RichardZhang
Borane
Optimization of Borane(3-21G)
Optimization of Borane(6-31G)
The optimisation file is liked to here
| BH3 |
| Mode | Vibration | Intensity | Symmetry | IR Active | Type |
|---|---|---|---|---|---|
| 1 | 1163 | 93 | A2' | Yes | out-of-plane bend |
| 2 | 1213 | 14 | E' | Yes | bend |
| 3 | 1213 | 14 | E' | Yes | bend |
| 4 | 2582 | 0 | A1' | No | symmetric stretch |
| 5 | 2715 | 126 | E' | Yes | asymmetric stretch |
| 6 | 2715 | 126 | E' | Yes | asymmetric stretch |
There are less than six peaks in the spectrum even though there are obvious six vibrations. This is because the translation modes are degenerate each other, such as mode 2 and mod 3, mode 5 and mode 6. In addition, the vibration mode 4 is IR inactive, which therefore also missed in the IR spectrum.
No obvious differences can be observed between the real and LCAO MOs, which means that the qualitative MO theory is quite accurate.
Association energy calculation
Optimization of Ammonia(6-31G)
1.RB3LYP/6-31G:
The optimisation file is liked to here
| Ammonia |
| Mode | Vibration | Intensity | Symmetry | IR Active | Type |
|---|---|---|---|---|---|
| 1 | 1694 | 145 | A | Yes | out-of-plane bend |
| 2 | 1694 | 13 | E | Yes | bend |
| 3 | 1694 | 13 | E | Yes | bend |
| 4 | 3461 | 1 | A1 | No | symmetric stretch |
| 5 | 3589 | 0 | E | No | asymmetric stretch |
| 6 | 3589 | 0 | E | No | asymmetric stretch |
Optimization of Ammonia Borane(6-31G)
1.RB3LYP/6-31G:
The optimisation file is liked to here
| Ammonia Borane |
Calculation process
E(NH3)=-56.55776863 a.u ≈ -1.48492x10^5 kJ/mol
E(BH3)=-26.61532360 a.u ≈ -6.9879x10^4 kJ/mol
E(NH3BH3)=-83.22469012 a.u ≈ -2.18506x10^5 kJ/mol
ΔE = E(NH3BH3)-[E(BH3)+E(NH3)] = -2.18506x10^5+(6.9879x10^4+1.48492x10^5) ≈ -135 kJ/mol
The value of association energy is a negative value, which means the B-N dative bond is stronger than the ?
Borone tribromide
Optimization of borone tribromide(GEN)
1. RB3LYP/GEN:
The optimisation file is liked to here
| Boron tribromide |
| Mode | Vibration | Intensity | Symmetry | IR Active | Type |
|---|---|---|---|---|---|
| 1 | 156 | 145 | E' | NO | asymmetric stretch |
| 2 | 156 | 13 | E' | NO | asymmetric stretch |
| 3 | 268 | 13 | A1' | NO | symmetric stretch |
| 4 | 378 | 1 | A2 | Yes | out-of-plane bend |
| 5 | 763 | 0 | E' | Yes | bend |
| 6 | 763 | 0 | E' | Yes | bend |
The pps-optimisation of BBr3: DOI:10042/202437
The pps-frequency of BBr3: DOI:10042/202439
Project of aromaticity
Optimization of Benzene
1.RB3YLP/6-31G:
The optimisation file is linked to here
| Benzene |
Optimization of Borazine
1.RB3YLP/6-31G:
The optimisation file is linked to here
| Borazine |
The Natural Bond Orbital analysis
| Atom | Charge/a.u | Electronegativity |
|---|---|---|
| c | -0.239 | 2.5 |
| H | 0.239 | 2.2 |
| Atom | Charge/a.u | Electronegativity |
|---|---|---|
| B | 0.747 | 2.0 |
| N | -1.102 | 3.04 |
| H-N | 0.432 | 2.2 |
| H-B | -0.077 | 2.2 |
According to the diagrams and tables shown above, it is obvious that the charge density in the benzene is evenly distributed. In addition, the charge of the hydrogen is 0.239 a.u and the charge of the carbon is -0.239, which is a big difference. This is mainly because of the electronegativity difference between H(2.2) and C(2.5). As carbon is more electronegative than hydrogen, it will attracts the charges toward itself, which therefore becomes more negative in charge density than hydrogen. For borazine, the distribution of charge density is more complex. The nitrogen is a strong electron withdrawing group as the electronegativity of N is around 3.04 which is much larger than the electronegativity of hydrogen(2.2)and boron(2.0). Therefore, it will pulls the charge density towards itself and away from the boron and hydrogen.
The aromaticity is applied in the organic chemistry to descirbe a cyclic, flat molecule with a ring of resonance bonds. These bonds induces more stability other types of structure or arrangements of atoms. In terms of the electronic nature of the molecule, aromaticity describes a conjugated system often made of alternating single and double bonds in a ring. This configuration allows for the electrons in the molecule's pi system to be delocalized around the ring, increasing the molecule's stability.