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		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:T01574856&amp;diff=805846</id>
		<title>MRD:T01574856</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:T01574856&amp;diff=805846"/>
		<updated>2020-05-15T21:41:51Z</updated>

		<summary type="html">&lt;p&gt;Tr318: /* Question 3 */&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;= Molecular Reaction Dynamics Lab =&lt;br /&gt;
&lt;br /&gt;
= &amp;lt;br&amp;gt; Exercise 1: H + H&amp;lt;sub&amp;gt;2 &amp;lt;/sub&amp;gt;System =&lt;br /&gt;
&lt;br /&gt;
== Question 1 ==&lt;br /&gt;
&#039;&#039;&#039;On a potential energy surface diagram, how is the transition state mathematically defined? How can the transition state be identified, and how can it be distinguished from a local minimum of the potential energy surface?&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
The transition state is mathematically defined as the maximum on the minimum energy path which links the reactants and products together. The transition state can be identified on a potential energy surface diagram by looking at the gradient of the potential, at the point of the transition state, the gradient would be zero (dV&amp;lt;sub&amp;gt;(ri)&amp;lt;/sub&amp;gt;/d&amp;lt;sub&amp;gt;ri&amp;lt;/sub&amp;gt;=0). This point is distinguished from a local minimum of the potential energy surface by starting trajectories near the transition state and observing the atoms rolling towards the reactants or the products.&lt;br /&gt;
&lt;br /&gt;
== Question 2 ==&lt;br /&gt;
&#039;&#039;&#039;Report your best estimate of the transition state position (r&amp;lt;sub&amp;gt;ts&amp;lt;/sub&amp;gt;) and explain your reasoning illustrating it with a “Internuclear Distances vs Time” plot for a relevant trajectory.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
The best estimate for the transition state position is at r&amp;lt;sub&amp;gt;ts&amp;lt;/sub&amp;gt;=0 and p=0. This is shown below in the contour diagram as this is in the saddle point; the maxima in one direction and the minima in another. This estimate is also supported by the internuclear distances vs time graph below as it shows the distances of the B-C bond and between the atoms A and C moving symmetrically at the same time. No product is formed at this point.[[File:TR H2HTScont.png|thumb|302x302px|Contour diagram showing the transition state involved in this reaction.|none]]&lt;br /&gt;
[[File:TR H2HTS.png|thumb|Internuclear distances vs time graph of H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt; + H reaction.|none]]&lt;br /&gt;
== Question 3 ==&lt;br /&gt;
&#039;&#039;&#039;Comment on how the &#039;&#039;mep&#039;&#039; and the trajectory you just calculated differ.&#039;&#039;&#039;&lt;br /&gt;
[[File:TrINDTMEP.png|centre|thumb]]&lt;br /&gt;
[[File:Tr77Dynamicq3.png|centre|thumb]]&lt;br /&gt;
[[File:MVTQ3.png|centre|thumb]]&lt;br /&gt;
&lt;br /&gt;
== Question 4 ==&lt;br /&gt;
&#039;&#039;&#039;Complete the table above by adding the total  energy, whether the trajectory is reactive or unreactive, and provide a  plot of the trajectory and a small description for what happens along  the trajectory. What can you conclude from the table?&#039;&#039;&#039;&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
!p&amp;lt;sub&amp;gt;1&amp;lt;/sub&amp;gt;/ g.mol&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;.pm.fs&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;&lt;br /&gt;
!p&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;/ g.mol&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;.pm.fs&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;&lt;br /&gt;
!E&amp;lt;sub&amp;gt;tot&amp;lt;/sub&amp;gt;/ kJ.mol&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;&lt;br /&gt;
!Reactive?&lt;br /&gt;
!Description of the dynamics&lt;br /&gt;
!Illustration of the trajectory&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-2.56&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-5.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-414.280&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|Reactive&lt;br /&gt;
|Reactants collide with the required energy to form the products. &lt;br /&gt;
|[[File:1zl.png|thumb|190x190px]]&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-3.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-4.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-420.007&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|Unreactive&lt;br /&gt;
|Reactants have momentum but do not collide so no reaction takes place and products are not formed.&lt;br /&gt;
|[[File:2zl.png|thumb|187x187px]]&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-3.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-5.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-413.977&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|Reactive&lt;br /&gt;
|Reactants collide with the required energy to form the products.&lt;br /&gt;
|[[File:3zl.png|thumb|191x191px]]&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-5.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-10.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-357.277&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|Unreactive&lt;br /&gt;
|Reactants collide but product is not formed since there is not enough energy for the reaction to take place.&lt;br /&gt;
|[[File:4zl.png|thumb|194x194px]]&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-5.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-10.6&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-349.477&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|Reactive&lt;br /&gt;
|Reactants collide and products form.&lt;br /&gt;
|[[File:5zl.png|thumb|206x206px]]&lt;br /&gt;
|}&lt;br /&gt;
This table tells us that every reaction here had the activation energy required for the reaction to take place but 2/5 times the reaction did not occur. There are other factors such as momenta involved which can effect the outcome.&lt;br /&gt;
&lt;br /&gt;
== Question 5 ==&lt;br /&gt;
&#039;&#039;&#039;Given the results you have obtained, how will Transition State Theory predictions for reaction rate values compare with experimental values?&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
Transition state theory uses the properties of the reactants and the transition state to rationalise and calculate the rate of chemical reactions. There are a few assumptions made in transition state theory; one is that all collisions with the required kinetic energy (activation energy) will result in a reaction. Another is that, once the collision occurs and the trajectory passes the barrier, it cannot turn back into the reactants. This does not always occur experimentally as seen in the table above as there are reactants which have the required activation energy which do not react and also there is an example of a collision occuring which resulted in the reactants reforming instead of products forming. In conclusion, this leads to transition theory over-estimating the reaction rates.&lt;br /&gt;
&lt;br /&gt;
= Exercise 2: F-H-H System =&lt;br /&gt;
&lt;br /&gt;
== Question 1 ==&lt;br /&gt;
&#039;&#039;&#039;By inspecting the potential energy surfaces, classify the F + H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;&amp;lt;nowiki&amp;gt; &amp;lt;/nowiki&amp;gt;and H + HF reactions according to their energetics (endothermic or exothermic). How does this relate to the bond strength of the chemical species involved?&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
To find out if these reactions are exothermic or endothermic a combination of Polanyi&#039;s rules and the Hammond&#039;s postulate was used. Polanyi&#039;s rules look at the early and late barriers of a reaction, this is where the transition state lies on the potential energy surface. An early barrier lies with the transition state closer to the reactants while in a late barrier the transition state lies closer to the products. Translational energy is more efficient to complete the reaction where there is an early barrier but vibrational energy is more efficient in a late barrier reaction. Alongside Polanyi&#039;s rules, the Hammond&#039;s postulate shows that an exothermic reaction has a transition state resembles the reactants  (early barrier) and an endothermic reaction has a transition state resembling the products (a late barrier).&lt;br /&gt;
&lt;br /&gt;
Looking at the potential energy surface of the reaction, F + H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;, it can be seen that there is an early barrier suggesting a transition state close to the reactants and an exothermic reaction. On the other hand , the reaction of H + HF shows a late transition state, late barrier and therfore an endothermic reaction. &lt;br /&gt;
&lt;br /&gt;
This relates to bond strength as more energy is needed to break the H-F bond than the H-H bond in the exothermic reaction resulting in showing that a H-F bond is stronger than a H-H bond.&lt;br /&gt;
&lt;br /&gt;
== Question 2 ==&lt;br /&gt;
&#039;&#039;&#039;Locate the approximate position of the transition state.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
The location state of both these reactions would have the same coordinates but in the opposite form. To locate the transition state Hammond&#039;s postulate was used alongside looking at the PES graph of the reaction of F with H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;. It was known that there was an early transition state so the distance of AB (F-H) would be longer than the already known distance of H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;. The point of the transition state was found to produce a single point on the graph at an AB distance of 181.4 pm and a BC distance of 74 pm.&lt;br /&gt;
[[File:TR 1 FH2TS.png|centre|thumb]]&lt;br /&gt;
&lt;br /&gt;
== Question 3 ==&lt;br /&gt;
&#039;&#039;&#039;Report the activation energy for both reactions.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
A resonable estimate was formed by performing an mep with 1500 steps and 0.1 step size from a structure neighbouring the transition state.&lt;br /&gt;
&lt;br /&gt;
The activation energy fro F + H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt; reaction was found by using an AB distance closer to the reactants (210 pm) due to its early transition state giving an activation energy of -0.341 kJ/ mol&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;. &lt;br /&gt;
[[File:Tr576FH2AE.png|none|thumb|Mep of F + FH&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;]]&lt;br /&gt;
The same activation energy value was found for the H + HF reaction but instead due to the late transition state, a BC value of 210 pm was used.&lt;br /&gt;
&lt;br /&gt;
[[File:Tr45HHFAE.png|none|thumb]]&lt;br /&gt;
&lt;br /&gt;
== Question 4 ==&lt;br /&gt;
I&#039;&#039;&#039;n light of the fact that energy is conserved, discuss the mechanism of release of the reaction energy. Explain how this could be confirmed experimentally.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
There are two mechanisms of the release of reaction energy; the release of translational kinetic energy and also the release of vibrational kinetic energy. A bomb calorimeter can not differentiate between these 2 mechanisms as it only measures the heat released; therefore IR could be used to measure the radiation emitted from the vibrational energy known as chemiluminescence.The momenta vs time graph below is formed by having an A-B distance of 190 pm and B-C distance of 74 pm with a momentum of -3 and -11 g.mol-&amp;lt;sup&amp;gt;1&amp;lt;/sup&amp;gt;.pm.fs&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt; respectively. It shows H-H moving with vibrational energy towards F creating some vibrational energy in H-F. After the collision occurs, H-F now has vibrational energy while the H moves with no vibrational energy.  &lt;br /&gt;
[[File:Tr 77 Momenta1.png|centre|thumb]]  &lt;br /&gt;
&lt;br /&gt;
== Question 5 ==&lt;br /&gt;
&#039;&#039;&#039;Discuss how the distribution of energy between&amp;lt;nowiki&amp;gt; &amp;lt;/nowiki&amp;gt;different modes (translation and vibration) affect the efficiency of the reaction, and how this is influenced by the position of the transition state.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
Referring back to Polanyi&#039;s rule where translational energy is more efficient with an early transition state and vibrational energy being more efficient with a late transition state; the efficiency of the reaction is influenced by which energy is used and where the transition state lies.&lt;/div&gt;</summary>
		<author><name>Tr318</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=File:TrINDTMEP.png&amp;diff=805829</id>
		<title>File:TrINDTMEP.png</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=File:TrINDTMEP.png&amp;diff=805829"/>
		<updated>2020-05-15T21:38:42Z</updated>

		<summary type="html">&lt;p&gt;Tr318: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;/div&gt;</summary>
		<author><name>Tr318</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=File:Tr77Dynamicq3.png&amp;diff=805825</id>
		<title>File:Tr77Dynamicq3.png</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=File:Tr77Dynamicq3.png&amp;diff=805825"/>
		<updated>2020-05-15T21:38:27Z</updated>

		<summary type="html">&lt;p&gt;Tr318: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;/div&gt;</summary>
		<author><name>Tr318</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=File:MVTQ3.png&amp;diff=805823</id>
		<title>File:MVTQ3.png</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=File:MVTQ3.png&amp;diff=805823"/>
		<updated>2020-05-15T21:38:11Z</updated>

		<summary type="html">&lt;p&gt;Tr318: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;/div&gt;</summary>
		<author><name>Tr318</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:T01574856&amp;diff=805808</id>
		<title>MRD:T01574856</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:T01574856&amp;diff=805808"/>
		<updated>2020-05-15T21:34:50Z</updated>

		<summary type="html">&lt;p&gt;Tr318: /* Question 3 */&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;= Molecular Reaction Dynamics Lab =&lt;br /&gt;
&lt;br /&gt;
= &amp;lt;br&amp;gt; Exercise 1: H + H&amp;lt;sub&amp;gt;2 &amp;lt;/sub&amp;gt;System =&lt;br /&gt;
&lt;br /&gt;
== Question 1 ==&lt;br /&gt;
&#039;&#039;&#039;On a potential energy surface diagram, how is the transition state mathematically defined? How can the transition state be identified, and how can it be distinguished from a local minimum of the potential energy surface?&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
The transition state is mathematically defined as the maximum on the minimum energy path which links the reactants and products together. The transition state can be identified on a potential energy surface diagram by looking at the gradient of the potential, at the point of the transition state, the gradient would be zero (dV&amp;lt;sub&amp;gt;(ri)&amp;lt;/sub&amp;gt;/d&amp;lt;sub&amp;gt;ri&amp;lt;/sub&amp;gt;=0). This point is distinguished from a local minimum of the potential energy surface by starting trajectories near the transition state and observing the atoms rolling towards the reactants or the products.&lt;br /&gt;
&lt;br /&gt;
== Question 2 ==&lt;br /&gt;
&#039;&#039;&#039;Report your best estimate of the transition state position (r&amp;lt;sub&amp;gt;ts&amp;lt;/sub&amp;gt;) and explain your reasoning illustrating it with a “Internuclear Distances vs Time” plot for a relevant trajectory.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
The best estimate for the transition state position is at r&amp;lt;sub&amp;gt;ts&amp;lt;/sub&amp;gt;=0 and p=0. This is shown below in the contour diagram as this is in the saddle point; the maxima in one direction and the minima in another. This estimate is also supported by the internuclear distances vs time graph below as it shows the distances of the B-C bond and between the atoms A and C moving symmetrically at the same time. No product is formed at this point.[[File:TR H2HTScont.png|thumb|302x302px|Contour diagram showing the transition state involved in this reaction.|none]]&lt;br /&gt;
[[File:TR H2HTS.png|thumb|Internuclear distances vs time graph of H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt; + H reaction.|none]]&lt;br /&gt;
== Question 3 ==&lt;br /&gt;
&#039;&#039;&#039;Comment on how the &#039;&#039;mep&#039;&#039; and the trajectory you just calculated differ.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
== Question 4 ==&lt;br /&gt;
&#039;&#039;&#039;Complete the table above by adding the total  energy, whether the trajectory is reactive or unreactive, and provide a  plot of the trajectory and a small description for what happens along  the trajectory. What can you conclude from the table?&#039;&#039;&#039;&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
!p&amp;lt;sub&amp;gt;1&amp;lt;/sub&amp;gt;/ g.mol&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;.pm.fs&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;&lt;br /&gt;
!p&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;/ g.mol&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;.pm.fs&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;&lt;br /&gt;
!E&amp;lt;sub&amp;gt;tot&amp;lt;/sub&amp;gt;/ kJ.mol&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;&lt;br /&gt;
!Reactive?&lt;br /&gt;
!Description of the dynamics&lt;br /&gt;
!Illustration of the trajectory&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-2.56&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-5.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-414.280&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|Reactive&lt;br /&gt;
|Reactants collide with the required energy to form the products. &lt;br /&gt;
|[[File:1zl.png|thumb|190x190px]]&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-3.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-4.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-420.007&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|Unreactive&lt;br /&gt;
|Reactants have momentum but do not collide so no reaction takes place and products are not formed.&lt;br /&gt;
|[[File:2zl.png|thumb|187x187px]]&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-3.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-5.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-413.977&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|Reactive&lt;br /&gt;
|Reactants collide with the required energy to form the products.&lt;br /&gt;
|[[File:3zl.png|thumb|191x191px]]&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-5.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-10.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-357.277&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|Unreactive&lt;br /&gt;
|Reactants collide but product is not formed since there is not enough energy for the reaction to take place.&lt;br /&gt;
|[[File:4zl.png|thumb|194x194px]]&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-5.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-10.6&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-349.477&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|Reactive&lt;br /&gt;
|Reactants collide and products form.&lt;br /&gt;
|[[File:5zl.png|thumb|206x206px]]&lt;br /&gt;
|}&lt;br /&gt;
This table tells us that every reaction here had the activation energy required for the reaction to take place but 2/5 times the reaction did not occur. There are other factors such as momenta involved which can effect the outcome.&lt;br /&gt;
&lt;br /&gt;
== Question 5 ==&lt;br /&gt;
&#039;&#039;&#039;Given the results you have obtained, how will Transition State Theory predictions for reaction rate values compare with experimental values?&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
Transition state theory uses the properties of the reactants and the transition state to rationalise and calculate the rate of chemical reactions. There are a few assumptions made in transition state theory; one is that all collisions with the required kinetic energy (activation energy) will result in a reaction. Another is that, once the collision occurs and the trajectory passes the barrier, it cannot turn back into the reactants. This does not always occur experimentally as seen in the table above as there are reactants which have the required activation energy which do not react and also there is an example of a collision occuring which resulted in the reactants reforming instead of products forming. In conclusion, this leads to transition theory over-estimating the reaction rates.&lt;br /&gt;
&lt;br /&gt;
= Exercise 2: F-H-H System =&lt;br /&gt;
&lt;br /&gt;
== Question 1 ==&lt;br /&gt;
&#039;&#039;&#039;By inspecting the potential energy surfaces, classify the F + H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;&amp;lt;nowiki&amp;gt; &amp;lt;/nowiki&amp;gt;and H + HF reactions according to their energetics (endothermic or exothermic). How does this relate to the bond strength of the chemical species involved?&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
To find out if these reactions are exothermic or endothermic a combination of Polanyi&#039;s rules and the Hammond&#039;s postulate was used. Polanyi&#039;s rules look at the early and late barriers of a reaction, this is where the transition state lies on the potential energy surface. An early barrier lies with the transition state closer to the reactants while in a late barrier the transition state lies closer to the products. Translational energy is more efficient to complete the reaction where there is an early barrier but vibrational energy is more efficient in a late barrier reaction. Alongside Polanyi&#039;s rules, the Hammond&#039;s postulate shows that an exothermic reaction has a transition state resembles the reactants  (early barrier) and an endothermic reaction has a transition state resembling the products (a late barrier).&lt;br /&gt;
&lt;br /&gt;
Looking at the potential energy surface of the reaction, F + H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;, it can be seen that there is an early barrier suggesting a transition state close to the reactants and an exothermic reaction. On the other hand , the reaction of H + HF shows a late transition state, late barrier and therfore an endothermic reaction. &lt;br /&gt;
&lt;br /&gt;
This relates to bond strength as more energy is needed to break the H-F bond than the H-H bond in the exothermic reaction resulting in showing that a H-F bond is stronger than a H-H bond.&lt;br /&gt;
&lt;br /&gt;
== Question 2 ==&lt;br /&gt;
&#039;&#039;&#039;Locate the approximate position of the transition state.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
The location state of both these reactions would have the same coordinates but in the opposite form. To locate the transition state Hammond&#039;s postulate was used alongside looking at the PES graph of the reaction of F with H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;. It was known that there was an early transition state so the distance of AB (F-H) would be longer than the already known distance of H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;. The point of the transition state was found to produce a single point on the graph at an AB distance of 181.4 pm and a BC distance of 74 pm.&lt;br /&gt;
[[File:TR 1 FH2TS.png|centre|thumb]]&lt;br /&gt;
&lt;br /&gt;
== Question 3 ==&lt;br /&gt;
&#039;&#039;&#039;Report the activation energy for both reactions.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
A resonable estimate was formed by performing an mep with 1500 steps and 0.1 step size from a structure neighbouring the transition state.&lt;br /&gt;
&lt;br /&gt;
The activation energy fro F + H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt; reaction was found by using an AB distance closer to the reactants (210 pm) due to its early transition state giving an activation energy of -0.341 kJ/ mol&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;. &lt;br /&gt;
[[File:Tr576FH2AE.png|none|thumb|Mep of F + FH&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;]]&lt;br /&gt;
The same activation energy value was found for the H + HF reaction but instead due to the late transition state, a BC value of 210 pm was used.&lt;br /&gt;
&lt;br /&gt;
[[File:Tr45HHFAE.png|none|thumb]]&lt;br /&gt;
&lt;br /&gt;
== Question 4 ==&lt;br /&gt;
I&#039;&#039;&#039;n light of the fact that energy is conserved, discuss the mechanism of release of the reaction energy. Explain how this could be confirmed experimentally.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
There are two mechanisms of the release of reaction energy; the release of translational kinetic energy and also the release of vibrational kinetic energy. A bomb calorimeter can not differentiate between these 2 mechanisms as it only measures the heat released; therefore IR could be used to measure the radiation emitted from the vibrational energy known as chemiluminescence.The momenta vs time graph below is formed by having an A-B distance of 190 pm and B-C distance of 74 pm with a momentum of -3 and -11 g.mol-&amp;lt;sup&amp;gt;1&amp;lt;/sup&amp;gt;.pm.fs&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt; respectively. It shows H-H moving with vibrational energy towards F creating some vibrational energy in H-F. After the collision occurs, H-F now has vibrational energy while the H moves with no vibrational energy.  &lt;br /&gt;
[[File:Tr 77 Momenta1.png|centre|thumb]]  &lt;br /&gt;
&lt;br /&gt;
== Question 5 ==&lt;br /&gt;
&#039;&#039;&#039;Discuss how the distribution of energy between&amp;lt;nowiki&amp;gt; &amp;lt;/nowiki&amp;gt;different modes (translation and vibration) affect the efficiency of the reaction, and how this is influenced by the position of the transition state.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
Referring back to Polanyi&#039;s rule where translational energy is more efficient with an early transition state and vibrational energy being more efficient with a late transition state; the efficiency of the reaction is influenced by which energy is used and where the transition state lies.&lt;/div&gt;</summary>
		<author><name>Tr318</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:T01574856&amp;diff=805784</id>
		<title>MRD:T01574856</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:T01574856&amp;diff=805784"/>
		<updated>2020-05-15T21:29:21Z</updated>

		<summary type="html">&lt;p&gt;Tr318: /* Question 2 */&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;= Molecular Reaction Dynamics Lab =&lt;br /&gt;
&lt;br /&gt;
= &amp;lt;br&amp;gt; Exercise 1: H + H&amp;lt;sub&amp;gt;2 &amp;lt;/sub&amp;gt;System =&lt;br /&gt;
&lt;br /&gt;
== Question 1 ==&lt;br /&gt;
&#039;&#039;&#039;On a potential energy surface diagram, how is the transition state mathematically defined? How can the transition state be identified, and how can it be distinguished from a local minimum of the potential energy surface?&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
The transition state is mathematically defined as the maximum on the minimum energy path which links the reactants and products together. The transition state can be identified on a potential energy surface diagram by looking at the gradient of the potential, at the point of the transition state, the gradient would be zero (dV&amp;lt;sub&amp;gt;(ri)&amp;lt;/sub&amp;gt;/d&amp;lt;sub&amp;gt;ri&amp;lt;/sub&amp;gt;=0). This point is distinguished from a local minimum of the potential energy surface by starting trajectories near the transition state and observing the atoms rolling towards the reactants or the products.&lt;br /&gt;
&lt;br /&gt;
== Question 2 ==&lt;br /&gt;
&#039;&#039;&#039;Report your best estimate of the transition state position (r&amp;lt;sub&amp;gt;ts&amp;lt;/sub&amp;gt;) and explain your reasoning illustrating it with a “Internuclear Distances vs Time” plot for a relevant trajectory.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
The best estimate for the transition state position is at r&amp;lt;sub&amp;gt;ts&amp;lt;/sub&amp;gt;=0 and p=0. This is shown below in the contour diagram as this is in the saddle point; the maxima in one direction and the minima in another. This estimate is also supported by the internuclear distances vs time graph below as it shows the distances of the B-C bond and between the atoms A and C moving symmetrically at the same time. No product is formed at this point.[[File:TR H2HTScont.png|left|thumb|302x302px|Contour diagram showing the transition state involved in this reaction.]]&lt;br /&gt;
[[File:TR H2HTS.png|thumb|Internuclear distances vs time graph of H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt; + H reaction.|centre]]&lt;br /&gt;
== Question 3 ==&lt;br /&gt;
&#039;&#039;&#039;Comment on how the &#039;&#039;mep&#039;&#039; and the trajectory you just calculated differ.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
== Question 4 ==&lt;br /&gt;
&#039;&#039;&#039;Complete the table above by adding the total  energy, whether the trajectory is reactive or unreactive, and provide a  plot of the trajectory and a small description for what happens along  the trajectory. What can you conclude from the table?&#039;&#039;&#039;&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
!p&amp;lt;sub&amp;gt;1&amp;lt;/sub&amp;gt;/ g.mol&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;.pm.fs&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;&lt;br /&gt;
!p&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;/ g.mol&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;.pm.fs&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;&lt;br /&gt;
!E&amp;lt;sub&amp;gt;tot&amp;lt;/sub&amp;gt;/ kJ.mol&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;&lt;br /&gt;
!Reactive?&lt;br /&gt;
!Description of the dynamics&lt;br /&gt;
!Illustration of the trajectory&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-2.56&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-5.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-414.280&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|Reactive&lt;br /&gt;
|Reactants collide with the required energy to form the products. &lt;br /&gt;
|[[File:1zl.png|thumb|190x190px]]&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-3.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-4.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-420.007&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|Unreactive&lt;br /&gt;
|Reactants have momentum but do not collide so no reaction takes place and products are not formed.&lt;br /&gt;
|[[File:2zl.png|thumb|187x187px]]&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-3.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-5.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-413.977&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|Reactive&lt;br /&gt;
|Reactants collide with the required energy to form the products.&lt;br /&gt;
|[[File:3zl.png|thumb|191x191px]]&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-5.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-10.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-357.277&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|Unreactive&lt;br /&gt;
|Reactants collide but product is not formed since there is not enough energy for the reaction to take place.&lt;br /&gt;
|[[File:4zl.png|thumb|194x194px]]&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-5.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-10.6&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-349.477&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|Reactive&lt;br /&gt;
|Reactants collide and products form.&lt;br /&gt;
|[[File:5zl.png|thumb|206x206px]]&lt;br /&gt;
|}&lt;br /&gt;
This table tells us that every reaction here had the activation energy required for the reaction to take place but 2/5 times the reaction did not occur. There are other factors such as momenta involved which can effect the outcome.&lt;br /&gt;
&lt;br /&gt;
== Question 5 ==&lt;br /&gt;
&#039;&#039;&#039;Given the results you have obtained, how will Transition State Theory predictions for reaction rate values compare with experimental values?&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
Transition state theory uses the properties of the reactants and the transition state to rationalise and calculate the rate of chemical reactions. There are a few assumptions made in transition state theory; one is that all collisions with the required kinetic energy (activation energy) will result in a reaction. Another is that, once the collision occurs and the trajectory passes the barrier, it cannot turn back into the reactants. This does not always occur experimentally as seen in the table above as there are reactants which have the required activation energy which do not react and also there is an example of a collision occuring which resulted in the reactants reforming instead of products forming. In conclusion, this leads to transition theory over-estimating the reaction rates.&lt;br /&gt;
&lt;br /&gt;
= Exercise 2: F-H-H System =&lt;br /&gt;
&lt;br /&gt;
== Question 1 ==&lt;br /&gt;
&#039;&#039;&#039;By inspecting the potential energy surfaces, classify the F + H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;&amp;lt;nowiki&amp;gt; &amp;lt;/nowiki&amp;gt;and H + HF reactions according to their energetics (endothermic or exothermic). How does this relate to the bond strength of the chemical species involved?&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
To find out if these reactions are exothermic or endothermic a combination of Polanyi&#039;s rules and the Hammond&#039;s postulate was used. Polanyi&#039;s rules look at the early and late barriers of a reaction, this is where the transition state lies on the potential energy surface. An early barrier lies with the transition state closer to the reactants while in a late barrier the transition state lies closer to the products. Translational energy is more efficient to complete the reaction where there is an early barrier but vibrational energy is more efficient in a late barrier reaction. Alongside Polanyi&#039;s rules, the Hammond&#039;s postulate shows that an exothermic reaction has a transition state resembles the reactants  (early barrier) and an endothermic reaction has a transition state resembling the products (a late barrier).&lt;br /&gt;
&lt;br /&gt;
Looking at the potential energy surface of the reaction, F + H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;, it can be seen that there is an early barrier suggesting a transition state close to the reactants and an exothermic reaction. On the other hand , the reaction of H + HF shows a late transition state, late barrier and therfore an endothermic reaction. &lt;br /&gt;
&lt;br /&gt;
This relates to bond strength as more energy is needed to break the H-F bond than the H-H bond in the exothermic reaction resulting in showing that a H-F bond is stronger than a H-H bond.&lt;br /&gt;
&lt;br /&gt;
== Question 2 ==&lt;br /&gt;
&#039;&#039;&#039;Locate the approximate position of the transition state.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
The location state of both these reactions would have the same coordinates but in the opposite form. To locate the transition state Hammond&#039;s postulate was used alongside looking at the PES graph of the reaction of F with H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;. It was known that there was an early transition state so the distance of AB (F-H) would be longer than the already known distance of H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;. The point of the transition state was found to produce a single point on the graph at an AB distance of 181.4 pm and a BC distance of 74 pm.&lt;br /&gt;
[[File:TR 1 FH2TS.png|centre|thumb]]&lt;br /&gt;
&lt;br /&gt;
== Question 3 ==&lt;br /&gt;
&#039;&#039;&#039;Report the activation energy for both reactions.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
A resonable estimate was formed by performing an mep with 1500 steps and 0.1 step size from a structure neighbouring the transition state.&lt;br /&gt;
&lt;br /&gt;
The activation energy fro F + H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt; reaction was found by using an AB distance closer to the reactants (210 pm) due to its early transition state giving an activation energy of -0.341 kJ/ mol&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;. &lt;br /&gt;
&lt;br /&gt;
The same activation energy value was found for the H + HF reaction but instead due to the late transition state, a BC value of 210 pm was used.&lt;br /&gt;
&lt;br /&gt;
== Question 4 ==&lt;br /&gt;
I&#039;&#039;&#039;n light of the fact that energy is conserved, discuss the mechanism of release of the reaction energy. Explain how this could be confirmed experimentally.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
There are two mechanisms of the release of reaction energy; the release of translational kinetic energy and also the release of vibrational kinetic energy. A bomb calorimeter can not differentiate between these 2 mechanisms as it only measures the heat released; therefore IR could be used to measure the radiation emitted from the vibrational energy known as chemiluminescence.The momenta vs time graph below is formed by having an A-B distance of 190 pm and B-C distance of 74 pm with a momentum of -3 and -11 g.mol-&amp;lt;sup&amp;gt;1&amp;lt;/sup&amp;gt;.pm.fs&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt; respectively. It shows H-H moving with vibrational energy towards F creating some vibrational energy in H-F. After the collision occurs, H-F now has vibrational energy while the H moves with no vibrational energy.  &lt;br /&gt;
&lt;br /&gt;
== Question 5 ==&lt;br /&gt;
&#039;&#039;&#039;Discuss how the distribution of energy between&amp;lt;nowiki&amp;gt; &amp;lt;/nowiki&amp;gt;different modes (translation and vibration) affect the efficiency of the reaction, and how this is influenced by the position of the transition state.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
Referring back to Polanyi&#039;s rule where translational energy is more efficient with an early transition state and vibrational energy being more efficient with a late transition state; the efficiency of the reaction is influenced by which energy is used and where the transition state lies.&lt;/div&gt;</summary>
		<author><name>Tr318</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=File:Tr576FH2AE.png&amp;diff=805780</id>
		<title>File:Tr576FH2AE.png</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=File:Tr576FH2AE.png&amp;diff=805780"/>
		<updated>2020-05-15T21:28:31Z</updated>

		<summary type="html">&lt;p&gt;Tr318: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;/div&gt;</summary>
		<author><name>Tr318</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=File:Tr45HHFAE.png&amp;diff=805777</id>
		<title>File:Tr45HHFAE.png</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=File:Tr45HHFAE.png&amp;diff=805777"/>
		<updated>2020-05-15T21:28:13Z</updated>

		<summary type="html">&lt;p&gt;Tr318: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;/div&gt;</summary>
		<author><name>Tr318</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=File:Tr_77_Momenta1.png&amp;diff=805775</id>
		<title>File:Tr 77 Momenta1.png</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=File:Tr_77_Momenta1.png&amp;diff=805775"/>
		<updated>2020-05-15T21:27:45Z</updated>

		<summary type="html">&lt;p&gt;Tr318: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;/div&gt;</summary>
		<author><name>Tr318</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=File:TR_1_FH2TS.png&amp;diff=805771</id>
		<title>File:TR 1 FH2TS.png</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=File:TR_1_FH2TS.png&amp;diff=805771"/>
		<updated>2020-05-15T21:26:45Z</updated>

		<summary type="html">&lt;p&gt;Tr318: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;/div&gt;</summary>
		<author><name>Tr318</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:T01574856&amp;diff=805767</id>
		<title>MRD:T01574856</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:T01574856&amp;diff=805767"/>
		<updated>2020-05-15T21:25:51Z</updated>

		<summary type="html">&lt;p&gt;Tr318: /* Question 4 */&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;= Molecular Reaction Dynamics Lab =&lt;br /&gt;
&lt;br /&gt;
= &amp;lt;br&amp;gt; Exercise 1: H + H&amp;lt;sub&amp;gt;2 &amp;lt;/sub&amp;gt;System =&lt;br /&gt;
&lt;br /&gt;
== Question 1 ==&lt;br /&gt;
&#039;&#039;&#039;On a potential energy surface diagram, how is the transition state mathematically defined? How can the transition state be identified, and how can it be distinguished from a local minimum of the potential energy surface?&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
The transition state is mathematically defined as the maximum on the minimum energy path which links the reactants and products together. The transition state can be identified on a potential energy surface diagram by looking at the gradient of the potential, at the point of the transition state, the gradient would be zero (dV&amp;lt;sub&amp;gt;(ri)&amp;lt;/sub&amp;gt;/d&amp;lt;sub&amp;gt;ri&amp;lt;/sub&amp;gt;=0). This point is distinguished from a local minimum of the potential energy surface by starting trajectories near the transition state and observing the atoms rolling towards the reactants or the products.&lt;br /&gt;
&lt;br /&gt;
== Question 2 ==&lt;br /&gt;
&#039;&#039;&#039;Report your best estimate of the transition state position (r&amp;lt;sub&amp;gt;ts&amp;lt;/sub&amp;gt;) and explain your reasoning illustrating it with a “Internuclear Distances vs Time” plot for a relevant trajectory.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
The best estimate for the transition state position is at r&amp;lt;sub&amp;gt;ts&amp;lt;/sub&amp;gt;=0 and p=0. This is shown below in the contour diagram as this is in the saddle point; the maxima in one direction and the minima in another. This estimate is also supported by the internuclear distances vs time graph below as it shows the distances of the B-C bond and between the atoms A and C moving symmetrically at the same time. No product is formed at this point.[[File:TR H2HTScont.png|left|thumb|302x302px|Contour diagram showing the transition state involved in this reaction.]]&lt;br /&gt;
[[File:TR H2HTS.png|thumb|Internuclear distances vs time graph of H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt; + H reaction.|centre]]&lt;br /&gt;
== Question 3 ==&lt;br /&gt;
&#039;&#039;&#039;Comment on how the &#039;&#039;mep&#039;&#039; and the trajectory you just calculated differ.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
== Question 4 ==&lt;br /&gt;
&#039;&#039;&#039;Complete the table above by adding the total  energy, whether the trajectory is reactive or unreactive, and provide a  plot of the trajectory and a small description for what happens along  the trajectory. What can you conclude from the table?&#039;&#039;&#039;&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
!p&amp;lt;sub&amp;gt;1&amp;lt;/sub&amp;gt;/ g.mol&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;.pm.fs&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;&lt;br /&gt;
!p&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;/ g.mol&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;.pm.fs&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;&lt;br /&gt;
!E&amp;lt;sub&amp;gt;tot&amp;lt;/sub&amp;gt;/ kJ.mol&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;&lt;br /&gt;
!Reactive?&lt;br /&gt;
!Description of the dynamics&lt;br /&gt;
!Illustration of the trajectory&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-2.56&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-5.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-414.280&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|Reactive&lt;br /&gt;
|Reactants collide with the required energy to form the products. &lt;br /&gt;
|[[File:1zl.png|thumb|190x190px]]&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-3.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-4.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-420.007&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|Unreactive&lt;br /&gt;
|Reactants have momentum but do not collide so no reaction takes place and products are not formed.&lt;br /&gt;
|[[File:2zl.png|thumb|187x187px]]&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-3.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-5.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-413.977&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|Reactive&lt;br /&gt;
|Reactants collide with the required energy to form the products.&lt;br /&gt;
|[[File:3zl.png|thumb|191x191px]]&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-5.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-10.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-357.277&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|Unreactive&lt;br /&gt;
|Reactants collide but product is not formed since there is not enough energy for the reaction to take place.&lt;br /&gt;
|[[File:4zl.png|thumb|194x194px]]&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-5.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-10.6&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-349.477&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|Reactive&lt;br /&gt;
|Reactants collide and products form.&lt;br /&gt;
|[[File:5zl.png|thumb|206x206px]]&lt;br /&gt;
|}&lt;br /&gt;
This table tells us that every reaction here had the activation energy required for the reaction to take place but 2/5 times the reaction did not occur. There are other factors such as momenta involved which can effect the outcome.&lt;br /&gt;
&lt;br /&gt;
== Question 5 ==&lt;br /&gt;
&#039;&#039;&#039;Given the results you have obtained, how will Transition State Theory predictions for reaction rate values compare with experimental values?&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
Transition state theory uses the properties of the reactants and the transition state to rationalise and calculate the rate of chemical reactions. There are a few assumptions made in transition state theory; one is that all collisions with the required kinetic energy (activation energy) will result in a reaction. Another is that, once the collision occurs and the trajectory passes the barrier, it cannot turn back into the reactants. This does not always occur experimentally as seen in the table above as there are reactants which have the required activation energy which do not react and also there is an example of a collision occuring which resulted in the reactants reforming instead of products forming. In conclusion, this leads to transition theory over-estimating the reaction rates.&lt;br /&gt;
&lt;br /&gt;
= Exercise 2: F-H-H System =&lt;br /&gt;
&lt;br /&gt;
== Question 1 ==&lt;br /&gt;
&#039;&#039;&#039;By inspecting the potential energy surfaces, classify the F + H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;&amp;lt;nowiki&amp;gt; &amp;lt;/nowiki&amp;gt;and H + HF reactions according to their energetics (endothermic or exothermic). How does this relate to the bond strength of the chemical species involved?&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
To find out if these reactions are exothermic or endothermic a combination of Polanyi&#039;s rules and the Hammond&#039;s postulate was used. Polanyi&#039;s rules look at the early and late barriers of a reaction, this is where the transition state lies on the potential energy surface. An early barrier lies with the transition state closer to the reactants while in a late barrier the transition state lies closer to the products. Translational energy is more efficient to complete the reaction where there is an early barrier but vibrational energy is more efficient in a late barrier reaction. Alongside Polanyi&#039;s rules, the Hammond&#039;s postulate shows that an exothermic reaction has a transition state resembles the reactants  (early barrier) and an endothermic reaction has a transition state resembling the products (a late barrier).&lt;br /&gt;
&lt;br /&gt;
Looking at the potential energy surface of the reaction, F + H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;, it can be seen that there is an early barrier suggesting a transition state close to the reactants and an exothermic reaction. On the other hand , the reaction of H + HF shows a late transition state, late barrier and therfore an endothermic reaction. &lt;br /&gt;
&lt;br /&gt;
This relates to bond strength as more energy is needed to break the H-F bond than the H-H bond in the exothermic reaction resulting in showing that a H-F bond is stronger than a H-H bond.&lt;br /&gt;
&lt;br /&gt;
== Question 2 ==&lt;br /&gt;
&#039;&#039;&#039;Locate the approximate position of the transition state.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
The location state of both these reactions would have the same coordinates but in the opposite form. To locate the transition state Hammond&#039;s postulate was used alongside looking at the PES graph of the reaction of F with H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;. It was known that there was an early transition state so the distance of AB (F-H) would be longer than the already known distance of H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;. The point of the transition state was found to produce a single point on the graph at an AB distance of 181.4 pm and a BC distance of 74 pm.&lt;br /&gt;
&lt;br /&gt;
== Question 3 ==&lt;br /&gt;
&#039;&#039;&#039;Report the activation energy for both reactions.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
A resonable estimate was formed by performing an mep with 1500 steps and 0.1 step size from a structure neighbouring the transition state.&lt;br /&gt;
&lt;br /&gt;
The activation energy fro F + H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt; reaction was found by using an AB distance closer to the reactants (210 pm) due to its early transition state giving an activation energy of -0.341 kJ/ mol&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;. &lt;br /&gt;
&lt;br /&gt;
The same activation energy value was found for the H + HF reaction but instead due to the late transition state, a BC value of 210 pm was used.&lt;br /&gt;
&lt;br /&gt;
== Question 4 ==&lt;br /&gt;
I&#039;&#039;&#039;n light of the fact that energy is conserved, discuss the mechanism of release of the reaction energy. Explain how this could be confirmed experimentally.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
There are two mechanisms of the release of reaction energy; the release of translational kinetic energy and also the release of vibrational kinetic energy. A bomb calorimeter can not differentiate between these 2 mechanisms as it only measures the heat released; therefore IR could be used to measure the radiation emitted from the vibrational energy known as chemiluminescence.The momenta vs time graph below is formed by having an A-B distance of 190 pm and B-C distance of 74 pm with a momentum of -3 and -11 g.mol-&amp;lt;sup&amp;gt;1&amp;lt;/sup&amp;gt;.pm.fs&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt; respectively. It shows H-H moving with vibrational energy towards F creating some vibrational energy in H-F. After the collision occurs, H-F now has vibrational energy while the H moves with no vibrational energy.  &lt;br /&gt;
&lt;br /&gt;
== Question 5 ==&lt;br /&gt;
&#039;&#039;&#039;Discuss how the distribution of energy between&amp;lt;nowiki&amp;gt; &amp;lt;/nowiki&amp;gt;different modes (translation and vibration) affect the efficiency of the reaction, and how this is influenced by the position of the transition state.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
Referring back to Polanyi&#039;s rule where translational energy is more efficient with an early transition state and vibrational energy being more efficient with a late transition state; the efficiency of the reaction is influenced by which energy is used and where the transition state lies.&lt;/div&gt;</summary>
		<author><name>Tr318</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:T01574856&amp;diff=805763</id>
		<title>MRD:T01574856</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:T01574856&amp;diff=805763"/>
		<updated>2020-05-15T21:24:11Z</updated>

		<summary type="html">&lt;p&gt;Tr318: /* Question 2 */&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;= Molecular Reaction Dynamics Lab =&lt;br /&gt;
&lt;br /&gt;
= &amp;lt;br&amp;gt; Exercise 1: H + H&amp;lt;sub&amp;gt;2 &amp;lt;/sub&amp;gt;System =&lt;br /&gt;
&lt;br /&gt;
== Question 1 ==&lt;br /&gt;
&#039;&#039;&#039;On a potential energy surface diagram, how is the transition state mathematically defined? How can the transition state be identified, and how can it be distinguished from a local minimum of the potential energy surface?&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
The transition state is mathematically defined as the maximum on the minimum energy path which links the reactants and products together. The transition state can be identified on a potential energy surface diagram by looking at the gradient of the potential, at the point of the transition state, the gradient would be zero (dV&amp;lt;sub&amp;gt;(ri)&amp;lt;/sub&amp;gt;/d&amp;lt;sub&amp;gt;ri&amp;lt;/sub&amp;gt;=0). This point is distinguished from a local minimum of the potential energy surface by starting trajectories near the transition state and observing the atoms rolling towards the reactants or the products.&lt;br /&gt;
&lt;br /&gt;
== Question 2 ==&lt;br /&gt;
[[File:TR H2HTScont.png|left|thumb|302x302px|Contour diagram showing the transition state involved in this reaction.]]&lt;br /&gt;
[[File:TR H2HTS.png|thumb|Internuclear distances vs time graph of H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt; + H reaction.]]&#039;&#039;&#039;Report your best estimate of the transition state position (r&amp;lt;sub&amp;gt;ts&amp;lt;/sub&amp;gt;) and explain your reasoning illustrating it with a “Internuclear Distances vs Time” plot for a relevant trajectory.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
The best estimate for the transition state position is at r&amp;lt;sub&amp;gt;ts&amp;lt;/sub&amp;gt;=0 and p=0. This is shown below in the contour diagram as this is in the saddle point; the maxima in one direction and the minima in another. This estimate is also supported by the internuclear distances vs time graph below as it shows the distances of the B-C bond and between the atoms A and C moving symmetrically at the same time. No product is formed at this point.&lt;br /&gt;
&lt;br /&gt;
== Question 3 ==&lt;br /&gt;
&#039;&#039;&#039;Comment on how the &#039;&#039;mep&#039;&#039; and the trajectory you just calculated differ.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
== Question 4 ==&lt;br /&gt;
&#039;&#039;&#039;Complete the table above by adding the total  energy, whether the trajectory is reactive or unreactive, and provide a  plot of the trajectory and a small description for what happens along  the trajectory. What can you conclude from the table?&#039;&#039;&#039;&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
!p&amp;lt;sub&amp;gt;1&amp;lt;/sub&amp;gt;/ g.mol&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;.pm.fs&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;&lt;br /&gt;
!p&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;/ g.mol&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;.pm.fs&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;&lt;br /&gt;
!E&amp;lt;sub&amp;gt;tot&amp;lt;/sub&amp;gt;/ kJ.mol&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;&lt;br /&gt;
!Reactive?&lt;br /&gt;
!Description of the dynamics&lt;br /&gt;
!Illustration of the trajectory&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-2.56&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-5.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-414.280&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|Reactive&lt;br /&gt;
|Reactants collide with the required energy to form the products. &lt;br /&gt;
|[[File:1zl.png|thumb|190x190px]]&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-3.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-4.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-420.007&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|Unreactive&lt;br /&gt;
|Reactants have momentum but do not collide so no reaction takes place and products are not formed.&lt;br /&gt;
|[[File:2zl.png|thumb|187x187px]]&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-3.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-5.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-413.977&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|Reactive&lt;br /&gt;
|Reactants collide with the required energy to form the products.&lt;br /&gt;
|[[File:3zl.png|thumb|191x191px]]&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-5.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-10.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-357.277&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|Unreactive&lt;br /&gt;
|Reactants collide but product is not formed since there is not enough energy for the reaction to take place.&lt;br /&gt;
|[[File:4zl.png|thumb|194x194px]]&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-5.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-10.6&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-349.477&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|Reactive&lt;br /&gt;
|&lt;br /&gt;
|[[File:5zl.png|thumb|206x206px]]&lt;br /&gt;
|}&lt;br /&gt;
This table tells us that every reaction here had the activation energy required for the reaction to take place but 2/5 times the reaction did not occur. There are other factors such as momenta involved which can effect the outcome.&lt;br /&gt;
&lt;br /&gt;
== Question 5 ==&lt;br /&gt;
&#039;&#039;&#039;Given the results you have obtained, how will Transition State Theory predictions for reaction rate values compare with experimental values?&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
Transition state theory uses the properties of the reactants and the transition state to rationalise and calculate the rate of chemical reactions. There are a few assumptions made in transition state theory; one is that all collisions with the required kinetic energy (activation energy) will result in a reaction. Another is that, once the collision occurs and the trajectory passes the barrier, it cannot turn back into the reactants. This does not always occur experimentally as seen in the table above as there are reactants which have the required activation energy which do not react and also there is an example of a collision occuring which resulted in the reactants reforming instead of products forming. In conclusion, this leads to transition theory over-estimating the reaction rates.&lt;br /&gt;
&lt;br /&gt;
= Exercise 2: F-H-H System =&lt;br /&gt;
&lt;br /&gt;
== Question 1 ==&lt;br /&gt;
&#039;&#039;&#039;By inspecting the potential energy surfaces, classify the F + H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;&amp;lt;nowiki&amp;gt; &amp;lt;/nowiki&amp;gt;and H + HF reactions according to their energetics (endothermic or exothermic). How does this relate to the bond strength of the chemical species involved?&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
To find out if these reactions are exothermic or endothermic a combination of Polanyi&#039;s rules and the Hammond&#039;s postulate was used. Polanyi&#039;s rules look at the early and late barriers of a reaction, this is where the transition state lies on the potential energy surface. An early barrier lies with the transition state closer to the reactants while in a late barrier the transition state lies closer to the products. Translational energy is more efficient to complete the reaction where there is an early barrier but vibrational energy is more efficient in a late barrier reaction. Alongside Polanyi&#039;s rules, the Hammond&#039;s postulate shows that an exothermic reaction has a transition state resembles the reactants  (early barrier) and an endothermic reaction has a transition state resembling the products (a late barrier).&lt;br /&gt;
&lt;br /&gt;
Looking at the potential energy surface of the reaction, F + H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;, it can be seen that there is an early barrier suggesting a transition state close to the reactants and an exothermic reaction. On the other hand , the reaction of H + HF shows a late transition state, late barrier and therfore an endothermic reaction. &lt;br /&gt;
&lt;br /&gt;
This relates to bond strength as more energy is needed to break the H-F bond than the H-H bond in the exothermic reaction resulting in showing that a H-F bond is stronger than a H-H bond.&lt;br /&gt;
&lt;br /&gt;
== Question 2 ==&lt;br /&gt;
&#039;&#039;&#039;Locate the approximate position of the transition state.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
The location state of both these reactions would have the same coordinates but in the opposite form. To locate the transition state Hammond&#039;s postulate was used alongside looking at the PES graph of the reaction of F with H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;. It was known that there was an early transition state so the distance of AB (F-H) would be longer than the already known distance of H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;. The point of the transition state was found to produce a single point on the graph at an AB distance of 181.4 pm and a BC distance of 74 pm.&lt;br /&gt;
&lt;br /&gt;
== Question 3 ==&lt;br /&gt;
&#039;&#039;&#039;Report the activation energy for both reactions.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
A resonable estimate was formed by performing an mep with 1500 steps and 0.1 step size from a structure neighbouring the transition state.&lt;br /&gt;
&lt;br /&gt;
The activation energy fro F + H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt; reaction was found by using an AB distance closer to the reactants (210 pm) due to its early transition state giving an activation energy of -0.341 kJ/ mol&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;. &lt;br /&gt;
&lt;br /&gt;
The same activation energy value was found for the H + HF reaction but instead due to the late transition state, a BC value of 210 pm was used.&lt;br /&gt;
&lt;br /&gt;
== Question 4 ==&lt;br /&gt;
I&#039;&#039;&#039;n light of the fact that energy is conserved, discuss the mechanism of release of the reaction energy. Explain how this could be confirmed experimentally.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
There are two mechanisms of the release of reaction energy; the release of translational kinetic energy and also the release of vibrational kinetic energy. A bomb calorimeter can not differentiate between these 2 mechanisms as it only measures the heat released; therefore IR could be used to measure the radiation emitted from the vibrational energy known as chemiluminescence.The momenta vs time graph below is formed by having an A-B distance of 190 pm and B-C distance of 74 pm with a momentum of -3 and -11 g.mol-&amp;lt;sup&amp;gt;1&amp;lt;/sup&amp;gt;.pm.fs&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt; respectively. It shows H-H moving with vibrational energy towards F creating some vibrational energy in H-F. After the collision occurs, H-F now has vibrational energy while the H moves with no vibrational energy.  &lt;br /&gt;
&lt;br /&gt;
== Question 5 ==&lt;br /&gt;
&#039;&#039;&#039;Discuss how the distribution of energy between&amp;lt;nowiki&amp;gt; &amp;lt;/nowiki&amp;gt;different modes (translation and vibration) affect the efficiency of the reaction, and how this is influenced by the position of the transition state.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
Referring back to Polanyi&#039;s rule where translational energy is more efficient with an early transition state and vibrational energy being more efficient with a late transition state; the efficiency of the reaction is influenced by which energy is used and where the transition state lies.&lt;/div&gt;</summary>
		<author><name>Tr318</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:T01574856&amp;diff=805761</id>
		<title>MRD:T01574856</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:T01574856&amp;diff=805761"/>
		<updated>2020-05-15T21:23:10Z</updated>

		<summary type="html">&lt;p&gt;Tr318: /* Question 4 */&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;= Molecular Reaction Dynamics Lab =&lt;br /&gt;
&lt;br /&gt;
= &amp;lt;br&amp;gt; Exercise 1: H + H&amp;lt;sub&amp;gt;2 &amp;lt;/sub&amp;gt;System =&lt;br /&gt;
&lt;br /&gt;
== Question 1 ==&lt;br /&gt;
&#039;&#039;&#039;On a potential energy surface diagram, how is the transition state mathematically defined? How can the transition state be identified, and how can it be distinguished from a local minimum of the potential energy surface?&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
The transition state is mathematically defined as the maximum on the minimum energy path which links the reactants and products together. The transition state can be identified on a potential energy surface diagram by looking at the gradient of the potential, at the point of the transition state, the gradient would be zero (dV&amp;lt;sub&amp;gt;(ri)&amp;lt;/sub&amp;gt;/d&amp;lt;sub&amp;gt;ri&amp;lt;/sub&amp;gt;=0). This point is distinguished from a local minimum of the potential energy surface by starting trajectories near the transition state and observing the atoms rolling towards the reactants or the products.&lt;br /&gt;
&lt;br /&gt;
== Question 2 ==&lt;br /&gt;
&#039;&#039;&#039;Report your best estimate of the transition state position (r&amp;lt;sub&amp;gt;ts&amp;lt;/sub&amp;gt;) and explain your reasoning illustrating it with a “Internuclear Distances vs Time” plot for a relevant trajectory.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
The best estimate for the transition state position is at r&amp;lt;sub&amp;gt;ts&amp;lt;/sub&amp;gt;=0 and p=0. This is shown below in the contour diagram as this is in the saddle point; the maxima in one direction and the minima in another. This estimate is also supported by the internuclear distances vs time graph below as it shows the distances of the B-C bond and between the atoms A and C moving symmetrically at the same time. No product is formed at this point.&lt;br /&gt;
[[File:TR H2HTScont.png|left|thumb|302x302px|Contour diagram showing the transition state involved in this reaction.]]&lt;br /&gt;
[[File:TR H2HTS.png|centre|thumb|Internuclear distances vs time graph of H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt; + H reaction.]]&lt;br /&gt;
&lt;br /&gt;
== Question 3 ==&lt;br /&gt;
&#039;&#039;&#039;Comment on how the &#039;&#039;mep&#039;&#039; and the trajectory you just calculated differ.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
== Question 4 ==&lt;br /&gt;
&#039;&#039;&#039;Complete the table above by adding the total  energy, whether the trajectory is reactive or unreactive, and provide a  plot of the trajectory and a small description for what happens along  the trajectory. What can you conclude from the table?&#039;&#039;&#039;&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
!p&amp;lt;sub&amp;gt;1&amp;lt;/sub&amp;gt;/ g.mol&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;.pm.fs&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;&lt;br /&gt;
!p&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;/ g.mol&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;.pm.fs&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;&lt;br /&gt;
!E&amp;lt;sub&amp;gt;tot&amp;lt;/sub&amp;gt;/ kJ.mol&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;&lt;br /&gt;
!Reactive?&lt;br /&gt;
!Description of the dynamics&lt;br /&gt;
!Illustration of the trajectory&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-2.56&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-5.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-414.280&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|Reactive&lt;br /&gt;
|Reactants collide with the required energy to form the products. &lt;br /&gt;
|[[File:1zl.png|thumb|190x190px]]&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-3.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-4.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-420.007&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|Unreactive&lt;br /&gt;
|Reactants have momentum but do not collide so no reaction takes place and products are not formed.&lt;br /&gt;
|[[File:2zl.png|thumb|187x187px]]&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-3.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-5.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-413.977&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|Reactive&lt;br /&gt;
|Reactants collide with the required energy to form the products.&lt;br /&gt;
|[[File:3zl.png|thumb|191x191px]]&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-5.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-10.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-357.277&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|Unreactive&lt;br /&gt;
|Reactants collide but product is not formed since there is not enough energy for the reaction to take place.&lt;br /&gt;
|[[File:4zl.png|thumb|194x194px]]&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-5.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-10.6&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-349.477&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|Reactive&lt;br /&gt;
|&lt;br /&gt;
|[[File:5zl.png|thumb|206x206px]]&lt;br /&gt;
|}&lt;br /&gt;
This table tells us that every reaction here had the activation energy required for the reaction to take place but 2/5 times the reaction did not occur. There are other factors such as momenta involved which can effect the outcome.&lt;br /&gt;
&lt;br /&gt;
== Question 5 ==&lt;br /&gt;
&#039;&#039;&#039;Given the results you have obtained, how will Transition State Theory predictions for reaction rate values compare with experimental values?&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
Transition state theory uses the properties of the reactants and the transition state to rationalise and calculate the rate of chemical reactions. There are a few assumptions made in transition state theory; one is that all collisions with the required kinetic energy (activation energy) will result in a reaction. Another is that, once the collision occurs and the trajectory passes the barrier, it cannot turn back into the reactants. This does not always occur experimentally as seen in the table above as there are reactants which have the required activation energy which do not react and also there is an example of a collision occuring which resulted in the reactants reforming instead of products forming. In conclusion, this leads to transition theory over-estimating the reaction rates.&lt;br /&gt;
&lt;br /&gt;
= Exercise 2: F-H-H System =&lt;br /&gt;
&lt;br /&gt;
== Question 1 ==&lt;br /&gt;
&#039;&#039;&#039;By inspecting the potential energy surfaces, classify the F + H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;&amp;lt;nowiki&amp;gt; &amp;lt;/nowiki&amp;gt;and H + HF reactions according to their energetics (endothermic or exothermic). How does this relate to the bond strength of the chemical species involved?&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
To find out if these reactions are exothermic or endothermic a combination of Polanyi&#039;s rules and the Hammond&#039;s postulate was used. Polanyi&#039;s rules look at the early and late barriers of a reaction, this is where the transition state lies on the potential energy surface. An early barrier lies with the transition state closer to the reactants while in a late barrier the transition state lies closer to the products. Translational energy is more efficient to complete the reaction where there is an early barrier but vibrational energy is more efficient in a late barrier reaction. Alongside Polanyi&#039;s rules, the Hammond&#039;s postulate shows that an exothermic reaction has a transition state resembles the reactants  (early barrier) and an endothermic reaction has a transition state resembling the products (a late barrier).&lt;br /&gt;
&lt;br /&gt;
Looking at the potential energy surface of the reaction, F + H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;, it can be seen that there is an early barrier suggesting a transition state close to the reactants and an exothermic reaction. On the other hand , the reaction of H + HF shows a late transition state, late barrier and therfore an endothermic reaction. &lt;br /&gt;
&lt;br /&gt;
This relates to bond strength as more energy is needed to break the H-F bond than the H-H bond in the exothermic reaction resulting in showing that a H-F bond is stronger than a H-H bond.&lt;br /&gt;
&lt;br /&gt;
== Question 2 ==&lt;br /&gt;
&#039;&#039;&#039;Locate the approximate position of the transition state.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
The location state of both these reactions would have the same coordinates but in the opposite form. To locate the transition state Hammond&#039;s postulate was used alongside looking at the PES graph of the reaction of F with H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;. It was known that there was an early transition state so the distance of AB (F-H) would be longer than the already known distance of H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;. The point of the transition state was found to produce a single point on the graph at an AB distance of 181.4 pm and a BC distance of 74 pm.&lt;br /&gt;
&lt;br /&gt;
== Question 3 ==&lt;br /&gt;
&#039;&#039;&#039;Report the activation energy for both reactions.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
A resonable estimate was formed by performing an mep with 1500 steps and 0.1 step size from a structure neighbouring the transition state.&lt;br /&gt;
&lt;br /&gt;
The activation energy fro F + H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt; reaction was found by using an AB distance closer to the reactants (210 pm) due to its early transition state giving an activation energy of -0.341 kJ/ mol&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;. &lt;br /&gt;
&lt;br /&gt;
The same activation energy value was found for the H + HF reaction but instead due to the late transition state, a BC value of 210 pm was used.&lt;br /&gt;
&lt;br /&gt;
== Question 4 ==&lt;br /&gt;
I&#039;&#039;&#039;n light of the fact that energy is conserved, discuss the mechanism of release of the reaction energy. Explain how this could be confirmed experimentally.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
There are two mechanisms of the release of reaction energy; the release of translational kinetic energy and also the release of vibrational kinetic energy. A bomb calorimeter can not differentiate between these 2 mechanisms as it only measures the heat released; therefore IR could be used to measure the radiation emitted from the vibrational energy known as chemiluminescence.The momenta vs time graph below is formed by having an A-B distance of 190 pm and B-C distance of 74 pm with a momentum of -3 and -11 g.mol-&amp;lt;sup&amp;gt;1&amp;lt;/sup&amp;gt;.pm.fs&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt; respectively. It shows H-H moving with vibrational energy towards F creating some vibrational energy in H-F. After the collision occurs, H-F now has vibrational energy while the H moves with no vibrational energy.  &lt;br /&gt;
&lt;br /&gt;
== Question 5 ==&lt;br /&gt;
&#039;&#039;&#039;Discuss how the distribution of energy between&amp;lt;nowiki&amp;gt; &amp;lt;/nowiki&amp;gt;different modes (translation and vibration) affect the efficiency of the reaction, and how this is influenced by the position of the transition state.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
Referring back to Polanyi&#039;s rule where translational energy is more efficient with an early transition state and vibrational energy being more efficient with a late transition state; the efficiency of the reaction is influenced by which energy is used and where the transition state lies.&lt;/div&gt;</summary>
		<author><name>Tr318</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:T01574856&amp;diff=805346</id>
		<title>MRD:T01574856</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:T01574856&amp;diff=805346"/>
		<updated>2020-05-15T19:13:20Z</updated>

		<summary type="html">&lt;p&gt;Tr318: /* Question 5 */&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;= Molecular Reaction Dynamics Lab =&lt;br /&gt;
&lt;br /&gt;
= &amp;lt;br&amp;gt; Exercise 1: H + H&amp;lt;sub&amp;gt;2 &amp;lt;/sub&amp;gt;System =&lt;br /&gt;
&lt;br /&gt;
== Question 1 ==&lt;br /&gt;
&#039;&#039;&#039;On a potential energy surface diagram, how is the transition state mathematically defined? How can the transition state be identified, and how can it be distinguished from a local minimum of the potential energy surface?&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
The transition state is mathematically defined as the maximum on the minimum energy path which links the reactants and products together. The transition state can be identified on a potential energy surface diagram by looking at the gradient of the potential, at the point of the transition state, the gradient would be zero (dV&amp;lt;sub&amp;gt;(ri)&amp;lt;/sub&amp;gt;/d&amp;lt;sub&amp;gt;ri&amp;lt;/sub&amp;gt;=0). This point is distinguished from a local minimum of the potential energy surface by starting trajectories near the transition state and observing the atoms rolling towards the reactants or the products.&lt;br /&gt;
&lt;br /&gt;
== Question 2 ==&lt;br /&gt;
&#039;&#039;&#039;Report your best estimate of the transition state position (r&amp;lt;sub&amp;gt;ts&amp;lt;/sub&amp;gt;) and explain your reasoning illustrating it with a “Internuclear Distances vs Time” plot for a relevant trajectory.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
The best estimate for the transition state position is at r&amp;lt;sub&amp;gt;ts&amp;lt;/sub&amp;gt;=0 and p=0. This is shown below in the contour diagram as this is in the saddle point; the maxima in one direction and the minima in another. This estimate is also supported by the internuclear distances vs time graph below as it shows the distances of the B-C bond and between the atoms A and C moving symmetrically at the same time. No product is formed at this point.&lt;br /&gt;
[[File:TR H2HTScont.png|left|thumb|302x302px|Contour diagram showing the transition state involved in this reaction.]]&lt;br /&gt;
[[File:TR H2HTS.png|centre|thumb|Internuclear distances vs time graph of H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt; + H reaction.]]&lt;br /&gt;
&lt;br /&gt;
== Question 3 ==&lt;br /&gt;
&#039;&#039;&#039;Comment on how the &#039;&#039;mep&#039;&#039; and the trajectory you just calculated differ.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
== Question 4 ==&lt;br /&gt;
&#039;&#039;&#039;Complete the table above by adding the total  energy, whether the trajectory is reactive or unreactive, and provide a  plot of the trajectory and a small description for what happens along  the trajectory. What can you conclude from the table?&#039;&#039;&#039;&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
!p&amp;lt;sub&amp;gt;1&amp;lt;/sub&amp;gt;/ g.mol&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;.pm.fs&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;&lt;br /&gt;
!p&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;/ g.mol&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;.pm.fs&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;&lt;br /&gt;
!E&amp;lt;sub&amp;gt;tot&amp;lt;/sub&amp;gt;/ kJ.mol&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;&lt;br /&gt;
!Reactive?&lt;br /&gt;
!Description of the dynamics&lt;br /&gt;
!Illustration of the trajectory&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-2.56&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-5.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-414.280&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|Reactive&lt;br /&gt;
|Reactants collide with the required energy to form the products. &lt;br /&gt;
|[[File:1zl.png|thumb|190x190px]]&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-3.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-4.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-420.007&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|Unreactive&lt;br /&gt;
|Reactants have momentum but do not collide so no reaction takes place and products are not formed.&lt;br /&gt;
|[[File:2zl.png|thumb|187x187px]]&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-3.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-5.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-413.977&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|Reactive&lt;br /&gt;
|Reactants collide with the required energy to form the products.&lt;br /&gt;
|[[File:3zl.png|thumb|191x191px]]&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-5.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-10.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-357.277&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|Unreactive&lt;br /&gt;
|Reactants collide but product is not formed since there is not enough energy for the reaction to take place.&lt;br /&gt;
|[[File:4zl.png|thumb|194x194px]]&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-5.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-10.6&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-349.477&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|Reactive&lt;br /&gt;
|Reactants collide and products are formed.&lt;br /&gt;
|[[File:5zl.png|thumb|206x206px]]&lt;br /&gt;
|}&lt;br /&gt;
&lt;br /&gt;
== Question 5 ==&lt;br /&gt;
&#039;&#039;&#039;Given the results you have obtained, how will Transition State Theory predictions for reaction rate values compare with experimental values?&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
Transition state theory uses the properties of the reactants and the transition state to rationalise and calculate the rate of chemical reactions. There are a few assumptions made in transition state theory; one is that all collisions with the required kinetic energy (activation energy) will result in a reaction. Another is that, once the collision occurs and the trajectory passes the barrier, it cannot turn back into the reactants. This does not always occur experimentally as seen in the table above as there are reactants which have the required activation energy which do not react and also there is an example of a collision occuring which resulted in the reactants reforming instead of products forming. In conclusion, this leads to transition theory over-estimating the reaction rates.&lt;br /&gt;
&lt;br /&gt;
= Exercise 2: F-H-H System =&lt;br /&gt;
&lt;br /&gt;
== Question 1 ==&lt;br /&gt;
&#039;&#039;&#039;By inspecting the potential energy surfaces, classify the F + H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;&amp;lt;nowiki&amp;gt; &amp;lt;/nowiki&amp;gt;and H + HF reactions according to their energetics (endothermic or exothermic). How does this relate to the bond strength of the chemical species involved?&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
To find out if these reactions are exothermic or endothermic a combination of Polanyi&#039;s rules and the Hammond&#039;s postulate was used. Polanyi&#039;s rules look at the early and late barriers of a reaction, this is where the transition state lies on the potential energy surface. An early barrier lies with the transition state closer to the reactants while in a late barrier the transition state lies closer to the products. Translational energy is more efficient to complete the reaction where there is an early barrier but vibrational energy is more efficient in a late barrier reaction. Alongside Polanyi&#039;s rules, the Hammond&#039;s postulate shows that an exothermic reaction has a transition state resembles the reactants  (early barrier) and an endothermic reaction has a transition state resembling the products (a late barrier).&lt;br /&gt;
&lt;br /&gt;
Looking at the potential energy surface of the reaction, F + H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;, it can be seen that there is an early barrier suggesting a transition state close to the reactants and an exothermic reaction. On the other hand , the reaction of H + HF shows a late transition state, late barrier and therfore an endothermic reaction. &lt;br /&gt;
&lt;br /&gt;
This relates to bond strength as more energy is needed to break the H-F bond than the H-H bond in the exothermic reaction resulting in showing that a H-F bond is stronger than a H-H bond.&lt;br /&gt;
&lt;br /&gt;
== Question 2 ==&lt;br /&gt;
&#039;&#039;&#039;Locate the approximate position of the transition state.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
The location state of both these reactions would have the same coordinates but in the opposite form. To locate the transition state Hammond&#039;s postulate was used alongside looking at the PES graph of the reaction of F with H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;. It was known that there was an early transition state so the distance of AB (F-H) would be longer than the already known distance of H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;. The point of the transition state was found to produce a single point on the graph at an AB distance of 181.4 pm and a BC distance of 74 pm.&lt;br /&gt;
&lt;br /&gt;
== Question 3 ==&lt;br /&gt;
&#039;&#039;&#039;Report the activation energy for both reactions.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
A resonable estimate was formed by performing an mep with 1500 steps and 0.1 step size from a structure neighbouring the transition state.&lt;br /&gt;
&lt;br /&gt;
The activation energy fro F + H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt; reaction was found by using an AB distance closer to the reactants (210 pm) due to its early transition state giving an activation energy of -0.341 kJ/ mol&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;. &lt;br /&gt;
&lt;br /&gt;
The same activation energy value was found for the H + HF reaction but instead due to the late transition state, a BC value of 210 pm was used.&lt;br /&gt;
&lt;br /&gt;
== Question 4 ==&lt;br /&gt;
I&#039;&#039;&#039;n light of the fact that energy is conserved, discuss the mechanism of release of the reaction energy. Explain how this could be confirmed experimentally.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
There are two mechanisms of the release of reaction energy; the release of translational kinetic energy and also the release of vibrational kinetic energy. A bomb calorimeter can not differentiate between these 2 mechanisms as it only measures the heat released; therefore  &lt;br /&gt;
&lt;br /&gt;
== Question 5 ==&lt;br /&gt;
&#039;&#039;&#039;Discuss how the distribution of energy between&amp;lt;nowiki&amp;gt; &amp;lt;/nowiki&amp;gt;different modes (translation and vibration) affect the efficiency of the reaction, and how this is influenced by the position of the transition state.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
When the system is relaxed, the ground state energy is populated the most.&lt;/div&gt;</summary>
		<author><name>Tr318</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:T01574856&amp;diff=805158</id>
		<title>MRD:T01574856</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:T01574856&amp;diff=805158"/>
		<updated>2020-05-15T18:12:19Z</updated>

		<summary type="html">&lt;p&gt;Tr318: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;= Molecular Reaction Dynamics Lab =&lt;br /&gt;
&lt;br /&gt;
= &amp;lt;br&amp;gt; Exercise 1: H + H&amp;lt;sub&amp;gt;2 &amp;lt;/sub&amp;gt;System =&lt;br /&gt;
&lt;br /&gt;
== Question 1 ==&lt;br /&gt;
&#039;&#039;&#039;On a potential energy surface diagram, how is the transition state mathematically defined? How can the transition state be identified, and how can it be distinguished from a local minimum of the potential energy surface?&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
The transition state is mathematically defined as the maximum on the minimum energy path which links the reactants and products together. The transition state can be identified on a potential energy surface diagram by looking at the gradient of the potential, at the point of the transition state, the gradient would be zero (dV&amp;lt;sub&amp;gt;(ri)&amp;lt;/sub&amp;gt;/d&amp;lt;sub&amp;gt;ri&amp;lt;/sub&amp;gt;=0). This point is distinguished from a local minimum of the potential energy surface by starting trajectories near the transition state and observing the atoms rolling towards the reactants or the products.&lt;br /&gt;
&lt;br /&gt;
== Question 2 ==&lt;br /&gt;
&#039;&#039;&#039;Report your best estimate of the transition state position (r&amp;lt;sub&amp;gt;ts&amp;lt;/sub&amp;gt;) and explain your reasoning illustrating it with a “Internuclear Distances vs Time” plot for a relevant trajectory.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
The best estimate for the transition state position is at r&amp;lt;sub&amp;gt;ts&amp;lt;/sub&amp;gt;=0 and p=0. This is shown below in the contour diagram as this is in the saddle point; the maxima in one direction and the minima in another. This estimate is also supported by the internuclear distances vs time graph below as it shows the distances of the B-C bond and between the atoms A and C moving symmetrically at the same time. No product is formed at this point.&lt;br /&gt;
[[File:TR H2HTScont.png|left|thumb|302x302px|Contour diagram showing the transition state involved in this reaction.]]&lt;br /&gt;
[[File:TR H2HTS.png|centre|thumb|Internuclear distances vs time graph of H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt; + H reaction.]]&lt;br /&gt;
&lt;br /&gt;
== Question 3 ==&lt;br /&gt;
&#039;&#039;&#039;Comment on how the &#039;&#039;mep&#039;&#039; and the trajectory you just calculated differ.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
== Question 4 ==&lt;br /&gt;
&#039;&#039;&#039;Complete the table above by adding the total  energy, whether the trajectory is reactive or unreactive, and provide a  plot of the trajectory and a small description for what happens along  the trajectory. What can you conclude from the table?&#039;&#039;&#039;&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
!p&amp;lt;sub&amp;gt;1&amp;lt;/sub&amp;gt;/ g.mol&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;.pm.fs&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;&lt;br /&gt;
!p&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;/ g.mol&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;.pm.fs&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;&lt;br /&gt;
!E&amp;lt;sub&amp;gt;tot&amp;lt;/sub&amp;gt;/ kJ.mol&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;&lt;br /&gt;
!Reactive?&lt;br /&gt;
!Description of the dynamics&lt;br /&gt;
!Illustration of the trajectory&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-2.56&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-5.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-414.280&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|Reactive&lt;br /&gt;
|Reactants collide with the required energy to form the products. &lt;br /&gt;
|[[File:1zl.png|thumb|190x190px]]&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-3.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-4.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-420.007&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|Unreactive&lt;br /&gt;
|Reactants have momentum but do not collide so no reaction takes place and products are not formed.&lt;br /&gt;
|[[File:2zl.png|thumb|187x187px]]&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-3.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-5.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-413.977&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|Reactive&lt;br /&gt;
|Reactants collide with the required energy to form the products.&lt;br /&gt;
|[[File:3zl.png|thumb|191x191px]]&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-5.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-10.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-357.277&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|Unreactive&lt;br /&gt;
|Reactants collide but product is not formed since there is not enough energy for the reaction to take place.&lt;br /&gt;
|[[File:4zl.png|thumb|194x194px]]&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-5.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-10.6&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-349.477&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|Reactive&lt;br /&gt;
|Reactants collide and products are formed.&lt;br /&gt;
|[[File:5zl.png|thumb|206x206px]]&lt;br /&gt;
|}&lt;br /&gt;
&lt;br /&gt;
== Question 5 ==&lt;br /&gt;
&#039;&#039;&#039;Given the results you have obtained, how will Transition State Theory predictions for reaction rate values compare with experimental values?&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
= Exercise 2: F-H-H System =&lt;br /&gt;
&lt;br /&gt;
== Question 1 ==&lt;br /&gt;
&#039;&#039;&#039;By inspecting the potential energy surfaces, classify the F + H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;&amp;lt;nowiki&amp;gt; &amp;lt;/nowiki&amp;gt;and H + HF reactions according to their energetics (endothermic or exothermic). How does this relate to the bond strength of the chemical species involved?&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
To find out if these reactions are exothermic or endothermic a combination of Polanyi&#039;s rules and the Hammond&#039;s postulate was used. Polanyi&#039;s rules look at the early and late barriers of a reaction, this is where the transition state lies on the potential energy surface. An early barrier lies with the transition state closer to the reactants while in a late barrier the transition state lies closer to the products. Translational energy is more efficient to complete the reaction where there is an early barrier but vibrational energy is more efficient in a late barrier reaction. Alongside Polanyi&#039;s rules, the Hammond&#039;s postulate shows that an exothermic reaction has a transition state resembles the reactants  (early barrier) and an endothermic reaction has a transition state resembling the products (a late barrier).&lt;br /&gt;
&lt;br /&gt;
Looking at the potential energy surface of the reaction, F + H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;, it can be seen that there is an early barrier suggesting a transition state close to the reactants and an exothermic reaction. On the other hand , the reaction of H + HF shows a late transition state, late barrier and therfore an endothermic reaction. &lt;br /&gt;
&lt;br /&gt;
This relates to bond strength as more energy is needed to break the H-F bond than the H-H bond in the exothermic reaction resulting in showing that a H-F bond is stronger than a H-H bond.&lt;br /&gt;
&lt;br /&gt;
== Question 2 ==&lt;br /&gt;
&#039;&#039;&#039;Locate the approximate position of the transition state.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
The location state of both these reactions would have the same coordinates but in the opposite form. To locate the transition state Hammond&#039;s postulate was used alongside looking at the PES graph of the reaction of F with H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;. It was known that there was an early transition state so the distance of AB (F-H) would be longer than the already known distance of H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;. The point of the transition state was found to produce a single point on the graph at an AB distance of 181.4 pm and a BC distance of 74 pm.&lt;br /&gt;
&lt;br /&gt;
== Question 3 ==&lt;br /&gt;
&#039;&#039;&#039;Report the activation energy for both reactions.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
A resonable estimate was formed by performing an mep with 1500 steps and 0.1 step size from a structure neighbouring the transition state.&lt;br /&gt;
&lt;br /&gt;
The activation energy fro F + H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt; reaction was found by using an AB distance closer to the reactants (210 pm) due to its early transition state giving an activation energy of -0.341 kJ/ mol&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;. &lt;br /&gt;
&lt;br /&gt;
The same activation energy value was found for the H + HF reaction but instead due to the late transition state, a BC value of 210 pm was used.&lt;br /&gt;
&lt;br /&gt;
== Question 4 ==&lt;br /&gt;
I&#039;&#039;&#039;n light of the fact that energy is conserved, discuss the mechanism of release of the reaction energy. Explain how this could be confirmed experimentally.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
There are two mechanisms of the release of reaction energy; the release of translational kinetic energy and also the release of vibrational kinetic energy. A bomb calorimeter can not differentiate between these 2 mechanisms as it only measures the heat released; therefore  &lt;br /&gt;
&lt;br /&gt;
== Question 5 ==&lt;br /&gt;
&#039;&#039;&#039;Discuss how the distribution of energy between&amp;lt;nowiki&amp;gt; &amp;lt;/nowiki&amp;gt;different modes (translation and vibration) affect the efficiency of the reaction, and how this is influenced by the position of the transition state.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
When the system is relaxed, the ground state energy is populated the most.&lt;/div&gt;</summary>
		<author><name>Tr318</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=File:TR_H2HTS.png&amp;diff=805135</id>
		<title>File:TR H2HTS.png</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=File:TR_H2HTS.png&amp;diff=805135"/>
		<updated>2020-05-15T18:02:45Z</updated>

		<summary type="html">&lt;p&gt;Tr318: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;/div&gt;</summary>
		<author><name>Tr318</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=File:TR_H2HTScont.png&amp;diff=805126</id>
		<title>File:TR H2HTScont.png</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=File:TR_H2HTScont.png&amp;diff=805126"/>
		<updated>2020-05-15T17:59:46Z</updated>

		<summary type="html">&lt;p&gt;Tr318: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;/div&gt;</summary>
		<author><name>Tr318</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=File:1TR01574856.png&amp;diff=804993</id>
		<title>File:1TR01574856.png</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=File:1TR01574856.png&amp;diff=804993"/>
		<updated>2020-05-15T17:13:29Z</updated>

		<summary type="html">&lt;p&gt;Tr318: Graph 1&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;Graph 1&lt;/div&gt;</summary>
		<author><name>Tr318</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=File:1zl.png&amp;diff=804983</id>
		<title>File:1zl.png</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=File:1zl.png&amp;diff=804983"/>
		<updated>2020-05-15T17:11:46Z</updated>

		<summary type="html">&lt;p&gt;Tr318: Tr318 uploaded a new version of File:1zl.png&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;/div&gt;</summary>
		<author><name>Tr318</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:T01574856&amp;diff=804965</id>
		<title>MRD:T01574856</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:T01574856&amp;diff=804965"/>
		<updated>2020-05-15T17:08:19Z</updated>

		<summary type="html">&lt;p&gt;Tr318: /* Question 4 */&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;= Molecular Reaction Dynamics Lab =&lt;br /&gt;
&lt;br /&gt;
= &amp;lt;br&amp;gt; Exercise 1: H + H&amp;lt;sub&amp;gt;2 &amp;lt;/sub&amp;gt;System =&lt;br /&gt;
&lt;br /&gt;
== Question 1 ==&lt;br /&gt;
&#039;&#039;&#039;On a potential energy surface diagram, how is the transition state mathematically defined? How can the transition state be identified, and how can it be distinguished from a local minimum of the potential energy surface?&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
The transition state is mathematically defined as the maximum on the minimum energy path which links the reactants and products together. The transition state can be identified on a potential energy surface diagram by looking at the gradient of the potential, at the point of the transition state, the gradient would be zero (dV&amp;lt;sub&amp;gt;(ri)&amp;lt;/sub&amp;gt;/d&amp;lt;sub&amp;gt;ri&amp;lt;/sub&amp;gt;=0). This point is distinguished from a local minimum of the potential energy surface by starting trajectories near the transition state and observing the atoms rolling towards the reactants or the products.&lt;br /&gt;
&lt;br /&gt;
== Question 2 ==&lt;br /&gt;
&#039;&#039;&#039;Report your best estimate of the transition state position (r&amp;lt;sub&amp;gt;ts&amp;lt;/sub&amp;gt;) and explain your reasoning illustrating it with a “Internuclear Distances vs Time” plot for a relevant trajectory.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
== Question 3 ==&lt;br /&gt;
&#039;&#039;&#039;Comment on how the &#039;&#039;mep&#039;&#039; and the trajectory you just calculated differ.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
== Question 4 ==&lt;br /&gt;
&#039;&#039;&#039;Complete the table above by adding the total  energy, whether the trajectory is reactive or unreactive, and provide a  plot of the trajectory and a small description for what happens along  the trajectory. What can you conclude from the table?&#039;&#039;&#039;&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
!p&amp;lt;sub&amp;gt;1&amp;lt;/sub&amp;gt;/ g.mol&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;.pm.fs&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;&lt;br /&gt;
!p&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;/ g.mol&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;.pm.fs&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;&lt;br /&gt;
!E&amp;lt;sub&amp;gt;tot&amp;lt;/sub&amp;gt;/ kJ.mol&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;&lt;br /&gt;
!Reactive?&lt;br /&gt;
!Description of the dynamics&lt;br /&gt;
!Illustration of the trajectory&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-2.56&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-5.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-414.280&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|Reactive&lt;br /&gt;
|Reactants collide with the required energy to form the products. &lt;br /&gt;
|&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-3.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-4.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-420.007&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|Unreactive&lt;br /&gt;
|Reactants have momentum but do not collide so no reaction takes place and products are not formed.&lt;br /&gt;
|&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-3.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-5.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-413.977&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|Reactive&lt;br /&gt;
|Reactants collide with the required energy to form the products.&lt;br /&gt;
|&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-5.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-10.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-357.277&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|Unreactive&lt;br /&gt;
|Reactants collide but product is not formed since there is not enough energy for the reaction to take place.&lt;br /&gt;
|&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-5.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-10.6&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-349.477&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|Reactive&lt;br /&gt;
|Reactants collide and products are formed.&lt;br /&gt;
|&lt;br /&gt;
|}&lt;br /&gt;
&lt;br /&gt;
== Question 5 ==&lt;br /&gt;
&#039;&#039;&#039;Given the results you have obtained, how will Transition State Theory predictions for reaction rate values compare with experimental values?&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
= Exercise 2: F-H-H System =&lt;br /&gt;
&lt;br /&gt;
== Question 1 ==&lt;br /&gt;
&#039;&#039;&#039;By inspecting the potential energy surfaces, classify the F + H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;&amp;lt;nowiki&amp;gt; &amp;lt;/nowiki&amp;gt;and H + HF reactions according to their energetics (endothermic or exothermic). How does this relate to the bond strength of the chemical species involved?&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
To find out if these reactions are exothermic or endothermic a combination of Polanyi&#039;s rules and the Hammond&#039;s postulate was used. Polanyi&#039;s rules look at the early and late barriers of a reaction, this is where the transition state lies on the potential energy surface. An early barrier lies with the transition state closer to the reactants while in a late barrier the transition state lies closer to the products. Translational energy is more efficient to complete the reaction where there is an early barrier but vibrational energy is more efficient in a late barrier reaction. Alongside Polanyi&#039;s rules, the Hammond&#039;s postulate shows that an exothermic reaction has a transition state resembles the reactants  (early barrier) and an endothermic reaction has a transition state resembling the products (a late barrier).&lt;br /&gt;
&lt;br /&gt;
Looking at the potential energy surface of the reaction, F + H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;, it can be seen that there is an early barrier suggesting a transition state close to the reactants and an exothermic reaction. On the other hand , the reaction of H + HF shows a late transition state, late barrier and therfore an endothermic reaction. &lt;br /&gt;
&lt;br /&gt;
This relates to bond strength as more energy is needed to break the H-F bond than the H-H bond in the exothermic reaction resulting in showing that a H-F bond is stronger than a H-H bond.&lt;br /&gt;
&lt;br /&gt;
== Question 2 ==&lt;br /&gt;
&#039;&#039;&#039;Locate the approximate position of the transition state.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
The location state of both these reactions would have the same coordinates but in the opposite form. To locate the transition state Hammond&#039;s postulate was used alongside looking at the PES graph of the reaction of F with H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;. It was known that there was an early transition state so the distance of AB (F-H) would be longer than the already known distance of H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;. The point of the transition state was found to produce a single point on the graph at an AB distance of 181.4 pm and a BC distance of 74 pm.&lt;br /&gt;
&lt;br /&gt;
== Question 3 ==&lt;br /&gt;
&#039;&#039;&#039;Report the activation energy for both reactions.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
A resonable estimate was formed by performing an mep with 1500 steps and 0.1 step size from a structure neighbouring the transition state.&lt;br /&gt;
&lt;br /&gt;
The activation energy fro F + H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt; reaction was found by using an AB distance closer to the reactants (210 pm) due to its early transition state giving an activation energy of -0.341 kJ/ mol&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;. &lt;br /&gt;
&lt;br /&gt;
The same activation energy value was found for the H + HF reaction but instead due to the late transition state, a BC value of 210 pm was used.&lt;br /&gt;
&lt;br /&gt;
== Question 4 ==&lt;br /&gt;
I&#039;&#039;&#039;n light of the fact that energy is conserved, discuss the mechanism of release of the reaction energy. Explain how this could be confirmed experimentally.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
There are two mechanisms of the release of reaction energy; the release of translational kinetic energy and also the release of vibrational kinetic energy. &lt;br /&gt;
&lt;br /&gt;
== Question 5 ==&lt;br /&gt;
&#039;&#039;&#039;Discuss how the distribution of energy between&amp;lt;nowiki&amp;gt; &amp;lt;/nowiki&amp;gt;different modes (translation and vibration) affect the efficiency of the reaction, and how this is influenced by the position of the transition state.&#039;&#039;&#039;&lt;/div&gt;</summary>
		<author><name>Tr318</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:T01574856&amp;diff=804859</id>
		<title>MRD:T01574856</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:T01574856&amp;diff=804859"/>
		<updated>2020-05-15T16:34:39Z</updated>

		<summary type="html">&lt;p&gt;Tr318: /* Question 2 */&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;= Molecular Reaction Dynamics Lab =&lt;br /&gt;
&lt;br /&gt;
= &amp;lt;br&amp;gt; Exercise 1: H + H&amp;lt;sub&amp;gt;2 &amp;lt;/sub&amp;gt;System =&lt;br /&gt;
&lt;br /&gt;
== Question 1 ==&lt;br /&gt;
&#039;&#039;&#039;On a potential energy surface diagram, how is the transition state mathematically defined? How can the transition state be identified, and how can it be distinguished from a local minimum of the potential energy surface?&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
The transition state is mathematically defined as the maximum on the minimum energy path which links the reactants and products together. The transition state can be identified on a potential energy surface diagram by looking at the gradient of the potential, at the point of the transition state, the gradient would be zero (dV&amp;lt;sub&amp;gt;(ri)&amp;lt;/sub&amp;gt;/d&amp;lt;sub&amp;gt;ri&amp;lt;/sub&amp;gt;=0). This point is distinguished from a local minimum of the potential energy surface by starting trajectories near the transition state and observing the atoms rolling towards the reactants or the products.&lt;br /&gt;
&lt;br /&gt;
== Question 2 ==&lt;br /&gt;
&#039;&#039;&#039;Report your best estimate of the transition state position (r&amp;lt;sub&amp;gt;ts&amp;lt;/sub&amp;gt;) and explain your reasoning illustrating it with a “Internuclear Distances vs Time” plot for a relevant trajectory.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
== Question 3 ==&lt;br /&gt;
&#039;&#039;&#039;Comment on how the &#039;&#039;mep&#039;&#039; and the trajectory you just calculated differ.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
== Question 4 ==&lt;br /&gt;
&#039;&#039;&#039;Complete the table above by adding the total  energy, whether the trajectory is reactive or unreactive, and provide a  plot of the trajectory and a small description for what happens along  the trajectory. What can you conclude from the table?&#039;&#039;&#039;&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
!p&amp;lt;sub&amp;gt;1&amp;lt;/sub&amp;gt;/ g.mol&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;.pm.fs&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;&lt;br /&gt;
!p&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;/ g.mol&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;.pm.fs&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;&lt;br /&gt;
!E&amp;lt;sub&amp;gt;tot&amp;lt;/sub&amp;gt;/ kJ.mol&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;&lt;br /&gt;
!Reactive?&lt;br /&gt;
!Description of the dynamics&lt;br /&gt;
!Illustration of the trajectory&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-2.56&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-5.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-414.280&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|Reactive&lt;br /&gt;
|Reactants collide with the required energy to form the products. &lt;br /&gt;
|&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-3.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-4.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-420.007&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|Unreactive&lt;br /&gt;
|Reactants have momentum but do not collide so no reaction takes place and products are not formed.&lt;br /&gt;
|&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-3.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-5.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-413.977&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|Reactive&lt;br /&gt;
|Reactants collide with the required energy to form the products.&lt;br /&gt;
|&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-5.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-10.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-357.277&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|Unreactive&lt;br /&gt;
|Reactants collide but product is not formed since there is not enough energy for the reaction to take place.&lt;br /&gt;
|&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-5.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-10.6&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-349.477&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|Reactive&lt;br /&gt;
|Reactants collide and products are formed.&lt;br /&gt;
|&lt;br /&gt;
|}&lt;br /&gt;
&lt;br /&gt;
== Question 5 ==&lt;br /&gt;
&#039;&#039;&#039;Given the results you have obtained, how will Transition State Theory predictions for reaction rate values compare with experimental values?&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
= Exercise 2: F-H-H System =&lt;br /&gt;
&lt;br /&gt;
== Question 1 ==&lt;br /&gt;
&#039;&#039;&#039;By inspecting the potential energy surfaces, classify the F + H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;&amp;lt;nowiki&amp;gt; &amp;lt;/nowiki&amp;gt;and H + HF reactions according to their energetics (endothermic or exothermic). How does this relate to the bond strength of the chemical species involved?&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
To find out if these reactions are exothermic or endothermic a combination of Polanyi&#039;s rules and the Hammond&#039;s postulate was used. Polanyi&#039;s rules look at the early and late barriers of a reaction, this is where the transition state lies on the potential energy surface. An early barrier lies with the transition state closer to the reactants while in a late barrier the transition state lies closer to the products. Translational energy is more efficient to complete the reaction where there is an early barrier but vibrational energy is more efficient in a late barrier reaction. Alongside Polanyi&#039;s rules, the Hammond&#039;s postulate shows that an exothermic reaction has a transition state resembles the reactants  (early barrier) and an endothermic reaction has a transition state resembling the products (a late barrier).&lt;br /&gt;
&lt;br /&gt;
Looking at the potential energy surface of the reaction, F + H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;, it can be seen that there is an early barrier suggesting a transition state close to the reactants and an exothermic reaction. On the other hand , the reaction of H + HF shows a late transition state, late barrier and therfore an endothermic reaction. &lt;br /&gt;
&lt;br /&gt;
This relates to bond strength as more energy is needed to break the H-F bond than the H-H bond in the exothermic reaction resulting in showing that a H-F bond is stronger than a H-H bond.&lt;br /&gt;
&lt;br /&gt;
== Question 2 ==&lt;br /&gt;
&#039;&#039;&#039;Locate the approximate position of the transition state.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
The location state of both these reactions would have the same coordinates but in the opposite form. To locate the transition state Hammond&#039;s postulate was used alongside looking at the PES graph of the reaction of F with H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;. It was known that there was an early transition state so the distance of AB (F-H) would be longer than the already known distance of H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;. The point of the transition state was found to produce a single point on the graph at an AB distance of 181.4 pm and a BC distance of 74 pm.&lt;br /&gt;
&lt;br /&gt;
== Question 3 ==&lt;br /&gt;
&#039;&#039;&#039;Report the activation energy for both reactions.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
A resonable estimate was formed by performing an mep with 1500 steps and 0.1 step size from a structure neighbouring the transition state.&lt;br /&gt;
&lt;br /&gt;
The activation energy fro F + H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt; reaction was found by using an AB distance closer to the reactants (210 pm) due to its early transition state giving an activation energy of -0.341 kJ/ mol&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;. &lt;br /&gt;
&lt;br /&gt;
The same activation energy value was found for the H + HF reaction but instead due to the late transition state, a BC value of 210 pm was used.&lt;br /&gt;
&lt;br /&gt;
== Question 4 ==&lt;br /&gt;
I&#039;&#039;&#039;n light of the fact that energy is conserved, discuss the mechanism of release of the reaction energy. Explain how this could be confirmed experimentally.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
== Question 5 ==&lt;br /&gt;
&#039;&#039;&#039;Discuss how the distribution of energy between&amp;lt;nowiki&amp;gt; &amp;lt;/nowiki&amp;gt;different modes (translation and vibration) affect the efficiency of the reaction, and how this is influenced by the position of the transition state.&#039;&#039;&#039;&lt;/div&gt;</summary>
		<author><name>Tr318</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:T01574856&amp;diff=804765</id>
		<title>MRD:T01574856</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:T01574856&amp;diff=804765"/>
		<updated>2020-05-15T15:50:05Z</updated>

		<summary type="html">&lt;p&gt;Tr318: /* Question 4 */&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;= Molecular Reaction Dynamics Lab =&lt;br /&gt;
&lt;br /&gt;
= &amp;lt;br&amp;gt; Exercise 1: H + H&amp;lt;sub&amp;gt;2 &amp;lt;/sub&amp;gt;System =&lt;br /&gt;
&lt;br /&gt;
== Question 1 ==&lt;br /&gt;
&#039;&#039;&#039;On a potential energy surface diagram, how is the transition state mathematically defined? How can the transition state be identified, and how can it be distinguished from a local minimum of the potential energy surface?&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
The transition state is mathematically defined as the maximum on the minimum energy path which links the reactants and products together. The transition state can be identified on a potential energy surface diagram by looking at the gradient of the potential, at the point of the transition state, the gradient would be zero (dV&amp;lt;sub&amp;gt;(ri)&amp;lt;/sub&amp;gt;/d&amp;lt;sub&amp;gt;ri&amp;lt;/sub&amp;gt;=0). This point is distinguished from a local minimum of the potential energy surface by starting trajectories near the transition state and observing the atoms rolling towards the reactants or the products.&lt;br /&gt;
&lt;br /&gt;
== Question 2 ==&lt;br /&gt;
&#039;&#039;&#039;Report your best estimate of the transition state position (r&amp;lt;sub&amp;gt;ts&amp;lt;/sub&amp;gt;) and explain your reasoning illustrating it with a “Internuclear Distances vs Time” plot for a relevant trajectory.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
== Question 3 ==&lt;br /&gt;
&#039;&#039;&#039;Comment on how the &#039;&#039;mep&#039;&#039; and the trajectory you just calculated differ.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
== Question 4 ==&lt;br /&gt;
&#039;&#039;&#039;Complete the table above by adding the total  energy, whether the trajectory is reactive or unreactive, and provide a  plot of the trajectory and a small description for what happens along  the trajectory. What can you conclude from the table?&#039;&#039;&#039;&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
!p&amp;lt;sub&amp;gt;1&amp;lt;/sub&amp;gt;/ g.mol&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;.pm.fs&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;&lt;br /&gt;
!p&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;/ g.mol&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;.pm.fs&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;&lt;br /&gt;
!E&amp;lt;sub&amp;gt;tot&amp;lt;/sub&amp;gt;/ kJ.mol&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;&lt;br /&gt;
!Reactive?&lt;br /&gt;
!Description of the dynamics&lt;br /&gt;
!Illustration of the trajectory&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-2.56&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-5.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-414.280&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|Reactive&lt;br /&gt;
|Reactants collide with the required energy to form the products. &lt;br /&gt;
|&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-3.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-4.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-420.007&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|Unreactive&lt;br /&gt;
|Reactants have momentum but do not collide so no reaction takes place and products are not formed.&lt;br /&gt;
|&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-3.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-5.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-413.977&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|Reactive&lt;br /&gt;
|Reactants collide with the required energy to form the products.&lt;br /&gt;
|&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-5.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-10.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-357.277&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|Unreactive&lt;br /&gt;
|Reactants collide but product is not formed since there is not enough energy for the reaction to take place.&lt;br /&gt;
|&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-5.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-10.6&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-349.477&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|Reactive&lt;br /&gt;
|Reactants collide and products are formed.&lt;br /&gt;
|&lt;br /&gt;
|}&lt;br /&gt;
&lt;br /&gt;
== Question 5 ==&lt;br /&gt;
&#039;&#039;&#039;Given the results you have obtained, how will Transition State Theory predictions for reaction rate values compare with experimental values?&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
= Exercise 2: F-H-H System =&lt;br /&gt;
&lt;br /&gt;
== Question 1 ==&lt;br /&gt;
&#039;&#039;&#039;By inspecting the potential energy surfaces, classify the F + H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;&amp;lt;nowiki&amp;gt; &amp;lt;/nowiki&amp;gt;and H + HF reactions according to their energetics (endothermic or exothermic). How does this relate to the bond strength of the chemical species involved?&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
To find out if these reactions are exothermic or endothermic a combination of Polanyi&#039;s rules and the Hammond&#039;s postulate was used. Polanyi&#039;s rules look at the early and late barriers of a reaction, this is where the transition state lies on the potential energy surface. An early barrier lies with the transition state closer to the reactants while in a late barrier the transition state lies closer to the products. Translational energy is more efficient to complete the reaction where there is an early barrier but vibrational energy is more efficient in a late barrier reaction. Alongside Polanyi&#039;s rules, the Hammond&#039;s postulate shows that an exothermic reaction has a transition state resembles the reactants  (early barrier) and an endothermic reaction has a transition state resembling the products (a late barrier).&lt;br /&gt;
&lt;br /&gt;
Looking at the potential energy surface of the reaction, F + H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;, it can be seen that there is an early barrier suggesting a transition state close to the reactants and an exothermic reaction. On the other hand , the reaction of H + HF shows a late transition state, late barrier and therfore an endothermic reaction. &lt;br /&gt;
&lt;br /&gt;
This relates to bond strength as more energy is needed to break the H-F bond than the H-H bond in the exothermic reaction resulting in showing that a H-F bond is stronger than a H-H bond.&lt;br /&gt;
&lt;br /&gt;
== Question 2 ==&lt;br /&gt;
Locate the approximate position of the transition state.&lt;br /&gt;
&lt;br /&gt;
== Question 3 ==&lt;br /&gt;
Report the activation energy for both reactions.&lt;br /&gt;
&lt;br /&gt;
== Question 4 ==&lt;br /&gt;
In light of the fact that energy is conserved,&lt;br /&gt;
&amp;lt;nowiki&amp;gt; &amp;lt;/nowiki&amp;gt;discuss the mechanism of release of the reaction energy. Explain how &lt;br /&gt;
this could be confirmed experimentally.&lt;br /&gt;
&lt;br /&gt;
== Question 5 ==&lt;br /&gt;
Discuss how the distribution of energy between&lt;br /&gt;
&amp;lt;nowiki&amp;gt; &amp;lt;/nowiki&amp;gt;different modes (translation and vibration) affect the efficiency of &lt;br /&gt;
the reaction, and how this is influenced by the position of the &lt;br /&gt;
transition state.&lt;/div&gt;</summary>
		<author><name>Tr318</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:T01574856&amp;diff=804260</id>
		<title>MRD:T01574856</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:T01574856&amp;diff=804260"/>
		<updated>2020-05-15T12:35:56Z</updated>

		<summary type="html">&lt;p&gt;Tr318: /* Question 4 */&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;= Molecular Reaction Dynamics Lab =&lt;br /&gt;
&lt;br /&gt;
= &amp;lt;br&amp;gt; Exercise 1: H + H&amp;lt;sub&amp;gt;2 &amp;lt;/sub&amp;gt;System =&lt;br /&gt;
&lt;br /&gt;
== Question 1 ==&lt;br /&gt;
&#039;&#039;&#039;On a potential energy surface diagram, how is the transition state mathematically defined? How can the transition state be identified, and how can it be distinguished from a local minimum of the potential energy surface?&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
The transition state is mathematically defined as the maximum on the minimum energy path which links the reactants and products together. The transition state can be identified on a potential energy surface diagram by looking at the gradient of the potential, at the point of the transition state, the gradient would be zero (dV&amp;lt;sub&amp;gt;(ri)&amp;lt;/sub&amp;gt;/d&amp;lt;sub&amp;gt;ri&amp;lt;/sub&amp;gt;=0). This point is distinguished from a local minimum of the potential energy surface by starting trajectories near the transition state and observing the atoms rolling towards the reactants or the products.&lt;br /&gt;
&lt;br /&gt;
== Question 2 ==&lt;br /&gt;
&#039;&#039;&#039;Report your best estimate of the transition state position (r&amp;lt;sub&amp;gt;ts&amp;lt;/sub&amp;gt;) and explain your reasoning illustrating it with a “Internuclear Distances vs Time” plot for a relevant trajectory.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
== Question 3 ==&lt;br /&gt;
&#039;&#039;&#039;Comment on how the &#039;&#039;mep&#039;&#039; and the trajectory you just calculated differ.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
== Question 4 ==&lt;br /&gt;
&#039;&#039;&#039;Complete the table above by adding the total  energy, whether the trajectory is reactive or unreactive, and provide a  plot of the trajectory and a small description for what happens along  the trajectory. What can you conclude from the table?&#039;&#039;&#039;&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
!p&amp;lt;sub&amp;gt;1&amp;lt;/sub&amp;gt;/ g.mol&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;.pm.fs&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;&lt;br /&gt;
!p&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;/ g.mol&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;.pm.fs&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;&lt;br /&gt;
!E&amp;lt;sub&amp;gt;tot&amp;lt;/sub&amp;gt;&lt;br /&gt;
!Reactive?&lt;br /&gt;
!Description of the dynamics&lt;br /&gt;
!Illustration of the trajectory&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-2.56&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-5.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-3.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-4.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-3.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-5.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-5.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-10.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&lt;br /&gt;
|Unreactive&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-5.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-10.6&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&lt;br /&gt;
|Unreactive&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|}&lt;br /&gt;
&lt;br /&gt;
== Question 5 ==&lt;br /&gt;
&#039;&#039;&#039;Given the results you have obtained, how will Transition State Theory predictions for reaction rate values compare with experimental values?&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
= Exercise 2: F-H-H System =&lt;br /&gt;
&lt;br /&gt;
== Question 1 ==&lt;br /&gt;
By inspecting the potential energy surfaces, classify the F + H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;&lt;br /&gt;
&amp;lt;nowiki&amp;gt; &amp;lt;/nowiki&amp;gt;and H + HF reactions according to their energetics (endothermic or &lt;br /&gt;
exothermic). How does this relate to the bond strength of the chemical &lt;br /&gt;
species involved?&lt;br /&gt;
&lt;br /&gt;
== Question 2 ==&lt;br /&gt;
Locate the approximate position of the transition state.&lt;br /&gt;
&lt;br /&gt;
== Question 3 ==&lt;br /&gt;
Report the activation energy for both reactions.&lt;br /&gt;
&lt;br /&gt;
== Question 4 ==&lt;br /&gt;
In light of the fact that energy is conserved,&lt;br /&gt;
&amp;lt;nowiki&amp;gt; &amp;lt;/nowiki&amp;gt;discuss the mechanism of release of the reaction energy. Explain how &lt;br /&gt;
this could be confirmed experimentally.&lt;br /&gt;
&lt;br /&gt;
== Question 5 ==&lt;br /&gt;
Discuss how the distribution of energy between&lt;br /&gt;
&amp;lt;nowiki&amp;gt; &amp;lt;/nowiki&amp;gt;different modes (translation and vibration) affect the efficiency of &lt;br /&gt;
the reaction, and how this is influenced by the position of the &lt;br /&gt;
transition state.&lt;/div&gt;</summary>
		<author><name>Tr318</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:T01574856&amp;diff=804241</id>
		<title>MRD:T01574856</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:T01574856&amp;diff=804241"/>
		<updated>2020-05-15T12:28:33Z</updated>

		<summary type="html">&lt;p&gt;Tr318: /* Question 1 */&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;= Molecular Reaction Dynamics Lab =&lt;br /&gt;
&lt;br /&gt;
= &amp;lt;br&amp;gt; Exercise 1: H + H&amp;lt;sub&amp;gt;2 &amp;lt;/sub&amp;gt;System =&lt;br /&gt;
&lt;br /&gt;
== Question 1 ==&lt;br /&gt;
&#039;&#039;&#039;On a potential energy surface diagram, how is the transition state mathematically defined? How can the transition state be identified, and how can it be distinguished from a local minimum of the potential energy surface?&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
The transition state is mathematically defined as the maximum on the minimum energy path which links the reactants and products together. The transition state can be identified on a potential energy surface diagram by looking at the gradient of the potential, at the point of the transition state, the gradient would be zero (dV&amp;lt;sub&amp;gt;(ri)&amp;lt;/sub&amp;gt;/d&amp;lt;sub&amp;gt;ri&amp;lt;/sub&amp;gt;=0). This point is distinguished from a local minimum of the potential energy surface by starting trajectories near the transition state and observing the atoms rolling towards the reactants or the products.&lt;br /&gt;
&lt;br /&gt;
== Question 2 ==&lt;br /&gt;
&#039;&#039;&#039;Report your best estimate of the transition state position (r&amp;lt;sub&amp;gt;ts&amp;lt;/sub&amp;gt;) and explain your reasoning illustrating it with a “Internuclear Distances vs Time” plot for a relevant trajectory.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
== Question 3 ==&lt;br /&gt;
&#039;&#039;&#039;Comment on how the &#039;&#039;mep&#039;&#039; and the trajectory you just calculated differ.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
== Question 4 ==&lt;br /&gt;
&#039;&#039;&#039;Complete the table above by adding the total  energy, whether the trajectory is reactive or unreactive, and provide a  plot of the trajectory and a small description for what happens along  the trajectory. What can you conclude from the table?&#039;&#039;&#039;&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
!p&amp;lt;sub&amp;gt;1&amp;lt;/sub&amp;gt;/ g.mol&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;.pm.fs&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;&lt;br /&gt;
!p&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;/ g.mol&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;.pm.fs&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;&lt;br /&gt;
!E&amp;lt;sub&amp;gt;tot&amp;lt;/sub&amp;gt;&lt;br /&gt;
!Reactive?&lt;br /&gt;
!Description of the dynamics&lt;br /&gt;
!Illustration of the trajectory&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-2.56&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-5.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-3.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-4.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-3.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-5.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-5.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-10.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-5.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-10.6&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|}&lt;br /&gt;
&lt;br /&gt;
== Question 5 ==&lt;br /&gt;
&#039;&#039;&#039;Given the results you have obtained, how will Transition State Theory predictions for reaction rate values compare with experimental values?&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
= Exercise 2: F-H-H System =&lt;br /&gt;
&lt;br /&gt;
== Question 1 ==&lt;br /&gt;
By inspecting the potential energy surfaces, classify the F + H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;&lt;br /&gt;
&amp;lt;nowiki&amp;gt; &amp;lt;/nowiki&amp;gt;and H + HF reactions according to their energetics (endothermic or &lt;br /&gt;
exothermic). How does this relate to the bond strength of the chemical &lt;br /&gt;
species involved?&lt;br /&gt;
&lt;br /&gt;
== Question 2 ==&lt;br /&gt;
Locate the approximate position of the transition state.&lt;br /&gt;
&lt;br /&gt;
== Question 3 ==&lt;br /&gt;
Report the activation energy for both reactions.&lt;br /&gt;
&lt;br /&gt;
== Question 4 ==&lt;br /&gt;
In light of the fact that energy is conserved,&lt;br /&gt;
&amp;lt;nowiki&amp;gt; &amp;lt;/nowiki&amp;gt;discuss the mechanism of release of the reaction energy. Explain how &lt;br /&gt;
this could be confirmed experimentally.&lt;br /&gt;
&lt;br /&gt;
== Question 5 ==&lt;br /&gt;
Discuss how the distribution of energy between&lt;br /&gt;
&amp;lt;nowiki&amp;gt; &amp;lt;/nowiki&amp;gt;different modes (translation and vibration) affect the efficiency of &lt;br /&gt;
the reaction, and how this is influenced by the position of the &lt;br /&gt;
transition state.&lt;/div&gt;</summary>
		<author><name>Tr318</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:T01574856&amp;diff=804237</id>
		<title>MRD:T01574856</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:T01574856&amp;diff=804237"/>
		<updated>2020-05-15T12:26:46Z</updated>

		<summary type="html">&lt;p&gt;Tr318: /* Question 4 */&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;= Molecular Reaction Dynamics Lab =&lt;br /&gt;
&lt;br /&gt;
= &amp;lt;br&amp;gt; Exercise 1: H + H&amp;lt;sub&amp;gt;2 &amp;lt;/sub&amp;gt;System =&lt;br /&gt;
&lt;br /&gt;
== Question 1 ==&lt;br /&gt;
&#039;&#039;&#039;On a potential energy surface diagram, how is the transition state mathematically defined? How can the transition state be identified, and how can it be distinguished from a local minimum of the potential energy surface?&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
The transition state is mathematically defined as the maximum on the minimum energy path which links the reactants and products together. The transition state can be identified on a potential energy surface diagram by looking at the gradient of the potential, at the point of the transition state, the gradient would be zero (dV(ri)/dri=0). This point is distinguished from a local minimum of the potential energy surface by starting trajectories near the transition state and observing the atoms rolling towards the reactants or the products.&lt;br /&gt;
&lt;br /&gt;
== Question 2 ==&lt;br /&gt;
&#039;&#039;&#039;Report your best estimate of the transition state position (r&amp;lt;sub&amp;gt;ts&amp;lt;/sub&amp;gt;) and explain your reasoning illustrating it with a “Internuclear Distances vs Time” plot for a relevant trajectory.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
== Question 3 ==&lt;br /&gt;
&#039;&#039;&#039;Comment on how the &#039;&#039;mep&#039;&#039; and the trajectory you just calculated differ.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
== Question 4 ==&lt;br /&gt;
&#039;&#039;&#039;Complete the table above by adding the total  energy, whether the trajectory is reactive or unreactive, and provide a  plot of the trajectory and a small description for what happens along  the trajectory. What can you conclude from the table?&#039;&#039;&#039;&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
!p&amp;lt;sub&amp;gt;1&amp;lt;/sub&amp;gt;/ g.mol&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;.pm.fs&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;&lt;br /&gt;
!p&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;/ g.mol&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;.pm.fs&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;&lt;br /&gt;
!E&amp;lt;sub&amp;gt;tot&amp;lt;/sub&amp;gt;&lt;br /&gt;
!Reactive?&lt;br /&gt;
!Description of the dynamics&lt;br /&gt;
!Illustration of the trajectory&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-2.56&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-5.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-3.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-4.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-3.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-5.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-5.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-10.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|-&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-5.1&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&amp;lt;nowiki&amp;gt;-10.6&amp;lt;/nowiki&amp;gt;&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|}&lt;br /&gt;
&lt;br /&gt;
== Question 5 ==&lt;br /&gt;
&#039;&#039;&#039;Given the results you have obtained, how will Transition State Theory predictions for reaction rate values compare with experimental values?&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
= Exercise 2: F-H-H System =&lt;br /&gt;
&lt;br /&gt;
== Question 1 ==&lt;br /&gt;
By inspecting the potential energy surfaces, classify the F + H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;&lt;br /&gt;
&amp;lt;nowiki&amp;gt; &amp;lt;/nowiki&amp;gt;and H + HF reactions according to their energetics (endothermic or &lt;br /&gt;
exothermic). How does this relate to the bond strength of the chemical &lt;br /&gt;
species involved?&lt;br /&gt;
&lt;br /&gt;
== Question 2 ==&lt;br /&gt;
Locate the approximate position of the transition state.&lt;br /&gt;
&lt;br /&gt;
== Question 3 ==&lt;br /&gt;
Report the activation energy for both reactions.&lt;br /&gt;
&lt;br /&gt;
== Question 4 ==&lt;br /&gt;
In light of the fact that energy is conserved,&lt;br /&gt;
&amp;lt;nowiki&amp;gt; &amp;lt;/nowiki&amp;gt;discuss the mechanism of release of the reaction energy. Explain how &lt;br /&gt;
this could be confirmed experimentally.&lt;br /&gt;
&lt;br /&gt;
== Question 5 ==&lt;br /&gt;
Discuss how the distribution of energy between&lt;br /&gt;
&amp;lt;nowiki&amp;gt; &amp;lt;/nowiki&amp;gt;different modes (translation and vibration) affect the efficiency of &lt;br /&gt;
the reaction, and how this is influenced by the position of the &lt;br /&gt;
transition state.&lt;/div&gt;</summary>
		<author><name>Tr318</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:T01574856&amp;diff=804233</id>
		<title>MRD:T01574856</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:T01574856&amp;diff=804233"/>
		<updated>2020-05-15T12:25:35Z</updated>

		<summary type="html">&lt;p&gt;Tr318: /* Complete the table above by adding the total  energy, whether the trajectory is reactive or unreactive, and provide a  plot of the trajectory and a small description for what happens along  the trajectory. What can you conclude from the table? */&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;= Molecular Reaction Dynamics Lab =&lt;br /&gt;
&lt;br /&gt;
= &amp;lt;br&amp;gt; Exercise 1: H + H&amp;lt;sub&amp;gt;2 &amp;lt;/sub&amp;gt;System =&lt;br /&gt;
&lt;br /&gt;
== Question 1 ==&lt;br /&gt;
&#039;&#039;&#039;On a potential energy surface diagram, how is the transition state mathematically defined? How can the transition state be identified, and how can it be distinguished from a local minimum of the potential energy surface?&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
The transition state is mathematically defined as the maximum on the minimum energy path which links the reactants and products together. The transition state can be identified on a potential energy surface diagram by looking at the gradient of the potential, at the point of the transition state, the gradient would be zero (dV(ri)/dri=0). This point is distinguished from a local minimum of the potential energy surface by starting trajectories near the transition state and observing the atoms rolling towards the reactants or the products.&lt;br /&gt;
&lt;br /&gt;
== Question 2 ==&lt;br /&gt;
&#039;&#039;&#039;Report your best estimate of the transition state position (r&amp;lt;sub&amp;gt;ts&amp;lt;/sub&amp;gt;) and explain your reasoning illustrating it with a “Internuclear Distances vs Time” plot for a relevant trajectory.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
== Question 3 ==&lt;br /&gt;
&#039;&#039;&#039;Comment on how the &#039;&#039;mep&#039;&#039; and the trajectory you just calculated differ.&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
== Question 4 ==&lt;br /&gt;
&#039;&#039;&#039;Complete the table above by adding the total  energy, whether the trajectory is reactive or unreactive, and provide a  plot of the trajectory and a small description for what happens along  the trajectory. What can you conclude from the table?&#039;&#039;&#039;&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
!p&amp;lt;sub&amp;gt;1&amp;lt;/sub&amp;gt;/ g.mol&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;.pm.fs&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;&lt;br /&gt;
!p&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;/ g.mol&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;.pm.fs&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;&lt;br /&gt;
!E&amp;lt;sub&amp;gt;tot&amp;lt;/sub&amp;gt;&lt;br /&gt;
!Reactive?&lt;br /&gt;
!Description of the dynamics&lt;br /&gt;
!Illustration of the trajectory&lt;br /&gt;
|-&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|-&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|-&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|-&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|-&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|}&lt;br /&gt;
&lt;br /&gt;
== Question 5 ==&lt;br /&gt;
&#039;&#039;&#039;Given the results you have obtained, how will Transition State Theory predictions for reaction rate values compare with experimental values?&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
= Exercise 2: F-H-H System =&lt;br /&gt;
&lt;br /&gt;
== Question 1 ==&lt;br /&gt;
By inspecting the potential energy surfaces, classify the F + H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;&lt;br /&gt;
&amp;lt;nowiki&amp;gt; &amp;lt;/nowiki&amp;gt;and H + HF reactions according to their energetics (endothermic or &lt;br /&gt;
exothermic). How does this relate to the bond strength of the chemical &lt;br /&gt;
species involved?&lt;br /&gt;
&lt;br /&gt;
== Question 2 ==&lt;br /&gt;
Locate the approximate position of the transition state.&lt;br /&gt;
&lt;br /&gt;
== Question 3 ==&lt;br /&gt;
Report the activation energy for both reactions.&lt;br /&gt;
&lt;br /&gt;
== Question 4 ==&lt;br /&gt;
In light of the fact that energy is conserved,&lt;br /&gt;
&amp;lt;nowiki&amp;gt; &amp;lt;/nowiki&amp;gt;discuss the mechanism of release of the reaction energy. Explain how &lt;br /&gt;
this could be confirmed experimentally.&lt;br /&gt;
&lt;br /&gt;
== Question 5 ==&lt;br /&gt;
Discuss how the distribution of energy between&lt;br /&gt;
&amp;lt;nowiki&amp;gt; &amp;lt;/nowiki&amp;gt;different modes (translation and vibration) affect the efficiency of &lt;br /&gt;
the reaction, and how this is influenced by the position of the &lt;br /&gt;
transition state.&lt;/div&gt;</summary>
		<author><name>Tr318</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:T01574856&amp;diff=804217</id>
		<title>MRD:T01574856</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:T01574856&amp;diff=804217"/>
		<updated>2020-05-15T12:21:09Z</updated>

		<summary type="html">&lt;p&gt;Tr318: /*  Exercise 1: H + H2 System */&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;= Molecular Reaction Dynamics Lab =&lt;br /&gt;
&lt;br /&gt;
= &amp;lt;br&amp;gt; Exercise 1: H + H&amp;lt;sub&amp;gt;2 &amp;lt;/sub&amp;gt;System =&lt;br /&gt;
&lt;br /&gt;
== On a potential energy surface diagram, how is the transition state mathematically defined? How can the transition state be identified, and how can it be distinguished from a local minimum of the potential energy surface? ==&lt;br /&gt;
The transition state is mathematically defined as the maximum on the minimum energy path which links the reactants and products together. The transition state can be identified on a potential energy surface diagram by looking at the gradient of the potential, at the point of the transition state, the gradient would be zero (dV(ri)/dri=0). This point is distinguished from a local minimum of the potential energy surface by starting trajectories near the transition state and observing the atoms rolling towards the reactants or the products.&lt;br /&gt;
&lt;br /&gt;
== Report your best estimate of the transition state position (&#039;&#039;&#039;r&amp;lt;sub&amp;gt;ts&amp;lt;/sub&amp;gt;&#039;&#039;&#039;) and explain your reasoning illustrating it with a “Internuclear Distances vs Time” plot for a relevant trajectory. ==&lt;br /&gt;
&lt;br /&gt;
== Comment on how the &#039;&#039;mep&#039;&#039; and the trajectory you just calculated differ. ==&lt;br /&gt;
&lt;br /&gt;
== Complete the table above by adding the total  energy, whether the trajectory is reactive or unreactive, and provide a  plot of the trajectory and a small description for what happens along  the trajectory. What can you conclude from the table? ==&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
!p&amp;lt;sub&amp;gt;1&amp;lt;/sub&amp;gt;/ g.mol&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;.pm.fs&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;&lt;br /&gt;
!p&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;/ g.mol&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;.pm.fs&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;&lt;br /&gt;
!E&amp;lt;sub&amp;gt;tot&amp;lt;/sub&amp;gt;&lt;br /&gt;
!Reactive?&lt;br /&gt;
!Description of the dynamics&lt;br /&gt;
!Illustration of the trajectory&lt;br /&gt;
|-&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|-&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|-&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|-&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|-&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|}&lt;/div&gt;</summary>
		<author><name>Tr318</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:T01574856&amp;diff=804212</id>
		<title>MRD:T01574856</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:T01574856&amp;diff=804212"/>
		<updated>2020-05-15T12:20:10Z</updated>

		<summary type="html">&lt;p&gt;Tr318: /*  Exercise 1: H + H2 System */&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;= Molecular Reaction Dynamics Lab =&lt;br /&gt;
&lt;br /&gt;
= &amp;lt;br&amp;gt; Exercise 1: H + H&amp;lt;sub&amp;gt;2 &amp;lt;/sub&amp;gt;System =&lt;br /&gt;
&lt;br /&gt;
== On a potential energy surface diagram, how is the transition state mathematically defined? How can the transition state be identified, and how can it be distinguished from a local minimum of the potential energy surface? ==&lt;br /&gt;
&lt;br /&gt;
== The transition state is mathematically defined as the maximum on the minimum energy path which links the reactants and products together. The transition state can be identified on a potential energy surface diagram by looking at the gradient of the potential, at the point of the transition state, the gradient would be zero (dV(ri)/dri=0). This point is distinguished from a local minimum of the potential energy surface by starting trajectories near the transition state and observing the atoms rolling towards the reactants or the products. ==&lt;br /&gt;
&lt;br /&gt;
== Report your best estimate of the transition state position (&#039;&#039;&#039;r&amp;lt;sub&amp;gt;ts&amp;lt;/sub&amp;gt;&#039;&#039;&#039;) and explain your reasoning illustrating it with a “Internuclear Distances vs Time” plot for a relevant trajectory. ==&lt;br /&gt;
&lt;br /&gt;
== Comment on how the &#039;&#039;mep&#039;&#039; and the trajectory you just calculated differ. ==&lt;br /&gt;
&lt;br /&gt;
== Complete the table above by adding the total  energy, whether the trajectory is reactive or unreactive, and provide a  plot of the trajectory and a small description for what happens along  the trajectory. What can you conclude from the table? ==&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
!p&amp;lt;sub&amp;gt;1&amp;lt;/sub&amp;gt;/ g.mol&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;.pm.fs&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;&lt;br /&gt;
!p&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;/ g.mol&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;.pm.fs&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;&lt;br /&gt;
!E&amp;lt;sub&amp;gt;tot&amp;lt;/sub&amp;gt;&lt;br /&gt;
!Reactive?&lt;br /&gt;
!Description of the dynamics&lt;br /&gt;
!Illustration of the trajectory&lt;br /&gt;
|-&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|-&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|-&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|-&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|-&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|}&lt;/div&gt;</summary>
		<author><name>Tr318</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:T01574856&amp;diff=804208</id>
		<title>MRD:T01574856</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:T01574856&amp;diff=804208"/>
		<updated>2020-05-15T12:19:13Z</updated>

		<summary type="html">&lt;p&gt;Tr318: /* Report your best estimate of the transition state position (rts) and explain your reasoning illustrating it with a “Internuclear Distances vs Time” plot for a relevant trajectory. */&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;= Molecular Reaction Dynamics Lab =&lt;br /&gt;
&lt;br /&gt;
== &amp;lt;br&amp;gt; Exercise 1: H + H&amp;lt;sub&amp;gt;2 &amp;lt;/sub&amp;gt;System ==&lt;br /&gt;
&lt;br /&gt;
=== On a potential energy surface diagram, how is the transition state mathematically defined? How can the transition state be identified, and how can it be distinguished from a local minimum of the potential energy surface? ===&lt;br /&gt;
The transition state is mathematically defined as the maximum on the minimum energy path which links the reactants and products together. The transition state can be identified on a potential energy surface diagram by looking at the gradient of the potential, at the point of the transition state, the gradient would be zero (dV(ri)/dri=0). This point is distinguished from a local minimum of the potential energy surface by starting trajectories near the transition state and observing the atoms rolling towards the reactants or the products. &lt;br /&gt;
&lt;br /&gt;
=== Report your best estimate of the transition state position (&#039;&#039;&#039;r&amp;lt;sub&amp;gt;ts&amp;lt;/sub&amp;gt;&#039;&#039;&#039;) and explain your reasoning illustrating it with a “Internuclear Distances vs Time” plot for a relevant trajectory. ===&lt;br /&gt;
&lt;br /&gt;
=== Comment on how the &#039;&#039;mep&#039;&#039; and the trajectory you just calculated differ. ===&lt;br /&gt;
&lt;br /&gt;
=== Complete the table above by adding the total  energy, whether the trajectory is reactive or unreactive, and provide a  plot of the trajectory and a small description for what happens along  the trajectory. What can you conclude from the table? ===&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
!p&amp;lt;sub&amp;gt;1&amp;lt;/sub&amp;gt;/ g.mol&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;.pm.fs&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;&lt;br /&gt;
!p&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;/ g.mol&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;.pm.fs&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;&lt;br /&gt;
!E&amp;lt;sub&amp;gt;tot&amp;lt;/sub&amp;gt;&lt;br /&gt;
!Reactive?&lt;br /&gt;
!Description of the dynamics&lt;br /&gt;
!Illustration of the trajectory&lt;br /&gt;
|-&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|-&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|-&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|-&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|-&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|}&lt;/div&gt;</summary>
		<author><name>Tr318</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:T01574856&amp;diff=804196</id>
		<title>MRD:T01574856</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:T01574856&amp;diff=804196"/>
		<updated>2020-05-15T12:14:20Z</updated>

		<summary type="html">&lt;p&gt;Tr318: /*  Exercise 1: H + H2 System */&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;= Molecular Reaction Dynamics Lab =&lt;br /&gt;
&lt;br /&gt;
== &amp;lt;br&amp;gt; Exercise 1: H + H&amp;lt;sub&amp;gt;2 &amp;lt;/sub&amp;gt;System ==&lt;br /&gt;
&lt;br /&gt;
=== On a potential energy surface diagram, how is the transition state mathematically defined? How can the transition state be identified, and how can it be distinguished from a local minimum of the potential energy surface? ===&lt;br /&gt;
The transition state is mathematically defined as the maximum on the minimum energy path which links the reactants and products together. The transition state can be identified on a potential energy surface diagram by looking at the gradient of the potential, at the point of the transition state, the gradient would be zero (dV(ri)/dri=0). This point is distinguished from a local minimum of the potential energy surface by starting trajectories near the transition state and observing the atoms rolling towards the reactants or the products. &lt;br /&gt;
&lt;br /&gt;
=== Report your best estimate of the transition state position (&#039;&#039;&#039;r&amp;lt;sub&amp;gt;ts&amp;lt;/sub&amp;gt;&#039;&#039;&#039;) and explain your reasoning illustrating it with a “Internuclear Distances vs Time” plot for a relevant trajectory. ===&lt;br /&gt;
&lt;br /&gt;
=== Comment on how the &#039;&#039;mep&#039;&#039; and the trajectory you just calculated differ. ===&lt;/div&gt;</summary>
		<author><name>Tr318</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:T01574856&amp;diff=802589</id>
		<title>MRD:T01574856</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:T01574856&amp;diff=802589"/>
		<updated>2020-05-14T06:04:13Z</updated>

		<summary type="html">&lt;p&gt;Tr318: /* On a potential energy surface diagram, how is the transition state mathematically defined? How can the transition state be identified, and how can it be distinguished from a local minimum of the potential energy surface? */&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;= Molecular Reaction Dynamics Lab =&lt;br /&gt;
&lt;br /&gt;
== &amp;lt;br&amp;gt; Exercise 1: H + H&amp;lt;sub&amp;gt;2 &amp;lt;/sub&amp;gt;System ==&lt;br /&gt;
&lt;br /&gt;
=== On a potential energy surface diagram, how is the transition state mathematically defined? How can the transition state be identified, and how can it be distinguished from a local minimum of the potential energy surface? ===&lt;br /&gt;
The transition state is mathematically defined as the maximum on the minimum energy path which links the reactants and products together. &lt;br /&gt;
&lt;br /&gt;
=== Report your best estimate of the transition state position (&#039;&#039;&#039;r&amp;lt;sub&amp;gt;ts&amp;lt;/sub&amp;gt;&#039;&#039;&#039;) and explain your reasoning illustrating it with a “Internuclear Distances vs Time” plot for a relevant trajectory. ===&lt;br /&gt;
&lt;br /&gt;
=== Comment on how the &#039;&#039;mep&#039;&#039; and the trajectory you just calculated differ. ===&lt;/div&gt;</summary>
		<author><name>Tr318</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:T01574856&amp;diff=802588</id>
		<title>MRD:T01574856</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:T01574856&amp;diff=802588"/>
		<updated>2020-05-14T03:24:44Z</updated>

		<summary type="html">&lt;p&gt;Tr318: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;= Molecular Reaction Dynamics Lab =&lt;br /&gt;
&lt;br /&gt;
== &amp;lt;br&amp;gt; Exercise 1: H + H&amp;lt;sub&amp;gt;2 &amp;lt;/sub&amp;gt;System ==&lt;br /&gt;
&lt;br /&gt;
=== On a potential energy surface diagram, how is the transition state mathematically defined? How can the transition state be identified, and how can it be distinguished from a local minimum of the potential energy surface? ===&lt;br /&gt;
The transition state is mathematically defined&lt;br /&gt;
&lt;br /&gt;
=== Report your best estimate of the transition state position (&#039;&#039;&#039;r&amp;lt;sub&amp;gt;ts&amp;lt;/sub&amp;gt;&#039;&#039;&#039;) and explain your reasoning illustrating it with a “Internuclear Distances vs Time” plot for a relevant trajectory. ===&lt;br /&gt;
&lt;br /&gt;
=== Comment on how the &#039;&#039;mep&#039;&#039; and the trajectory you just calculated differ. ===&lt;/div&gt;</summary>
		<author><name>Tr318</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:T01574856&amp;diff=802587</id>
		<title>MRD:T01574856</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:T01574856&amp;diff=802587"/>
		<updated>2020-05-14T03:21:45Z</updated>

		<summary type="html">&lt;p&gt;Tr318: /* Molecular Reaction Dynamics Lab */&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;= &#039;&#039;&#039;Molecular Reaction Dynamics Lab&#039;&#039;&#039; =&lt;br /&gt;
&lt;br /&gt;
== &amp;lt;br&amp;gt; &#039;&#039;&#039;Exercise 1&#039;&#039;&#039; ==&lt;br /&gt;
&lt;br /&gt;
=== On a potential energy surface diagram, how is the transition state mathematically defined? How can the transition state be identified, and how can it be distinguished from a local minimum of the potential energy surface? ===&lt;br /&gt;
The transition state is mathematically defined&lt;br /&gt;
&lt;br /&gt;
=== Report your best estimate of the transition state position (&#039;&#039;&#039;r&amp;lt;sub&amp;gt;ts&amp;lt;/sub&amp;gt;&#039;&#039;&#039;) and explain your reasoning illustrating it with a “Internuclear Distances vs Time” plot for a relevant trajectory. ===&lt;br /&gt;
&lt;br /&gt;
=== Comment on how the &#039;&#039;mep&#039;&#039; and the trajectory you just calculated differ. ===&lt;/div&gt;</summary>
		<author><name>Tr318</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:T01574856&amp;diff=802542</id>
		<title>MRD:T01574856</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:T01574856&amp;diff=802542"/>
		<updated>2020-05-13T21:21:29Z</updated>

		<summary type="html">&lt;p&gt;Tr318: /* Molecular Reaction Dynamics Lab */&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;== &#039;&#039;&#039;Molecular Reaction Dynamics Lab&#039;&#039;&#039; ==&lt;br /&gt;
&lt;br /&gt;
=== &amp;lt;br&amp;gt; &#039;&#039;&#039;Exercise 1&#039;&#039;&#039; ===&lt;br /&gt;
&lt;br /&gt;
==== On a potential energy surface diagram, how is the transition state mathematically defined? How can the transition state be identified, and how can it be distinguished from a local minimum of the potential energy surface? ====&lt;br /&gt;
The transition state is mathematically defined&lt;br /&gt;
&lt;br /&gt;
==== Report your best estimate of the transition state position (&#039;&#039;&#039;r&amp;lt;sub&amp;gt;ts&amp;lt;/sub&amp;gt;&#039;&#039;&#039;) and explain your reasoning illustrating it with a “Internuclear Distances vs Time” plot for a relevant trajectory. ====&lt;br /&gt;
&lt;br /&gt;
==== Comment on how the &#039;&#039;mep&#039;&#039; and the trajectory you just calculated differ. ====&lt;/div&gt;</summary>
		<author><name>Tr318</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:T01574856&amp;diff=802350</id>
		<title>MRD:T01574856</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:T01574856&amp;diff=802350"/>
		<updated>2020-05-13T15:48:41Z</updated>

		<summary type="html">&lt;p&gt;Tr318: Created page with &amp;quot; == &amp;#039;&amp;#039;&amp;#039;Molecular Reaction Dynamics Lab&amp;#039;&amp;#039;&amp;#039; ==   &amp;#039;&amp;#039;&amp;#039;Exercise 1&amp;#039;&amp;#039;&amp;#039; On a potential energy surface diagram, how is the transition state mathematically defined? How can the transiti...&amp;quot;&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;br /&gt;
== &#039;&#039;&#039;Molecular Reaction Dynamics Lab&#039;&#039;&#039; ==&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&#039;&#039;&#039;Exercise 1&#039;&#039;&#039;&lt;br /&gt;
On a potential energy surface diagram, how is the transition state mathematically defined? How can the transition state be identified, and how can it be distinguished from a local minimum of the potential energy surface?&lt;br /&gt;
&lt;br /&gt;
The transition state is mathematically defined&lt;/div&gt;</summary>
		<author><name>Tr318</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=Rep:Mod:01574856&amp;diff=742528</id>
		<title>Rep:Mod:01574856</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=Rep:Mod:01574856&amp;diff=742528"/>
		<updated>2019-02-22T15:59:14Z</updated>

		<summary type="html">&lt;p&gt;Tr318: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;== NH&amp;lt;sub&amp;gt;3&amp;lt;/sub&amp;gt; Optimisation     ==&lt;br /&gt;
What is the calculation method? RB3LYP&lt;br /&gt;
&lt;br /&gt;
What is the basis set? 6-31G(d,p)&lt;br /&gt;
&lt;br /&gt;
What is the final energy E(RB3LYP) in atomic units (au)? -56.55776873&lt;br /&gt;
&lt;br /&gt;
What is the RMS gradient? 0.00000485&lt;br /&gt;
&lt;br /&gt;
What is the point group of your molecule? C3V&lt;br /&gt;
&lt;br /&gt;
optimised N-H bond distance and the optimised H-N-H bond angle? 1.02 &amp;amp; 106&lt;br /&gt;
&lt;br /&gt;
=== Item Table ===&lt;br /&gt;
&amp;lt;pre&amp;gt;&lt;br /&gt;
         Item               Value     Threshold  Converged?&lt;br /&gt;
 Maximum Force            0.000004     0.000450     YES&lt;br /&gt;
 RMS     Force            0.000004     0.000300     YES&lt;br /&gt;
 Maximum Displacement     0.000072     0.001800     YES&lt;br /&gt;
 RMS     Displacement     0.000035     0.001200     YES&lt;br /&gt;
 Predicted change in Energy=-5.986295D-10&lt;br /&gt;
&amp;lt;/pre&amp;gt;&lt;br /&gt;
&lt;br /&gt;
=== Jmol&amp;lt;br&amp;gt;  ===&lt;br /&gt;
&lt;br /&gt;
&amp;lt;jmol&amp;gt;&amp;lt;jmolApplet&amp;gt;&lt;br /&gt;
  &amp;lt;title&amp;gt;NH3_Molecule_01574856&amp;lt;/title&amp;gt;&lt;br /&gt;
  &amp;lt;color&amp;gt;black&amp;lt;/color&amp;gt;&lt;br /&gt;
  &amp;lt;size&amp;gt;200&amp;lt;/size&amp;gt;&lt;br /&gt;
  &amp;lt;uploadedFileContents&amp;gt;TAMIM_RAHMAN_NH3_OPTIMISATION_POP.log&amp;lt;/uploadedFileContents&amp;gt;&lt;br /&gt;
&amp;lt;/jmolApplet&amp;gt;&amp;lt;/jmol&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Link to completed NH&amp;lt;sub&amp;gt;3&amp;lt;/sub&amp;gt; optimisation https://wiki.ch.ic.ac.uk/wiki/images/f/fe/TAMIM_RAHMAN_NH3_OPTIMISATION_POP.log&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations ===&lt;br /&gt;
[[File:Display_Vibrations.PNG|centre]]&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations Table ===&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
!Wavenumber (cm&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;)&lt;br /&gt;
|1090&lt;br /&gt;
|1694&lt;br /&gt;
|1694&lt;br /&gt;
|3461&lt;br /&gt;
|3590&lt;br /&gt;
|3590&lt;br /&gt;
|-&lt;br /&gt;
!Symmetry&lt;br /&gt;
|A1&lt;br /&gt;
|E&lt;br /&gt;
|E&lt;br /&gt;
|A1&lt;br /&gt;
|E&lt;br /&gt;
|E&lt;br /&gt;
|-&lt;br /&gt;
!Intensity (a.u.)&lt;br /&gt;
|145&lt;br /&gt;
|14&lt;br /&gt;
|14&lt;br /&gt;
|1&lt;br /&gt;
|0&lt;br /&gt;
|0&lt;br /&gt;
|-&lt;br /&gt;
!Images&lt;br /&gt;
|[[File:Tamim Vib 1.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim Vib 2.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim Vib 3.PNG|centre|thumb|212x212px]]&lt;br /&gt;
|[[File:Tamim Vib 4.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim Vib 5.PNG|centre|thumb|208x208px]]&lt;br /&gt;
|[[File:Tamim Vib 6.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|}&lt;br /&gt;
* How many modes do you expect from the 3N-6 rule? 6&lt;br /&gt;
* Which modes are degenerate (ie have the same energy)? 2&amp;amp;3 and 5&amp;amp;6&lt;br /&gt;
* Which modes are &amp;quot;bending&amp;quot; vibrations and which are &amp;quot;bond stretch&amp;quot; vibrations? 1,2 and 3 are bending vibrations while 4,5 and 6 are bond stretch vibrations. &lt;br /&gt;
* Which mode is highly symmetric? 4&lt;br /&gt;
* One mode is known as the &amp;quot;umbrella&amp;quot; mode, which one is this? 11&lt;br /&gt;
* How many bands would you expect to see in an experimental spectrum of gaseous ammonia? 3&lt;br /&gt;
&lt;br /&gt;
=== Charge Distribution ===&lt;br /&gt;
[[File:Tamim Charge Distribution.PNG|thumb|Charge Distribution of NH&amp;lt;sub&amp;gt;3&amp;lt;/sub&amp;gt;|centre]]&lt;br /&gt;
&lt;br /&gt;
The charge on nitrogen should be slightly negative whereas the hydrogen atoms will have a slightly positive charge. This is due to the difference in electronegativity, nitrogen is more electronegative than hydrogen and therefore has a higher electron density to it leading to its slightly negative charge.&lt;br /&gt;
&lt;br /&gt;
== N&amp;lt;sub&amp;gt;2 &amp;lt;/sub&amp;gt;Optimisation ==&lt;br /&gt;
What is the calculation method? RB3LYP&lt;br /&gt;
&lt;br /&gt;
What is the basis set? 6-31G(d,p)&lt;br /&gt;
&lt;br /&gt;
What is the final energy E(RB3LYP) in atomic units (au)? -109.52412868&lt;br /&gt;
&lt;br /&gt;
What is the RMS gradient? 0.00000060&lt;br /&gt;
&lt;br /&gt;
What is the point group of your molecule? D*H&lt;br /&gt;
&lt;br /&gt;
Optimised N-N bond distance? 1.11&lt;br /&gt;
&lt;br /&gt;
=== Item Table ===&lt;br /&gt;
 &lt;br /&gt;
&amp;lt;pre&amp;gt;&lt;br /&gt;
         Item              Value      Threshold  Converged?&lt;br /&gt;
 Maximum Force            0.000001     0.000450     YES&lt;br /&gt;
 RMS     Force            0.000001     0.000300     YES&lt;br /&gt;
 Maximum Displacement     0.000000     0.001800     YES&lt;br /&gt;
 RMS     Displacement     0.000000     0.001200     YES&lt;br /&gt;
 Predicted change in Energy=-3.400972D-13&lt;br /&gt;
&amp;lt;/pre&amp;gt;&lt;br /&gt;
&lt;br /&gt;
=== Jmol ===&lt;br /&gt;
&lt;br /&gt;
&amp;lt;jmol&amp;gt;&amp;lt;jmolApplet&amp;gt;&lt;br /&gt;
  &amp;lt;title&amp;gt;N2_molecule&amp;lt;/title&amp;gt;&lt;br /&gt;
  &amp;lt;color&amp;gt;black&amp;lt;/color&amp;gt;&lt;br /&gt;
  &amp;lt;size&amp;gt;200&amp;lt;/size&amp;gt;&lt;br /&gt;
  &amp;lt;uploadedFileContents&amp;gt;TAMIM_N2_1.LOG&amp;lt;/uploadedFileContents&amp;gt;&lt;br /&gt;
&amp;lt;/jmolApplet&amp;gt;&amp;lt;/jmol&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Link to completed N&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt; optimisation: https://wiki.ch.ic.ac.uk/wiki/images/c/c7/TAMIM_N2_1.LOG&lt;br /&gt;
&lt;br /&gt;
=== DIsplay Vibrations ===&lt;br /&gt;
[[File:Tamim N2 Disp.PNG|thumb|centre|464x464px]]&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations Table ===&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
!Wavenumber (cm&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;)&lt;br /&gt;
|2457           &lt;br /&gt;
|-&lt;br /&gt;
!Symmetry&lt;br /&gt;
|SGG&lt;br /&gt;
|-&lt;br /&gt;
!Intensity (a.u.)&lt;br /&gt;
|0&lt;br /&gt;
|-&lt;br /&gt;
!Images&lt;br /&gt;
|[[File:Tamim N2 vib.PNG|centre|thumb|250x250px]]&lt;br /&gt;
|}&lt;br /&gt;
* How many modes do you expect from the 3N-6 rule? 0&lt;br /&gt;
* Which modes are &amp;quot;bending&amp;quot; vibrations and which are &amp;quot;bond stretch&amp;quot; vibrations? Only 1 bond stretching vibration &lt;br /&gt;
* Which mode is highly symmetric? 1&lt;br /&gt;
&lt;br /&gt;
=== Charge Distribution ===&lt;br /&gt;
[[File:Tamim n2 charge.PNG|centre|thumb|Charge Distribution for N&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;]]&lt;br /&gt;
The charges on both Nitrogen atoms are zero as they have the same electronegativity which means there is no dipole in the diatomic moleule.&lt;br /&gt;
&lt;br /&gt;
== H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt; Optimisation ==&lt;br /&gt;
What is the calculation method? RB3LYP&lt;br /&gt;
&lt;br /&gt;
What is the basis set? 6-31G(d,p)&lt;br /&gt;
&lt;br /&gt;
What is the final energy E(RB3LYP) in atomic units (au)? -1.17853936&lt;br /&gt;
&lt;br /&gt;
What is the RMS gradient? 0.00000017&lt;br /&gt;
&lt;br /&gt;
What is the point group of your molecule? D*H&lt;br /&gt;
&lt;br /&gt;
Optimised H-H bond distance? 0.74&lt;br /&gt;
&lt;br /&gt;
=== Item Table ===&lt;br /&gt;
&lt;br /&gt;
&amp;lt;pre&amp;gt;&lt;br /&gt;
         Item               Value     Threshold  Converged?&lt;br /&gt;
 Maximum Force            0.000000     0.000450     YES&lt;br /&gt;
 RMS     Force            0.000000     0.000300     YES&lt;br /&gt;
 Maximum Displacement     0.000000     0.001800     YES&lt;br /&gt;
 RMS     Displacement     0.000001     0.001200     YES&lt;br /&gt;
 Predicted change in Energy=-1.164080D-13&amp;lt;/pre&amp;gt;&lt;br /&gt;
&lt;br /&gt;
=== Jmol ===&lt;br /&gt;
&lt;br /&gt;
&amp;lt;jmol&amp;gt;&amp;lt;jmolApplet&amp;gt;&lt;br /&gt;
  &amp;lt;title&amp;gt;h2_molecule&amp;lt;/title&amp;gt;&lt;br /&gt;
  &amp;lt;color&amp;gt;black&amp;lt;/color&amp;gt;&lt;br /&gt;
  &amp;lt;size&amp;gt;200&amp;lt;/size&amp;gt;&lt;br /&gt;
  &amp;lt;uploadedFileContents&amp;gt;TAMIM_H2_1.LOG&amp;lt;/uploadedFileContents&amp;gt;&lt;br /&gt;
&amp;lt;/jmolApplet&amp;gt;&amp;lt;/jmol&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Link to completed H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt; optimisation: https://wiki.ch.ic.ac.uk/wiki/images/d/d4/TAMIM_H2_1.LOG&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations ===&lt;br /&gt;
[[File:Tamim h2 disp.PNG|thumb|centre|463x463px]]&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations Table ===&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
!Wavenumber (cm-1)&lt;br /&gt;
|4466&lt;br /&gt;
|-&lt;br /&gt;
!Symmetry&lt;br /&gt;
|SGG&lt;br /&gt;
|-&lt;br /&gt;
!Intensity (a.u.)&lt;br /&gt;
|0&lt;br /&gt;
|-&lt;br /&gt;
!Images&lt;br /&gt;
|[[File:Tamim h2 vib.PNG|centre|thumb]]&lt;br /&gt;
|}&lt;br /&gt;
* How many modes do you expect from the 3N-6 rule? 0&lt;br /&gt;
* Which modes are &amp;quot;bending&amp;quot; vibrations and which are &amp;quot;bond stretch&amp;quot; vibrations? Only 1 bond stretching vibration &lt;br /&gt;
* Which mode is highly symmetric? 1&lt;br /&gt;
&lt;br /&gt;
=== Charge Distribution ===&lt;br /&gt;
[[File:Tamim h2 charge.PNG|centre|thumb|Charge distribution for H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;]]&lt;br /&gt;
The charges on both Hydrogen atoms are zero as they have the same electronegativity which means there is no dipole in the diatomic moleule.&lt;br /&gt;
&lt;br /&gt;
== Mono-metallic Transition Metal Complex ==&lt;br /&gt;
The transition metal complex chosen was (dinitrogen)-(2,6-bis(1-(2,6-diisopropylphenylimino)propyl)pyridine)-iron with the reference code &#039;&#039;&#039;BARTOF&#039;&#039;&#039;.&lt;br /&gt;
[[File:Tamim TM.PNG|centre|thumb]]&lt;br /&gt;
The bond length of N&amp;lt;sub&amp;gt;2 &amp;lt;/sub&amp;gt;in the molecule above is slightly higher than the bond length of N&amp;lt;sub&amp;gt;2 &amp;lt;/sub&amp;gt;that was calculated before (1.112 compared ot 1.1055). This is due to the lone pair of one nitrogen being donated to the central Iron atom which lowers the electron density on the nitrogen atom; this leads to less overlap of orbitals leading to a higher bond length.  &lt;br /&gt;
&lt;br /&gt;
Link to journal: https://pubs.acs.org/doi/10.1021/ic202750n&lt;br /&gt;
&lt;br /&gt;
== Haber-Bosch Process ==&lt;br /&gt;
* E(NH&amp;lt;sub&amp;gt;3&amp;lt;/sub&amp;gt;) = -56.55776873 &lt;br /&gt;
* 2*E(NH&amp;lt;sub&amp;gt;3&amp;lt;/sub&amp;gt;) = -113.11553746 &lt;br /&gt;
* E(N&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;) = -109.52412868 &lt;br /&gt;
* E(H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;) = -1.17853936 &lt;br /&gt;
* 3*E(H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;) = -3.53561808 &lt;br /&gt;
* ΔE=2*E(NH&amp;lt;sub&amp;gt;3&amp;lt;/sub&amp;gt;)-[E(N&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;)+3*E(H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;)] = -0.05579076&lt;br /&gt;
&lt;br /&gt;
The product ammonia is more stable than the gaseous reactants as it has a lower energy than the reactants. This means it is more stable as the forward reaction is exothermic. &lt;br /&gt;
&lt;br /&gt;
== Own Molecule - SH&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt; ==&lt;br /&gt;
What is the calculation method? RB3LYP&lt;br /&gt;
&lt;br /&gt;
What is the basis set? 6-31G(d,p)&lt;br /&gt;
&lt;br /&gt;
What is the final energy E(RB3LYP) in atomic units (au)? -399.39162414&lt;br /&gt;
&lt;br /&gt;
What is the RMS gradient? 0.00012068&lt;br /&gt;
&lt;br /&gt;
What is the point group of your molecule? C2V&lt;br /&gt;
&lt;br /&gt;
Bond angle of H-S-H? 92.681&lt;br /&gt;
&lt;br /&gt;
=== Item Table ===&lt;br /&gt;
&amp;lt;pre&amp;gt;&lt;br /&gt;
         Item               Value     Threshold  Converged?&amp;lt;br&amp;gt;&lt;br /&gt;
 Maximum Force            0.000175     0.000450     YES&amp;lt;br&amp;gt;&lt;br /&gt;
 RMS     Force            0.000145     0.000300     YES&amp;lt;br&amp;gt;&lt;br /&gt;
 Maximum Displacement     0.000386     0.001800     YES&amp;lt;br&amp;gt;&lt;br /&gt;
 RMS     Displacement     0.000386     0.001200     YES&amp;lt;/pre&amp;gt;&lt;br /&gt;
&lt;br /&gt;
=== Jmol ===&lt;br /&gt;
&lt;br /&gt;
&amp;lt;jmol&amp;gt;&amp;lt;jmolApplet&amp;gt;&lt;br /&gt;
  &amp;lt;title&amp;gt;sh2_molecule&amp;lt;/title&amp;gt;&lt;br /&gt;
  &amp;lt;color&amp;gt;black&amp;lt;/color&amp;gt;&lt;br /&gt;
  &amp;lt;size&amp;gt;200&amp;lt;/size&amp;gt;&lt;br /&gt;
  &amp;lt;uploadedFileContents&amp;gt;TAMIM_SH2.LOG&amp;lt;/uploadedFileContents&amp;gt;&lt;br /&gt;
&amp;lt;/jmolApplet&amp;gt;&amp;lt;/jmol&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Link to completed SH&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt; optimisation: https://wiki.ch.ic.ac.uk/wiki/images/f/f8/TAMIM_SH2.LOG&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations ===&lt;br /&gt;
[[File:Tamim disp.PNG|centre|thumb]]&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations Table ===&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
!Wavenumber (cm&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;)&lt;br /&gt;
|1224&lt;br /&gt;
|2692&lt;br /&gt;
|2712&lt;br /&gt;
|-&lt;br /&gt;
!Symmetry&lt;br /&gt;
|A1&lt;br /&gt;
|A1&lt;br /&gt;
|B2&lt;br /&gt;
|-&lt;br /&gt;
!Intensity&lt;br /&gt;
|5&lt;br /&gt;
|7&lt;br /&gt;
|9&lt;br /&gt;
|-&lt;br /&gt;
!Images&lt;br /&gt;
|[[File:Tamim vib1.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim vib2.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim vib3.PNG|centre|thumb|217x217px]]&lt;br /&gt;
|}&lt;br /&gt;
* How many modes do you expect from the 3N-6 rule? 3&lt;br /&gt;
* Which modes are &amp;quot;bending&amp;quot; vibrations and which are &amp;quot;bond stretch&amp;quot; vibrations? 1 is a bending vibration while 2 and 3 are bond stretch vibrations.  &lt;br /&gt;
* Which mode is highly symmetric? 2&lt;br /&gt;
&lt;br /&gt;
=== Charge Distributions ===&lt;br /&gt;
[[File:Tamim chargesh2.PNG|centre|thumb|Charge distribution for SH&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;]]&lt;br /&gt;
The charge on Sulfur is slightly negative whereas the hydrogen atoms have a slightly positive charge. This is due to the difference in electronegativity, sulfur is more electronegative than hydrogen and therefore has a higher electron density to it leading to its slightly negative charge.&lt;br /&gt;
&lt;br /&gt;
=== Molecular Orbitals ===&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
|[[File:Tamim mo1.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim mo2.PNG|centre|thumb|201x201px]]&lt;br /&gt;
|[[File:Tamim mo3.PNG|centre|thumb|210x210px]]&lt;br /&gt;
|[[File:Tamim mo4.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim mo5.PNG|centre|thumb|205x205px]]&lt;br /&gt;
|-&lt;br /&gt;
|Bonding molecular orbital between 3s electrons from sulfur and 1s electrons from the hydrogen. It is also an occupied orbital and has an energy of -0.74654. &lt;br /&gt;
|Non-bonding orbital consisting of the 2p orbital from the sulfur. Occupied orbital with energy of -5.91268.  &lt;br /&gt;
|Anti-bonding molecular orbital created between the 3p orbitals from sulfur and1 s orbitals from hydrogen. This is an unoccupied orbital with an energy of 0.02126. &lt;br /&gt;
|Bonding molecular orbital whihc is created due to the 3p orbital of sulfur and 1s orbital from the hydrogens. This is an occupied orbital with an energy of -0.44963. &lt;br /&gt;
|SP mixnig between the s and p orbitals of sulfur and also consists of molecular orbital being created between the p orbital of sulfur and s orbitals of hydrogen. This is an occupied orbital with an energy of -0.36725.&lt;br /&gt;
|}&lt;/div&gt;</summary>
		<author><name>Tr318</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=Rep:Mod:01574856&amp;diff=742527</id>
		<title>Rep:Mod:01574856</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=Rep:Mod:01574856&amp;diff=742527"/>
		<updated>2019-02-22T15:57:04Z</updated>

		<summary type="html">&lt;p&gt;Tr318: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;== NH&amp;lt;sub&amp;gt;3&amp;lt;/sub&amp;gt; Optimisation     ==&lt;br /&gt;
What is the calculation method? RB3LYP&lt;br /&gt;
&lt;br /&gt;
What is the basis set? 6-31G(d,p)&lt;br /&gt;
&lt;br /&gt;
What is the final energy E(RB3LYP) in atomic units (au)? -56.55776873&lt;br /&gt;
&lt;br /&gt;
What is the RMS gradient? 0.00000485&lt;br /&gt;
&lt;br /&gt;
What is the point group of your molecule? C3V&lt;br /&gt;
&lt;br /&gt;
optimised N-H bond distance and the optimised H-N-H bond angle? 1.02 &amp;amp; 106&lt;br /&gt;
&lt;br /&gt;
=== Item Table ===&lt;br /&gt;
&amp;lt;pre&amp;gt;&lt;br /&gt;
         Item               Value     Threshold  Converged?&lt;br /&gt;
 Maximum Force            0.000004     0.000450     YES&lt;br /&gt;
 RMS     Force            0.000004     0.000300     YES&lt;br /&gt;
 Maximum Displacement     0.000072     0.001800     YES&lt;br /&gt;
 RMS     Displacement     0.000035     0.001200     YES&lt;br /&gt;
 Predicted change in Energy=-5.986295D-10&lt;br /&gt;
&amp;lt;/pre&amp;gt;&lt;br /&gt;
&lt;br /&gt;
=== Jmol&amp;lt;br&amp;gt;  ===&lt;br /&gt;
Link to completed NH&amp;lt;sub&amp;gt;3&amp;lt;/sub&amp;gt; optimisation https://wiki.ch.ic.ac.uk/wiki/images/f/fe/TAMIM_RAHMAN_NH3_OPTIMISATION_POP.log&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations ===&lt;br /&gt;
[[File:Display_Vibrations.PNG|centre]]&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations Table ===&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
!Wavenumber (cm&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;)&lt;br /&gt;
|1090&lt;br /&gt;
|1694&lt;br /&gt;
|1694&lt;br /&gt;
|3461&lt;br /&gt;
|3590&lt;br /&gt;
|3590&lt;br /&gt;
|-&lt;br /&gt;
!Symmetry&lt;br /&gt;
|A1&lt;br /&gt;
|E&lt;br /&gt;
|E&lt;br /&gt;
|A1&lt;br /&gt;
|E&lt;br /&gt;
|E&lt;br /&gt;
|-&lt;br /&gt;
!Intensity (a.u.)&lt;br /&gt;
|145&lt;br /&gt;
|14&lt;br /&gt;
|14&lt;br /&gt;
|1&lt;br /&gt;
|0&lt;br /&gt;
|0&lt;br /&gt;
|-&lt;br /&gt;
!Images&lt;br /&gt;
|[[File:Tamim Vib 1.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim Vib 2.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim Vib 3.PNG|centre|thumb|212x212px]]&lt;br /&gt;
|[[File:Tamim Vib 4.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim Vib 5.PNG|centre|thumb|208x208px]]&lt;br /&gt;
|[[File:Tamim Vib 6.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|}&lt;br /&gt;
* How many modes do you expect from the 3N-6 rule? 6&lt;br /&gt;
* Which modes are degenerate (ie have the same energy)? 2&amp;amp;3 and 5&amp;amp;6&lt;br /&gt;
* Which modes are &amp;quot;bending&amp;quot; vibrations and which are &amp;quot;bond stretch&amp;quot; vibrations? 1,2 and 3 are bending vibrations while 4,5 and 6 are bond stretch vibrations. &lt;br /&gt;
* Which mode is highly symmetric? 4&lt;br /&gt;
* One mode is known as the &amp;quot;umbrella&amp;quot; mode, which one is this? 11&lt;br /&gt;
* How many bands would you expect to see in an experimental spectrum of gaseous ammonia? 3&lt;br /&gt;
&lt;br /&gt;
=== Charge Distribution ===&lt;br /&gt;
[[File:Tamim Charge Distribution.PNG|thumb|Charge Distribution of NH&amp;lt;sub&amp;gt;3&amp;lt;/sub&amp;gt;|centre]]&lt;br /&gt;
&lt;br /&gt;
The charge on nitrogen should be slightly negative whereas the hydrogen atoms will have a slightly positive charge. This is due to the difference in electronegativity, nitrogen is more electronegative than hydrogen and therefore has a higher electron density to it leading to its slightly negative charge.&lt;br /&gt;
&lt;br /&gt;
== N&amp;lt;sub&amp;gt;2 &amp;lt;/sub&amp;gt;Optimisation ==&lt;br /&gt;
What is the calculation method? RB3LYP&lt;br /&gt;
&lt;br /&gt;
What is the basis set? 6-31G(d,p)&lt;br /&gt;
&lt;br /&gt;
What is the final energy E(RB3LYP) in atomic units (au)? -109.52412868&lt;br /&gt;
&lt;br /&gt;
What is the RMS gradient? 0.00000060&lt;br /&gt;
&lt;br /&gt;
What is the point group of your molecule? D*H&lt;br /&gt;
&lt;br /&gt;
Optimised N-N bond distance? 1.11&lt;br /&gt;
&lt;br /&gt;
=== Item Table ===&lt;br /&gt;
 &lt;br /&gt;
&amp;lt;pre&amp;gt;&lt;br /&gt;
         Item              Value      Threshold  Converged?&lt;br /&gt;
 Maximum Force            0.000001     0.000450     YES&lt;br /&gt;
 RMS     Force            0.000001     0.000300     YES&lt;br /&gt;
 Maximum Displacement     0.000000     0.001800     YES&lt;br /&gt;
 RMS     Displacement     0.000000     0.001200     YES&lt;br /&gt;
 Predicted change in Energy=-3.400972D-13&lt;br /&gt;
&amp;lt;/pre&amp;gt;&lt;br /&gt;
&lt;br /&gt;
=== Jmol ===&lt;br /&gt;
&lt;br /&gt;
Link to completed N&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt; optimisation: https://wiki.ch.ic.ac.uk/wiki/images/c/c7/TAMIM_N2_1.LOG&lt;br /&gt;
&lt;br /&gt;
=== DIsplay Vibrations ===&lt;br /&gt;
[[File:Tamim N2 Disp.PNG|thumb|centre|464x464px]]&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations Table ===&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
!Wavenumber (cm&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;)&lt;br /&gt;
|2457           &lt;br /&gt;
|-&lt;br /&gt;
!Symmetry&lt;br /&gt;
|SGG&lt;br /&gt;
|-&lt;br /&gt;
!Intensity (a.u.)&lt;br /&gt;
|0&lt;br /&gt;
|-&lt;br /&gt;
!Images&lt;br /&gt;
|[[File:Tamim N2 vib.PNG|centre|thumb|250x250px]]&lt;br /&gt;
|}&lt;br /&gt;
* How many modes do you expect from the 3N-6 rule? 0&lt;br /&gt;
* Which modes are &amp;quot;bending&amp;quot; vibrations and which are &amp;quot;bond stretch&amp;quot; vibrations? Only 1 bond stretching vibration &lt;br /&gt;
* Which mode is highly symmetric? 1&lt;br /&gt;
&lt;br /&gt;
=== Charge Distribution ===&lt;br /&gt;
[[File:Tamim n2 charge.PNG|centre|thumb|Charge Distribution for N&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;]]&lt;br /&gt;
The charges on both Nitrogen atoms are zero as they have the same electronegativity which means there is no dipole in the diatomic moleule.&lt;br /&gt;
&lt;br /&gt;
== H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt; Optimisation ==&lt;br /&gt;
What is the calculation method? RB3LYP&lt;br /&gt;
&lt;br /&gt;
What is the basis set? 6-31G(d,p)&lt;br /&gt;
&lt;br /&gt;
What is the final energy E(RB3LYP) in atomic units (au)? -1.17853936&lt;br /&gt;
&lt;br /&gt;
What is the RMS gradient? 0.00000017&lt;br /&gt;
&lt;br /&gt;
What is the point group of your molecule? D*H&lt;br /&gt;
&lt;br /&gt;
Optimised H-H bond distance? 0.74&lt;br /&gt;
&lt;br /&gt;
=== Item Table ===&lt;br /&gt;
&lt;br /&gt;
&amp;lt;pre&amp;gt;&lt;br /&gt;
         Item               Value     Threshold  Converged?&lt;br /&gt;
 Maximum Force            0.000000     0.000450     YES&lt;br /&gt;
 RMS     Force            0.000000     0.000300     YES&lt;br /&gt;
 Maximum Displacement     0.000000     0.001800     YES&lt;br /&gt;
 RMS     Displacement     0.000001     0.001200     YES&lt;br /&gt;
 Predicted change in Energy=-1.164080D-13&amp;lt;/pre&amp;gt;&lt;br /&gt;
&lt;br /&gt;
=== Jmol ===&lt;br /&gt;
Link to completed H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt; optimisation: https://wiki.ch.ic.ac.uk/wiki/images/d/d4/TAMIM_H2_1.LOG&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations ===&lt;br /&gt;
[[File:Tamim h2 disp.PNG|thumb|centre|463x463px]]&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations Table ===&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
!Wavenumber (cm-1)&lt;br /&gt;
|4466&lt;br /&gt;
|-&lt;br /&gt;
!Symmetry&lt;br /&gt;
|SGG&lt;br /&gt;
|-&lt;br /&gt;
!Intensity (a.u.)&lt;br /&gt;
|0&lt;br /&gt;
|-&lt;br /&gt;
!Images&lt;br /&gt;
|[[File:Tamim h2 vib.PNG|centre|thumb]]&lt;br /&gt;
|}&lt;br /&gt;
* How many modes do you expect from the 3N-6 rule? 0&lt;br /&gt;
* Which modes are &amp;quot;bending&amp;quot; vibrations and which are &amp;quot;bond stretch&amp;quot; vibrations? Only 1 bond stretching vibration &lt;br /&gt;
* Which mode is highly symmetric? 1&lt;br /&gt;
&lt;br /&gt;
=== Charge Distribution ===&lt;br /&gt;
[[File:Tamim h2 charge.PNG|centre|thumb|Charge distribution for H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;]]&lt;br /&gt;
The charges on both Hydrogen atoms are zero as they have the same electronegativity which means there is no dipole in the diatomic moleule.&lt;br /&gt;
&lt;br /&gt;
== Mono-metallic Transition Metal Complex ==&lt;br /&gt;
The transition metal complex chosen was (dinitrogen)-(2,6-bis(1-(2,6-diisopropylphenylimino)propyl)pyridine)-iron with the reference code &#039;&#039;&#039;BARTOF&#039;&#039;&#039;.&lt;br /&gt;
[[File:Tamim TM.PNG|centre|thumb]]&lt;br /&gt;
The bond length of N&amp;lt;sub&amp;gt;2 &amp;lt;/sub&amp;gt;in the molecule above is slightly higher than the bond length of N&amp;lt;sub&amp;gt;2 &amp;lt;/sub&amp;gt;that was calculated before (1.112 compared ot 1.1055). This is due to the lone pair of one nitrogen being donated to the central Iron atom which lowers the electron density on the nitrogen atom; this leads to less overlap of orbitals leading to a higher bond length.  &lt;br /&gt;
&lt;br /&gt;
Link to journal: https://pubs.acs.org/doi/10.1021/ic202750n&lt;br /&gt;
&lt;br /&gt;
== Haber-Bosch Process ==&lt;br /&gt;
* E(NH&amp;lt;sub&amp;gt;3&amp;lt;/sub&amp;gt;) = -56.55776873 &lt;br /&gt;
* 2*E(NH&amp;lt;sub&amp;gt;3&amp;lt;/sub&amp;gt;) = -113.11553746 &lt;br /&gt;
* E(N&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;) = -109.52412868 &lt;br /&gt;
* E(H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;) = -1.17853936 &lt;br /&gt;
* 3*E(H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;) = -3.53561808 &lt;br /&gt;
* ΔE=2*E(NH&amp;lt;sub&amp;gt;3&amp;lt;/sub&amp;gt;)-[E(N&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;)+3*E(H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;)] = -0.05579076&lt;br /&gt;
&lt;br /&gt;
The product ammonia is more stable than the gaseous reactants as it has a lower energy than the reactants. This means it is more stable as the forward reaction is exothermic. &lt;br /&gt;
&lt;br /&gt;
== Own Molecule - SH&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt; ==&lt;br /&gt;
What is the calculation method? RB3LYP&lt;br /&gt;
&lt;br /&gt;
What is the basis set? 6-31G(d,p)&lt;br /&gt;
&lt;br /&gt;
What is the final energy E(RB3LYP) in atomic units (au)? -399.39162414&lt;br /&gt;
&lt;br /&gt;
What is the RMS gradient? 0.00012068&lt;br /&gt;
&lt;br /&gt;
What is the point group of your molecule? C2V&lt;br /&gt;
&lt;br /&gt;
Bond angle of H-S-H? 92.681&lt;br /&gt;
&lt;br /&gt;
=== Item Table ===&lt;br /&gt;
&amp;lt;pre&amp;gt;&lt;br /&gt;
         Item               Value     Threshold  Converged?&amp;lt;br&amp;gt;&lt;br /&gt;
 Maximum Force            0.000175     0.000450     YES&amp;lt;br&amp;gt;&lt;br /&gt;
 RMS     Force            0.000145     0.000300     YES&amp;lt;br&amp;gt;&lt;br /&gt;
 Maximum Displacement     0.000386     0.001800     YES&amp;lt;br&amp;gt;&lt;br /&gt;
 RMS     Displacement     0.000386     0.001200     YES&amp;lt;/pre&amp;gt;&lt;br /&gt;
&lt;br /&gt;
=== Jmol ===&lt;br /&gt;
Link to completed SH&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt; optimisation: https://wiki.ch.ic.ac.uk/wiki/images/f/f8/TAMIM_SH2.LOG&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations ===&lt;br /&gt;
[[File:Tamim disp.PNG|centre|thumb]]&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations Table ===&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
!Wavenumber (cm&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;)&lt;br /&gt;
|1224&lt;br /&gt;
|2692&lt;br /&gt;
|2712&lt;br /&gt;
|-&lt;br /&gt;
!Symmetry&lt;br /&gt;
|A1&lt;br /&gt;
|A1&lt;br /&gt;
|B2&lt;br /&gt;
|-&lt;br /&gt;
!Intensity&lt;br /&gt;
|5&lt;br /&gt;
|7&lt;br /&gt;
|9&lt;br /&gt;
|-&lt;br /&gt;
!Images&lt;br /&gt;
|[[File:Tamim vib1.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim vib2.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim vib3.PNG|centre|thumb|217x217px]]&lt;br /&gt;
|}&lt;br /&gt;
* How many modes do you expect from the 3N-6 rule? 3&lt;br /&gt;
* Which modes are &amp;quot;bending&amp;quot; vibrations and which are &amp;quot;bond stretch&amp;quot; vibrations? 1 is a bending vibration while 2 and 3 are bond stretch vibrations.  &lt;br /&gt;
* Which mode is highly symmetric? 2&lt;br /&gt;
&lt;br /&gt;
=== Charge Distributions ===&lt;br /&gt;
[[File:Tamim chargesh2.PNG|centre|thumb|Charge distribution for SH&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;]]&lt;br /&gt;
The charge on Sulfur is slightly negative whereas the hydrogen atoms have a slightly positive charge. This is due to the difference in electronegativity, sulfur is more electronegative than hydrogen and therefore has a higher electron density to it leading to its slightly negative charge.&lt;br /&gt;
&lt;br /&gt;
=== Molecular Orbitals ===&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
|[[File:Tamim mo1.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim mo2.PNG|centre|thumb|201x201px]]&lt;br /&gt;
|[[File:Tamim mo3.PNG|centre|thumb|210x210px]]&lt;br /&gt;
|[[File:Tamim mo4.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim mo5.PNG|centre|thumb|205x205px]]&lt;br /&gt;
|-&lt;br /&gt;
|Bonding molecular orbital between 3s electrons from sulfur and 1s electrons from the hydrogen. It is also an occupied orbital and has an energy of -0.74654. &lt;br /&gt;
|Non-bonding orbital consisting of the 2p orbital from the sulfur. Occupied orbital with energy of -5.91268.  &lt;br /&gt;
|Anti-bonding molecular orbital created between the 3p orbitals from sulfur and1 s orbitals from hydrogen. This is an unoccupied orbital with an energy of 0.02126. &lt;br /&gt;
|Bonding molecular orbital whihc is created due to the 3p orbital of sulfur and 1s orbital from the hydrogens. This is an occupied orbital with an energy of -0.44963. &lt;br /&gt;
|SP mixnig between the s and p orbitals of sulfur and also consists of molecular orbital being created between the p orbital of sulfur and s orbitals of hydrogen. This is an occupied orbital with an energy of -0.36725.&lt;br /&gt;
|}&lt;/div&gt;</summary>
		<author><name>Tr318</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=Rep:Mod:01574856&amp;diff=742522</id>
		<title>Rep:Mod:01574856</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=Rep:Mod:01574856&amp;diff=742522"/>
		<updated>2019-02-22T15:55:02Z</updated>

		<summary type="html">&lt;p&gt;Tr318: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;== NH&amp;lt;sub&amp;gt;3&amp;lt;/sub&amp;gt; Optimisation     ==&lt;br /&gt;
What is the calculation method? RB3LYP&lt;br /&gt;
&lt;br /&gt;
What is the basis set? 6-31G(d,p)&lt;br /&gt;
&lt;br /&gt;
What is the final energy E(RB3LYP) in atomic units (au)? -56.55776873&lt;br /&gt;
&lt;br /&gt;
What is the RMS gradient? 0.00000485&lt;br /&gt;
&lt;br /&gt;
What is the point group of your molecule? C3V&lt;br /&gt;
&lt;br /&gt;
optimised N-H bond distance and the optimised H-N-H bond angle? 1.02 &amp;amp; 106&lt;br /&gt;
&lt;br /&gt;
=== Item Table ===&lt;br /&gt;
&amp;lt;pre&amp;gt;&lt;br /&gt;
         Item               Value     Threshold  Converged?&lt;br /&gt;
 Maximum Force            0.000004     0.000450     YES&lt;br /&gt;
 RMS     Force            0.000004     0.000300     YES&lt;br /&gt;
 Maximum Displacement     0.000072     0.001800     YES&lt;br /&gt;
 RMS     Displacement     0.000035     0.001200     YES&lt;br /&gt;
 Predicted change in Energy=-5.986295D-10&lt;br /&gt;
&amp;lt;/pre&amp;gt;&lt;br /&gt;
&lt;br /&gt;
=== Jmol&amp;lt;br&amp;gt;  ===&lt;br /&gt;
Link to completed NH&amp;lt;sub&amp;gt;3&amp;lt;/sub&amp;gt; optimisation https://wiki.ch.ic.ac.uk/wiki/images/f/fe/TAMIM_RAHMAN_NH3_OPTIMISATION_POP.log&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations ===&lt;br /&gt;
[[File:Display_Vibrations.PNG|centre]]&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations Table ===&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
!Wavenumber (cm&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;)&lt;br /&gt;
|1090&lt;br /&gt;
|1694&lt;br /&gt;
|1694&lt;br /&gt;
|3461&lt;br /&gt;
|3590&lt;br /&gt;
|3590&lt;br /&gt;
|-&lt;br /&gt;
!Symmetry&lt;br /&gt;
|A1&lt;br /&gt;
|E&lt;br /&gt;
|E&lt;br /&gt;
|A1&lt;br /&gt;
|E&lt;br /&gt;
|E&lt;br /&gt;
|-&lt;br /&gt;
!Intensity (a.u.)&lt;br /&gt;
|145&lt;br /&gt;
|14&lt;br /&gt;
|14&lt;br /&gt;
|1&lt;br /&gt;
|0&lt;br /&gt;
|0&lt;br /&gt;
|-&lt;br /&gt;
!Images&lt;br /&gt;
|[[File:Tamim Vib 1.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim Vib 2.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim Vib 3.PNG|centre|thumb|212x212px]]&lt;br /&gt;
|[[File:Tamim Vib 4.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim Vib 5.PNG|centre|thumb|208x208px]]&lt;br /&gt;
|[[File:Tamim Vib 6.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|}&lt;br /&gt;
* How many modes do you expect from the 3N-6 rule? 6&lt;br /&gt;
* Which modes are degenerate (ie have the same energy)? 2&amp;amp;3 and 5&amp;amp;6&lt;br /&gt;
* Which modes are &amp;quot;bending&amp;quot; vibrations and which are &amp;quot;bond stretch&amp;quot; vibrations? 1,2 and 3 are bending vibrations while 4,5 and 6 are bond stretch vibrations. &lt;br /&gt;
* Which mode is highly symmetric? 4&lt;br /&gt;
* One mode is known as the &amp;quot;umbrella&amp;quot; mode, which one is this? 11&lt;br /&gt;
* How many bands would you expect to see in an experimental spectrum of gaseous ammonia? 3&lt;br /&gt;
&lt;br /&gt;
=== Charge Distribution ===&lt;br /&gt;
[[File:Tamim Charge Distribution.PNG|thumb|Charge Distribution of NH&amp;lt;sub&amp;gt;3&amp;lt;/sub&amp;gt;|centre]]&lt;br /&gt;
&lt;br /&gt;
The charge on nitrogen should be slightly negative whereas the hydrogen atoms will have a slightly positive charge. This is due to the difference in electronegativity, nitrogen is more electronegative than hydrogen and therefore has a higher electron density to it leading to its slightly negative charge.&lt;br /&gt;
&lt;br /&gt;
== N&amp;lt;sub&amp;gt;2 &amp;lt;/sub&amp;gt;Optimisation ==&lt;br /&gt;
What is the calculation method? RB3LYP&lt;br /&gt;
&lt;br /&gt;
What is the basis set? 6-31G(d,p)&lt;br /&gt;
&lt;br /&gt;
What is the final energy E(RB3LYP) in atomic units (au)? -109.52412868&lt;br /&gt;
&lt;br /&gt;
What is the RMS gradient? 0.00000060&lt;br /&gt;
&lt;br /&gt;
What is the point group of your molecule? D*H&lt;br /&gt;
&lt;br /&gt;
Optimised N-N bond distance? 1.11&lt;br /&gt;
&lt;br /&gt;
=== Item Table ===&lt;br /&gt;
 &lt;br /&gt;
&amp;lt;pre&amp;gt;&lt;br /&gt;
         Item              Value      Threshold  Converged?&lt;br /&gt;
 Maximum Force            0.000001     0.000450     YES&lt;br /&gt;
 RMS     Force            0.000001     0.000300     YES&lt;br /&gt;
 Maximum Displacement     0.000000     0.001800     YES&lt;br /&gt;
 RMS     Displacement     0.000000     0.001200     YES&lt;br /&gt;
 Predicted change in Energy=-3.400972D-13&lt;br /&gt;
&amp;lt;/pre&amp;gt;&lt;br /&gt;
&lt;br /&gt;
=== Jmol ===&lt;br /&gt;
&lt;br /&gt;
Link to completed N&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt; optimisation: https://wiki.ch.ic.ac.uk/wiki/images/c/c7/TAMIM_N2_1.LOG&lt;br /&gt;
&lt;br /&gt;
=== DIsplay Vibrations ===&lt;br /&gt;
[[File:Tamim N2 Disp.PNG|thumb|centre|464x464px]]&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations Table ===&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
!Wavenumber (cm&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;)&lt;br /&gt;
|2457           &lt;br /&gt;
|-&lt;br /&gt;
!Symmetry&lt;br /&gt;
|SGG&lt;br /&gt;
|-&lt;br /&gt;
!Intensity (a.u.)&lt;br /&gt;
|0&lt;br /&gt;
|-&lt;br /&gt;
!Images&lt;br /&gt;
|[[File:Tamim N2 vib.PNG|centre|thumb|250x250px]]&lt;br /&gt;
|}&lt;br /&gt;
* How many modes do you expect from the 3N-6 rule? 0&lt;br /&gt;
* Which modes are &amp;quot;bending&amp;quot; vibrations and which are &amp;quot;bond stretch&amp;quot; vibrations? Only 1 bond stretching vibration &lt;br /&gt;
* Which mode is highly symmetric? 1&lt;br /&gt;
&lt;br /&gt;
=== Charge Distribution ===&lt;br /&gt;
[[File:Tamim n2 charge.PNG|centre|thumb|Charge Distribution for N&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;]]&lt;br /&gt;
The charges on both Nitrogen atoms are zero as they have the same electronegativity which means there is no dipole in the diatomic moleule.&lt;br /&gt;
&lt;br /&gt;
== H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt; Optimisation ==&lt;br /&gt;
What is the calculation method? RB3LYP&lt;br /&gt;
&lt;br /&gt;
What is the basis set? 6-31G(d,p)&lt;br /&gt;
&lt;br /&gt;
What is the final energy E(RB3LYP) in atomic units (au)? -1.17853936&lt;br /&gt;
&lt;br /&gt;
What is the RMS gradient? 0.00000017&lt;br /&gt;
&lt;br /&gt;
What is the point group of your molecule? D*H&lt;br /&gt;
&lt;br /&gt;
Optimised H-H bond distance? 0.74&lt;br /&gt;
&lt;br /&gt;
=== Item Table ===&lt;br /&gt;
&lt;br /&gt;
&amp;lt;pre&amp;gt;&lt;br /&gt;
         Item               Value     Threshold  Converged?&lt;br /&gt;
 Maximum Force            0.000000     0.000450     YES&lt;br /&gt;
 RMS     Force            0.000000     0.000300     YES&lt;br /&gt;
 Maximum Displacement     0.000000     0.001800     YES&lt;br /&gt;
 RMS     Displacement     0.000001     0.001200     YES&lt;br /&gt;
 Predicted change in Energy=-1.164080D-13&amp;lt;/pre&amp;gt;&lt;br /&gt;
&lt;br /&gt;
=== Jmol ===&lt;br /&gt;
Link to completed H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt; optimisation: https://wiki.ch.ic.ac.uk/wiki/images/d/d4/TAMIM_H2_1.LOG&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations ===&lt;br /&gt;
[[File:Tamim h2 disp.PNG|thumb|centre|463x463px]]&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations Table ===&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
!Wavenumber (cm-1)&lt;br /&gt;
|4466&lt;br /&gt;
|-&lt;br /&gt;
!Symmetry&lt;br /&gt;
|SGG&lt;br /&gt;
|-&lt;br /&gt;
!Intensity (a.u.)&lt;br /&gt;
|0&lt;br /&gt;
|-&lt;br /&gt;
!Images&lt;br /&gt;
|[[File:Tamim h2 vib.PNG|centre|thumb]]&lt;br /&gt;
|}&lt;br /&gt;
* How many modes do you expect from the 3N-6 rule? 0&lt;br /&gt;
* Which modes are &amp;quot;bending&amp;quot; vibrations and which are &amp;quot;bond stretch&amp;quot; vibrations? Only 1 bond stretching vibration &lt;br /&gt;
* Which mode is highly symmetric? 1&lt;br /&gt;
&lt;br /&gt;
=== Charge Distribution ===&lt;br /&gt;
[[File:Tamim h2 charge.PNG|centre|thumb|Charge distribution for H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;]]&lt;br /&gt;
The charges on both Hydrogen atoms are zero as they have the same electronegativity which means there is no dipole in the diatomic moleule.&lt;br /&gt;
&lt;br /&gt;
== Mono-metallic Transition Metal Complex ==&lt;br /&gt;
The transition metal complex chosen was (dinitrogen)-(2,6-bis(1-(2,6-diisopropylphenylimino)propyl)pyridine)-iron with the reference code &#039;&#039;&#039;BARTOF&#039;&#039;&#039;.&lt;br /&gt;
[[File:Tamim TM.PNG|centre|thumb]]&lt;br /&gt;
The bond length of N&amp;lt;sub&amp;gt;2 &amp;lt;/sub&amp;gt;in the molecule above is slightly higher than the bond length of N&amp;lt;sub&amp;gt;2 &amp;lt;/sub&amp;gt;that was calculated before (1.112 compared ot 1.1055). This is due to the lone pair of one nitrogen being donated to the central Iron atom which lowers the electron density on the nitrogen atom; this leads to less overlap of orbitals leading to a higher bond length.  &lt;br /&gt;
&lt;br /&gt;
Link to journal: https://pubs.acs.org/doi/10.1021/ic202750n&lt;br /&gt;
&lt;br /&gt;
== Haber-Bosch Process ==&lt;br /&gt;
* E(NH&amp;lt;sub&amp;gt;3&amp;lt;/sub&amp;gt;) = -56.55776873 &lt;br /&gt;
* 2*E(NH&amp;lt;sub&amp;gt;3&amp;lt;/sub&amp;gt;) = -113.11553746 &lt;br /&gt;
* E(N&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;) = -109.52412868 &lt;br /&gt;
* E(H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;) = -1.17853936 &lt;br /&gt;
* 3*E(H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;) = -3.53561808 &lt;br /&gt;
* ΔE=2*E(NH&amp;lt;sub&amp;gt;3&amp;lt;/sub&amp;gt;)-[E(N&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;)+3*E(H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;)] = -0.05579076&lt;br /&gt;
&lt;br /&gt;
The product ammonia is more stable than the gaseous reactants as it has a lower energy than the reactants. This means it is more stable as the forward reaction is exothermic. &lt;br /&gt;
&lt;br /&gt;
== Own Molecule - SH&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt; ==&lt;br /&gt;
What is the calculation method? RB3LYP&lt;br /&gt;
&lt;br /&gt;
What is the basis set? 6-31G(d,p)&lt;br /&gt;
&lt;br /&gt;
What is the final energy E(RB3LYP) in atomic units (au)? -399.39162414&lt;br /&gt;
&lt;br /&gt;
What is the RMS gradient? 0.00012068&lt;br /&gt;
&lt;br /&gt;
What is the point group of your molecule? C2V&lt;br /&gt;
&lt;br /&gt;
Bond angle of H-S-H? 92.681&lt;br /&gt;
&lt;br /&gt;
=== Item Table ===&lt;br /&gt;
&amp;lt;pre&amp;gt;&lt;br /&gt;
         Item               Value     Threshold  Converged?&amp;lt;br&amp;gt;&lt;br /&gt;
 Maximum Force            0.000175     0.000450     YES&amp;lt;br&amp;gt;&lt;br /&gt;
 RMS     Force            0.000145     0.000300     YES&amp;lt;br&amp;gt;&lt;br /&gt;
 Maximum Displacement     0.000386     0.001800     YES&amp;lt;br&amp;gt;&lt;br /&gt;
 RMS     Displacement     0.000386     0.001200     YES&amp;lt;/pre&amp;gt;&lt;br /&gt;
&lt;br /&gt;
=== Jmol ===&lt;br /&gt;
Link to completed SH&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt; optimisation: https://wiki.ch.ic.ac.uk/wiki/images/f/f8/TAMIM_SH2.LOG&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations ===&lt;br /&gt;
[[File:Tamim disp.PNG|centre|thumb]]&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations Table ===&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
!Wavenumber (cm&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;)&lt;br /&gt;
|1224&lt;br /&gt;
|2692&lt;br /&gt;
|2712&lt;br /&gt;
|-&lt;br /&gt;
!Symmetry&lt;br /&gt;
|A1&lt;br /&gt;
|A1&lt;br /&gt;
|B2&lt;br /&gt;
|-&lt;br /&gt;
!Intensity&lt;br /&gt;
|5&lt;br /&gt;
|7&lt;br /&gt;
|9&lt;br /&gt;
|-&lt;br /&gt;
!Images&lt;br /&gt;
|[[File:Tamim vib1.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim vib2.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim vib3.PNG|centre|thumb|217x217px]]&lt;br /&gt;
|}&lt;br /&gt;
* How many modes do you expect from the 3N-6 rule? 3&lt;br /&gt;
* Which modes are &amp;quot;bending&amp;quot; vibrations and which are &amp;quot;bond stretch&amp;quot; vibrations? 1 is a bending vibration while 2 and 3 are bond stretch vibrations.  &lt;br /&gt;
* Which mode is highly symmetric? 2&lt;br /&gt;
&lt;br /&gt;
=== Charge Distributions ===&lt;br /&gt;
[[File:Tamim chargesh2.PNG|centre|thumb|Charge distribution for SH&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;]]&lt;br /&gt;
The charge on Sulfur is slightly negative whereas the hydrogen atoms have a slightly positive charge. This is due to the difference in electronegativity, sulfur is more electronegative than hydrogen and therefore has a higher electron density to it leading to its slightly negative charge.&lt;br /&gt;
&lt;br /&gt;
=== Molecular Orbitals ===&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
|[[File:Tamim mo1.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim mo2.PNG|centre|thumb|201x201px]]&lt;br /&gt;
|[[File:Tamim mo3.PNG|centre|thumb|210x210px]]&lt;br /&gt;
|[[File:Tamim mo4.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim mo5.PNG|centre|thumb|205x205px]]&lt;br /&gt;
|-&lt;br /&gt;
|Bonding molecular orbital between 3s electrons from sulfur and 1s electrons from the hydrogen. It is also an occupied orbital and has an energy of -0.74654. &lt;br /&gt;
|Non-bonding orbital consisting of the 2p orbital from the sulfur. Occupied orbital with energy of -5.91268.  &lt;br /&gt;
|Anti-bonding molecular orbital created between the 3p orbitals from sulfur and1 s orbitals from hydrogen. This is an unoccupied orbital with an energy of 0.02126. &lt;br /&gt;
|Bonding molecular orbital whihc is created due to the 3p orbital of sulfur and 1s orbital from the hydrogens. &lt;br /&gt;
|SP mixnig between the s and p orbitals of sulfur and also consists of molecular orbital being created between the p orbital of sulfur and s orbitals of hydrogen.&lt;br /&gt;
|}&lt;/div&gt;</summary>
		<author><name>Tr318</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=Rep:Mod:01574856&amp;diff=742478</id>
		<title>Rep:Mod:01574856</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=Rep:Mod:01574856&amp;diff=742478"/>
		<updated>2019-02-22T15:45:51Z</updated>

		<summary type="html">&lt;p&gt;Tr318: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;== NH&amp;lt;sub&amp;gt;3&amp;lt;/sub&amp;gt; Optimisation     ==&lt;br /&gt;
What is the calculation method? RB3LYP&lt;br /&gt;
&lt;br /&gt;
What is the basis set? 6-31G(d,p)&lt;br /&gt;
&lt;br /&gt;
What is the final energy E(RB3LYP) in atomic units (au)? -56.55776873&lt;br /&gt;
&lt;br /&gt;
What is the RMS gradient? 0.00000485&lt;br /&gt;
&lt;br /&gt;
What is the point group of your molecule? C3V&lt;br /&gt;
&lt;br /&gt;
optimised N-H bond distance and the optimised H-N-H bond angle? 1.02 &amp;amp; 106&lt;br /&gt;
&lt;br /&gt;
=== Item Table ===&lt;br /&gt;
&amp;lt;pre&amp;gt;&lt;br /&gt;
         Item               Value     Threshold  Converged?&lt;br /&gt;
 Maximum Force            0.000004     0.000450     YES&lt;br /&gt;
 RMS     Force            0.000004     0.000300     YES&lt;br /&gt;
 Maximum Displacement     0.000072     0.001800     YES&lt;br /&gt;
 RMS     Displacement     0.000035     0.001200     YES&lt;br /&gt;
 Predicted change in Energy=-5.986295D-10&lt;br /&gt;
&amp;lt;/pre&amp;gt;&lt;br /&gt;
&lt;br /&gt;
=== Jmol&amp;lt;br&amp;gt;  ===&lt;br /&gt;
Link to completed NH&amp;lt;sub&amp;gt;3&amp;lt;/sub&amp;gt; optimisation https://wiki.ch.ic.ac.uk/wiki/images/f/fe/TAMIM_RAHMAN_NH3_OPTIMISATION_POP.log&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations ===&lt;br /&gt;
[[File:Display_Vibrations.PNG|centre]]&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations Table ===&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
!Wavenumber (cm&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;)&lt;br /&gt;
|1090&lt;br /&gt;
|1694&lt;br /&gt;
|1694&lt;br /&gt;
|3461&lt;br /&gt;
|3590&lt;br /&gt;
|3590&lt;br /&gt;
|-&lt;br /&gt;
!Symmetry&lt;br /&gt;
|A1&lt;br /&gt;
|E&lt;br /&gt;
|E&lt;br /&gt;
|A1&lt;br /&gt;
|E&lt;br /&gt;
|E&lt;br /&gt;
|-&lt;br /&gt;
!Intensity (a.u.)&lt;br /&gt;
|145&lt;br /&gt;
|14&lt;br /&gt;
|14&lt;br /&gt;
|1&lt;br /&gt;
|0&lt;br /&gt;
|0&lt;br /&gt;
|-&lt;br /&gt;
!Images&lt;br /&gt;
|[[File:Tamim Vib 1.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim Vib 2.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim Vib 3.PNG|centre|thumb|212x212px]]&lt;br /&gt;
|[[File:Tamim Vib 4.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim Vib 5.PNG|centre|thumb|208x208px]]&lt;br /&gt;
|[[File:Tamim Vib 6.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|}&lt;br /&gt;
* How many modes do you expect from the 3N-6 rule? 6&lt;br /&gt;
* Which modes are degenerate (ie have the same energy)? 2&amp;amp;3 and 5&amp;amp;6&lt;br /&gt;
* Which modes are &amp;quot;bending&amp;quot; vibrations and which are &amp;quot;bond stretch&amp;quot; vibrations? 1,2 and 3 are bending vibrations while 4,5 and 6 are bond stretch vibrations. &lt;br /&gt;
* Which mode is highly symmetric? 4&lt;br /&gt;
* One mode is known as the &amp;quot;umbrella&amp;quot; mode, which one is this? 11&lt;br /&gt;
* How many bands would you expect to see in an experimental spectrum of gaseous ammonia? 3&lt;br /&gt;
&lt;br /&gt;
=== Charge Distribution ===&lt;br /&gt;
[[File:Tamim Charge Distribution.PNG|thumb|Charge Distribution of NH&amp;lt;sub&amp;gt;3&amp;lt;/sub&amp;gt;|centre]]&lt;br /&gt;
&lt;br /&gt;
The charge on nitrogen should be slightly negative whereas the hydrogen atoms will have a slightly positive charge. This is due to the difference in electronegativity, nitrogen is more electronegative than hydrogen and therefore has a higher electron density to it leading to its slightly negative charge.&lt;br /&gt;
&lt;br /&gt;
== N&amp;lt;sub&amp;gt;2 &amp;lt;/sub&amp;gt;Optimisation ==&lt;br /&gt;
What is the calculation method? RB3LYP&lt;br /&gt;
&lt;br /&gt;
What is the basis set? 6-31G(d,p)&lt;br /&gt;
&lt;br /&gt;
What is the final energy E(RB3LYP) in atomic units (au)? -109.52412868&lt;br /&gt;
&lt;br /&gt;
What is the RMS gradient? 0.00000060&lt;br /&gt;
&lt;br /&gt;
What is the point group of your molecule? D*H&lt;br /&gt;
&lt;br /&gt;
Optimised N-N bond distance? 1.11&lt;br /&gt;
&lt;br /&gt;
=== Item Table ===&lt;br /&gt;
 &lt;br /&gt;
&amp;lt;pre&amp;gt;&lt;br /&gt;
         Item              Value      Threshold  Converged?&lt;br /&gt;
 Maximum Force            0.000001     0.000450     YES&lt;br /&gt;
 RMS     Force            0.000001     0.000300     YES&lt;br /&gt;
 Maximum Displacement     0.000000     0.001800     YES&lt;br /&gt;
 RMS     Displacement     0.000000     0.001200     YES&lt;br /&gt;
 Predicted change in Energy=-3.400972D-13&lt;br /&gt;
&amp;lt;/pre&amp;gt;&lt;br /&gt;
&lt;br /&gt;
=== Jmol ===&lt;br /&gt;
&lt;br /&gt;
Link to completed N&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt; optimisation: https://wiki.ch.ic.ac.uk/wiki/images/c/c7/TAMIM_N2_1.LOG&lt;br /&gt;
&lt;br /&gt;
=== DIsplay Vibrations ===&lt;br /&gt;
[[File:Tamim N2 Disp.PNG|thumb|centre|464x464px]]&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations Table ===&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
!Wavenumber (cm&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;)&lt;br /&gt;
|2457           &lt;br /&gt;
|-&lt;br /&gt;
!Symmetry&lt;br /&gt;
|SGG&lt;br /&gt;
|-&lt;br /&gt;
!Intensity (a.u.)&lt;br /&gt;
|0&lt;br /&gt;
|-&lt;br /&gt;
!Images&lt;br /&gt;
|[[File:Tamim N2 vib.PNG|centre|thumb|250x250px]]&lt;br /&gt;
|}&lt;br /&gt;
* How many modes do you expect from the 3N-6 rule? 0&lt;br /&gt;
* Which modes are &amp;quot;bending&amp;quot; vibrations and which are &amp;quot;bond stretch&amp;quot; vibrations? Only 1 bond stretching vibration &lt;br /&gt;
* Which mode is highly symmetric? 1&lt;br /&gt;
&lt;br /&gt;
=== Charge Distribution ===&lt;br /&gt;
[[File:Tamim n2 charge.PNG|centre|thumb|Charge Distribution for N&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;]]&lt;br /&gt;
The charges on both Nitrogen atoms are zero as they have the same electronegativity which means there is no dipole in the diatomic moleule.&lt;br /&gt;
&lt;br /&gt;
== H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt; Optimisation ==&lt;br /&gt;
What is the calculation method? RB3LYP&lt;br /&gt;
&lt;br /&gt;
What is the basis set? 6-31G(d,p)&lt;br /&gt;
&lt;br /&gt;
What is the final energy E(RB3LYP) in atomic units (au)? -1.17853936&lt;br /&gt;
&lt;br /&gt;
What is the RMS gradient? 0.00000017&lt;br /&gt;
&lt;br /&gt;
What is the point group of your molecule? D*H&lt;br /&gt;
&lt;br /&gt;
Optimised H-H bond distance? 0.74&lt;br /&gt;
&lt;br /&gt;
=== Item Table ===&lt;br /&gt;
&lt;br /&gt;
&amp;lt;pre&amp;gt;&lt;br /&gt;
         Item               Value     Threshold  Converged?&lt;br /&gt;
 Maximum Force            0.000000     0.000450     YES&lt;br /&gt;
 RMS     Force            0.000000     0.000300     YES&lt;br /&gt;
 Maximum Displacement     0.000000     0.001800     YES&lt;br /&gt;
 RMS     Displacement     0.000001     0.001200     YES&lt;br /&gt;
 Predicted change in Energy=-1.164080D-13&amp;lt;/pre&amp;gt;&lt;br /&gt;
&lt;br /&gt;
=== Jmol ===&lt;br /&gt;
Link to completed H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt; optimisation: https://wiki.ch.ic.ac.uk/wiki/images/d/d4/TAMIM_H2_1.LOG&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations ===&lt;br /&gt;
[[File:Tamim h2 disp.PNG|thumb|centre|463x463px]]&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations Table ===&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
!Wavenumber (cm-1)&lt;br /&gt;
|4466&lt;br /&gt;
|-&lt;br /&gt;
!Symmetry&lt;br /&gt;
|SGG&lt;br /&gt;
|-&lt;br /&gt;
!Intensity (a.u.)&lt;br /&gt;
|0&lt;br /&gt;
|-&lt;br /&gt;
!Images&lt;br /&gt;
|[[File:Tamim h2 vib.PNG|centre|thumb]]&lt;br /&gt;
|}&lt;br /&gt;
* How many modes do you expect from the 3N-6 rule? 0&lt;br /&gt;
* Which modes are &amp;quot;bending&amp;quot; vibrations and which are &amp;quot;bond stretch&amp;quot; vibrations? Only 1 bond stretching vibration &lt;br /&gt;
* Which mode is highly symmetric? 1&lt;br /&gt;
&lt;br /&gt;
=== Charge Distribution ===&lt;br /&gt;
[[File:Tamim h2 charge.PNG|centre|thumb|Charge distribution for H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;]]&lt;br /&gt;
The charges on both Hydrogen atoms are zero as they have the same electronegativity which means there is no dipole in the diatomic moleule.&lt;br /&gt;
&lt;br /&gt;
== Mono-metallic Transition Metal Complex ==&lt;br /&gt;
The transition metal complex chosen was (dinitrogen)-(2,6-bis(1-(2,6-diisopropylphenylimino)propyl)pyridine)-iron with the reference code &#039;&#039;&#039;BARTOF&#039;&#039;&#039;.&lt;br /&gt;
[[File:Tamim TM.PNG|centre|thumb]]&lt;br /&gt;
The bond length of N&amp;lt;sub&amp;gt;2 &amp;lt;/sub&amp;gt;in the molecule above is slightly higher than the bond length of N&amp;lt;sub&amp;gt;2 &amp;lt;/sub&amp;gt;that was calculated before (1.112 compared ot 1.1055). This is due to the lone pair of one nitrogen being donated to the central Iron atom which lowers the electron density on the nitrogen atom; this leads to less overlap of orbitals leading to a higher bond length.  &lt;br /&gt;
&lt;br /&gt;
Link to journal: https://pubs.acs.org/doi/10.1021/ic202750n&lt;br /&gt;
&lt;br /&gt;
== Haber-Bosch Process ==&lt;br /&gt;
* E(NH&amp;lt;sub&amp;gt;3&amp;lt;/sub&amp;gt;) = -56.55776873 &lt;br /&gt;
* 2*E(NH&amp;lt;sub&amp;gt;3&amp;lt;/sub&amp;gt;) = -113.11553746 &lt;br /&gt;
* E(N&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;) = -109.52412868 &lt;br /&gt;
* E(H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;) = -1.17853936 &lt;br /&gt;
* 3*E(H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;) = -3.53561808 &lt;br /&gt;
* ΔE=2*E(NH&amp;lt;sub&amp;gt;3&amp;lt;/sub&amp;gt;)-[E(N&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;)+3*E(H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;)] = -0.05579076&lt;br /&gt;
&lt;br /&gt;
The product ammonia is more stable than the gaseous reactants as it has a lower energy than the reactants. This means it is more stable as the forward reaction is exothermic. &lt;br /&gt;
&lt;br /&gt;
== Own Molecule - SH&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt; ==&lt;br /&gt;
What is the calculation method? RB3LYP&lt;br /&gt;
&lt;br /&gt;
What is the basis set? 6-31G(d,p)&lt;br /&gt;
&lt;br /&gt;
What is the final energy E(RB3LYP) in atomic units (au)? -399.39162414&lt;br /&gt;
&lt;br /&gt;
What is the RMS gradient? 0.00012068&lt;br /&gt;
&lt;br /&gt;
What is the point group of your molecule? C2V&lt;br /&gt;
&lt;br /&gt;
Bond angle of H-S-H? 92.681&lt;br /&gt;
&lt;br /&gt;
=== Item Table ===&lt;br /&gt;
&amp;lt;pre&amp;gt;&lt;br /&gt;
         Item               Value     Threshold  Converged?&amp;lt;br&amp;gt;&lt;br /&gt;
 Maximum Force            0.000175     0.000450     YES&amp;lt;br&amp;gt;&lt;br /&gt;
 RMS     Force            0.000145     0.000300     YES&amp;lt;br&amp;gt;&lt;br /&gt;
 Maximum Displacement     0.000386     0.001800     YES&amp;lt;br&amp;gt;&lt;br /&gt;
 RMS     Displacement     0.000386     0.001200     YES&amp;lt;/pre&amp;gt;&lt;br /&gt;
&lt;br /&gt;
=== Jmol ===&lt;br /&gt;
Link to completed SH&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt; optimisation: https://wiki.ch.ic.ac.uk/wiki/images/f/f8/TAMIM_SH2.LOG&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations ===&lt;br /&gt;
[[File:Tamim disp.PNG|centre|thumb]]&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations Table ===&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
!Wavenumber (cm&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;)&lt;br /&gt;
|1224&lt;br /&gt;
|2692&lt;br /&gt;
|2712&lt;br /&gt;
|-&lt;br /&gt;
!Symmetry&lt;br /&gt;
|A1&lt;br /&gt;
|A1&lt;br /&gt;
|B2&lt;br /&gt;
|-&lt;br /&gt;
!Intensity&lt;br /&gt;
|5&lt;br /&gt;
|7&lt;br /&gt;
|9&lt;br /&gt;
|-&lt;br /&gt;
!Images&lt;br /&gt;
|[[File:Tamim vib1.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim vib2.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim vib3.PNG|centre|thumb|217x217px]]&lt;br /&gt;
|}&lt;br /&gt;
* How many modes do you expect from the 3N-6 rule? 3&lt;br /&gt;
* Which modes are &amp;quot;bending&amp;quot; vibrations and which are &amp;quot;bond stretch&amp;quot; vibrations? 1 is a bending vibration while 2 and 3 are bond stretch vibrations.  &lt;br /&gt;
* Which mode is highly symmetric? 2&lt;br /&gt;
&lt;br /&gt;
=== Charge Distributions ===&lt;br /&gt;
[[File:Tamim chargesh2.PNG|centre|thumb|Charge distribution for SH&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;]]&lt;br /&gt;
The charge on Sulfur is slightly negative whereas the hydrogen atoms have a slightly positive charge. This is due to the difference in electronegativity, sulfur is more electronegative than hydrogen and therefore has a higher electron density to it leading to its slightly negative charge.&lt;br /&gt;
&lt;br /&gt;
=== Molecular Orbitals ===&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
|[[File:Tamim mo1.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim mo2.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim mo3.PNG|centre|thumb|209x209px]]&lt;br /&gt;
|[[File:Tamim mo4.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim mo5.PNG|centre|thumb|205x205px]]&lt;br /&gt;
|-&lt;br /&gt;
|Bonding molecular orbital between 3s electrons from sulfur and 1s electrons from the hydrogen. &lt;br /&gt;
|Non-bonding orbital consisting of the 2p orbital from the sulfur. &lt;br /&gt;
|Anti-bonding molecular orbital created between the 3p orbitals from sulfur and1 s orbitals from hydrogen. &lt;br /&gt;
|Bonding molecular orbital whihc is created due to the 3p orbital of sulfur and 1s orbital from the hydrogens. &lt;br /&gt;
|SP mixnig between the s and p orbitals of sulfur and also consists of molecular orbital being created between the p orbital of sulfur and s orbitals of hydrogen.&lt;br /&gt;
|}&lt;/div&gt;</summary>
		<author><name>Tr318</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=File:Tamim_vib3.PNG&amp;diff=742465</id>
		<title>File:Tamim vib3.PNG</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=File:Tamim_vib3.PNG&amp;diff=742465"/>
		<updated>2019-02-22T15:40:08Z</updated>

		<summary type="html">&lt;p&gt;Tr318: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;/div&gt;</summary>
		<author><name>Tr318</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=File:Tamim_vib2.PNG&amp;diff=742462</id>
		<title>File:Tamim vib2.PNG</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=File:Tamim_vib2.PNG&amp;diff=742462"/>
		<updated>2019-02-22T15:39:58Z</updated>

		<summary type="html">&lt;p&gt;Tr318: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;/div&gt;</summary>
		<author><name>Tr318</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=File:Tamim_vib1.PNG&amp;diff=742461</id>
		<title>File:Tamim vib1.PNG</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=File:Tamim_vib1.PNG&amp;diff=742461"/>
		<updated>2019-02-22T15:39:46Z</updated>

		<summary type="html">&lt;p&gt;Tr318: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;/div&gt;</summary>
		<author><name>Tr318</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=Rep:Mod:01574856&amp;diff=742452</id>
		<title>Rep:Mod:01574856</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=Rep:Mod:01574856&amp;diff=742452"/>
		<updated>2019-02-22T15:34:59Z</updated>

		<summary type="html">&lt;p&gt;Tr318: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;== NH&amp;lt;sub&amp;gt;3&amp;lt;/sub&amp;gt; Optimisation     ==&lt;br /&gt;
What is the calculation method? RB3LYP&lt;br /&gt;
&lt;br /&gt;
What is the basis set? 6-31G(d,p)&lt;br /&gt;
&lt;br /&gt;
What is the final energy E(RB3LYP) in atomic units (au)? -56.55776873&lt;br /&gt;
&lt;br /&gt;
What is the RMS gradient? 0.00000485&lt;br /&gt;
&lt;br /&gt;
What is the point group of your molecule? C3V&lt;br /&gt;
&lt;br /&gt;
optimised N-H bond distance and the optimised H-N-H bond angle? 1.02 &amp;amp; 106&lt;br /&gt;
&lt;br /&gt;
=== Item Table ===&lt;br /&gt;
&amp;lt;pre&amp;gt;&lt;br /&gt;
         Item               Value     Threshold  Converged?&lt;br /&gt;
 Maximum Force            0.000004     0.000450     YES&lt;br /&gt;
 RMS     Force            0.000004     0.000300     YES&lt;br /&gt;
 Maximum Displacement     0.000072     0.001800     YES&lt;br /&gt;
 RMS     Displacement     0.000035     0.001200     YES&lt;br /&gt;
 Predicted change in Energy=-5.986295D-10&lt;br /&gt;
&amp;lt;/pre&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Link to completed NH3 optimisation https://wiki.ch.ic.ac.uk/wiki/images/f/fe/TAMIM_RAHMAN_NH3_OPTIMISATION_POP.log&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations ===&lt;br /&gt;
[[File:Display_Vibrations.PNG|centre]]&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations Table ===&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
!Wavenumber (cm&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;)&lt;br /&gt;
|1090&lt;br /&gt;
|1694&lt;br /&gt;
|1694&lt;br /&gt;
|3461&lt;br /&gt;
|3590&lt;br /&gt;
|3590&lt;br /&gt;
|-&lt;br /&gt;
!Symmetry&lt;br /&gt;
|A1&lt;br /&gt;
|E&lt;br /&gt;
|E&lt;br /&gt;
|A1&lt;br /&gt;
|E&lt;br /&gt;
|E&lt;br /&gt;
|-&lt;br /&gt;
!Intensity (a.u.)&lt;br /&gt;
|145&lt;br /&gt;
|14&lt;br /&gt;
|14&lt;br /&gt;
|1&lt;br /&gt;
|0&lt;br /&gt;
|0&lt;br /&gt;
|-&lt;br /&gt;
!Images&lt;br /&gt;
|[[File:Tamim Vib 1.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim Vib 2.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim Vib 3.PNG|centre|thumb|212x212px]]&lt;br /&gt;
|[[File:Tamim Vib 4.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim Vib 5.PNG|centre|thumb|208x208px]]&lt;br /&gt;
|[[File:Tamim Vib 6.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|}&lt;br /&gt;
* How many modes do you expect from the 3N-6 rule? 6&lt;br /&gt;
* Which modes are degenerate (ie have the same energy)? 2&amp;amp;3 and 5&amp;amp;6&lt;br /&gt;
* Which modes are &amp;quot;bending&amp;quot; vibrations and which are &amp;quot;bond stretch&amp;quot; vibrations? 1,2 and 3 are bending vibrations while 4,5 and 6 are bond stretch vibrations. &lt;br /&gt;
* Which mode is highly symmetric? 4&lt;br /&gt;
* One mode is known as the &amp;quot;umbrella&amp;quot; mode, which one is this? 11&lt;br /&gt;
* How many bands would you expect to see in an experimental spectrum of gaseous ammonia? 3&lt;br /&gt;
&lt;br /&gt;
=== Charge Distribution ===&lt;br /&gt;
[[File:Tamim Charge Distribution.PNG|thumb|Charge Distribution of NH&amp;lt;sub&amp;gt;3&amp;lt;/sub&amp;gt;|centre]]&lt;br /&gt;
&lt;br /&gt;
The charge on nitrogen should be slightly negative whereas the hydrogen atoms will have a slightly positive charge. This is due to the difference in electronegativity, nitrogen is more electronegative than hydrogen and therefore has a higher electron density to it leading to its slightly negative charge.&lt;br /&gt;
&lt;br /&gt;
== N&amp;lt;sub&amp;gt;2 &amp;lt;/sub&amp;gt;Optimisation ==&lt;br /&gt;
What is the calculation method? RB3LYP&lt;br /&gt;
&lt;br /&gt;
What is the basis set? 6-31G(d,p)&lt;br /&gt;
&lt;br /&gt;
What is the final energy E(RB3LYP) in atomic units (au)? -109.52412868&lt;br /&gt;
&lt;br /&gt;
What is the RMS gradient? 0.00000060&lt;br /&gt;
&lt;br /&gt;
What is the point group of your molecule? D*H&lt;br /&gt;
&lt;br /&gt;
Optimised N-N bond distance? 1.11&lt;br /&gt;
&lt;br /&gt;
=== Item Table ===&lt;br /&gt;
 &lt;br /&gt;
&amp;lt;pre&amp;gt;&lt;br /&gt;
         Item              Value      Threshold  Converged?&lt;br /&gt;
 Maximum Force            0.000001     0.000450     YES&lt;br /&gt;
 RMS     Force            0.000001     0.000300     YES&lt;br /&gt;
 Maximum Displacement     0.000000     0.001800     YES&lt;br /&gt;
 RMS     Displacement     0.000000     0.001200     YES&lt;br /&gt;
 Predicted change in Energy=-3.400972D-13&lt;br /&gt;
&amp;lt;/pre&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
=== DIsplay Vibrations ===&lt;br /&gt;
[[File:Tamim N2 Disp.PNG|thumb|centre|464x464px]]&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations Table ===&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
!Wavenumber (cm&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;)&lt;br /&gt;
|2457           &lt;br /&gt;
|-&lt;br /&gt;
!Symmetry&lt;br /&gt;
|SGG&lt;br /&gt;
|-&lt;br /&gt;
!Intensity (a.u.)&lt;br /&gt;
|0&lt;br /&gt;
|-&lt;br /&gt;
!Images&lt;br /&gt;
|[[File:Tamim N2 vib.PNG|centre|thumb|250x250px]]&lt;br /&gt;
|}&lt;br /&gt;
* How many modes do you expect from the 3N-6 rule? 0&lt;br /&gt;
* Which modes are &amp;quot;bending&amp;quot; vibrations and which are &amp;quot;bond stretch&amp;quot; vibrations? Only 1 bond stretching vibration &lt;br /&gt;
* Which mode is highly symmetric? 1&lt;br /&gt;
&lt;br /&gt;
=== Charge Distribution ===&lt;br /&gt;
[[File:Tamim n2 charge.PNG|centre|thumb|Charge Distribution for N&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;]]&lt;br /&gt;
The charges on both Nitrogen atoms are zero as they have the same electronegativity which means there is no dipole in the diatomic moleule.&lt;br /&gt;
&lt;br /&gt;
== H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt; Optimisation ==&lt;br /&gt;
What is the calculation method? RB3LYP&lt;br /&gt;
&lt;br /&gt;
What is the basis set? 6-31G(d,p)&lt;br /&gt;
&lt;br /&gt;
What is the final energy E(RB3LYP) in atomic units (au)? -1.17853936&lt;br /&gt;
&lt;br /&gt;
What is the RMS gradient? 0.00000017&lt;br /&gt;
&lt;br /&gt;
What is the point group of your molecule? D*H&lt;br /&gt;
&lt;br /&gt;
Optimised H-H bond distance? 0.74&lt;br /&gt;
&lt;br /&gt;
=== Item Table ===&lt;br /&gt;
&lt;br /&gt;
&amp;lt;pre&amp;gt;&lt;br /&gt;
         Item               Value     Threshold  Converged?&lt;br /&gt;
 Maximum Force            0.000000     0.000450     YES&lt;br /&gt;
 RMS     Force            0.000000     0.000300     YES&lt;br /&gt;
 Maximum Displacement     0.000000     0.001800     YES&lt;br /&gt;
 RMS     Displacement     0.000001     0.001200     YES&lt;br /&gt;
 Predicted change in Energy=-1.164080D-13&amp;lt;/pre&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations ===&lt;br /&gt;
[[File:Tamim h2 disp.PNG|thumb|centre|463x463px]]&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations Table ===&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
!Wavenumber (cm-1)&lt;br /&gt;
|4466&lt;br /&gt;
|-&lt;br /&gt;
!Symmetry&lt;br /&gt;
|SGG&lt;br /&gt;
|-&lt;br /&gt;
!Intensity (a.u.)&lt;br /&gt;
|0&lt;br /&gt;
|-&lt;br /&gt;
!Images&lt;br /&gt;
|[[File:Tamim h2 vib.PNG|centre|thumb]]&lt;br /&gt;
|}&lt;br /&gt;
* How many modes do you expect from the 3N-6 rule? 0&lt;br /&gt;
* Which modes are &amp;quot;bending&amp;quot; vibrations and which are &amp;quot;bond stretch&amp;quot; vibrations? Only 1 bond stretching vibration &lt;br /&gt;
* Which mode is highly symmetric? 1&lt;br /&gt;
&lt;br /&gt;
=== Charge Distribution ===&lt;br /&gt;
[[File:Tamim h2 charge.PNG|centre|thumb|Charge distribution for H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;]]&lt;br /&gt;
The charges on both Hydrogen atoms are zero as they have the same electronegativity which means there is no dipole in the diatomic moleule.&lt;br /&gt;
&lt;br /&gt;
== Mono-metallic Transition Metal Complex ==&lt;br /&gt;
The transition metal complex chosen was (dinitrogen)-(2,6-bis(1-(2,6-diisopropylphenylimino)propyl)pyridine)-iron with the reference code &#039;&#039;&#039;BARTOF&#039;&#039;&#039;.&lt;br /&gt;
[[File:Tamim TM.PNG|centre|thumb]]&lt;br /&gt;
The bond length of N&amp;lt;sub&amp;gt;2 &amp;lt;/sub&amp;gt;in the molecule above is slightly higher than the bond length of N&amp;lt;sub&amp;gt;2 &amp;lt;/sub&amp;gt;that was calculated before (1.112 compared ot 1.1055). This is due to the lone pair of one nitrogen being donated to the central Iron atom which lowers the electron density on the nitrogen atom; this leads to less overlap of orbitals leading to a higher bond length.  &lt;br /&gt;
&lt;br /&gt;
Link to journal: https://pubs.acs.org/doi/10.1021/ic202750n&lt;br /&gt;
&lt;br /&gt;
== Haber-Bosch Process ==&lt;br /&gt;
* E(NH&amp;lt;sub&amp;gt;3&amp;lt;/sub&amp;gt;) = -56.55776873 &lt;br /&gt;
* 2*E(NH&amp;lt;sub&amp;gt;3&amp;lt;/sub&amp;gt;) = -113.11553746 &lt;br /&gt;
* E(N&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;) = -109.52412868 &lt;br /&gt;
* E(H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;) = -1.17853936 &lt;br /&gt;
* 3*E(H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;) = -3.53561808 &lt;br /&gt;
* ΔE=2*E(NH&amp;lt;sub&amp;gt;3&amp;lt;/sub&amp;gt;)-[E(N&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;)+3*E(H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;)] = -0.05579076&lt;br /&gt;
&lt;br /&gt;
The product ammonia is more stable than the gaseous reactants as it has a lower energy than the reactants. This means it is more stable as the forward reaction is exothermic. &lt;br /&gt;
&lt;br /&gt;
== Own Molecule - SH&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt; ==&lt;br /&gt;
What is the calculation method? RB3LYP&lt;br /&gt;
&lt;br /&gt;
What is the basis set? 6-31G(d,p)&lt;br /&gt;
&lt;br /&gt;
What is the final energy E(RB3LYP) in atomic units (au)? -399.39162414&lt;br /&gt;
&lt;br /&gt;
What is the RMS gradient? 0.00012068&lt;br /&gt;
&lt;br /&gt;
What is the point group of your molecule? C2V&lt;br /&gt;
&lt;br /&gt;
Bond angle of H-S-H? 92.681&lt;br /&gt;
&lt;br /&gt;
=== Item Table ===&lt;br /&gt;
&amp;lt;pre&amp;gt;&lt;br /&gt;
         Item               Value     Threshold  Converged?&amp;lt;br&amp;gt;&lt;br /&gt;
 Maximum Force            0.000175     0.000450     YES&amp;lt;br&amp;gt;&lt;br /&gt;
 RMS     Force            0.000145     0.000300     YES&amp;lt;br&amp;gt;&lt;br /&gt;
 Maximum Displacement     0.000386     0.001800     YES&amp;lt;br&amp;gt;&lt;br /&gt;
 RMS     Displacement     0.000386     0.001200     YES&amp;lt;/pre&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations ===&lt;br /&gt;
[[File:Tamim disp.PNG|centre|thumb]]&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations Table ===&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
!Wavenumber (cm&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;)&lt;br /&gt;
|1224&lt;br /&gt;
|2692&lt;br /&gt;
|2712&lt;br /&gt;
|-&lt;br /&gt;
!Symmetry&lt;br /&gt;
|A1&lt;br /&gt;
|A1&lt;br /&gt;
|B2&lt;br /&gt;
|-&lt;br /&gt;
!Intensity&lt;br /&gt;
|5&lt;br /&gt;
|7&lt;br /&gt;
|9&lt;br /&gt;
|-&lt;br /&gt;
!Images&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|}&lt;br /&gt;
* How many modes do you expect from the 3N-6 rule? 3&lt;br /&gt;
* Which modes are &amp;quot;bending&amp;quot; vibrations and which are &amp;quot;bond stretch&amp;quot; vibrations? 1 is a bending vibration while 2 and 3 are bond stretch vibrations.  &lt;br /&gt;
* Which mode is highly symmetric? 2&lt;br /&gt;
&lt;br /&gt;
=== Charge Distributions ===&lt;br /&gt;
[[File:Tamim chargesh2.PNG|centre|thumb|Charge distribution for SH&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;]]&lt;br /&gt;
The charge on Sulfur is slightly negative whereas the hydrogen atoms have a slightly positive charge. This is due to the difference in electronegativity, sulfur is more electronegative than hydrogen and therefore has a higher electron density to it leading to its slightly negative charge.&lt;br /&gt;
&lt;br /&gt;
=== Molecular Orbitals ===&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
|[[File:Tamim mo1.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim mo2.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim mo3.PNG|centre|thumb|209x209px]]&lt;br /&gt;
|[[File:Tamim mo4.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim mo5.PNG|centre|thumb|205x205px]]&lt;br /&gt;
|-&lt;br /&gt;
|Bonding molecular orbital between 3s electrons from sulfur and 1s electrons from the hydrogen. &lt;br /&gt;
|Non-bonding orbital consisting of the 2p orbital from the sulfur. &lt;br /&gt;
|Anti-bonding molecular orbital created between the 3p orbitals from sulfur and1 s orbitals from hydrogen. &lt;br /&gt;
|Bonding molecular orbital whihc is created due to the 3p orbital of sulfur and 1s orbital from the hydrogens. &lt;br /&gt;
|SP mixnig between the s and p orbitals of sulfur and also consists of molecular orbital being created between the p orbital of sulfur and s orbitals of hydrogen.&lt;br /&gt;
|}&lt;/div&gt;</summary>
		<author><name>Tr318</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=Rep:Mod:01574856&amp;diff=742449</id>
		<title>Rep:Mod:01574856</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=Rep:Mod:01574856&amp;diff=742449"/>
		<updated>2019-02-22T15:34:15Z</updated>

		<summary type="html">&lt;p&gt;Tr318: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;== NH&amp;lt;sub&amp;gt;3&amp;lt;/sub&amp;gt; Optimisation     ==&lt;br /&gt;
What is the calculation method? RB3LYP&lt;br /&gt;
&lt;br /&gt;
What is the basis set? 6-31G(d,p)&lt;br /&gt;
&lt;br /&gt;
What is the final energy E(RB3LYP) in atomic units (au)? -56.55776873&lt;br /&gt;
&lt;br /&gt;
What is the RMS gradient? 0.00000485&lt;br /&gt;
&lt;br /&gt;
What is the point group of your molecule? C3V&lt;br /&gt;
&lt;br /&gt;
optimised N-H bond distance and the optimised H-N-H bond angle? 1.02 &amp;amp; 106&lt;br /&gt;
&lt;br /&gt;
=== Item Table ===&lt;br /&gt;
&amp;lt;pre&amp;gt;&lt;br /&gt;
         Item               Value     Threshold  Converged?&lt;br /&gt;
 Maximum Force            0.000004     0.000450     YES&lt;br /&gt;
 RMS     Force            0.000004     0.000300     YES&lt;br /&gt;
 Maximum Displacement     0.000072     0.001800     YES&lt;br /&gt;
 RMS     Displacement     0.000035     0.001200     YES&lt;br /&gt;
 Predicted change in Energy=-5.986295D-10&lt;br /&gt;
&amp;lt;/pre&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Link to completed NH3 optimisation https://wiki.ch.ic.ac.uk/wiki/images/f/fe/TAMIM_RAHMAN_NH3_OPTIMISATION_POP.log&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations ===&lt;br /&gt;
[[File:Display_Vibrations.PNG|centre]]&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations Table ===&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
!Wavenumber (cm&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;)&lt;br /&gt;
|1090&lt;br /&gt;
|1694&lt;br /&gt;
|1694&lt;br /&gt;
|3461&lt;br /&gt;
|3590&lt;br /&gt;
|3590&lt;br /&gt;
|-&lt;br /&gt;
!Symmetry&lt;br /&gt;
|A1&lt;br /&gt;
|E&lt;br /&gt;
|E&lt;br /&gt;
|A1&lt;br /&gt;
|E&lt;br /&gt;
|E&lt;br /&gt;
|-&lt;br /&gt;
!Intensity (a.u.)&lt;br /&gt;
|145&lt;br /&gt;
|14&lt;br /&gt;
|14&lt;br /&gt;
|1&lt;br /&gt;
|0&lt;br /&gt;
|0&lt;br /&gt;
|-&lt;br /&gt;
!Images&lt;br /&gt;
|[[File:Tamim Vib 1.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim Vib 2.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim Vib 3.PNG|centre|thumb|212x212px]]&lt;br /&gt;
|[[File:Tamim Vib 4.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim Vib 5.PNG|centre|thumb|208x208px]]&lt;br /&gt;
|[[File:Tamim Vib 6.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|}&lt;br /&gt;
* How many modes do you expect from the 3N-6 rule? 6&lt;br /&gt;
* Which modes are degenerate (ie have the same energy)? 2&amp;amp;3 and 5&amp;amp;6&lt;br /&gt;
* Which modes are &amp;quot;bending&amp;quot; vibrations and which are &amp;quot;bond stretch&amp;quot; vibrations? 1,2 and 3 are bending vibrations while 4,5 and 6 are bond stretch vibrations. &lt;br /&gt;
* Which mode is highly symmetric? 4&lt;br /&gt;
* One mode is known as the &amp;quot;umbrella&amp;quot; mode, which one is this? 11&lt;br /&gt;
* How many bands would you expect to see in an experimental spectrum of gaseous ammonia? 3&lt;br /&gt;
&lt;br /&gt;
=== Charge Distribution ===&lt;br /&gt;
[[File:Tamim Charge Distribution.PNG|thumb|Charge Distribution of NH&amp;lt;sub&amp;gt;3&amp;lt;/sub&amp;gt;|centre]]&lt;br /&gt;
&lt;br /&gt;
The charge on nitrogen should be slightly negative whereas the hydrogen atoms will have a slightly positive charge. This is due to the difference in electronegativity, nitrogen is more electronegative than hydrogen and therefore has a higher electron density to it leading to its slightly negative charge.&lt;br /&gt;
&lt;br /&gt;
== N&amp;lt;sub&amp;gt;2 &amp;lt;/sub&amp;gt;Optimisation ==&lt;br /&gt;
What is the calculation method? RB3LYP&lt;br /&gt;
&lt;br /&gt;
What is the basis set? 6-31G(d,p)&lt;br /&gt;
&lt;br /&gt;
What is the final energy E(RB3LYP) in atomic units (au)? -109.52412868&lt;br /&gt;
&lt;br /&gt;
What is the RMS gradient? 0.00000060&lt;br /&gt;
&lt;br /&gt;
What is the point group of your molecule? D*H&lt;br /&gt;
&lt;br /&gt;
Optimised N-N bond distance? 1.11&lt;br /&gt;
&lt;br /&gt;
=== Item Table ===&lt;br /&gt;
 &lt;br /&gt;
&amp;lt;pre&amp;gt;&lt;br /&gt;
         Item              Value      Threshold  Converged?&lt;br /&gt;
 Maximum Force            0.000001     0.000450     YES&lt;br /&gt;
 RMS     Force            0.000001     0.000300     YES&lt;br /&gt;
 Maximum Displacement     0.000000     0.001800     YES&lt;br /&gt;
 RMS     Displacement     0.000000     0.001200     YES&lt;br /&gt;
 Predicted change in Energy=-3.400972D-13&lt;br /&gt;
&amp;lt;/pre&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
=== DIsplay Vibrations ===&lt;br /&gt;
[[File:Tamim N2 Disp.PNG|thumb|centre|464x464px]]&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations Table ===&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
!Wavenumber (cm&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;)&lt;br /&gt;
|2457           &lt;br /&gt;
|-&lt;br /&gt;
!Symmetry&lt;br /&gt;
|SGG&lt;br /&gt;
|-&lt;br /&gt;
!Intensity (a.u.)&lt;br /&gt;
|0&lt;br /&gt;
|-&lt;br /&gt;
!Images&lt;br /&gt;
|[[File:Tamim N2 vib.PNG|centre|thumb|250x250px]]&lt;br /&gt;
|}&lt;br /&gt;
* How many modes do you expect from the 3N-6 rule? 0&lt;br /&gt;
* Which modes are &amp;quot;bending&amp;quot; vibrations and which are &amp;quot;bond stretch&amp;quot; vibrations? Only 1 bond stretching vibration &lt;br /&gt;
* Which mode is highly symmetric? 1&lt;br /&gt;
&lt;br /&gt;
=== Charge Distribution ===&lt;br /&gt;
[[File:Tamim n2 charge.PNG|centre|thumb|Charge Distribution for N&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;]]&lt;br /&gt;
The charges on both Nitrogen atoms are zero as they have the same electronegativity which means there is no dipole in the diatomic moleule.&lt;br /&gt;
&lt;br /&gt;
== H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt; Optimisation ==&lt;br /&gt;
What is the calculation method? RB3LYP&lt;br /&gt;
&lt;br /&gt;
What is the basis set? 6-31G(d,p)&lt;br /&gt;
&lt;br /&gt;
What is the final energy E(RB3LYP) in atomic units (au)? -1.17853936&lt;br /&gt;
&lt;br /&gt;
What is the RMS gradient? 0.00000017&lt;br /&gt;
&lt;br /&gt;
What is the point group of your molecule? D*H&lt;br /&gt;
&lt;br /&gt;
Optimised H-H bond distance? 0.74&lt;br /&gt;
&lt;br /&gt;
=== Item Table ===&lt;br /&gt;
&lt;br /&gt;
&amp;lt;pre&amp;gt;&lt;br /&gt;
         Item               Value     Threshold  Converged?&lt;br /&gt;
 Maximum Force            0.000000     0.000450     YES&lt;br /&gt;
 RMS     Force            0.000000     0.000300     YES&lt;br /&gt;
 Maximum Displacement     0.000000     0.001800     YES&lt;br /&gt;
 RMS     Displacement     0.000001     0.001200     YES&lt;br /&gt;
 Predicted change in Energy=-1.164080D-13&amp;lt;/pre&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations ===&lt;br /&gt;
[[File:Tamim h2 disp.PNG|thumb|centre|463x463px]]&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations Table ===&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
!Wavenumber (cm-1)&lt;br /&gt;
|4466&lt;br /&gt;
|-&lt;br /&gt;
!Symmetry&lt;br /&gt;
|SGG&lt;br /&gt;
|-&lt;br /&gt;
!Intensity (a.u.)&lt;br /&gt;
|0&lt;br /&gt;
|-&lt;br /&gt;
!Images&lt;br /&gt;
|[[File:Tamim h2 vib.PNG|centre|thumb]]&lt;br /&gt;
|}&lt;br /&gt;
* How many modes do you expect from the 3N-6 rule? 0&lt;br /&gt;
* Which modes are &amp;quot;bending&amp;quot; vibrations and which are &amp;quot;bond stretch&amp;quot; vibrations? Only 1 bond stretching vibration &lt;br /&gt;
* Which mode is highly symmetric? 1&lt;br /&gt;
&lt;br /&gt;
=== Charge Distribution ===&lt;br /&gt;
[[File:Tamim h2 charge.PNG|centre|thumb|Charge distribution for H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;]]&lt;br /&gt;
The charges on both Hydrogen atoms are zero as they have the same electronegativity which means there is no dipole in the diatomic moleule.&lt;br /&gt;
&lt;br /&gt;
== Mono-metallic Transition Metal Complex ==&lt;br /&gt;
The transition metal complex chosen was (dinitrogen)-(2,6-bis(1-(2,6-diisopropylphenylimino)propyl)pyridine)-iron with the reference code &#039;&#039;&#039;BARTOF&#039;&#039;&#039;.&lt;br /&gt;
[[File:Tamim TM.PNG|centre|thumb]]&lt;br /&gt;
The bond length of N&amp;lt;sub&amp;gt;2 &amp;lt;/sub&amp;gt;in the molecule above is slightly higher than the bond length of N&amp;lt;sub&amp;gt;2 &amp;lt;/sub&amp;gt;that was calculated before (1.112 compared ot 1.1055). This is due to the lone pair of one nitrogen being donated to the central Iron atom which lowers the electron density on the nitrogen atom; this leads to less overlap of orbitals leading to a higher bond length.  &lt;br /&gt;
&lt;br /&gt;
Link to journal: https://pubs.acs.org/doi/10.1021/ic202750n&lt;br /&gt;
&lt;br /&gt;
== Haber-Bosch Process ==&lt;br /&gt;
* E(NH&amp;lt;sub&amp;gt;3&amp;lt;/sub&amp;gt;) = -56.55776873 &lt;br /&gt;
* 2*E(NH&amp;lt;sub&amp;gt;3&amp;lt;/sub&amp;gt;) = -113.11553746 &lt;br /&gt;
* E(N&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;) = -109.52412868 &lt;br /&gt;
* E(H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;) = -1.17853936 &lt;br /&gt;
* 3*E(H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;) = -3.53561808 &lt;br /&gt;
* ΔE=2*E(NH&amp;lt;sub&amp;gt;3&amp;lt;/sub&amp;gt;)-[E(N&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;)+3*E(H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;)] = -0.05579076&lt;br /&gt;
&lt;br /&gt;
The product ammonia is more stable than the gaseous reactants as it has a lower energy than the reactants. This means it is more stable as the forward reaction is exothermic. &lt;br /&gt;
&lt;br /&gt;
== Own Molecule - SH&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt; ==&lt;br /&gt;
What is the calculation method? RB3LYP&lt;br /&gt;
&lt;br /&gt;
What is the basis set? 6-31G(d,p)&lt;br /&gt;
&lt;br /&gt;
What is the final energy E(RB3LYP) in atomic units (au)? -399.39162414&lt;br /&gt;
&lt;br /&gt;
What is the RMS gradient? 0.00012068&lt;br /&gt;
&lt;br /&gt;
What is the point group of your molecule? C2V&lt;br /&gt;
&lt;br /&gt;
Bond angle of H-S-H? 92.681&lt;br /&gt;
&lt;br /&gt;
=== Item Table ===&lt;br /&gt;
&amp;lt;pre&amp;gt;&lt;br /&gt;
         Item               Value     Threshold  Converged?&amp;lt;br&amp;gt;&lt;br /&gt;
 Maximum Force            0.000175     0.000450     YES&amp;lt;br&amp;gt;&lt;br /&gt;
 RMS     Force            0.000145     0.000300     YES&amp;lt;br&amp;gt;&lt;br /&gt;
 Maximum Displacement     0.000386     0.001800     YES&amp;lt;br&amp;gt;&lt;br /&gt;
 RMS     Displacement     0.000386     0.001200     YES&amp;lt;/pre&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&amp;lt;jmol&amp;gt;&amp;lt;jmolApplet&amp;gt;&lt;br /&gt;
  &amp;lt;title&amp;gt;sh2_molecule&amp;lt;/title&amp;gt;&lt;br /&gt;
  &amp;lt;color&amp;gt;black&amp;lt;/color&amp;gt;&lt;br /&gt;
  &amp;lt;size&amp;gt;200&amp;lt;/size&amp;gt;&lt;br /&gt;
  &amp;lt;uploadedFileContents&amp;gt;TAMIM_SH2.LOG&amp;lt;/uploadedFileContents&amp;gt;&lt;br /&gt;
&amp;lt;/jmolApplet&amp;gt;&amp;lt;/jmol&amp;gt;&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations ===&lt;br /&gt;
[[File:Tamim disp.PNG|centre|thumb]]&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations Table ===&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
!Wavenumber (cm&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;)&lt;br /&gt;
|1224&lt;br /&gt;
|2692&lt;br /&gt;
|2712&lt;br /&gt;
|-&lt;br /&gt;
!Symmetry&lt;br /&gt;
|A1&lt;br /&gt;
|A1&lt;br /&gt;
|B2&lt;br /&gt;
|-&lt;br /&gt;
!Intensity&lt;br /&gt;
|5&lt;br /&gt;
|7&lt;br /&gt;
|9&lt;br /&gt;
|-&lt;br /&gt;
!Images&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|}&lt;br /&gt;
* How many modes do you expect from the 3N-6 rule? 3&lt;br /&gt;
* Which modes are &amp;quot;bending&amp;quot; vibrations and which are &amp;quot;bond stretch&amp;quot; vibrations? 1 is a bending vibration while 2 and 3 are bond stretch vibrations.  &lt;br /&gt;
* Which mode is highly symmetric? 2&lt;br /&gt;
&lt;br /&gt;
=== Charge Distributions ===&lt;br /&gt;
[[File:Tamim chargesh2.PNG|centre|thumb|Charge distribution for SH&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;]]&lt;br /&gt;
The charge on Sulfur is slightly negative whereas the hydrogen atoms have a slightly positive charge. This is due to the difference in electronegativity, sulfur is more electronegative than hydrogen and therefore has a higher electron density to it leading to its slightly negative charge.&lt;br /&gt;
&lt;br /&gt;
=== Molecular Orbitals ===&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
|[[File:Tamim mo1.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim mo2.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim mo3.PNG|centre|thumb|209x209px]]&lt;br /&gt;
|[[File:Tamim mo4.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim mo5.PNG|centre|thumb|205x205px]]&lt;br /&gt;
|-&lt;br /&gt;
|Bonding molecular orbital between 3s electrons from sulfur and 1s electrons from the hydrogen. &lt;br /&gt;
|Non-bonding orbital consisting of the 2p orbital from the sulfur. &lt;br /&gt;
|Anti-bonding molecular orbital created between the 3p orbitals from sulfur and1 s orbitals from hydrogen. &lt;br /&gt;
|Bonding molecular orbital whihc is created due to the 3p orbital of sulfur and 1s orbital from the hydrogens. &lt;br /&gt;
|SP mixnig between the s and p orbitals of sulfur and also consists of molecular orbital being created between the p orbital of sulfur and s orbitals of hydrogen.&lt;br /&gt;
|}&lt;/div&gt;</summary>
		<author><name>Tr318</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=Rep:Mod:01574856&amp;diff=742435</id>
		<title>Rep:Mod:01574856</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=Rep:Mod:01574856&amp;diff=742435"/>
		<updated>2019-02-22T15:31:14Z</updated>

		<summary type="html">&lt;p&gt;Tr318: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;== NH&amp;lt;sub&amp;gt;3&amp;lt;/sub&amp;gt; Optimisation     ==&lt;br /&gt;
What is the calculation method? RB3LYP&lt;br /&gt;
&lt;br /&gt;
What is the basis set? 6-31G(d,p)&lt;br /&gt;
&lt;br /&gt;
What is the final energy E(RB3LYP) in atomic units (au)? -56.55776873&lt;br /&gt;
&lt;br /&gt;
What is the RMS gradient? 0.00000485&lt;br /&gt;
&lt;br /&gt;
What is the point group of your molecule? C3V&lt;br /&gt;
&lt;br /&gt;
optimised N-H bond distance and the optimised H-N-H bond angle? 1.02 &amp;amp; 106&lt;br /&gt;
&lt;br /&gt;
=== Item Table ===&lt;br /&gt;
&amp;lt;pre&amp;gt;&lt;br /&gt;
         Item               Value     Threshold  Converged?&lt;br /&gt;
 Maximum Force            0.000004     0.000450     YES&lt;br /&gt;
 RMS     Force            0.000004     0.000300     YES&lt;br /&gt;
 Maximum Displacement     0.000072     0.001800     YES&lt;br /&gt;
 RMS     Displacement     0.000035     0.001200     YES&lt;br /&gt;
 Predicted change in Energy=-5.986295D-10&lt;br /&gt;
&amp;lt;/pre&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;jmol&amp;gt;&amp;lt;jmolApplet&amp;gt;&lt;br /&gt;
  &amp;lt;title&amp;gt;NH3_Molecule_01574856&amp;lt;/title&amp;gt;&lt;br /&gt;
  &amp;lt;color&amp;gt;black&amp;lt;/color&amp;gt;&lt;br /&gt;
  &amp;lt;size&amp;gt;200&amp;lt;/size&amp;gt;&lt;br /&gt;
  &amp;lt;uploadedFileContents&amp;gt;TAMIM_RAHMAN_NH3_OPTIMISATION_POP.log&amp;lt;/uploadedFileContents&amp;gt;&lt;br /&gt;
&amp;lt;/jmolApplet&amp;gt;&amp;lt;/jmol&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Link to completed NH3 optimisation https://wiki.ch.ic.ac.uk/wiki/images/f/fe/TAMIM_RAHMAN_NH3_OPTIMISATION_POP.log&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations ===&lt;br /&gt;
[[File:Display_Vibrations.PNG|centre]]&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations Table ===&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
!Wavenumber (cm&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;)&lt;br /&gt;
|1090&lt;br /&gt;
|1694&lt;br /&gt;
|1694&lt;br /&gt;
|3461&lt;br /&gt;
|3590&lt;br /&gt;
|3590&lt;br /&gt;
|-&lt;br /&gt;
!Symmetry&lt;br /&gt;
|A1&lt;br /&gt;
|E&lt;br /&gt;
|E&lt;br /&gt;
|A1&lt;br /&gt;
|E&lt;br /&gt;
|E&lt;br /&gt;
|-&lt;br /&gt;
!Intensity (a.u.)&lt;br /&gt;
|145&lt;br /&gt;
|14&lt;br /&gt;
|14&lt;br /&gt;
|1&lt;br /&gt;
|0&lt;br /&gt;
|0&lt;br /&gt;
|-&lt;br /&gt;
!Images&lt;br /&gt;
|[[File:Tamim Vib 1.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim Vib 2.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim Vib 3.PNG|centre|thumb|212x212px]]&lt;br /&gt;
|[[File:Tamim Vib 4.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim Vib 5.PNG|centre|thumb|208x208px]]&lt;br /&gt;
|[[File:Tamim Vib 6.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|}&lt;br /&gt;
* How many modes do you expect from the 3N-6 rule? 6&lt;br /&gt;
* Which modes are degenerate (ie have the same energy)? 2&amp;amp;3 and 5&amp;amp;6&lt;br /&gt;
* Which modes are &amp;quot;bending&amp;quot; vibrations and which are &amp;quot;bond stretch&amp;quot; vibrations? 1,2 and 3 are bending vibrations while 4,5 and 6 are bond stretch vibrations. &lt;br /&gt;
* Which mode is highly symmetric? 4&lt;br /&gt;
* One mode is known as the &amp;quot;umbrella&amp;quot; mode, which one is this? 11&lt;br /&gt;
* How many bands would you expect to see in an experimental spectrum of gaseous ammonia? 3&lt;br /&gt;
&lt;br /&gt;
=== Charge Distribution ===&lt;br /&gt;
[[File:Tamim Charge Distribution.PNG|thumb|Charge Distribution of NH&amp;lt;sub&amp;gt;3&amp;lt;/sub&amp;gt;|centre]]&lt;br /&gt;
&lt;br /&gt;
The charge on nitrogen should be slightly negative whereas the hydrogen atoms will have a slightly positive charge. This is due to the difference in electronegativity, nitrogen is more electronegative than hydrogen and therefore has a higher electron density to it leading to its slightly negative charge.&lt;br /&gt;
&lt;br /&gt;
== N&amp;lt;sub&amp;gt;2 &amp;lt;/sub&amp;gt;Optimisation ==&lt;br /&gt;
What is the calculation method? RB3LYP&lt;br /&gt;
&lt;br /&gt;
What is the basis set? 6-31G(d,p)&lt;br /&gt;
&lt;br /&gt;
What is the final energy E(RB3LYP) in atomic units (au)? -109.52412868&lt;br /&gt;
&lt;br /&gt;
What is the RMS gradient? 0.00000060&lt;br /&gt;
&lt;br /&gt;
What is the point group of your molecule? D*H&lt;br /&gt;
&lt;br /&gt;
Optimised N-N bond distance? 1.11&lt;br /&gt;
&lt;br /&gt;
=== Item Table ===&lt;br /&gt;
 &lt;br /&gt;
&amp;lt;pre&amp;gt;&lt;br /&gt;
         Item              Value      Threshold  Converged?&lt;br /&gt;
 Maximum Force            0.000001     0.000450     YES&lt;br /&gt;
 RMS     Force            0.000001     0.000300     YES&lt;br /&gt;
 Maximum Displacement     0.000000     0.001800     YES&lt;br /&gt;
 RMS     Displacement     0.000000     0.001200     YES&lt;br /&gt;
 Predicted change in Energy=-3.400972D-13&lt;br /&gt;
&amp;lt;/pre&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;jmol&amp;gt;&amp;lt;jmolApplet&amp;gt;&lt;br /&gt;
  &amp;lt;title&amp;gt;N2_molecule&amp;lt;/title&amp;gt;&lt;br /&gt;
  &amp;lt;color&amp;gt;black&amp;lt;/color&amp;gt;&lt;br /&gt;
  &amp;lt;size&amp;gt;200&amp;lt;/size&amp;gt;&lt;br /&gt;
  &amp;lt;uploadedFileContents&amp;gt;TAMIM_N2_1.LOG&amp;lt;/uploadedFileContents&amp;gt;&lt;br /&gt;
&amp;lt;/jmolApplet&amp;gt;&amp;lt;/jmol&amp;gt;&lt;br /&gt;
&lt;br /&gt;
=== DIsplay Vibrations ===&lt;br /&gt;
[[File:Tamim N2 Disp.PNG|thumb|centre|464x464px]]&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations Table ===&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
!Wavenumber (cm&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;)&lt;br /&gt;
|2457           &lt;br /&gt;
|-&lt;br /&gt;
!Symmetry&lt;br /&gt;
|SGG&lt;br /&gt;
|-&lt;br /&gt;
!Intensity (a.u.)&lt;br /&gt;
|0&lt;br /&gt;
|-&lt;br /&gt;
!Images&lt;br /&gt;
|[[File:Tamim N2 vib.PNG|centre|thumb|250x250px]]&lt;br /&gt;
|}&lt;br /&gt;
* How many modes do you expect from the 3N-6 rule? 0&lt;br /&gt;
* Which modes are &amp;quot;bending&amp;quot; vibrations and which are &amp;quot;bond stretch&amp;quot; vibrations? Only 1 bond stretching vibration &lt;br /&gt;
* Which mode is highly symmetric? 1&lt;br /&gt;
&lt;br /&gt;
=== Charge Distribution ===&lt;br /&gt;
[[File:Tamim n2 charge.PNG|centre|thumb|Charge Distribution for N&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;]]&lt;br /&gt;
The charges on both Nitrogen atoms are zero as they have the same electronegativity which means there is no dipole in the diatomic moleule.&lt;br /&gt;
&lt;br /&gt;
== H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt; Optimisation ==&lt;br /&gt;
What is the calculation method? RB3LYP&lt;br /&gt;
&lt;br /&gt;
What is the basis set? 6-31G(d,p)&lt;br /&gt;
&lt;br /&gt;
What is the final energy E(RB3LYP) in atomic units (au)? -1.17853936&lt;br /&gt;
&lt;br /&gt;
What is the RMS gradient? 0.00000017&lt;br /&gt;
&lt;br /&gt;
What is the point group of your molecule? D*H&lt;br /&gt;
&lt;br /&gt;
Optimised H-H bond distance? 0.74&lt;br /&gt;
&lt;br /&gt;
=== Item Table ===&lt;br /&gt;
&lt;br /&gt;
&amp;lt;pre&amp;gt;&lt;br /&gt;
         Item               Value     Threshold  Converged?&lt;br /&gt;
 Maximum Force            0.000000     0.000450     YES&lt;br /&gt;
 RMS     Force            0.000000     0.000300     YES&lt;br /&gt;
 Maximum Displacement     0.000000     0.001800     YES&lt;br /&gt;
 RMS     Displacement     0.000001     0.001200     YES&lt;br /&gt;
 Predicted change in Energy=-1.164080D-13&amp;lt;/pre&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;jmol&amp;gt;&amp;lt;jmolApplet&amp;gt;&lt;br /&gt;
  &amp;lt;title&amp;gt;h2_molecule&amp;lt;/title&amp;gt;&lt;br /&gt;
  &amp;lt;color&amp;gt;black&amp;lt;/color&amp;gt;&lt;br /&gt;
  &amp;lt;size&amp;gt;200&amp;lt;/size&amp;gt;&lt;br /&gt;
  &amp;lt;uploadedFileContents&amp;gt;TAMIM_H2_1.LOG&amp;lt;/uploadedFileContents&amp;gt;&lt;br /&gt;
&amp;lt;/jmolApplet&amp;gt;&amp;lt;/jmol&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations ===&lt;br /&gt;
[[File:Tamim h2 disp.PNG|thumb|centre|463x463px]]&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations Table ===&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
!Wavenumber (cm-1)&lt;br /&gt;
|4466&lt;br /&gt;
|-&lt;br /&gt;
!Symmetry&lt;br /&gt;
|SGG&lt;br /&gt;
|-&lt;br /&gt;
!Intensity (a.u.)&lt;br /&gt;
|0&lt;br /&gt;
|-&lt;br /&gt;
!Images&lt;br /&gt;
|[[File:Tamim h2 vib.PNG|centre|thumb]]&lt;br /&gt;
|}&lt;br /&gt;
* How many modes do you expect from the 3N-6 rule? 0&lt;br /&gt;
* Which modes are &amp;quot;bending&amp;quot; vibrations and which are &amp;quot;bond stretch&amp;quot; vibrations? Only 1 bond stretching vibration &lt;br /&gt;
* Which mode is highly symmetric? 1&lt;br /&gt;
&lt;br /&gt;
=== Charge Distribution ===&lt;br /&gt;
[[File:Tamim h2 charge.PNG|centre|thumb|Charge distribution for H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;]]&lt;br /&gt;
The charges on both Hydrogen atoms are zero as they have the same electronegativity which means there is no dipole in the diatomic moleule.&lt;br /&gt;
&lt;br /&gt;
== Mono-metallic Transition Metal Complex ==&lt;br /&gt;
The transition metal complex chosen was (dinitrogen)-(2,6-bis(1-(2,6-diisopropylphenylimino)propyl)pyridine)-iron with the reference code &#039;&#039;&#039;BARTOF&#039;&#039;&#039;.&lt;br /&gt;
[[File:Tamim TM.PNG|centre|thumb]]&lt;br /&gt;
The bond length of N&amp;lt;sub&amp;gt;2 &amp;lt;/sub&amp;gt;in the molecule above is slightly higher than the bond length of N&amp;lt;sub&amp;gt;2 &amp;lt;/sub&amp;gt;that was calculated before (1.112 compared ot 1.1055). This is due to the lone pair of one nitrogen being donated to the central Iron atom which lowers the electron density on the nitrogen atom; this leads to less overlap of orbitals leading to a higher bond length.  &lt;br /&gt;
&lt;br /&gt;
Link to journal: https://pubs.acs.org/doi/10.1021/ic202750n&lt;br /&gt;
&lt;br /&gt;
== Haber-Bosch Process ==&lt;br /&gt;
* E(NH&amp;lt;sub&amp;gt;3&amp;lt;/sub&amp;gt;) = -56.55776873 &lt;br /&gt;
* 2*E(NH&amp;lt;sub&amp;gt;3&amp;lt;/sub&amp;gt;) = -113.11553746 &lt;br /&gt;
* E(N&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;) = -109.52412868 &lt;br /&gt;
* E(H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;) = -1.17853936 &lt;br /&gt;
* 3*E(H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;) = -3.53561808 &lt;br /&gt;
* ΔE=2*E(NH&amp;lt;sub&amp;gt;3&amp;lt;/sub&amp;gt;)-[E(N&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;)+3*E(H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;)] = -0.05579076&lt;br /&gt;
&lt;br /&gt;
The product ammonia is more stable than the gaseous reactants as it has a lower energy than the reactants. This means it is more stable as the forward reaction is exothermic. &lt;br /&gt;
&lt;br /&gt;
== Own Molecule - SH&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt; ==&lt;br /&gt;
What is the calculation method? RB3LYP&lt;br /&gt;
&lt;br /&gt;
What is the basis set? 6-31G(d,p)&lt;br /&gt;
&lt;br /&gt;
What is the final energy E(RB3LYP) in atomic units (au)? -399.39162414&lt;br /&gt;
&lt;br /&gt;
What is the RMS gradient? 0.00012068&lt;br /&gt;
&lt;br /&gt;
What is the point group of your molecule? C2V&lt;br /&gt;
&lt;br /&gt;
Bond angle of H-S-H? 92.681&lt;br /&gt;
&lt;br /&gt;
=== Item Table ===&lt;br /&gt;
&amp;lt;pre&amp;gt;&lt;br /&gt;
         Item               Value     Threshold  Converged?&amp;lt;br&amp;gt;&lt;br /&gt;
 Maximum Force            0.000175     0.000450     YES&amp;lt;br&amp;gt;&lt;br /&gt;
 RMS     Force            0.000145     0.000300     YES&amp;lt;br&amp;gt;&lt;br /&gt;
 Maximum Displacement     0.000386     0.001800     YES&amp;lt;br&amp;gt;&lt;br /&gt;
 RMS     Displacement     0.000386     0.001200     YES&amp;lt;/pre&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&amp;lt;jmol&amp;gt;&amp;lt;jmolApplet&amp;gt;&lt;br /&gt;
  &amp;lt;title&amp;gt;sh2_molecule&amp;lt;/title&amp;gt;&lt;br /&gt;
  &amp;lt;color&amp;gt;black&amp;lt;/color&amp;gt;&lt;br /&gt;
  &amp;lt;size&amp;gt;200&amp;lt;/size&amp;gt;&lt;br /&gt;
  &amp;lt;uploadedFileContents&amp;gt;TAMIM_SH2.LOG&amp;lt;/uploadedFileContents&amp;gt;&lt;br /&gt;
&amp;lt;/jmolApplet&amp;gt;&amp;lt;/jmol&amp;gt;&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations ===&lt;br /&gt;
[[File:Tamim disp.PNG|centre|thumb]]&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations Table ===&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
!Wavenumber (cm&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;)&lt;br /&gt;
|1224&lt;br /&gt;
|2692&lt;br /&gt;
|2712&lt;br /&gt;
|-&lt;br /&gt;
!Symmetry&lt;br /&gt;
|A1&lt;br /&gt;
|A1&lt;br /&gt;
|B2&lt;br /&gt;
|-&lt;br /&gt;
!Intensity&lt;br /&gt;
|5&lt;br /&gt;
|7&lt;br /&gt;
|9&lt;br /&gt;
|-&lt;br /&gt;
!Images&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|}&lt;br /&gt;
* How many modes do you expect from the 3N-6 rule? 3&lt;br /&gt;
* Which modes are &amp;quot;bending&amp;quot; vibrations and which are &amp;quot;bond stretch&amp;quot; vibrations? 1 is a bending vibration while 2 and 3 are bond stretch vibrations.  &lt;br /&gt;
* Which mode is highly symmetric? 2&lt;br /&gt;
&lt;br /&gt;
=== Charge Distributions ===&lt;br /&gt;
[[File:Tamim chargesh2.PNG|centre|thumb|Charge distribution for SH&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;]]&lt;br /&gt;
The charge on Sulfur is slightly negative whereas the hydrogen atoms have a slightly positive charge. This is due to the difference in electronegativity, sulfur is more electronegative than hydrogen and therefore has a higher electron density to it leading to its slightly negative charge.&lt;br /&gt;
&lt;br /&gt;
=== Molecular Orbitals ===&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
|[[File:Tamim mo1.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim mo2.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim mo3.PNG|centre|thumb|209x209px]]&lt;br /&gt;
|[[File:Tamim mo4.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim mo5.PNG|centre|thumb|205x205px]]&lt;br /&gt;
|-&lt;br /&gt;
|Bonding molecular orbital between 3s electrons from sulfur and 1s electrons from the hydrogen. &lt;br /&gt;
|Non-bonding orbital consisting of the 2p orbital from the sulfur. &lt;br /&gt;
|Anti-bonding molecular orbital created between the 3p orbitals from sulfur and1 s orbitals from hydrogen. &lt;br /&gt;
|Bonding molecular orbital whihc is created due to the 3p orbital of sulfur and 1s orbital from the hydrogens. &lt;br /&gt;
|SP mixnig between the s and p orbitals of sulfur and also consists of molecular orbital being created between the p orbital of sulfur and s orbitals of hydrogen.&lt;br /&gt;
|}&lt;/div&gt;</summary>
		<author><name>Tr318</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=Rep:Mod:01574856&amp;diff=742432</id>
		<title>Rep:Mod:01574856</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=Rep:Mod:01574856&amp;diff=742432"/>
		<updated>2019-02-22T15:29:47Z</updated>

		<summary type="html">&lt;p&gt;Tr318: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;== NH&amp;lt;sub&amp;gt;3&amp;lt;/sub&amp;gt; Optimisation     ==&lt;br /&gt;
What is the calculation method? RB3LYP&lt;br /&gt;
&lt;br /&gt;
What is the basis set? 6-31G(d,p)&lt;br /&gt;
&lt;br /&gt;
What is the final energy E(RB3LYP) in atomic units (au)? -56.55776873&lt;br /&gt;
&lt;br /&gt;
What is the RMS gradient? 0.00000485&lt;br /&gt;
&lt;br /&gt;
What is the point group of your molecule? C3V&lt;br /&gt;
&lt;br /&gt;
optimised N-H bond distance and the optimised H-N-H bond angle? 1.02 &amp;amp; 106&lt;br /&gt;
&lt;br /&gt;
=== Item Table ===&lt;br /&gt;
&amp;lt;pre&amp;gt;&lt;br /&gt;
         Item               Value     Threshold  Converged?&lt;br /&gt;
 Maximum Force            0.000004     0.000450     YES&lt;br /&gt;
 RMS     Force            0.000004     0.000300     YES&lt;br /&gt;
 Maximum Displacement     0.000072     0.001800     YES&lt;br /&gt;
 RMS     Displacement     0.000035     0.001200     YES&lt;br /&gt;
 Predicted change in Energy=-5.986295D-10&lt;br /&gt;
&amp;lt;/pre&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;jmol&amp;gt;&amp;lt;jmolApplet&amp;gt;&lt;br /&gt;
  &amp;lt;title&amp;gt;NH3_Molecule_01574856&amp;lt;/title&amp;gt;&lt;br /&gt;
  &amp;lt;color&amp;gt;black&amp;lt;/color&amp;gt;&lt;br /&gt;
  &amp;lt;size&amp;gt;200&amp;lt;/size&amp;gt;&lt;br /&gt;
  &amp;lt;uploadedFileContents&amp;gt;TAMIM_RAHMAN_NH3_OPTIMISATION_POP.log&amp;lt;/uploadedFileContents&amp;gt;&lt;br /&gt;
&amp;lt;/jmolApplet&amp;gt;&amp;lt;/jmol&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Link to completed NH3 optimisation https://wiki.ch.ic.ac.uk/wiki/images/f/fe/TAMIM_RAHMAN_NH3_OPTIMISATION_POP.log&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations ===&lt;br /&gt;
[[File:Display_Vibrations.PNG|centre]]&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations Table ===&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
!Wavenumber (cm&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;)&lt;br /&gt;
|1090&lt;br /&gt;
|1694&lt;br /&gt;
|1694&lt;br /&gt;
|3461&lt;br /&gt;
|3590&lt;br /&gt;
|3590&lt;br /&gt;
|-&lt;br /&gt;
!Symmetry&lt;br /&gt;
|A1&lt;br /&gt;
|E&lt;br /&gt;
|E&lt;br /&gt;
|A1&lt;br /&gt;
|E&lt;br /&gt;
|E&lt;br /&gt;
|-&lt;br /&gt;
!Intensity (a.u.)&lt;br /&gt;
|145&lt;br /&gt;
|14&lt;br /&gt;
|14&lt;br /&gt;
|1&lt;br /&gt;
|0&lt;br /&gt;
|0&lt;br /&gt;
|-&lt;br /&gt;
!Images&lt;br /&gt;
|[[File:Tamim Vib 1.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim Vib 2.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim Vib 3.PNG|centre|thumb|212x212px]]&lt;br /&gt;
|[[File:Tamim Vib 4.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim Vib 5.PNG|centre|thumb|208x208px]]&lt;br /&gt;
|[[File:Tamim Vib 6.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|}&lt;br /&gt;
* How many modes do you expect from the 3N-6 rule? 6&lt;br /&gt;
* Which modes are degenerate (ie have the same energy)? 2&amp;amp;3 and 5&amp;amp;6&lt;br /&gt;
* Which modes are &amp;quot;bending&amp;quot; vibrations and which are &amp;quot;bond stretch&amp;quot; vibrations? 1,2 and 3 are bending vibrations while 4,5 and 6 are bond stretch vibrations. &lt;br /&gt;
* Which mode is highly symmetric? 4&lt;br /&gt;
* One mode is known as the &amp;quot;umbrella&amp;quot; mode, which one is this? 11&lt;br /&gt;
* How many bands would you expect to see in an experimental spectrum of gaseous ammonia? 3&lt;br /&gt;
&lt;br /&gt;
=== Charge Distribution ===&lt;br /&gt;
[[File:Tamim Charge Distribution.PNG|thumb|Charge Distribution of NH&amp;lt;sub&amp;gt;3&amp;lt;/sub&amp;gt;|centre]]&lt;br /&gt;
&lt;br /&gt;
The charge on nitrogen should be slightly negative whereas the hydrogen atoms will have a slightly positive charge. This is due to the difference in electronegativity, nitrogen is more electronegative than hydrogen and therefore has a higher electron density to it leading to its slightly negative charge.&lt;br /&gt;
&lt;br /&gt;
== N&amp;lt;sub&amp;gt;2 &amp;lt;/sub&amp;gt;Optimisation ==&lt;br /&gt;
What is the calculation method? RB3LYP&lt;br /&gt;
&lt;br /&gt;
What is the basis set? 6-31G(d,p)&lt;br /&gt;
&lt;br /&gt;
What is the final energy E(RB3LYP) in atomic units (au)? -109.52412868&lt;br /&gt;
&lt;br /&gt;
What is the RMS gradient? 0.00000060&lt;br /&gt;
&lt;br /&gt;
What is the point group of your molecule? D*H&lt;br /&gt;
&lt;br /&gt;
Optimised N-N bond distance? 1.11&lt;br /&gt;
&lt;br /&gt;
=== Item Table ===&lt;br /&gt;
 &lt;br /&gt;
&amp;lt;pre&amp;gt;&lt;br /&gt;
         Item              Value      Threshold  Converged?&lt;br /&gt;
 Maximum Force            0.000001     0.000450     YES&lt;br /&gt;
 RMS     Force            0.000001     0.000300     YES&lt;br /&gt;
 Maximum Displacement     0.000000     0.001800     YES&lt;br /&gt;
 RMS     Displacement     0.000000     0.001200     YES&lt;br /&gt;
 Predicted change in Energy=-3.400972D-13&lt;br /&gt;
&amp;lt;/pre&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;jmol&amp;gt;&amp;lt;jmolApplet&amp;gt;&lt;br /&gt;
  &amp;lt;title&amp;gt;N2_molecule&amp;lt;/title&amp;gt;&lt;br /&gt;
  &amp;lt;color&amp;gt;black&amp;lt;/color&amp;gt;&lt;br /&gt;
  &amp;lt;size&amp;gt;200&amp;lt;/size&amp;gt;&lt;br /&gt;
  &amp;lt;uploadedFileContents&amp;gt;TAMIM_N2_1.LOG&amp;lt;/uploadedFileContents&amp;gt;&lt;br /&gt;
&amp;lt;/jmolApplet&amp;gt;&amp;lt;/jmol&amp;gt;&lt;br /&gt;
&lt;br /&gt;
=== DIsplay Vibrations ===&lt;br /&gt;
[[File:Tamim N2 Disp.PNG|thumb|centre|464x464px]]&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations Table ===&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
!Wavenumber (cm&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;)&lt;br /&gt;
|2457           &lt;br /&gt;
|-&lt;br /&gt;
!Symmetry&lt;br /&gt;
|SGG&lt;br /&gt;
|-&lt;br /&gt;
!Intensity (a.u.)&lt;br /&gt;
|0&lt;br /&gt;
|-&lt;br /&gt;
!Images&lt;br /&gt;
|[[File:Tamim N2 vib.PNG|centre|thumb|250x250px]]&lt;br /&gt;
|}&lt;br /&gt;
* How many modes do you expect from the 3N-6 rule? 0&lt;br /&gt;
* Which modes are &amp;quot;bending&amp;quot; vibrations and which are &amp;quot;bond stretch&amp;quot; vibrations? Only 1 bond stretching vibration &lt;br /&gt;
* Which mode is highly symmetric? 1&lt;br /&gt;
&lt;br /&gt;
=== Charge Distribution ===&lt;br /&gt;
[[File:Tamim n2 charge.PNG|centre|thumb|Charge Distribution for N&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;]]&lt;br /&gt;
The charges on both Nitrogen atoms are zero as they have the same electronegativity which means there is no dipole in the diatomic moleule.&lt;br /&gt;
&lt;br /&gt;
== H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt; Optimisation ==&lt;br /&gt;
What is the calculation method? RB3LYP&lt;br /&gt;
&lt;br /&gt;
What is the basis set? 6-31G(d,p)&lt;br /&gt;
&lt;br /&gt;
What is the final energy E(RB3LYP) in atomic units (au)? -1.17853936&lt;br /&gt;
&lt;br /&gt;
What is the RMS gradient? 0.00000017&lt;br /&gt;
&lt;br /&gt;
What is the point group of your molecule? D*H&lt;br /&gt;
&lt;br /&gt;
Optimised H-H bond distance? 0.74&lt;br /&gt;
&lt;br /&gt;
=== Item Table ===&lt;br /&gt;
&lt;br /&gt;
&amp;lt;pre&amp;gt;&lt;br /&gt;
         Item               Value     Threshold  Converged?&lt;br /&gt;
 Maximum Force            0.000000     0.000450     YES&lt;br /&gt;
 RMS     Force            0.000000     0.000300     YES&lt;br /&gt;
 Maximum Displacement     0.000000     0.001800     YES&lt;br /&gt;
 RMS     Displacement     0.000001     0.001200     YES&lt;br /&gt;
 Predicted change in Energy=-1.164080D-13&amp;lt;/pre&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;jmol&amp;gt;&amp;lt;jmolApplet&amp;gt;&lt;br /&gt;
  &amp;lt;title&amp;gt;h2_molecule&amp;lt;/title&amp;gt;&lt;br /&gt;
  &amp;lt;color&amp;gt;black&amp;lt;/color&amp;gt;&lt;br /&gt;
  &amp;lt;size&amp;gt;200&amp;lt;/size&amp;gt;&lt;br /&gt;
  &amp;lt;uploadedFileContents&amp;gt;TAMIM_H2_1.LOG&amp;lt;/uploadedFileContents&amp;gt;&lt;br /&gt;
&amp;lt;/jmolApplet&amp;gt;&amp;lt;/jmol&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations ===&lt;br /&gt;
[[File:Tamim h2 disp.PNG|thumb|centre|463x463px]]&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations Table ===&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
!Wavenumber (cm-1)&lt;br /&gt;
|4466&lt;br /&gt;
|-&lt;br /&gt;
!Symmetry&lt;br /&gt;
|SGG&lt;br /&gt;
|-&lt;br /&gt;
!Intensity (a.u.)&lt;br /&gt;
|0&lt;br /&gt;
|-&lt;br /&gt;
!Images&lt;br /&gt;
|[[File:Tamim h2 vib.PNG|centre|thumb]]&lt;br /&gt;
|}&lt;br /&gt;
* How many modes do you expect from the 3N-6 rule? 0&lt;br /&gt;
* Which modes are &amp;quot;bending&amp;quot; vibrations and which are &amp;quot;bond stretch&amp;quot; vibrations? Only 1 bond stretching vibration &lt;br /&gt;
* Which mode is highly symmetric? 1&lt;br /&gt;
&lt;br /&gt;
=== Charge Distribution ===&lt;br /&gt;
[[File:Tamim h2 charge.PNG|centre|thumb|Charge distribution for H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;]]&lt;br /&gt;
The charges on both Hydrogen atoms are zero as they have the same electronegativity which means there is no dipole in the diatomic moleule.&lt;br /&gt;
&lt;br /&gt;
== Mono-metallic Transition Metal Complex ==&lt;br /&gt;
The transition metal complex chosen was (dinitrogen)-(2,6-bis(1-(2,6-diisopropylphenylimino)propyl)pyridine)-iron with the reference code &#039;&#039;&#039;BARTOF&#039;&#039;&#039;.&lt;br /&gt;
[[File:Tamim TM.PNG|centre|thumb]]&lt;br /&gt;
The bond length of N&amp;lt;sub&amp;gt;2 &amp;lt;/sub&amp;gt;in the molecule above is slightly higher than the bond length of N&amp;lt;sub&amp;gt;2 &amp;lt;/sub&amp;gt;that was calculated before (1.112 compared ot 1.1055). This is due to the lone pair of one nitrogen being donated to the central Iron atom which lowers the electron density on the nitrogen atom; this leads to less overlap of orbitals leading to a higher bond length.  &lt;br /&gt;
&lt;br /&gt;
Link to journal: https://pubs.acs.org/doi/10.1021/ic202750n&lt;br /&gt;
&lt;br /&gt;
== Haber-Bosch Process ==&lt;br /&gt;
* E(NH&amp;lt;sub&amp;gt;3&amp;lt;/sub&amp;gt;) = -56.55776873 &lt;br /&gt;
* 2*E(NH&amp;lt;sub&amp;gt;3&amp;lt;/sub&amp;gt;) = -113.11553746 &lt;br /&gt;
* E(N&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;) = -109.52412868 &lt;br /&gt;
* E(H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;) = -1.17853936 &lt;br /&gt;
* 3*E(H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;) = -3.53561808 &lt;br /&gt;
* ΔE=2*E(NH&amp;lt;sub&amp;gt;3&amp;lt;/sub&amp;gt;)-[E(N&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;)+3*E(H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;)] = -0.05579076&lt;br /&gt;
&lt;br /&gt;
The product ammonia is more stable than the gaseous reactants as it has a lower energy than the reactants. This means it is more stable as the forward reaction is exothermic. &lt;br /&gt;
&lt;br /&gt;
== Own Molecule - SH&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt; ==&lt;br /&gt;
What is the calculation method? RB3LYP&lt;br /&gt;
&lt;br /&gt;
What is the basis set? 6-31G(d,p)&lt;br /&gt;
&lt;br /&gt;
What is the final energy E(RB3LYP) in atomic units (au)? -399.39162414&lt;br /&gt;
&lt;br /&gt;
What is the RMS gradient? 0.00012068&lt;br /&gt;
&lt;br /&gt;
What is the point group of your molecule? C2V&lt;br /&gt;
&lt;br /&gt;
Bond angle of H-S-H? 92.681&lt;br /&gt;
&lt;br /&gt;
=== Item Table ===&lt;br /&gt;
&amp;lt;pre&amp;gt;&lt;br /&gt;
         Item               Value     Threshold  Converged?&amp;lt;br&amp;gt;&lt;br /&gt;
 Maximum Force            0.000175     0.000450     YES&amp;lt;br&amp;gt;&lt;br /&gt;
 RMS     Force            0.000145     0.000300     YES&amp;lt;br&amp;gt;&lt;br /&gt;
 Maximum Displacement     0.000386     0.001800     YES&amp;lt;br&amp;gt;&lt;br /&gt;
 RMS     Displacement     0.000386     0.001200     YES&amp;lt;/pre&amp;gt;&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations ===&lt;br /&gt;
[[File:Tamim disp.PNG|centre|thumb]]&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations Table ===&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
!Wavenumber (cm&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;)&lt;br /&gt;
|1224&lt;br /&gt;
|2692&lt;br /&gt;
|2712&lt;br /&gt;
|-&lt;br /&gt;
!Symmetry&lt;br /&gt;
|A1&lt;br /&gt;
|A1&lt;br /&gt;
|B2&lt;br /&gt;
|-&lt;br /&gt;
!Intensity&lt;br /&gt;
|5&lt;br /&gt;
|7&lt;br /&gt;
|9&lt;br /&gt;
|-&lt;br /&gt;
!Images&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|}&lt;br /&gt;
* How many modes do you expect from the 3N-6 rule? 3&lt;br /&gt;
* Which modes are &amp;quot;bending&amp;quot; vibrations and which are &amp;quot;bond stretch&amp;quot; vibrations? 1 is a bending vibration while 2 and 3 are bond stretch vibrations.  &lt;br /&gt;
* Which mode is highly symmetric? 2&lt;br /&gt;
&lt;br /&gt;
=== Charge Distributions ===&lt;br /&gt;
[[File:Tamim chargesh2.PNG|centre|thumb|Charge distribution for SH&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;]]&lt;br /&gt;
The charge on Sulfur is slightly negative whereas the hydrogen atoms have a slightly positive charge. This is due to the difference in electronegativity, sulfur is more electronegative than hydrogen and therefore has a higher electron density to it leading to its slightly negative charge.&lt;br /&gt;
&lt;br /&gt;
=== Molecular Orbitals ===&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
|[[File:Tamim mo1.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim mo2.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim mo3.PNG|centre|thumb|209x209px]]&lt;br /&gt;
|[[File:Tamim mo4.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim mo5.PNG|centre|thumb|205x205px]]&lt;br /&gt;
|-&lt;br /&gt;
|Bonding molecular orbital between 3s electrons from sulfur and 1s electrons from the hydrogen. &lt;br /&gt;
|Non-bonding orbital consisting of the 2p orbital from the sulfur. &lt;br /&gt;
|Anti-bonding molecular orbital created between the 3p orbitals from sulfur and1 s orbitals from hydrogen. &lt;br /&gt;
|Bonding molecular orbital whihc is created due to the 3p orbital of sulfur and 1s orbital from the hydrogens. &lt;br /&gt;
|SP mixnig between the s and p orbitals of sulfur and also consists of molecular orbital being created between the p orbital of sulfur and s orbitals of hydrogen.&lt;br /&gt;
|}&lt;/div&gt;</summary>
		<author><name>Tr318</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=Rep:Mod:01574856&amp;diff=742425</id>
		<title>Rep:Mod:01574856</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=Rep:Mod:01574856&amp;diff=742425"/>
		<updated>2019-02-22T15:27:14Z</updated>

		<summary type="html">&lt;p&gt;Tr318: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;== NH&amp;lt;sub&amp;gt;3&amp;lt;/sub&amp;gt; Optimisation     ==&lt;br /&gt;
What is the calculation method? RB3LYP&lt;br /&gt;
&lt;br /&gt;
What is the basis set? 6-31G(d,p)&lt;br /&gt;
&lt;br /&gt;
What is the final energy E(RB3LYP) in atomic units (au)? -56.55776873&lt;br /&gt;
&lt;br /&gt;
What is the RMS gradient? 0.00000485&lt;br /&gt;
&lt;br /&gt;
What is the point group of your molecule? C3V&lt;br /&gt;
&lt;br /&gt;
optimised N-H bond distance and the optimised H-N-H bond angle? 1.02 &amp;amp; 106&lt;br /&gt;
&lt;br /&gt;
=== Item Table ===&lt;br /&gt;
&amp;lt;pre&amp;gt;&lt;br /&gt;
         Item               Value     Threshold  Converged?&lt;br /&gt;
 Maximum Force            0.000004     0.000450     YES&lt;br /&gt;
 RMS     Force            0.000004     0.000300     YES&lt;br /&gt;
 Maximum Displacement     0.000072     0.001800     YES&lt;br /&gt;
 RMS     Displacement     0.000035     0.001200     YES&lt;br /&gt;
 Predicted change in Energy=-5.986295D-10&lt;br /&gt;
&amp;lt;/pre&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;jmol&amp;gt;&amp;lt;jmolApplet&amp;gt;&lt;br /&gt;
  &amp;lt;title&amp;gt;NH3_Molecule_01574856&amp;lt;/title&amp;gt;&lt;br /&gt;
  &amp;lt;color&amp;gt;black&amp;lt;/color&amp;gt;&lt;br /&gt;
  &amp;lt;size&amp;gt;200&amp;lt;/size&amp;gt;&lt;br /&gt;
  &amp;lt;uploadedFileContents&amp;gt;TAMIM_RAHMAN_NH3_OPTIMISATION_POP.log&amp;lt;/uploadedFileContents&amp;gt;&lt;br /&gt;
&amp;lt;/jmolApplet&amp;gt;&amp;lt;/jmol&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Link to completed NH3 optimisation https://wiki.ch.ic.ac.uk/wiki/images/f/fe/TAMIM_RAHMAN_NH3_OPTIMISATION_POP.log&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations ===&lt;br /&gt;
[[File:Display_Vibrations.PNG|centre]]&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations Table ===&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
!Wavenumber (cm&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;)&lt;br /&gt;
|1090&lt;br /&gt;
|1694&lt;br /&gt;
|1694&lt;br /&gt;
|3461&lt;br /&gt;
|3590&lt;br /&gt;
|3590&lt;br /&gt;
|-&lt;br /&gt;
!Symmetry&lt;br /&gt;
|A1&lt;br /&gt;
|E&lt;br /&gt;
|E&lt;br /&gt;
|A1&lt;br /&gt;
|E&lt;br /&gt;
|E&lt;br /&gt;
|-&lt;br /&gt;
!Intensity (a.u.)&lt;br /&gt;
|145&lt;br /&gt;
|14&lt;br /&gt;
|14&lt;br /&gt;
|1&lt;br /&gt;
|0&lt;br /&gt;
|0&lt;br /&gt;
|-&lt;br /&gt;
!Images&lt;br /&gt;
|[[File:Tamim Vib 1.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim Vib 2.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim Vib 3.PNG|centre|thumb|212x212px]]&lt;br /&gt;
|[[File:Tamim Vib 4.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim Vib 5.PNG|centre|thumb|208x208px]]&lt;br /&gt;
|[[File:Tamim Vib 6.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|}&lt;br /&gt;
* How many modes do you expect from the 3N-6 rule? 6&lt;br /&gt;
* Which modes are degenerate (ie have the same energy)? 2&amp;amp;3 and 5&amp;amp;6&lt;br /&gt;
* Which modes are &amp;quot;bending&amp;quot; vibrations and which are &amp;quot;bond stretch&amp;quot; vibrations? 1,2 and 3 are bending vibrations while 4,5 and 6 are bond stretch vibrations. &lt;br /&gt;
* Which mode is highly symmetric? 4&lt;br /&gt;
* One mode is known as the &amp;quot;umbrella&amp;quot; mode, which one is this? 11&lt;br /&gt;
* How many bands would you expect to see in an experimental spectrum of gaseous ammonia? 3&lt;br /&gt;
&lt;br /&gt;
=== Charge Distribution ===&lt;br /&gt;
[[File:Tamim Charge Distribution.PNG|thumb|Charge Distribution of NH&amp;lt;sub&amp;gt;3&amp;lt;/sub&amp;gt;|centre]]&lt;br /&gt;
&lt;br /&gt;
The charge on nitrogen should be slightly negative whereas the hydrogen atoms will have a slightly positive charge. This is due to the difference in electronegativity, nitrogen is more electronegative than hydrogen and therefore has a higher electron density to it leading to its slightly negative charge.&lt;br /&gt;
&lt;br /&gt;
== N&amp;lt;sub&amp;gt;2 &amp;lt;/sub&amp;gt;Optimisation ==&lt;br /&gt;
What is the calculation method? RB3LYP&lt;br /&gt;
&lt;br /&gt;
What is the basis set? 6-31G(d,p)&lt;br /&gt;
&lt;br /&gt;
What is the final energy E(RB3LYP) in atomic units (au)? -109.52412868&lt;br /&gt;
&lt;br /&gt;
What is the RMS gradient? 0.00000060&lt;br /&gt;
&lt;br /&gt;
What is the point group of your molecule? D*H&lt;br /&gt;
&lt;br /&gt;
Optimised N-N bond distance? 1.11&lt;br /&gt;
&lt;br /&gt;
=== Item Table ===&lt;br /&gt;
 &lt;br /&gt;
&amp;lt;pre&amp;gt;&lt;br /&gt;
         Item              Value      Threshold  Converged?&lt;br /&gt;
 Maximum Force            0.000001     0.000450     YES&lt;br /&gt;
 RMS     Force            0.000001     0.000300     YES&lt;br /&gt;
 Maximum Displacement     0.000000     0.001800     YES&lt;br /&gt;
 RMS     Displacement     0.000000     0.001200     YES&lt;br /&gt;
 Predicted change in Energy=-3.400972D-13&lt;br /&gt;
&amp;lt;/pre&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;jmol&amp;gt;&amp;lt;jmolApplet&amp;gt;&lt;br /&gt;
  &amp;lt;title&amp;gt;N2_molecule&amp;lt;/title&amp;gt;&lt;br /&gt;
  &amp;lt;color&amp;gt;black&amp;lt;/color&amp;gt;&lt;br /&gt;
  &amp;lt;size&amp;gt;200&amp;lt;/size&amp;gt;&lt;br /&gt;
  &amp;lt;uploadedFileContents&amp;gt;TAMIM_N2_1.LOG&amp;lt;/uploadedFileContents&amp;gt;&lt;br /&gt;
&amp;lt;/jmolApplet&amp;gt;&amp;lt;/jmol&amp;gt;&lt;br /&gt;
&lt;br /&gt;
=== DIsplay Vibrations ===&lt;br /&gt;
[[File:Tamim N2 Disp.PNG|thumb|centre|464x464px]]&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations Table ===&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
!Wavenumber (cm&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;)&lt;br /&gt;
|2457           &lt;br /&gt;
|-&lt;br /&gt;
!Symmetry&lt;br /&gt;
|SGG&lt;br /&gt;
|-&lt;br /&gt;
!Intensity (a.u.)&lt;br /&gt;
|0&lt;br /&gt;
|-&lt;br /&gt;
!Images&lt;br /&gt;
|[[File:Tamim N2 vib.PNG|centre|thumb|250x250px]]&lt;br /&gt;
|}&lt;br /&gt;
* How many modes do you expect from the 3N-6 rule? 0&lt;br /&gt;
* Which modes are &amp;quot;bending&amp;quot; vibrations and which are &amp;quot;bond stretch&amp;quot; vibrations? Only 1 bond stretching vibration &lt;br /&gt;
* Which mode is highly symmetric? 1&lt;br /&gt;
&lt;br /&gt;
=== Charge Distribution ===&lt;br /&gt;
[[File:Tamim n2 charge.PNG|centre|thumb|Charge Distribution for N&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;]]&lt;br /&gt;
The charges on both Nitrogen atoms are zero as they have the same electronegativity which means there is no dipole in the diatomic moleule.&lt;br /&gt;
&lt;br /&gt;
== H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt; Optimisation ==&lt;br /&gt;
What is the calculation method? RB3LYP&lt;br /&gt;
&lt;br /&gt;
What is the basis set? 6-31G(d,p)&lt;br /&gt;
&lt;br /&gt;
What is the final energy E(RB3LYP) in atomic units (au)? -1.17853936&lt;br /&gt;
&lt;br /&gt;
What is the RMS gradient? 0.00000017&lt;br /&gt;
&lt;br /&gt;
What is the point group of your molecule? D*H&lt;br /&gt;
&lt;br /&gt;
Optimised H-H bond distance? 0.74&lt;br /&gt;
&lt;br /&gt;
=== Item Table ===&lt;br /&gt;
&lt;br /&gt;
&amp;lt;pre&amp;gt;&lt;br /&gt;
         Item               Value     Threshold  Converged?&lt;br /&gt;
 Maximum Force            0.000000     0.000450     YES&lt;br /&gt;
 RMS     Force            0.000000     0.000300     YES&lt;br /&gt;
 Maximum Displacement     0.000000     0.001800     YES&lt;br /&gt;
 RMS     Displacement     0.000001     0.001200     YES&lt;br /&gt;
 Predicted change in Energy=-1.164080D-13&amp;lt;/pre&amp;gt;&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations ===&lt;br /&gt;
[[File:Tamim h2 disp.PNG|thumb|centre|463x463px]]&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations Table ===&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
!Wavenumber (cm-1)&lt;br /&gt;
|4466&lt;br /&gt;
|-&lt;br /&gt;
!Symmetry&lt;br /&gt;
|SGG&lt;br /&gt;
|-&lt;br /&gt;
!Intensity (a.u.)&lt;br /&gt;
|0&lt;br /&gt;
|-&lt;br /&gt;
!Images&lt;br /&gt;
|[[File:Tamim h2 vib.PNG|centre|thumb]]&lt;br /&gt;
|}&lt;br /&gt;
* How many modes do you expect from the 3N-6 rule? 0&lt;br /&gt;
* Which modes are &amp;quot;bending&amp;quot; vibrations and which are &amp;quot;bond stretch&amp;quot; vibrations? Only 1 bond stretching vibration &lt;br /&gt;
* Which mode is highly symmetric? 1&lt;br /&gt;
&lt;br /&gt;
=== Charge Distribution ===&lt;br /&gt;
[[File:Tamim h2 charge.PNG|centre|thumb|Charge distribution for H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;]]&lt;br /&gt;
The charges on both Hydrogen atoms are zero as they have the same electronegativity which means there is no dipole in the diatomic moleule.&lt;br /&gt;
&lt;br /&gt;
== Mono-metallic Transition Metal Complex ==&lt;br /&gt;
The transition metal complex chosen was (dinitrogen)-(2,6-bis(1-(2,6-diisopropylphenylimino)propyl)pyridine)-iron with the reference code &#039;&#039;&#039;BARTOF&#039;&#039;&#039;.&lt;br /&gt;
[[File:Tamim TM.PNG|centre|thumb]]&lt;br /&gt;
The bond length of N&amp;lt;sub&amp;gt;2 &amp;lt;/sub&amp;gt;in the molecule above is slightly higher than the bond length of N&amp;lt;sub&amp;gt;2 &amp;lt;/sub&amp;gt;that was calculated before (1.112 compared ot 1.1055). This is due to the lone pair of one nitrogen being donated to the central Iron atom which lowers the electron density on the nitrogen atom; this leads to less overlap of orbitals leading to a higher bond length.  &lt;br /&gt;
&lt;br /&gt;
Link to journal: https://pubs.acs.org/doi/10.1021/ic202750n&lt;br /&gt;
&lt;br /&gt;
== Haber-Bosch Process ==&lt;br /&gt;
* E(NH&amp;lt;sub&amp;gt;3&amp;lt;/sub&amp;gt;) = -56.55776873 &lt;br /&gt;
* 2*E(NH&amp;lt;sub&amp;gt;3&amp;lt;/sub&amp;gt;) = -113.11553746 &lt;br /&gt;
* E(N&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;) = -109.52412868 &lt;br /&gt;
* E(H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;) = -1.17853936 &lt;br /&gt;
* 3*E(H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;) = -3.53561808 &lt;br /&gt;
* ΔE=2*E(NH&amp;lt;sub&amp;gt;3&amp;lt;/sub&amp;gt;)-[E(N&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;)+3*E(H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;)] = -0.05579076&lt;br /&gt;
&lt;br /&gt;
The product ammonia is more stable than the gaseous reactants as it has a lower energy than the reactants. This means it is more stable as the forward reaction is exothermic. &lt;br /&gt;
&lt;br /&gt;
== Own Molecule - SH&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt; ==&lt;br /&gt;
What is the calculation method? RB3LYP&lt;br /&gt;
&lt;br /&gt;
What is the basis set? 6-31G(d,p)&lt;br /&gt;
&lt;br /&gt;
What is the final energy E(RB3LYP) in atomic units (au)? -399.39162414&lt;br /&gt;
&lt;br /&gt;
What is the RMS gradient? 0.00012068&lt;br /&gt;
&lt;br /&gt;
What is the point group of your molecule? C2V&lt;br /&gt;
&lt;br /&gt;
Bond angle of H-S-H? 92.681&lt;br /&gt;
&lt;br /&gt;
=== Item Table ===&lt;br /&gt;
&amp;lt;pre&amp;gt;&lt;br /&gt;
         Item               Value     Threshold  Converged?&amp;lt;br&amp;gt;&lt;br /&gt;
 Maximum Force            0.000175     0.000450     YES&amp;lt;br&amp;gt;&lt;br /&gt;
 RMS     Force            0.000145     0.000300     YES&amp;lt;br&amp;gt;&lt;br /&gt;
 Maximum Displacement     0.000386     0.001800     YES&amp;lt;br&amp;gt;&lt;br /&gt;
 RMS     Displacement     0.000386     0.001200     YES&amp;lt;/pre&amp;gt;&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations ===&lt;br /&gt;
[[File:Tamim disp.PNG|centre|thumb]]&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations Table ===&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
!Wavenumber (cm&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;)&lt;br /&gt;
|1224&lt;br /&gt;
|2692&lt;br /&gt;
|2712&lt;br /&gt;
|-&lt;br /&gt;
!Symmetry&lt;br /&gt;
|A1&lt;br /&gt;
|A1&lt;br /&gt;
|B2&lt;br /&gt;
|-&lt;br /&gt;
!Intensity&lt;br /&gt;
|5&lt;br /&gt;
|7&lt;br /&gt;
|9&lt;br /&gt;
|-&lt;br /&gt;
!Images&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|}&lt;br /&gt;
* How many modes do you expect from the 3N-6 rule? 3&lt;br /&gt;
* Which modes are &amp;quot;bending&amp;quot; vibrations and which are &amp;quot;bond stretch&amp;quot; vibrations? 1 is a bending vibration while 2 and 3 are bond stretch vibrations.  &lt;br /&gt;
* Which mode is highly symmetric? 2&lt;br /&gt;
&lt;br /&gt;
=== Charge Distributions ===&lt;br /&gt;
[[File:Tamim chargesh2.PNG|centre|thumb|Charge distribution for SH&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;]]&lt;br /&gt;
The charge on Sulfur is slightly negative whereas the hydrogen atoms have a slightly positive charge. This is due to the difference in electronegativity, sulfur is more electronegative than hydrogen and therefore has a higher electron density to it leading to its slightly negative charge.&lt;br /&gt;
&lt;br /&gt;
=== Molecular Orbitals ===&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
|[[File:Tamim mo1.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim mo2.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim mo3.PNG|centre|thumb|209x209px]]&lt;br /&gt;
|[[File:Tamim mo4.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim mo5.PNG|centre|thumb|205x205px]]&lt;br /&gt;
|-&lt;br /&gt;
|Bonding molecular orbital between 3s electrons from sulfur and 1s electrons from the hydrogen. &lt;br /&gt;
|Non-bonding orbital consisting of the 2p orbital from the sulfur. &lt;br /&gt;
|Anti-bonding molecular orbital created between the 3p orbitals from sulfur and1 s orbitals from hydrogen. &lt;br /&gt;
|Bonding molecular orbital whihc is created due to the 3p orbital of sulfur and 1s orbital from the hydrogens. &lt;br /&gt;
|SP mixnig between the s and p orbitals of sulfur and also consists of molecular orbital being created between the p orbital of sulfur and s orbitals of hydrogen.&lt;br /&gt;
|}&lt;/div&gt;</summary>
		<author><name>Tr318</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=Rep:Mod:01574856&amp;diff=742419</id>
		<title>Rep:Mod:01574856</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=Rep:Mod:01574856&amp;diff=742419"/>
		<updated>2019-02-22T15:23:49Z</updated>

		<summary type="html">&lt;p&gt;Tr318: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;== NH&amp;lt;sub&amp;gt;3&amp;lt;/sub&amp;gt; Optimisation     ==&lt;br /&gt;
What is the calculation method? RB3LYP&lt;br /&gt;
&lt;br /&gt;
What is the basis set? 6-31G(d,p)&lt;br /&gt;
&lt;br /&gt;
What is the final energy E(RB3LYP) in atomic units (au)? -56.55776873&lt;br /&gt;
&lt;br /&gt;
What is the RMS gradient? 0.00000485&lt;br /&gt;
&lt;br /&gt;
What is the point group of your molecule? C3V&lt;br /&gt;
&lt;br /&gt;
optimised N-H bond distance and the optimised H-N-H bond angle? 1.02 &amp;amp; 106&lt;br /&gt;
&lt;br /&gt;
=== Item Table ===&lt;br /&gt;
&amp;lt;pre&amp;gt;&lt;br /&gt;
         Item               Value     Threshold  Converged?&lt;br /&gt;
 Maximum Force            0.000004     0.000450     YES&lt;br /&gt;
 RMS     Force            0.000004     0.000300     YES&lt;br /&gt;
 Maximum Displacement     0.000072     0.001800     YES&lt;br /&gt;
 RMS     Displacement     0.000035     0.001200     YES&lt;br /&gt;
 Predicted change in Energy=-5.986295D-10&lt;br /&gt;
&amp;lt;/pre&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;jmol&amp;gt;&amp;lt;jmolApplet&amp;gt;&lt;br /&gt;
  &amp;lt;title&amp;gt;NH3_Molecule_01574856&amp;lt;/title&amp;gt;&lt;br /&gt;
  &amp;lt;color&amp;gt;black&amp;lt;/color&amp;gt;&lt;br /&gt;
  &amp;lt;size&amp;gt;200&amp;lt;/size&amp;gt;&lt;br /&gt;
  &amp;lt;uploadedFileContents&amp;gt;TAMIM_RAHMAN_NH3_OPTIMISATION_POP.log&amp;lt;/uploadedFileContents&amp;gt;&lt;br /&gt;
&amp;lt;/jmolApplet&amp;gt;&amp;lt;/jmol&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Link to completed NH3 optimisation https://wiki.ch.ic.ac.uk/wiki/images/f/fe/TAMIM_RAHMAN_NH3_OPTIMISATION_POP.log&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations ===&lt;br /&gt;
[[File:Display_Vibrations.PNG|centre]]&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations Table ===&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
!Wavenumber (cm&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;)&lt;br /&gt;
|1090&lt;br /&gt;
|1694&lt;br /&gt;
|1694&lt;br /&gt;
|3461&lt;br /&gt;
|3590&lt;br /&gt;
|3590&lt;br /&gt;
|-&lt;br /&gt;
!Symmetry&lt;br /&gt;
|A1&lt;br /&gt;
|E&lt;br /&gt;
|E&lt;br /&gt;
|A1&lt;br /&gt;
|E&lt;br /&gt;
|E&lt;br /&gt;
|-&lt;br /&gt;
!Intensity (a.u.)&lt;br /&gt;
|145&lt;br /&gt;
|14&lt;br /&gt;
|14&lt;br /&gt;
|1&lt;br /&gt;
|0&lt;br /&gt;
|0&lt;br /&gt;
|-&lt;br /&gt;
!Images&lt;br /&gt;
|[[File:Tamim Vib 1.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim Vib 2.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim Vib 3.PNG|centre|thumb|212x212px]]&lt;br /&gt;
|[[File:Tamim Vib 4.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim Vib 5.PNG|centre|thumb|208x208px]]&lt;br /&gt;
|[[File:Tamim Vib 6.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|}&lt;br /&gt;
* How many modes do you expect from the 3N-6 rule? 6&lt;br /&gt;
* Which modes are degenerate (ie have the same energy)? 2&amp;amp;3 and 5&amp;amp;6&lt;br /&gt;
* Which modes are &amp;quot;bending&amp;quot; vibrations and which are &amp;quot;bond stretch&amp;quot; vibrations? 1,2 and 3 are bending vibrations while 4,5 and 6 are bond stretch vibrations. &lt;br /&gt;
* Which mode is highly symmetric? 4&lt;br /&gt;
* One mode is known as the &amp;quot;umbrella&amp;quot; mode, which one is this? 11&lt;br /&gt;
* How many bands would you expect to see in an experimental spectrum of gaseous ammonia? 3&lt;br /&gt;
&lt;br /&gt;
=== Charge Distribution ===&lt;br /&gt;
[[File:Tamim Charge Distribution.PNG|thumb|Charge Distribution of NH&amp;lt;sub&amp;gt;3&amp;lt;/sub&amp;gt;|centre]]&lt;br /&gt;
&lt;br /&gt;
The charge on nitrogen should be slightly negative whereas the hydrogen atoms will have a slightly positive charge. This is due to the difference in electronegativity, nitrogen is more electronegative than hydrogen and therefore has a higher electron density to it leading to its slightly negative charge.&lt;br /&gt;
&lt;br /&gt;
== N&amp;lt;sub&amp;gt;2 &amp;lt;/sub&amp;gt;Optimisation ==&lt;br /&gt;
What is the calculation method? RB3LYP&lt;br /&gt;
&lt;br /&gt;
What is the basis set? 6-31G(d,p)&lt;br /&gt;
&lt;br /&gt;
What is the final energy E(RB3LYP) in atomic units (au)? -109.52412868&lt;br /&gt;
&lt;br /&gt;
What is the RMS gradient? 0.00000060&lt;br /&gt;
&lt;br /&gt;
What is the point group of your molecule? D*H&lt;br /&gt;
&lt;br /&gt;
Optimised N-N bond distance? 1.11&lt;br /&gt;
&lt;br /&gt;
=== Item Table ===&lt;br /&gt;
 &lt;br /&gt;
&amp;lt;pre&amp;gt;&lt;br /&gt;
         Item              Value      Threshold  Converged?&lt;br /&gt;
 Maximum Force            0.000001     0.000450     YES&lt;br /&gt;
 RMS     Force            0.000001     0.000300     YES&lt;br /&gt;
 Maximum Displacement     0.000000     0.001800     YES&lt;br /&gt;
 RMS     Displacement     0.000000     0.001200     YES&lt;br /&gt;
 Predicted change in Energy=-3.400972D-13&lt;br /&gt;
&amp;lt;/pre&amp;gt;&lt;br /&gt;
&lt;br /&gt;
=== DIsplay Vibrations ===&lt;br /&gt;
[[File:Tamim N2 Disp.PNG|thumb|centre|464x464px]]&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations Table ===&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
!Wavenumber (cm&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;)&lt;br /&gt;
|2457           &lt;br /&gt;
|-&lt;br /&gt;
!Symmetry&lt;br /&gt;
|SGG&lt;br /&gt;
|-&lt;br /&gt;
!Intensity (a.u.)&lt;br /&gt;
|0&lt;br /&gt;
|-&lt;br /&gt;
!Images&lt;br /&gt;
|[[File:Tamim N2 vib.PNG|centre|thumb|250x250px]]&lt;br /&gt;
|}&lt;br /&gt;
* How many modes do you expect from the 3N-6 rule? 0&lt;br /&gt;
* Which modes are &amp;quot;bending&amp;quot; vibrations and which are &amp;quot;bond stretch&amp;quot; vibrations? Only 1 bond stretching vibration &lt;br /&gt;
* Which mode is highly symmetric? 1&lt;br /&gt;
&lt;br /&gt;
=== Charge Distribution ===&lt;br /&gt;
[[File:Tamim n2 charge.PNG|centre|thumb|Charge Distribution for N&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;]]&lt;br /&gt;
The charges on both Nitrogen atoms are zero as they have the same electronegativity which means there is no dipole in the diatomic moleule.&lt;br /&gt;
&lt;br /&gt;
== H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt; Optimisation ==&lt;br /&gt;
What is the calculation method? RB3LYP&lt;br /&gt;
&lt;br /&gt;
What is the basis set? 6-31G(d,p)&lt;br /&gt;
&lt;br /&gt;
What is the final energy E(RB3LYP) in atomic units (au)? -1.17853936&lt;br /&gt;
&lt;br /&gt;
What is the RMS gradient? 0.00000017&lt;br /&gt;
&lt;br /&gt;
What is the point group of your molecule? D*H&lt;br /&gt;
&lt;br /&gt;
Optimised H-H bond distance? 0.74&lt;br /&gt;
&lt;br /&gt;
=== Item Table ===&lt;br /&gt;
&lt;br /&gt;
&amp;lt;pre&amp;gt;&lt;br /&gt;
         Item               Value     Threshold  Converged?&lt;br /&gt;
 Maximum Force            0.000000     0.000450     YES&lt;br /&gt;
 RMS     Force            0.000000     0.000300     YES&lt;br /&gt;
 Maximum Displacement     0.000000     0.001800     YES&lt;br /&gt;
 RMS     Displacement     0.000001     0.001200     YES&lt;br /&gt;
 Predicted change in Energy=-1.164080D-13&amp;lt;/pre&amp;gt;&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations ===&lt;br /&gt;
[[File:Tamim h2 disp.PNG|thumb|centre|463x463px]]&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations Table ===&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
!Wavenumber (cm-1)&lt;br /&gt;
|4466&lt;br /&gt;
|-&lt;br /&gt;
!Symmetry&lt;br /&gt;
|SGG&lt;br /&gt;
|-&lt;br /&gt;
!Intensity (a.u.)&lt;br /&gt;
|0&lt;br /&gt;
|-&lt;br /&gt;
!Images&lt;br /&gt;
|[[File:Tamim h2 vib.PNG|centre|thumb]]&lt;br /&gt;
|}&lt;br /&gt;
* How many modes do you expect from the 3N-6 rule? 0&lt;br /&gt;
* Which modes are &amp;quot;bending&amp;quot; vibrations and which are &amp;quot;bond stretch&amp;quot; vibrations? Only 1 bond stretching vibration &lt;br /&gt;
* Which mode is highly symmetric? 1&lt;br /&gt;
&lt;br /&gt;
=== Charge Distribution ===&lt;br /&gt;
[[File:Tamim h2 charge.PNG|centre|thumb|Charge distribution for H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;]]&lt;br /&gt;
The charges on both Hydrogen atoms are zero as they have the same electronegativity which means there is no dipole in the diatomic moleule.&lt;br /&gt;
&lt;br /&gt;
== Mono-metallic Transition Metal Complex ==&lt;br /&gt;
The transition metal complex chosen was (dinitrogen)-(2,6-bis(1-(2,6-diisopropylphenylimino)propyl)pyridine)-iron with the reference code &#039;&#039;&#039;BARTOF&#039;&#039;&#039;.&lt;br /&gt;
[[File:Tamim TM.PNG|centre|thumb]]&lt;br /&gt;
The bond length of N&amp;lt;sub&amp;gt;2 &amp;lt;/sub&amp;gt;in the molecule above is slightly higher than the bond length of N&amp;lt;sub&amp;gt;2 &amp;lt;/sub&amp;gt;that was calculated before (1.112 compared ot 1.1055). This is due to the lone pair of one nitrogen being donated to the central Iron atom which lowers the electron density on the nitrogen atom; this leads to less overlap of orbitals leading to a higher bond length.  &lt;br /&gt;
&lt;br /&gt;
Link to journal: https://pubs.acs.org/doi/10.1021/ic202750n&lt;br /&gt;
&lt;br /&gt;
== Haber-Bosch Process ==&lt;br /&gt;
* E(NH&amp;lt;sub&amp;gt;3&amp;lt;/sub&amp;gt;) = -56.55776873 &lt;br /&gt;
* 2*E(NH&amp;lt;sub&amp;gt;3&amp;lt;/sub&amp;gt;) = -113.11553746 &lt;br /&gt;
* E(N&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;) = -109.52412868 &lt;br /&gt;
* E(H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;) = -1.17853936 &lt;br /&gt;
* 3*E(H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;) = -3.53561808 &lt;br /&gt;
* ΔE=2*E(NH&amp;lt;sub&amp;gt;3&amp;lt;/sub&amp;gt;)-[E(N&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;)+3*E(H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;)] = -0.05579076&lt;br /&gt;
&lt;br /&gt;
The product ammonia is more stable than the gaseous reactants as it has a lower energy than the reactants. This means it is more stable as the forward reaction is exothermic. &lt;br /&gt;
&lt;br /&gt;
== Own Molecule - SH&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt; ==&lt;br /&gt;
What is the calculation method? RB3LYP&lt;br /&gt;
&lt;br /&gt;
What is the basis set? 6-31G(d,p)&lt;br /&gt;
&lt;br /&gt;
What is the final energy E(RB3LYP) in atomic units (au)? -399.39162414&lt;br /&gt;
&lt;br /&gt;
What is the RMS gradient? 0.00012068&lt;br /&gt;
&lt;br /&gt;
What is the point group of your molecule? C2V&lt;br /&gt;
&lt;br /&gt;
Bond angle of H-S-H? 92.681&lt;br /&gt;
&lt;br /&gt;
=== Item Table ===&lt;br /&gt;
&amp;lt;pre&amp;gt;&lt;br /&gt;
         Item               Value     Threshold  Converged?&amp;lt;br&amp;gt;&lt;br /&gt;
 Maximum Force            0.000175     0.000450     YES&amp;lt;br&amp;gt;&lt;br /&gt;
 RMS     Force            0.000145     0.000300     YES&amp;lt;br&amp;gt;&lt;br /&gt;
 Maximum Displacement     0.000386     0.001800     YES&amp;lt;br&amp;gt;&lt;br /&gt;
 RMS     Displacement     0.000386     0.001200     YES&amp;lt;/pre&amp;gt;&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations ===&lt;br /&gt;
[[File:Tamim disp.PNG|centre|thumb]]&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations Table ===&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
!Wavenumber (cm&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;)&lt;br /&gt;
|1224&lt;br /&gt;
|2692&lt;br /&gt;
|2712&lt;br /&gt;
|-&lt;br /&gt;
!Symmetry&lt;br /&gt;
|A1&lt;br /&gt;
|A1&lt;br /&gt;
|B2&lt;br /&gt;
|-&lt;br /&gt;
!Intensity&lt;br /&gt;
|5&lt;br /&gt;
|7&lt;br /&gt;
|9&lt;br /&gt;
|-&lt;br /&gt;
!Images&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|}&lt;br /&gt;
* How many modes do you expect from the 3N-6 rule? 3&lt;br /&gt;
* Which modes are &amp;quot;bending&amp;quot; vibrations and which are &amp;quot;bond stretch&amp;quot; vibrations? 1 is a bending vibration while 2 and 3 are bond stretch vibrations.  &lt;br /&gt;
* Which mode is highly symmetric? 2&lt;br /&gt;
&lt;br /&gt;
=== Charge Distributions ===&lt;br /&gt;
[[File:Tamim chargesh2.PNG|centre|thumb|Charge distribution for SH&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;]]&lt;br /&gt;
The charge on Sulfur is slightly negative whereas the hydrogen atoms have a slightly positive charge. This is due to the difference in electronegativity, sulfur is more electronegative than hydrogen and therefore has a higher electron density to it leading to its slightly negative charge.&lt;br /&gt;
&lt;br /&gt;
=== Molecular Orbitals ===&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
|[[File:Tamim mo1.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim mo2.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim mo3.PNG|centre|thumb|209x209px]]&lt;br /&gt;
|[[File:Tamim mo4.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim mo5.PNG|centre|thumb|205x205px]]&lt;br /&gt;
|-&lt;br /&gt;
|Bonding molecular orbital between 3s electrons from sulfur and 1s electrons from the hydrogen. &lt;br /&gt;
|Non-bonding orbital consisting of the 2p orbital from the sulfur. &lt;br /&gt;
|Anti-bonding molecular orbital created between the 3p orbitals from sulfur and1 s orbitals from hydrogen. &lt;br /&gt;
|Bonding molecular orbital whihc is created due to the 3p orbital of sulfur and 1s orbital from the hydrogens. &lt;br /&gt;
|SP mixnig between the s and p orbitals of sulfur and also consists of molecular orbital being created between the p orbital of sulfur and s orbitals of hydrogen.&lt;br /&gt;
|}&lt;/div&gt;</summary>
		<author><name>Tr318</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=Rep:Mod:01574856&amp;diff=742418</id>
		<title>Rep:Mod:01574856</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=Rep:Mod:01574856&amp;diff=742418"/>
		<updated>2019-02-22T15:22:17Z</updated>

		<summary type="html">&lt;p&gt;Tr318: /* NH3 Optimisation */&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;== NH&amp;lt;sub&amp;gt;3&amp;lt;/sub&amp;gt; Optimisation     ==&lt;br /&gt;
What is the calculation method? RB3LYP&lt;br /&gt;
&lt;br /&gt;
What is the basis set? 6-31G(d,p)&lt;br /&gt;
&lt;br /&gt;
What is the final energy E(RB3LYP) in atomic units (au)? -56.55776873&lt;br /&gt;
&lt;br /&gt;
What is the RMS gradient? 0.00000485&lt;br /&gt;
&lt;br /&gt;
What is the point group of your molecule? C3V&lt;br /&gt;
&lt;br /&gt;
optimised N-H bond distance and the optimised H-N-H bond angle? 1.02 &amp;amp; 106&lt;br /&gt;
&lt;br /&gt;
=== Item Table ===&lt;br /&gt;
&amp;lt;pre&amp;gt;&lt;br /&gt;
         Item               Value     Threshold  Converged?&lt;br /&gt;
 Maximum Force            0.000004     0.000450     YES&lt;br /&gt;
 RMS     Force            0.000004     0.000300     YES&lt;br /&gt;
 Maximum Displacement     0.000072     0.001800     YES&lt;br /&gt;
 RMS     Displacement     0.000035     0.001200     YES&lt;br /&gt;
 Predicted change in Energy=-5.986295D-10&lt;br /&gt;
&amp;lt;/pre&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Link to completed NH3 optimisation https://wiki.ch.ic.ac.uk/wiki/images/f/fe/TAMIM_RAHMAN_NH3_OPTIMISATION_POP.log&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations ===&lt;br /&gt;
[[File:Display_Vibrations.PNG|centre]]&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations Table ===&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
!Wavenumber (cm&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;)&lt;br /&gt;
|1090&lt;br /&gt;
|1694&lt;br /&gt;
|1694&lt;br /&gt;
|3461&lt;br /&gt;
|3590&lt;br /&gt;
|3590&lt;br /&gt;
|-&lt;br /&gt;
!Symmetry&lt;br /&gt;
|A1&lt;br /&gt;
|E&lt;br /&gt;
|E&lt;br /&gt;
|A1&lt;br /&gt;
|E&lt;br /&gt;
|E&lt;br /&gt;
|-&lt;br /&gt;
!Intensity (a.u.)&lt;br /&gt;
|145&lt;br /&gt;
|14&lt;br /&gt;
|14&lt;br /&gt;
|1&lt;br /&gt;
|0&lt;br /&gt;
|0&lt;br /&gt;
|-&lt;br /&gt;
!Images&lt;br /&gt;
|[[File:Tamim Vib 1.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim Vib 2.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim Vib 3.PNG|centre|thumb|212x212px]]&lt;br /&gt;
|[[File:Tamim Vib 4.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim Vib 5.PNG|centre|thumb|208x208px]]&lt;br /&gt;
|[[File:Tamim Vib 6.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|}&lt;br /&gt;
* How many modes do you expect from the 3N-6 rule? 6&lt;br /&gt;
* Which modes are degenerate (ie have the same energy)? 2&amp;amp;3 and 5&amp;amp;6&lt;br /&gt;
* Which modes are &amp;quot;bending&amp;quot; vibrations and which are &amp;quot;bond stretch&amp;quot; vibrations? 1,2 and 3 are bending vibrations while 4,5 and 6 are bond stretch vibrations. &lt;br /&gt;
* Which mode is highly symmetric? 4&lt;br /&gt;
* One mode is known as the &amp;quot;umbrella&amp;quot; mode, which one is this? 11&lt;br /&gt;
* How many bands would you expect to see in an experimental spectrum of gaseous ammonia? 3&lt;br /&gt;
&lt;br /&gt;
=== Charge Distribution ===&lt;br /&gt;
[[File:Tamim Charge Distribution.PNG|thumb|Charge Distribution of NH&amp;lt;sub&amp;gt;3&amp;lt;/sub&amp;gt;|centre]]&lt;br /&gt;
&lt;br /&gt;
The charge on nitrogen should be slightly negative whereas the hydrogen atoms will have a slightly positive charge. This is due to the difference in electronegativity, nitrogen is more electronegative than hydrogen and therefore has a higher electron density to it leading to its slightly negative charge.&lt;br /&gt;
&lt;br /&gt;
== N&amp;lt;sub&amp;gt;2 &amp;lt;/sub&amp;gt;Optimisation ==&lt;br /&gt;
What is the calculation method? RB3LYP&lt;br /&gt;
&lt;br /&gt;
What is the basis set? 6-31G(d,p)&lt;br /&gt;
&lt;br /&gt;
What is the final energy E(RB3LYP) in atomic units (au)? -109.52412868&lt;br /&gt;
&lt;br /&gt;
What is the RMS gradient? 0.00000060&lt;br /&gt;
&lt;br /&gt;
What is the point group of your molecule? D*H&lt;br /&gt;
&lt;br /&gt;
Optimised N-N bond distance? 1.11&lt;br /&gt;
&lt;br /&gt;
=== Item Table ===&lt;br /&gt;
 &lt;br /&gt;
&amp;lt;pre&amp;gt;&lt;br /&gt;
         Item              Value      Threshold  Converged?&lt;br /&gt;
 Maximum Force            0.000001     0.000450     YES&lt;br /&gt;
 RMS     Force            0.000001     0.000300     YES&lt;br /&gt;
 Maximum Displacement     0.000000     0.001800     YES&lt;br /&gt;
 RMS     Displacement     0.000000     0.001200     YES&lt;br /&gt;
 Predicted change in Energy=-3.400972D-13&lt;br /&gt;
&amp;lt;/pre&amp;gt;&lt;br /&gt;
&lt;br /&gt;
=== DIsplay Vibrations ===&lt;br /&gt;
[[File:Tamim N2 Disp.PNG|thumb|centre|464x464px]]&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations Table ===&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
!Wavenumber (cm&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;)&lt;br /&gt;
|2457           &lt;br /&gt;
|-&lt;br /&gt;
!Symmetry&lt;br /&gt;
|SGG&lt;br /&gt;
|-&lt;br /&gt;
!Intensity (a.u.)&lt;br /&gt;
|0&lt;br /&gt;
|-&lt;br /&gt;
!Images&lt;br /&gt;
|[[File:Tamim N2 vib.PNG|centre|thumb|250x250px]]&lt;br /&gt;
|}&lt;br /&gt;
* How many modes do you expect from the 3N-6 rule? 0&lt;br /&gt;
* Which modes are &amp;quot;bending&amp;quot; vibrations and which are &amp;quot;bond stretch&amp;quot; vibrations? Only 1 bond stretching vibration &lt;br /&gt;
* Which mode is highly symmetric? 1&lt;br /&gt;
&lt;br /&gt;
=== Charge Distribution ===&lt;br /&gt;
[[File:Tamim n2 charge.PNG|centre|thumb|Charge Distribution for N&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;]]&lt;br /&gt;
The charges on both Nitrogen atoms are zero as they have the same electronegativity which means there is no dipole in the diatomic moleule.&lt;br /&gt;
&lt;br /&gt;
== H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt; Optimisation ==&lt;br /&gt;
What is the calculation method? RB3LYP&lt;br /&gt;
&lt;br /&gt;
What is the basis set? 6-31G(d,p)&lt;br /&gt;
&lt;br /&gt;
What is the final energy E(RB3LYP) in atomic units (au)? -1.17853936&lt;br /&gt;
&lt;br /&gt;
What is the RMS gradient? 0.00000017&lt;br /&gt;
&lt;br /&gt;
What is the point group of your molecule? D*H&lt;br /&gt;
&lt;br /&gt;
Optimised H-H bond distance? 0.74&lt;br /&gt;
&lt;br /&gt;
=== Item Table ===&lt;br /&gt;
&lt;br /&gt;
&amp;lt;pre&amp;gt;&lt;br /&gt;
         Item               Value     Threshold  Converged?&lt;br /&gt;
 Maximum Force            0.000000     0.000450     YES&lt;br /&gt;
 RMS     Force            0.000000     0.000300     YES&lt;br /&gt;
 Maximum Displacement     0.000000     0.001800     YES&lt;br /&gt;
 RMS     Displacement     0.000001     0.001200     YES&lt;br /&gt;
 Predicted change in Energy=-1.164080D-13&amp;lt;/pre&amp;gt;&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations ===&lt;br /&gt;
[[File:Tamim h2 disp.PNG|thumb|centre|463x463px]]&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations Table ===&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
!Wavenumber (cm-1)&lt;br /&gt;
|4466&lt;br /&gt;
|-&lt;br /&gt;
!Symmetry&lt;br /&gt;
|SGG&lt;br /&gt;
|-&lt;br /&gt;
!Intensity (a.u.)&lt;br /&gt;
|0&lt;br /&gt;
|-&lt;br /&gt;
!Images&lt;br /&gt;
|[[File:Tamim h2 vib.PNG|centre|thumb]]&lt;br /&gt;
|}&lt;br /&gt;
* How many modes do you expect from the 3N-6 rule? 0&lt;br /&gt;
* Which modes are &amp;quot;bending&amp;quot; vibrations and which are &amp;quot;bond stretch&amp;quot; vibrations? Only 1 bond stretching vibration &lt;br /&gt;
* Which mode is highly symmetric? 1&lt;br /&gt;
&lt;br /&gt;
=== Charge Distribution ===&lt;br /&gt;
[[File:Tamim h2 charge.PNG|centre|thumb|Charge distribution for H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;]]&lt;br /&gt;
The charges on both Hydrogen atoms are zero as they have the same electronegativity which means there is no dipole in the diatomic moleule.&lt;br /&gt;
&lt;br /&gt;
== Mono-metallic Transition Metal Complex ==&lt;br /&gt;
The transition metal complex chosen was (dinitrogen)-(2,6-bis(1-(2,6-diisopropylphenylimino)propyl)pyridine)-iron with the reference code &#039;&#039;&#039;BARTOF&#039;&#039;&#039;.&lt;br /&gt;
[[File:Tamim TM.PNG|centre|thumb]]&lt;br /&gt;
The bond length of N&amp;lt;sub&amp;gt;2 &amp;lt;/sub&amp;gt;in the molecule above is slightly higher than the bond length of N&amp;lt;sub&amp;gt;2 &amp;lt;/sub&amp;gt;that was calculated before (1.112 compared ot 1.1055). This is due to the lone pair of one nitrogen being donated to the central Iron atom which lowers the electron density on the nitrogen atom; this leads to less overlap of orbitals leading to a higher bond length.  &lt;br /&gt;
&lt;br /&gt;
Link to journal: https://pubs.acs.org/doi/10.1021/ic202750n&lt;br /&gt;
&lt;br /&gt;
== Haber-Bosch Process ==&lt;br /&gt;
* E(NH&amp;lt;sub&amp;gt;3&amp;lt;/sub&amp;gt;) = -56.55776873 &lt;br /&gt;
* 2*E(NH&amp;lt;sub&amp;gt;3&amp;lt;/sub&amp;gt;) = -113.11553746 &lt;br /&gt;
* E(N&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;) = -109.52412868 &lt;br /&gt;
* E(H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;) = -1.17853936 &lt;br /&gt;
* 3*E(H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;) = -3.53561808 &lt;br /&gt;
* ΔE=2*E(NH&amp;lt;sub&amp;gt;3&amp;lt;/sub&amp;gt;)-[E(N&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;)+3*E(H&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;)] = -0.05579076&lt;br /&gt;
&lt;br /&gt;
The product ammonia is more stable than the gaseous reactants as it has a lower energy than the reactants. This means it is more stable as the forward reaction is exothermic. &lt;br /&gt;
&lt;br /&gt;
== Own Molecule - SH&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt; ==&lt;br /&gt;
What is the calculation method? RB3LYP&lt;br /&gt;
&lt;br /&gt;
What is the basis set? 6-31G(d,p)&lt;br /&gt;
&lt;br /&gt;
What is the final energy E(RB3LYP) in atomic units (au)? -399.39162414&lt;br /&gt;
&lt;br /&gt;
What is the RMS gradient? 0.00012068&lt;br /&gt;
&lt;br /&gt;
What is the point group of your molecule? C2V&lt;br /&gt;
&lt;br /&gt;
Bond angle of H-S-H? 92.681&lt;br /&gt;
&lt;br /&gt;
=== Item Table ===&lt;br /&gt;
&amp;lt;pre&amp;gt;&lt;br /&gt;
         Item               Value     Threshold  Converged?&amp;lt;br&amp;gt;&lt;br /&gt;
 Maximum Force            0.000175     0.000450     YES&amp;lt;br&amp;gt;&lt;br /&gt;
 RMS     Force            0.000145     0.000300     YES&amp;lt;br&amp;gt;&lt;br /&gt;
 Maximum Displacement     0.000386     0.001800     YES&amp;lt;br&amp;gt;&lt;br /&gt;
 RMS     Displacement     0.000386     0.001200     YES&amp;lt;/pre&amp;gt;&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations ===&lt;br /&gt;
[[File:Tamim disp.PNG|centre|thumb]]&lt;br /&gt;
&lt;br /&gt;
=== Display Vibrations Table ===&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
!Wavenumber (cm&amp;lt;sup&amp;gt;-1&amp;lt;/sup&amp;gt;)&lt;br /&gt;
|1224&lt;br /&gt;
|2692&lt;br /&gt;
|2712&lt;br /&gt;
|-&lt;br /&gt;
!Symmetry&lt;br /&gt;
|A1&lt;br /&gt;
|A1&lt;br /&gt;
|B2&lt;br /&gt;
|-&lt;br /&gt;
!Intensity&lt;br /&gt;
|5&lt;br /&gt;
|7&lt;br /&gt;
|9&lt;br /&gt;
|-&lt;br /&gt;
!Images&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|&lt;br /&gt;
|}&lt;br /&gt;
* How many modes do you expect from the 3N-6 rule? 3&lt;br /&gt;
* Which modes are &amp;quot;bending&amp;quot; vibrations and which are &amp;quot;bond stretch&amp;quot; vibrations? 1 is a bending vibration while 2 and 3 are bond stretch vibrations.  &lt;br /&gt;
* Which mode is highly symmetric? 2&lt;br /&gt;
&lt;br /&gt;
=== Charge Distributions ===&lt;br /&gt;
[[File:Tamim chargesh2.PNG|centre|thumb|Charge distribution for SH&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;]]&lt;br /&gt;
The charge on Sulfur is slightly negative whereas the hydrogen atoms have a slightly positive charge. This is due to the difference in electronegativity, sulfur is more electronegative than hydrogen and therefore has a higher electron density to it leading to its slightly negative charge.&lt;br /&gt;
&lt;br /&gt;
=== Molecular Orbitals ===&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot;&lt;br /&gt;
|[[File:Tamim mo1.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim mo2.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim mo3.PNG|centre|thumb|209x209px]]&lt;br /&gt;
|[[File:Tamim mo4.PNG|centre|thumb|200x200px]]&lt;br /&gt;
|[[File:Tamim mo5.PNG|centre|thumb|205x205px]]&lt;br /&gt;
|-&lt;br /&gt;
|Bonding molecular orbital between 3s electrons from sulfur and 1s electrons from the hydrogen. &lt;br /&gt;
|Non-bonding orbital consisting of the 2p orbital from the sulfur. &lt;br /&gt;
|Anti-bonding molecular orbital created between the 3p orbitals from sulfur and1 s orbitals from hydrogen. &lt;br /&gt;
|Bonding molecular orbital whihc is created due to the 3p orbital of sulfur and 1s orbital from the hydrogens. &lt;br /&gt;
|SP mixnig between the s and p orbitals of sulfur and also consists of molecular orbital being created between the p orbital of sulfur and s orbitals of hydrogen.&lt;br /&gt;
|}&lt;/div&gt;</summary>
		<author><name>Tr318</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=File:TAMIM_SH2.LOG&amp;diff=742413</id>
		<title>File:TAMIM SH2.LOG</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=File:TAMIM_SH2.LOG&amp;diff=742413"/>
		<updated>2019-02-22T15:21:19Z</updated>

		<summary type="html">&lt;p&gt;Tr318: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;/div&gt;</summary>
		<author><name>Tr318</name></author>
	</entry>
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