 RMS     Force            0.000001     0.000300     YES
 Maximum Displacement     0.000000     0.001800     YES
 RMS     Displacement     0.000000     0.001200     YES

N2

File:SHAZEEN N2 CALCULATION.LOG

Ensuring optimisation completed correctly

No negative frequencies present therefore optimisation completed successfully

Optimisation of a H2

Summary

Calculation Method: RB3LYP

Basis Set: 6-31G(d,p)

Total Energy, E: -1.17853936 a.u.

RMS Gradient: 0.00000017 a.u.

Point Group: D∞h

Optimisation Output

        Item               Value     Threshold  Converged?
Maximum Force            0.000000     0.000450     YES
RMS     Force            0.000000     0.000300     YES
Maximum Displacement     0.000000     0.001800     YES
RMS     Displacement     0.000001     0.001200     YES

File:SHAZEEN H2 CALCULATION.LOG

H2

No negative frequencies suggest optimisation completed correctly.

Evaluating The Haber-Bosch Process

A Hess Cycle can be used to calculate the enthalpy of the reaction:

E(NH3)= -56.55776873 a.u.

2*E(NH3)= -113.11553746 a.u.

E(N2)= -109.52412868 a.u.

E(H2)= -1.17853936 a.u.

3*E(H2)= -3.53561808 a.u.

ΔE=2*E(NH3)-[E(N2)+3*E(H2)]= -0.0557907 a.u.

ΔE in KJ/mol: -146.47849401

The negative value for ΔE suggests the reaction is exothermic, therefore releasing energy. This means that NH3 is more stable than nitrogen and hydrogen as it has less energy.

Optimisation of a F2 Molecule

Summary

Calculation Method: RB3LYP

Basis Set: 6-31G(d,p)

Total Energy, E: -199.42620785

RMS Gradient: 0.23253407

Point Group: D∞h

Optimisation Output

         Item               Value     Threshold  Converged?
 Maximum Force            0.000128     0.000450     YES
 RMS     Force            0.000128     0.000300     YES
 Maximum Displacement     0.000156     0.001800     YES
 RMS     Displacement     0.000221     0.001200     YES

File:SAA F2 OPTIMISATION.LOG

F2

No negative frequencies can be seen suggesting optimisation has completed correctly.

Charges on individual F atoms: 0

F2 is expected to be neutral molecule with no dipole as the individual atoms are the same so the electron density is shared equally.

Molecular Orbitals

The electronic configuration of a nitrogen atom is 1s22s22p5. When the fluorine atoms combine to from F2, the atomic orbitals (AOs) combine to form molecular orbitals (MOs).

The core 1s atomic orbitals are so far apart in energy that they do not overlap so become non-bonding orbitals being held tightly to their respective nuclei and are not involved in chemical bonding. They are very deep in energy, -24.797 au which is much deeper than the molecular orbitals formed from the valence shell atomic orbitals shown below.

Molecular Orbital 3 is the bonding combination of the 2s atomic orbitals and 4 is the antibonding combination. The overlap is stronger with a greater energy. The bonding overlap is really strong which is why one extensive surface is seen. There is also a greater difference between the bonding and antibonding orbitals due to the better overlap.

The bonding molecular orbital 5 is formed from the overlap of the 2p orbitals in the plane of the bond, forming the sigma bond. MOs 6 and 7 are also bonding combinations of the two 2p orbitals but in the orthogonal directions and are degenerate (have the same energy).