MRD:ED2618

Molecular Reaction Dynamics

In this lab we are using molecular dynamic trajectories to study the reactivity of triatomic systems, namely when an atom collides with a diatomic molecule.

ADD CONTENTS TABLE

EXERCISE 1: H + H₂ system

Dynamics from the transition state region

Question 1: On a potential energy surface diagram, how is the transition state mathematically defined? How can the transition state be identified, and how can it be distinguished from a local minimum of the potential energy surface?

Answer 1: On a potential energy surface diagram the transition state is defined, mathematically, as a saddle point. A transition state is the maximum energy present in the minimum energy pathway taken from reactants to products. A saddle point is of symmetric configuration at which the distance between three separate atoms is the same.

A saddle point is different to a local minima. For both, the gradient of the potential energy surface is zero, is given as the first partial derivative:

∂V(r_i)/ ∂r_i = 0

However, the saddle point and local minima may be distinguished though inspection of their second partial derivatives. For a local minima, calculating partial second derivatives in orthogonal directions to the saddle point will give a result that is greater than 0, independent from which plane it has been measured. By contrast, for the saddle point, is second partial derivative will either be greater than zero or smaller than zero dependent on which plane it has been measured. This explanation is summarised below:

For a local minima:  ∂²V(r_i)/ ∂r_i² > 0

For a saddle point:  ∂²V(r_i)/ ∂r_i² > 0 and  ∂²V(r_i)/ ∂r_i² < 0

An example of a saddle point can be seen in the figure below:

Figure 1: An example of a saddle point, orthogonal directions from which have opposite signs for their partial second derivative.

Question 2: Report your best estimate of the transition state position (r_ts) and explain your reasoning illustrating it with a “Internuclear Distances vs Time” plot for a relevant trajectory.

Answer 2: The transition state occurs at the saddle point, which is of symmetric configuration. Hence, r₁ = r₂ as the H + H₂ surface is symmetric, where, r₁ = BC and r₂ = AB. At the transition state p₁ = p₂ = 0 g.mol^-1.pm.fs^-1. Through trial and error an estimate for the transition state position is when AB = BC = 90.75 pm. Using this distance produces the contour plot below. It can be seen that there is no gradient at right angles to the point of the transition state.

Figure 2: A contour plot showing the transition state. There are no oscillations or directions of motion towards either reactants or products, thus the system is stationary

The plot of 'Internuclear Distances vs Time' below shows the distances of A-B, B-C, and A-C constant with time, consolidating the fact that this position is the transition state position. Running an animation with the r₁ = r₂ = 90.75 pm shows the species as stationary, as there are no fluctuations of interatomic distance with time.

Figure 3: A plot of Internuclear Distances vs Time

Question 3: Comment on how the mep and the trajectory you just calculated differ.

Answer 3: The initial conditions are set so that the system is slightly displaced from the transition state and so that there is zero initial momenta, where r₁ = r_ts + 1 pm, r₂ = r_ts and the momenta p₁ = p₂ = 0 g.mol^-1.pm.fs^-1. This can be shown in the figures below, where r₁ (BC) = 91.75 pm and r₂ (AB) = 90.75 pm.

Figure 4a: Contour Plot (Calculation Type: Dynamics)

Figure 5a: Contour Plot (Calculation Type: MEP)

It can be deduced that the trajectory is greatly dependent on calculation type. To obtain a complete MEP the step number was increased to 3000.