Ahp3018
NH3
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Optimised N-H bond length (Å) | 1.01798 |
Optimised H-N-H bond angle (°) | 105.741] |
Due to a compromise between accuracy and speed of calculation, these values will have some uncertainty. Bond length is accurate to ≈ 0.01Å; bond angle is accurate to ≈ 1°
Molecule | NH3 |
Calculation method | RB3LYP |
Basis Set | 6-31G(d.p) |
Final energy E(RB3LYP) (a.u.) | -56.55776873 |
RMS gradient (a.u.) | 0.00000485 |
Point group | C3V |
Item Value Threshold Converged? Maximum Force 0.000004 0.000450 YES RMS Force 0.000004 0.000300 YES Maximum Displacement 0.000072 0.001800 YES RMS Displacement 0.000035 0.001200 YES
Ammonia molecule |
The optimisation file is linked to here
Wavenumber (cm-1) | 1090 | 1694 | 1694 | 3461 | 3590 | 3590 |
Symmetry | A1 | E | E | A1 | E | E |
IR Intensity (KM/mol) | 145 | 14 | 14 | 1 | 0 | 0 |
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File:Ahp nh6 vib1.gif |
Frequency analysis
how many modes do you expect from the 3N-6 rule? (3*4) – 6 = 6 modes Which modes are degenerate (ie have the same energy)? Both E symmetries (1694 cm-1 and 3590 cm-1 Which modes are “bending” vibrations and which are “bond stretch” vibrations? 1090 cm-1 (A1) bending 1694 cm-1 (E) stretching 1694 cm-1 (E) bending 3461 cm-1 (A1) stretching 3590 cm-1 (E) stretching 3590 cm-1 (E) stretching Which mode is highly symmetric? The mode with frequency of 3461 cm-1 One mode is known as the “umbrella” mode, which one is this? The mode with frequency of 1090 cm-1 How many bands would you expect to see in an experimental spectrum of gaseous ammonia? 4 bands as the last two frequencies have an intensity of zero.
Charge analysis
As nitrogen is more electronegative than hydrogen, one would expect the N atom to have a more negative charge than the H atoms.
Atom | Charge | Pauling Electronegativity1 |
---|---|---|
Nitrogen | -1.125 | 3.04 |
Hydrogen | +0.375 | 2.20 |
H2
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