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NH3 Molecule

Summary

Calculation Method RB3LYP

Basis Method 6-31G(d.p)

Final energy E(RB3LYP) -56.55776873 a.u.

RMS gradient 0.00000485a.u.

Point group C3V

Bond Length (N-H) 1.01798 Å

Optimised Bond Angle (H-N-H) 105.741°

Item table

        Item               Value     Threshold  Converged?
Maximum Force            0.000004     0.000450     YES
RMS     Force            0.000004     0.000300     YES
Maximum Displacement     0.000072     0.001800     YES
RMS     Displacement     0.000035     0.001200     YES
Predicted change in Energy=-5.986288D-10
Optimization completed.
   -- Stationary point found.
                          ----------------------------
                          !   Optimized Parameters   !
                          ! (Angstroms and Degrees)  !
--------------------------                            --------------------------
! Name  Definition              Value          Derivative Info.                !
--------------------------------------------------------------------------------
! R1    R(1,2)                  1.018          -DE/DX =    0.0                 !
! R2    R(1,3)                  1.018          -DE/DX =    0.0                 !
! R3    R(1,4)                  1.018          -DE/DX =    0.0                 !
! A1    A(2,1,3)              105.7412         -DE/DX =    0.0                 !
! A2    A(2,1,4)              105.7412         -DE/DX =    0.0                 !
! A3    A(3,1,4)              105.7412         -DE/DX =    0.0                 !
! D1    D(2,1,4,3)           -111.8571         -DE/DX =    0.0                 !
--------------------------------------------------------------------------------
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File:SIMRAN NH3 OPT.log

Optimised NH3 molecule

Media:SIMRAN_NH3_OPT.log

Vibrations

NH3 Vibrations

How many modes do we expect 6

Which modes are degenerate 2 and 3; 5 and 6

Which modes are bending 1 and 2 and 3

Which modes are bond strength 4 and 5 and 6

Which mode is highly symmetric 4 Which mode is the umbrella mode 1 How many bands do we expect in the experimental spectrum of gaseous ammonia 2

Charges

Charge on the N atom -1.125

Charge on each of the H atoms 0.375

Explaining charges It is as expected that the N would have a negative charge and that the Hs would be positive as N is the more electronegative atom. The molecule is neutral overall and the 3 Hs are equivalent so the -1.125 charge is stabilised equally by the 3 Hs (1.125/3=0.375).

N2 Molecule

Summary

Calculation Method RB3LYP

Basis Method 6-31G(d,p)

Final energy E(RB3LYP) -109.52412868 a.u.

RMS gradient 0.0000060 a.u.

Point group D*H

Bond Length (N-N) 1.10550 Å

Optimised Bond Angle (N-N) 180°

Item table

        Item               Value     Threshold  Converged?
Maximum Force            0.000001     0.000450     YES
RMS     Force            0.000001     0.000300     YES
Maximum Displacement     0.000000     0.001800     YES
RMS     Displacement     0.000000     0.001200     YES
Predicted change in Energy=-3.401107D-13
Optimization completed.
   -- Stationary point found.
                          ----------------------------
                          !   Optimized Parameters   !
                          ! (Angstroms and Degrees)  !
--------------------------                            --------------------------
! Name  Definition              Value          Derivative Info.                !
--------------------------------------------------------------------------------
! R1    R(1,2)                  1.1055         -DE/DX =    0.0                 !
--------------------------------------------------------------------------------
GradGradGradGradGradGradGradGradGradGradGradGradGradGradGradGradGradGrad

File:SIMRAN N2 OPT.LOG

Optimised N2 molecule

Media:SIMRAN_N2_OPT.LOG

N2 Vibrations

Vibrations

How many modes do we expect 1

Which modes are degenerate Not applicable

Which modes are bending 0

Which modes are bond strength 1

Which mode is highly symmetric 1

Which mode is the umbrella mode Not applicable

How many bands do we expect in the experimental spectrum of gaseous Nitrogen 0

Charges

Charge on each N atom 0

Explaining charges Nitrogen is a neutral molecule, both Ns are equivalent so both have 0 charge.

H2 Molecule

Calculation Method RB3LYP

Basis Set 6-31G(d,p)

Final energy E(RB3LYP) -1.17853936 a.u.

RMS gradient 0.00000017 a.u.

Point group D*H

Bond Length (H-H) 0.74279 Å

Optimised Bond Angle (H-H) 180°

Item table

        Item               Value     Threshold  Converged?
Maximum Force            0.000000     0.000450     YES
RMS     Force            0.000000     0.000300     YES
Maximum Displacement     0.000000     0.001800     YES
RMS     Displacement     0.000001     0.001200     YES
Predicted change in Energy=-1.164080D-13
Optimization completed.
   -- Stationary point found.
                          ----------------------------
                          !   Optimized Parameters   !
                          ! (Angstroms and Degrees)  !
--------------------------                            --------------------------
! Name  Definition              Value          Derivative Info.                !
--------------------------------------------------------------------------------
! R1    R(1,2)                  0.7428         -DE/DX =    0.0                 !
--------------------------------------------------------------------------------
GradGradGradGradGradGradGradGradGradGradGradGradGradGradGradGradGradGrad

File:SIMRAN H2 OPT.LOG

Optimised H2 molecule

Media:SIMRAN_H2_OPT.LOG

H2 Vibrations

Vibrations

How many modes do we expect 1

Which modes are degenerat Not applicable

Which modes are bending 0

Which modes are bond strength 1

Which mode is highly symmetric 1

Which mode is the umbrella mode Not applicable

How many bands do we expect in the experimental spectrum of gaseous Hydrogen 0

Charge on each H atom 0

Explaining charges

Hydrogen is a neutral molecule, both Hs are equivalent so both have 0 charge.

Reaction Energies

E(NH3)= -56.55776873 a.u.
2*E(NH3)= -113.1155375 a.u.
E(N2)= -109.52412868 a.u.
E(H2)= -1.17853936 a.u.
3*E(H2)= -3.53561808 a.u.
ΔE=2*E(NH3)-[E(N2)+3*E(H2)]= -0.0557907 a.u. 

-0.0557907 a.u. x 2625.5 = -146.4784829 kJ/mol

Explanation This is an exothermic reaction, so the products are more stable than the reactants.

Literature The value in the literature was -99.2 kJ/mol. This is not too far off our value however, there may be differences due to limitations in the computers optimization. [1]


O2 Molecule

Summary

Calculation Method RB3LYP

Basis Set 6-31G(d,p)

Final energy E(RB3LYP) -150.25742434 a.u.

RMS gradient 0.00007502 a.u.

Point group D*H

Bond Length (N-H) 1.21602 Å

Optimised Bond Angle (H-N-H) 180°

Item table

       Item               Value     Threshold  Converged?
Maximum Force            0.000130     0.000450     YES
RMS     Force            0.000130     0.000300     YES
Maximum Displacement     0.000080     0.001800     YES
RMS     Displacement     0.000113     0.001200     YES
Predicted change in Energy=-1.033738D-08
Optimization completed.
   -- Stationary point found.
                          ----------------------------
                          !   Optimized Parameters   !
                          ! (Angstroms and Degrees)  !
--------------------------                            --------------------------
! Name  Definition              Value          Derivative Info.                !
--------------------------------------------------------------------------------
! R1    R(1,2)                  1.216          -DE/DX =   -0.0001              !
--------------------------------------------------------------------------------
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File:SIMRAN O2 OPT.log

Optimised O2 molecule

Media:SIMRAN_O2_OPT.log

Vibrations

O2 Vibrations

How many modes do we expect 1

Which modes are degenerate Not applicable

Which modes are bending 0

Which modes are bond strength 1

Which mode is highly symmetric 1

Which mode is the umbrella mode Not applicable

How many bands do we expect in the experimental spectrum of gaseous oxygen 0

Charges

Charge on each O atom 0.375

Explaining charges Oxygen is a neutral molecule, both Os are equivalent so both have 0 charge.


Molecular orbitals

In the transparent orbital pictures we can determine some information about the orbitals above.

1) These orbitals are not interacting. It's occupied. 2) These MOs are made of 2 s orbitals, they are out of phase therefore they are antibonding orbitals. It's occupied. 3) These MOs are made up from the 2p AOs. It's occupied. 4) These MOs are pi orbitals; made of p AOs. It's occupied. 5) These MOs are 2 p orbitals out of phase, therefore they are antibonding. They are unoccupied. This is the LUMO as it is the lowest energy orbital without any electrons in.

References

[1] Periodicity, Quantitative equilibrium and Functional group chemistry Nelson Advanced Science Series