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	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=781477</id>
		<title>MRD:ql2817</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=781477"/>
		<updated>2019-05-16T15:47:46Z</updated>

		<summary type="html">&lt;p&gt;Ql2817: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;br /&gt;
== &#039;&#039;&#039;Question 1&#039;&#039;&#039; ==&lt;br /&gt;
&lt;br /&gt;
=== On a potential energy surface diagram, how is the transition state mathematically defined? How can the transition state be identified, and how can it be distinguished from a local minimum of the potential energy surface?===&lt;br /&gt;
&lt;br /&gt;
The transition state is defined as the maximum on the minimum energy path linking reactants and the products.It is located at the saddle point in the potential energy surface diagram, which defined as : ∂V(ri)/∂ri=0 and H &amp;lt; 0, where H = frr(r0​,V0​)fVV(r0​,V0​)−f2rV​(r0​,V0​) .&lt;br /&gt;
&lt;br /&gt;
The transition state is the specific combination of internuclear distances AB and BC at which the trajectory is a point on the contour plot.&lt;br /&gt;
&lt;br /&gt;
=== Report your best estimate of the transition state position (rts) and explain your reasoning illustrating it with a “Internuclear Distances vs Time” plot for a relevant trajectory. ===&lt;br /&gt;
When r(AB)=r(BC)=0.907 Å, p1 = p2 = 0.0, the transition state occurs. The internuclear distance vs time graph gives a relatively straight line which indicates a constant distance.&lt;br /&gt;
&lt;br /&gt;
=== Comment on how the mep and the trajectory you just calculated differ. ===&lt;br /&gt;
The mep trajectory keeps the potential energy at the minimum in a straight line, whereas the dynamic trajectory is wavy.&lt;br /&gt;
&lt;br /&gt;
r1 = 0.907, r2 = 0.917&lt;br /&gt;
&lt;br /&gt;
Molecules and atome moving away from each other.&lt;br /&gt;
&lt;br /&gt;
Setup a calculation where the initial positions correspond to the final positions of the trajectory you calculated above, the same final momenta values but with their signs reversed.&lt;br /&gt;
&lt;br /&gt;
r1 = rts+δ, r2 = rts&lt;br /&gt;
&lt;br /&gt;
final values of the positions r1(t) = 3.45, r2(t) = 0.72 and the average momenta  p1(t) = -1.45, p2(t) = -2.48 at large t.&lt;br /&gt;
&lt;br /&gt;
The molecule and the atom moving close together instead of moving apart.&lt;br /&gt;
&lt;br /&gt;
=== Complete the table above by adding the total energy, whether the trajectory is reactive or unreactive, and provide a plot of the trajectory and a small description for what happens along the trajectory. What can you conclude from the table? ===&lt;br /&gt;
&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot; border=&amp;quot;5&amp;quot;&lt;br /&gt;
! P1!!P2 !! Etot!! Reactive?!!Description of the dyanmics!!Illustration of the trajectory&lt;br /&gt;
|-&lt;br /&gt;
| -1.25 || -2.5|| -99.08|| yes||The trajectory goes through the transition state and also go into the products. ||[[File:Surface01_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -1.5|| -2.0|| -100.22|| no||The trajectory falls back down into the reactants because there was not enough energy for reactants to pass over the transition state. || [[File:Surface02_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -1.5||  -2.5|| -98.91|| yes||The trajectory goes through the transition state and also go into the products with enough energy. || [[File:Surface03_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -2.5|| -5.0|| -84.62|| no||The trajectory was carrying enough energy towards products but then it shifts back into the reactants. || [[File:Surface04_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -2.5||  -5.2|| -83.40|| yes||The trajectory goes through the transition state and also go into the products with enough energy. || [[File:Surface05_ql2817.png]]&lt;br /&gt;
|}&lt;br /&gt;
&lt;br /&gt;
=== State what are the main assumptions of Transition State Theory. Given the results you have obtained, how will Transition State Theory predictions for reaction rate values compare with experimental values? ===&lt;br /&gt;
Assumptions &amp;lt;ref name=&amp;quot;main&amp;quot;&amp;gt;https://en.wikibooks.org/wiki/Statistical_Thermodynamics_and_Rate_Theories/Eyring_Transition_State_Theory#Assumptions_of_Transition_State_Theory&lt;br /&gt;
&amp;lt;/ref&amp;gt;&lt;br /&gt;
&lt;br /&gt;
*Reactants are in constant equilibrium with the transition state structure.&lt;br /&gt;
*The energy of the particles follow a Boltzmann distribution.&lt;br /&gt;
*Once reactants become the transition state, the transition state structure does not collapse back to the reactants.&lt;br /&gt;
&lt;br /&gt;
Transition state theory will predict a higher reaction rate than experimental one.&lt;br /&gt;
&lt;br /&gt;
== &#039;&#039;&#039;Exercise 2: F-H-H system&#039;&#039;&#039; ==&lt;br /&gt;
&lt;br /&gt;
===By inspecting the potential energy surfaces, classify the F + H2 and H + HF reactions according to their energetics (endothermic or exothermic). How does this relate to the bond strength of the chemical species involved? ===&lt;br /&gt;
&#039;&#039;&#039;F+H2:&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
r(AB)=1.5,r(BC)=0.74, AB,BC m=0&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-01.png]]&lt;br /&gt;
&lt;br /&gt;
exothermic, because the trajectory goes from a higher PE to a lower PE.&lt;br /&gt;
&lt;br /&gt;
&#039;&#039;&#039;H+F2:&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
r(AB)=1.5,r(BC)=0.74, AB,BC m=0&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-02.png]]&lt;br /&gt;
&lt;br /&gt;
endothermic, because the trajectory goes from a lower PE to a higher PE.&lt;br /&gt;
&lt;br /&gt;
===Locate the approximate position of the transition state. ===&lt;br /&gt;
&#039;&#039;&#039;F+H2:&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
r(AB): 1.8108&lt;br /&gt;
r(BC): 0.744877&lt;br /&gt;
AB BC m: 0&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-03.png]]&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&#039;&#039;&#039;H+HF:&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
r(AB): 0.744877&lt;br /&gt;
r(BC): 1.8108&lt;br /&gt;
AB BC m: 0&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-04.png]]&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
===Report the activation energy for both reactions. ===&lt;br /&gt;
&#039;&#039;&#039;F+H2:&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
activation energy: 30 kcal/mol&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-05.png]]&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&#039;&#039;&#039;H+FH::&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
activation energy: 0.44kcal/mol&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-06.png]]&lt;br /&gt;
&lt;br /&gt;
=== In light of the fact that energy is conserved, discuss the mechanism of release of the reaction energy. Explain how this could be confirmed experimentally.===&lt;br /&gt;
&lt;br /&gt;
reactive trajectory:&lt;br /&gt;
&lt;br /&gt;
r(AB):1.6, r(BC):0.74, P AB:-0.5, P BC:0&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-07.png]]&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-08.png]]&lt;br /&gt;
&lt;br /&gt;
From the graph above, it is clearly shown that total energy remains the same. Kinetic energy increases to the same extent as potential energy decreases.&lt;br /&gt;
This proves that energy is conserved. This can be confirmed experimentally by measuring the kinetic and potential energy in the real experiment, ie measure temperature change and potential energy can be measured using this software.&lt;br /&gt;
&lt;br /&gt;
===Discuss how the distribution of energy between different modes (translation and vibration) affect the efficiency of the reaction, and how this is influenced by the position of the transition state. ===&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-09.png]]&lt;br /&gt;
&lt;br /&gt;
high translational energy, r(AB)=2, r(BC)=0.74, P AB=-7, P BC=0.5&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-10.png]]&lt;br /&gt;
&lt;br /&gt;
high vibrational energy, r(AB)=2, r(BC)=0.74, P AB=-1, P BC=6&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
The reaction is a late TS reaction, also Polanyi&#039;s empirical rules tells us that vibrational energy is more important in compare to vibrational energy in a late transition state reaction, which can also be proved in the graphs above.&lt;br /&gt;
&lt;br /&gt;
==&#039;&#039;&#039;References&#039;&#039;&#039;==&lt;br /&gt;
&amp;lt;references/&amp;gt;:&lt;/div&gt;</summary>
		<author><name>Ql2817</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=781451</id>
		<title>MRD:ql2817</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=781451"/>
		<updated>2019-05-16T15:42:45Z</updated>

		<summary type="html">&lt;p&gt;Ql2817: /* In light of the fact that energy is conserved, discuss the mechanism of release of the reaction energy. Explain how this could be confirmed experimentally. */&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;br /&gt;
== &#039;&#039;&#039;Question 1&#039;&#039;&#039; ==&lt;br /&gt;
&lt;br /&gt;
=== On a potential energy surface diagram, how is the transition state mathematically defined? How can the transition state be identified, and how can it be distinguished from a local minimum of the potential energy surface?===&lt;br /&gt;
&lt;br /&gt;
The transition state is defined as the maximum on the minimum energy path linking reactants and the products.It is located at the saddle point in the potential energy surface diagram, which defined as : ∂V(ri)/∂ri=0 and H &amp;lt; 0, where H = frr(r0​,V0​)fVV(r0​,V0​)−f2rV​(r0​,V0​) .&lt;br /&gt;
&lt;br /&gt;
The transition state is the specific combination of internuclear distances AB and BC at which the trajectory is a point on the contour plot.&lt;br /&gt;
&lt;br /&gt;
=== Report your best estimate of the transition state position (rts) and explain your reasoning illustrating it with a “Internuclear Distances vs Time” plot for a relevant trajectory. ===&lt;br /&gt;
When r(AB)=r(BC)=0.907 Å, p1 = p2 = 0.0, the transition state occurs. The internuclear distance vs time graph gives a relatively straight line which indicates a constant distance.&lt;br /&gt;
&lt;br /&gt;
=== Comment on how the mep and the trajectory you just calculated differ. ===&lt;br /&gt;
The mep trajectory keeps the potential energy at the minimum in a straight line, whereas the dynamic trajectory is wavy.&lt;br /&gt;
&lt;br /&gt;
r1 = 0.907, r2 = 0.917&lt;br /&gt;
&lt;br /&gt;
Molecules and atome moving away from each other.&lt;br /&gt;
&lt;br /&gt;
Setup a calculation where the initial positions correspond to the final positions of the trajectory you calculated above, the same final momenta values but with their signs reversed.&lt;br /&gt;
&lt;br /&gt;
r1 = rts+δ, r2 = rts&lt;br /&gt;
&lt;br /&gt;
final values of the positions r1(t) = 3.45, r2(t) = 0.72 and the average momenta  p1(t) = -1.45, p2(t) = -2.48 at large t.&lt;br /&gt;
&lt;br /&gt;
The molecule and the atom moving close together instead of moving apart.&lt;br /&gt;
&lt;br /&gt;
=== Complete the table above by adding the total energy, whether the trajectory is reactive or unreactive, and provide a plot of the trajectory and a small description for what happens along the trajectory. What can you conclude from the table? ===&lt;br /&gt;
&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot; border=&amp;quot;5&amp;quot;&lt;br /&gt;
! P1!!P2 !! Etot!! Reactive?!!Description of the dyanmics!!Illustration of the trajectory&lt;br /&gt;
|-&lt;br /&gt;
| -1.25 || -2.5|| -99.08|| yes||The trajectory goes through the transition state and also go into the products. ||[[File:Surface01_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -1.5|| -2.0|| -100.22|| no||The trajectory falls back down into the reactants because there was not enough energy for reactants to pass over the transition state. || [[File:Surface02_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -1.5||  -2.5|| -98.91|| yes||The trajectory goes through the transition state and also go into the products with enough energy. || [[File:Surface03_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -2.5|| -5.0|| -84.62|| no||The trajectory was carrying enough energy towards products but then it shifts back into the reactants. || [[File:Surface04_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -2.5||  -5.2|| -83.40|| yes||The trajectory goes through the transition state and also go into the products with enough energy. || [[File:Surface05_ql2817.png]]&lt;br /&gt;
|}&lt;br /&gt;
&lt;br /&gt;
=== State what are the main assumptions of Transition State Theory. Given the results you have obtained, how will Transition State Theory predictions for reaction rate values compare with experimental values? ===&lt;br /&gt;
Assumptions &amp;lt;ref name=&amp;quot;main&amp;quot;&amp;gt;https://en.wikibooks.org/wiki/Statistical_Thermodynamics_and_Rate_Theories/Eyring_Transition_State_Theory#Assumptions_of_Transition_State_Theory&lt;br /&gt;
&amp;lt;/ref&amp;gt;&lt;br /&gt;
&lt;br /&gt;
*Reactants are in constant equilibrium with the transition state structure.&lt;br /&gt;
*The energy of the particles follow a Boltzmann distribution.&lt;br /&gt;
*Once reactants become the transition state, the transition state structure does not collapse back to the reactants.&lt;br /&gt;
&lt;br /&gt;
Transition state theory will predict a higher reaction rate than experimental one.&lt;br /&gt;
&lt;br /&gt;
== &#039;&#039;&#039;Exercise 2: F-H-H system&#039;&#039;&#039; ==&lt;br /&gt;
&lt;br /&gt;
===By inspecting the potential energy surfaces, classify the F + H2 and H + HF reactions according to their energetics (endothermic or exothermic). How does this relate to the bond strength of the chemical species involved? ===&lt;br /&gt;
&#039;&#039;&#039;F+H2:&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
r(AB)=1.5,r(BC)=0.74, AB,BC m=0&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-01.png]]&lt;br /&gt;
&lt;br /&gt;
exothermic, because the trajectory goes from a higher PE to a lower PE.&lt;br /&gt;
&lt;br /&gt;
&#039;&#039;&#039;H+F2:&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
r(AB)=1.5,r(BC)=0.74, AB,BC m=0&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-02.png]]&lt;br /&gt;
&lt;br /&gt;
endothermic, because the trajectory goes from a lower PE to a higher PE.&lt;br /&gt;
&lt;br /&gt;
===Locate the approximate position of the transition state. ===&lt;br /&gt;
&#039;&#039;&#039;F+H2:&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
r(AB): 1.8108&lt;br /&gt;
r(BC): 0.744877&lt;br /&gt;
AB BC m: 0&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-03.png]]&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&#039;&#039;&#039;H+HF:&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
r(AB): 0.744877&lt;br /&gt;
r(BC): 1.8108&lt;br /&gt;
AB BC m: 0&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-04.png]]&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
===Report the activation energy for both reactions. ===&lt;br /&gt;
&#039;&#039;&#039;F+H2:&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
activation energy: 30 kcal/mol&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-05.png]]&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&#039;&#039;&#039;H+FH::&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
activation energy: 0.44kcal/mol&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-06.png]]&lt;br /&gt;
&lt;br /&gt;
=== In light of the fact that energy is conserved, discuss the mechanism of release of the reaction energy. Explain how this could be confirmed experimentally.===&lt;br /&gt;
&lt;br /&gt;
reactive trajectory:&lt;br /&gt;
&lt;br /&gt;
r(AB):1.6, r(BC):0.74, P AB:-0.5, P BC:0&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-07.png]]&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-08.png]]&lt;br /&gt;
&lt;br /&gt;
From the graph above, it is clearly shown that total energy remains the same. Kinetic energy increases to the same extent as potential energy decreases.&lt;br /&gt;
This proves that energy is conserved. This can be confirmed experimentally by measuring the kinetic and potential energy in the real experiment, ie measure temperature change and potential energy can be measured using this software.&lt;br /&gt;
&lt;br /&gt;
===Discuss how the distribution of energy between different modes (translation and vibration) affect the efficiency of the reaction, and how this is influenced by the position of the transition state. ===&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-09.png]]&lt;br /&gt;
&lt;br /&gt;
high translational energy, r(AB)=2, r(BC)=0.74, P AB=-7, P BC=0.5&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-10.png]]&lt;br /&gt;
&lt;br /&gt;
high vibrational energy, r(AB)=2, r(BC)=0.74, P AB=-1, P BC=6&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Polanyi&#039;s empirical rules tells us that vibrational energy is mor important in compare to vibrational energy, as shown in the graphs above.&lt;br /&gt;
&lt;br /&gt;
==&#039;&#039;&#039;References&#039;&#039;&#039;==&lt;br /&gt;
&amp;lt;references/&amp;gt;:&lt;/div&gt;</summary>
		<author><name>Ql2817</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=781399</id>
		<title>MRD:ql2817</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=781399"/>
		<updated>2019-05-16T15:35:52Z</updated>

		<summary type="html">&lt;p&gt;Ql2817: /* In light of the fact that energy is conserved, discuss the mechanism of release of the reaction energy. Explain how this could be confirmed experimentally. */&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;br /&gt;
== &#039;&#039;&#039;Question 1&#039;&#039;&#039; ==&lt;br /&gt;
&lt;br /&gt;
=== On a potential energy surface diagram, how is the transition state mathematically defined? How can the transition state be identified, and how can it be distinguished from a local minimum of the potential energy surface?===&lt;br /&gt;
&lt;br /&gt;
The transition state is defined as the maximum on the minimum energy path linking reactants and the products.It is located at the saddle point in the potential energy surface diagram, which defined as : ∂V(ri)/∂ri=0 and H &amp;lt; 0, where H = frr(r0​,V0​)fVV(r0​,V0​)−f2rV​(r0​,V0​) .&lt;br /&gt;
&lt;br /&gt;
The transition state is the specific combination of internuclear distances AB and BC at which the trajectory is a point on the contour plot.&lt;br /&gt;
&lt;br /&gt;
=== Report your best estimate of the transition state position (rts) and explain your reasoning illustrating it with a “Internuclear Distances vs Time” plot for a relevant trajectory. ===&lt;br /&gt;
When r(AB)=r(BC)=0.907 Å, p1 = p2 = 0.0, the transition state occurs. The internuclear distance vs time graph gives a relatively straight line which indicates a constant distance.&lt;br /&gt;
&lt;br /&gt;
=== Comment on how the mep and the trajectory you just calculated differ. ===&lt;br /&gt;
The mep trajectory keeps the potential energy at the minimum in a straight line, whereas the dynamic trajectory is wavy.&lt;br /&gt;
&lt;br /&gt;
r1 = 0.907, r2 = 0.917&lt;br /&gt;
&lt;br /&gt;
Molecules and atome moving away from each other.&lt;br /&gt;
&lt;br /&gt;
Setup a calculation where the initial positions correspond to the final positions of the trajectory you calculated above, the same final momenta values but with their signs reversed.&lt;br /&gt;
&lt;br /&gt;
r1 = rts+δ, r2 = rts&lt;br /&gt;
&lt;br /&gt;
final values of the positions r1(t) = 3.45, r2(t) = 0.72 and the average momenta  p1(t) = -1.45, p2(t) = -2.48 at large t.&lt;br /&gt;
&lt;br /&gt;
The molecule and the atom moving close together instead of moving apart.&lt;br /&gt;
&lt;br /&gt;
=== Complete the table above by adding the total energy, whether the trajectory is reactive or unreactive, and provide a plot of the trajectory and a small description for what happens along the trajectory. What can you conclude from the table? ===&lt;br /&gt;
&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot; border=&amp;quot;5&amp;quot;&lt;br /&gt;
! P1!!P2 !! Etot!! Reactive?!!Description of the dyanmics!!Illustration of the trajectory&lt;br /&gt;
|-&lt;br /&gt;
| -1.25 || -2.5|| -99.08|| yes||The trajectory goes through the transition state and also go into the products. ||[[File:Surface01_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -1.5|| -2.0|| -100.22|| no||The trajectory falls back down into the reactants because there was not enough energy for reactants to pass over the transition state. || [[File:Surface02_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -1.5||  -2.5|| -98.91|| yes||The trajectory goes through the transition state and also go into the products with enough energy. || [[File:Surface03_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -2.5|| -5.0|| -84.62|| no||The trajectory was carrying enough energy towards products but then it shifts back into the reactants. || [[File:Surface04_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -2.5||  -5.2|| -83.40|| yes||The trajectory goes through the transition state and also go into the products with enough energy. || [[File:Surface05_ql2817.png]]&lt;br /&gt;
|}&lt;br /&gt;
&lt;br /&gt;
=== State what are the main assumptions of Transition State Theory. Given the results you have obtained, how will Transition State Theory predictions for reaction rate values compare with experimental values? ===&lt;br /&gt;
Assumptions &amp;lt;ref name=&amp;quot;main&amp;quot;&amp;gt;https://en.wikibooks.org/wiki/Statistical_Thermodynamics_and_Rate_Theories/Eyring_Transition_State_Theory#Assumptions_of_Transition_State_Theory&lt;br /&gt;
&amp;lt;/ref&amp;gt;&lt;br /&gt;
&lt;br /&gt;
*Reactants are in constant equilibrium with the transition state structure.&lt;br /&gt;
*The energy of the particles follow a Boltzmann distribution.&lt;br /&gt;
*Once reactants become the transition state, the transition state structure does not collapse back to the reactants.&lt;br /&gt;
&lt;br /&gt;
Transition state theory will predict a higher reaction rate than experimental one.&lt;br /&gt;
&lt;br /&gt;
== &#039;&#039;&#039;Exercise 2: F-H-H system&#039;&#039;&#039; ==&lt;br /&gt;
&lt;br /&gt;
===By inspecting the potential energy surfaces, classify the F + H2 and H + HF reactions according to their energetics (endothermic or exothermic). How does this relate to the bond strength of the chemical species involved? ===&lt;br /&gt;
&#039;&#039;&#039;F+H2:&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
r(AB)=1.5,r(BC)=0.74, AB,BC m=0&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-01.png]]&lt;br /&gt;
&lt;br /&gt;
exothermic, because the trajectory goes from a higher PE to a lower PE.&lt;br /&gt;
&lt;br /&gt;
&#039;&#039;&#039;H+F2:&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
r(AB)=1.5,r(BC)=0.74, AB,BC m=0&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-02.png]]&lt;br /&gt;
&lt;br /&gt;
endothermic, because the trajectory goes from a lower PE to a higher PE.&lt;br /&gt;
&lt;br /&gt;
===Locate the approximate position of the transition state. ===&lt;br /&gt;
&#039;&#039;&#039;F+H2:&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
r(AB): 1.8108&lt;br /&gt;
r(BC): 0.744877&lt;br /&gt;
AB BC m: 0&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-03.png]]&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&#039;&#039;&#039;H+HF:&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
r(AB): 0.744877&lt;br /&gt;
r(BC): 1.8108&lt;br /&gt;
AB BC m: 0&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-04.png]]&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
===Report the activation energy for both reactions. ===&lt;br /&gt;
&#039;&#039;&#039;F+H2:&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
activation energy: 30 kcal/mol&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-05.png]]&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&#039;&#039;&#039;H+FH::&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
activation energy: 0.44kcal/mol&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-06.png]]&lt;br /&gt;
&lt;br /&gt;
=== In light of the fact that energy is conserved, discuss the mechanism of release of the reaction energy. Explain how this could be confirmed experimentally.===&lt;br /&gt;
&lt;br /&gt;
reactive trajectory:&lt;br /&gt;
&lt;br /&gt;
r(AB):1.6, r(BC):0.74, P AB:-0.5, P BC:0&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-07.png]]&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-08.png]]&lt;br /&gt;
&lt;br /&gt;
From the graph above, it is clearly shown that total energy remains the same. Kinetic energy increases to the same extent as potential energy decreases.&lt;br /&gt;
This proves that energy is conserved.&lt;br /&gt;
&lt;br /&gt;
===Discuss how the distribution of energy between different modes (translation and vibration) affect the efficiency of the reaction, and how this is influenced by the position of the transition state. ===&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-09.png]]&lt;br /&gt;
&lt;br /&gt;
high translational energy, r(AB)=2, r(BC)=0.74, P AB=-7, P BC=0.5&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-10.png]]&lt;br /&gt;
&lt;br /&gt;
high vibrational energy, r(AB)=2, r(BC)=0.74, P AB=-1, P BC=6&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Polanyi&#039;s empirical rules tells us that vibrational energy is mor important in compare to vibrational energy, as shown in the graphs above.&lt;br /&gt;
&lt;br /&gt;
==&#039;&#039;&#039;References&#039;&#039;&#039;==&lt;br /&gt;
&amp;lt;references/&amp;gt;:&lt;/div&gt;</summary>
		<author><name>Ql2817</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=781388</id>
		<title>MRD:ql2817</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=781388"/>
		<updated>2019-05-16T15:33:26Z</updated>

		<summary type="html">&lt;p&gt;Ql2817: /* Discuss how the distribution of energy between different modes (translation and vibration) affect the efficiency of the reaction, and how this is influenced by the position of the transition state. */&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;br /&gt;
== &#039;&#039;&#039;Question 1&#039;&#039;&#039; ==&lt;br /&gt;
&lt;br /&gt;
=== On a potential energy surface diagram, how is the transition state mathematically defined? How can the transition state be identified, and how can it be distinguished from a local minimum of the potential energy surface?===&lt;br /&gt;
&lt;br /&gt;
The transition state is defined as the maximum on the minimum energy path linking reactants and the products.It is located at the saddle point in the potential energy surface diagram, which defined as : ∂V(ri)/∂ri=0 and H &amp;lt; 0, where H = frr(r0​,V0​)fVV(r0​,V0​)−f2rV​(r0​,V0​) .&lt;br /&gt;
&lt;br /&gt;
The transition state is the specific combination of internuclear distances AB and BC at which the trajectory is a point on the contour plot.&lt;br /&gt;
&lt;br /&gt;
=== Report your best estimate of the transition state position (rts) and explain your reasoning illustrating it with a “Internuclear Distances vs Time” plot for a relevant trajectory. ===&lt;br /&gt;
When r(AB)=r(BC)=0.907 Å, p1 = p2 = 0.0, the transition state occurs. The internuclear distance vs time graph gives a relatively straight line which indicates a constant distance.&lt;br /&gt;
&lt;br /&gt;
=== Comment on how the mep and the trajectory you just calculated differ. ===&lt;br /&gt;
The mep trajectory keeps the potential energy at the minimum in a straight line, whereas the dynamic trajectory is wavy.&lt;br /&gt;
&lt;br /&gt;
r1 = 0.907, r2 = 0.917&lt;br /&gt;
&lt;br /&gt;
Molecules and atome moving away from each other.&lt;br /&gt;
&lt;br /&gt;
Setup a calculation where the initial positions correspond to the final positions of the trajectory you calculated above, the same final momenta values but with their signs reversed.&lt;br /&gt;
&lt;br /&gt;
r1 = rts+δ, r2 = rts&lt;br /&gt;
&lt;br /&gt;
final values of the positions r1(t) = 3.45, r2(t) = 0.72 and the average momenta  p1(t) = -1.45, p2(t) = -2.48 at large t.&lt;br /&gt;
&lt;br /&gt;
The molecule and the atom moving close together instead of moving apart.&lt;br /&gt;
&lt;br /&gt;
=== Complete the table above by adding the total energy, whether the trajectory is reactive or unreactive, and provide a plot of the trajectory and a small description for what happens along the trajectory. What can you conclude from the table? ===&lt;br /&gt;
&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot; border=&amp;quot;5&amp;quot;&lt;br /&gt;
! P1!!P2 !! Etot!! Reactive?!!Description of the dyanmics!!Illustration of the trajectory&lt;br /&gt;
|-&lt;br /&gt;
| -1.25 || -2.5|| -99.08|| yes||The trajectory goes through the transition state and also go into the products. ||[[File:Surface01_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -1.5|| -2.0|| -100.22|| no||The trajectory falls back down into the reactants because there was not enough energy for reactants to pass over the transition state. || [[File:Surface02_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -1.5||  -2.5|| -98.91|| yes||The trajectory goes through the transition state and also go into the products with enough energy. || [[File:Surface03_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -2.5|| -5.0|| -84.62|| no||The trajectory was carrying enough energy towards products but then it shifts back into the reactants. || [[File:Surface04_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -2.5||  -5.2|| -83.40|| yes||The trajectory goes through the transition state and also go into the products with enough energy. || [[File:Surface05_ql2817.png]]&lt;br /&gt;
|}&lt;br /&gt;
&lt;br /&gt;
=== State what are the main assumptions of Transition State Theory. Given the results you have obtained, how will Transition State Theory predictions for reaction rate values compare with experimental values? ===&lt;br /&gt;
Assumptions &amp;lt;ref name=&amp;quot;main&amp;quot;&amp;gt;https://en.wikibooks.org/wiki/Statistical_Thermodynamics_and_Rate_Theories/Eyring_Transition_State_Theory#Assumptions_of_Transition_State_Theory&lt;br /&gt;
&amp;lt;/ref&amp;gt;&lt;br /&gt;
&lt;br /&gt;
*Reactants are in constant equilibrium with the transition state structure.&lt;br /&gt;
*The energy of the particles follow a Boltzmann distribution.&lt;br /&gt;
*Once reactants become the transition state, the transition state structure does not collapse back to the reactants.&lt;br /&gt;
&lt;br /&gt;
Transition state theory will predict a higher reaction rate than experimental one.&lt;br /&gt;
&lt;br /&gt;
== &#039;&#039;&#039;Exercise 2: F-H-H system&#039;&#039;&#039; ==&lt;br /&gt;
&lt;br /&gt;
===By inspecting the potential energy surfaces, classify the F + H2 and H + HF reactions according to their energetics (endothermic or exothermic). How does this relate to the bond strength of the chemical species involved? ===&lt;br /&gt;
&#039;&#039;&#039;F+H2:&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
r(AB)=1.5,r(BC)=0.74, AB,BC m=0&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-01.png]]&lt;br /&gt;
&lt;br /&gt;
exothermic, because the trajectory goes from a higher PE to a lower PE.&lt;br /&gt;
&lt;br /&gt;
&#039;&#039;&#039;H+F2:&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
r(AB)=1.5,r(BC)=0.74, AB,BC m=0&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-02.png]]&lt;br /&gt;
&lt;br /&gt;
endothermic, because the trajectory goes from a lower PE to a higher PE.&lt;br /&gt;
&lt;br /&gt;
===Locate the approximate position of the transition state. ===&lt;br /&gt;
&#039;&#039;&#039;F+H2:&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
r(AB): 1.8108&lt;br /&gt;
r(BC): 0.744877&lt;br /&gt;
AB BC m: 0&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-03.png]]&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&#039;&#039;&#039;H+HF:&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
r(AB): 0.744877&lt;br /&gt;
r(BC): 1.8108&lt;br /&gt;
AB BC m: 0&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-04.png]]&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
===Report the activation energy for both reactions. ===&lt;br /&gt;
&#039;&#039;&#039;F+H2:&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
activation energy: 30 kcal/mol&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-05.png]]&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&#039;&#039;&#039;H+FH::&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
activation energy: 0.44kcal/mol&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-06.png]]&lt;br /&gt;
&lt;br /&gt;
=== In light of the fact that energy is conserved, discuss the mechanism of release of the reaction energy. Explain how this could be confirmed experimentally.===&lt;br /&gt;
&lt;br /&gt;
reactive trajectory:&lt;br /&gt;
&lt;br /&gt;
r(AB):1.6, r(BC):0.74, P AB:-0.5, P BC:0&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-07.png]]&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-08.png]]&lt;br /&gt;
&lt;br /&gt;
===Discuss how the distribution of energy between different modes (translation and vibration) affect the efficiency of the reaction, and how this is influenced by the position of the transition state. ===&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-09.png]]&lt;br /&gt;
&lt;br /&gt;
high translational energy, r(AB)=2, r(BC)=0.74, P AB=-7, P BC=0.5&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-10.png]]&lt;br /&gt;
&lt;br /&gt;
high vibrational energy, r(AB)=2, r(BC)=0.74, P AB=-1, P BC=6&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Polanyi&#039;s empirical rules tells us that vibrational energy is mor important in compare to vibrational energy, as shown in the graphs above.&lt;br /&gt;
&lt;br /&gt;
==&#039;&#039;&#039;References&#039;&#039;&#039;==&lt;br /&gt;
&amp;lt;references/&amp;gt;:&lt;/div&gt;</summary>
		<author><name>Ql2817</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=781372</id>
		<title>MRD:ql2817</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=781372"/>
		<updated>2019-05-16T15:30:16Z</updated>

		<summary type="html">&lt;p&gt;Ql2817: /* Discuss how the distribution of energy between different modes (translation and vibration) affect the efficiency of the reaction, and how this is influenced by the position of the transition state. */&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;br /&gt;
== &#039;&#039;&#039;Question 1&#039;&#039;&#039; ==&lt;br /&gt;
&lt;br /&gt;
=== On a potential energy surface diagram, how is the transition state mathematically defined? How can the transition state be identified, and how can it be distinguished from a local minimum of the potential energy surface?===&lt;br /&gt;
&lt;br /&gt;
The transition state is defined as the maximum on the minimum energy path linking reactants and the products.It is located at the saddle point in the potential energy surface diagram, which defined as : ∂V(ri)/∂ri=0 and H &amp;lt; 0, where H = frr(r0​,V0​)fVV(r0​,V0​)−f2rV​(r0​,V0​) .&lt;br /&gt;
&lt;br /&gt;
The transition state is the specific combination of internuclear distances AB and BC at which the trajectory is a point on the contour plot.&lt;br /&gt;
&lt;br /&gt;
=== Report your best estimate of the transition state position (rts) and explain your reasoning illustrating it with a “Internuclear Distances vs Time” plot for a relevant trajectory. ===&lt;br /&gt;
When r(AB)=r(BC)=0.907 Å, p1 = p2 = 0.0, the transition state occurs. The internuclear distance vs time graph gives a relatively straight line which indicates a constant distance.&lt;br /&gt;
&lt;br /&gt;
=== Comment on how the mep and the trajectory you just calculated differ. ===&lt;br /&gt;
The mep trajectory keeps the potential energy at the minimum in a straight line, whereas the dynamic trajectory is wavy.&lt;br /&gt;
&lt;br /&gt;
r1 = 0.907, r2 = 0.917&lt;br /&gt;
&lt;br /&gt;
Molecules and atome moving away from each other.&lt;br /&gt;
&lt;br /&gt;
Setup a calculation where the initial positions correspond to the final positions of the trajectory you calculated above, the same final momenta values but with their signs reversed.&lt;br /&gt;
&lt;br /&gt;
r1 = rts+δ, r2 = rts&lt;br /&gt;
&lt;br /&gt;
final values of the positions r1(t) = 3.45, r2(t) = 0.72 and the average momenta  p1(t) = -1.45, p2(t) = -2.48 at large t.&lt;br /&gt;
&lt;br /&gt;
The molecule and the atom moving close together instead of moving apart.&lt;br /&gt;
&lt;br /&gt;
=== Complete the table above by adding the total energy, whether the trajectory is reactive or unreactive, and provide a plot of the trajectory and a small description for what happens along the trajectory. What can you conclude from the table? ===&lt;br /&gt;
&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot; border=&amp;quot;5&amp;quot;&lt;br /&gt;
! P1!!P2 !! Etot!! Reactive?!!Description of the dyanmics!!Illustration of the trajectory&lt;br /&gt;
|-&lt;br /&gt;
| -1.25 || -2.5|| -99.08|| yes||The trajectory goes through the transition state and also go into the products. ||[[File:Surface01_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -1.5|| -2.0|| -100.22|| no||The trajectory falls back down into the reactants because there was not enough energy for reactants to pass over the transition state. || [[File:Surface02_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -1.5||  -2.5|| -98.91|| yes||The trajectory goes through the transition state and also go into the products with enough energy. || [[File:Surface03_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -2.5|| -5.0|| -84.62|| no||The trajectory was carrying enough energy towards products but then it shifts back into the reactants. || [[File:Surface04_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -2.5||  -5.2|| -83.40|| yes||The trajectory goes through the transition state and also go into the products with enough energy. || [[File:Surface05_ql2817.png]]&lt;br /&gt;
|}&lt;br /&gt;
&lt;br /&gt;
=== State what are the main assumptions of Transition State Theory. Given the results you have obtained, how will Transition State Theory predictions for reaction rate values compare with experimental values? ===&lt;br /&gt;
Assumptions &amp;lt;ref name=&amp;quot;main&amp;quot;&amp;gt;https://en.wikibooks.org/wiki/Statistical_Thermodynamics_and_Rate_Theories/Eyring_Transition_State_Theory#Assumptions_of_Transition_State_Theory&lt;br /&gt;
&amp;lt;/ref&amp;gt;&lt;br /&gt;
&lt;br /&gt;
*Reactants are in constant equilibrium with the transition state structure.&lt;br /&gt;
*The energy of the particles follow a Boltzmann distribution.&lt;br /&gt;
*Once reactants become the transition state, the transition state structure does not collapse back to the reactants.&lt;br /&gt;
&lt;br /&gt;
Transition state theory will predict a higher reaction rate than experimental one.&lt;br /&gt;
&lt;br /&gt;
== &#039;&#039;&#039;Exercise 2: F-H-H system&#039;&#039;&#039; ==&lt;br /&gt;
&lt;br /&gt;
===By inspecting the potential energy surfaces, classify the F + H2 and H + HF reactions according to their energetics (endothermic or exothermic). How does this relate to the bond strength of the chemical species involved? ===&lt;br /&gt;
&#039;&#039;&#039;F+H2:&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
r(AB)=1.5,r(BC)=0.74, AB,BC m=0&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-01.png]]&lt;br /&gt;
&lt;br /&gt;
exothermic, because the trajectory goes from a higher PE to a lower PE.&lt;br /&gt;
&lt;br /&gt;
&#039;&#039;&#039;H+F2:&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
r(AB)=1.5,r(BC)=0.74, AB,BC m=0&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-02.png]]&lt;br /&gt;
&lt;br /&gt;
endothermic, because the trajectory goes from a lower PE to a higher PE.&lt;br /&gt;
&lt;br /&gt;
===Locate the approximate position of the transition state. ===&lt;br /&gt;
&#039;&#039;&#039;F+H2:&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
r(AB): 1.8108&lt;br /&gt;
r(BC): 0.744877&lt;br /&gt;
AB BC m: 0&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-03.png]]&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&#039;&#039;&#039;H+HF:&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
r(AB): 0.744877&lt;br /&gt;
r(BC): 1.8108&lt;br /&gt;
AB BC m: 0&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-04.png]]&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
===Report the activation energy for both reactions. ===&lt;br /&gt;
&#039;&#039;&#039;F+H2:&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
activation energy: 30 kcal/mol&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-05.png]]&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&#039;&#039;&#039;H+FH::&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
activation energy: 0.44kcal/mol&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-06.png]]&lt;br /&gt;
&lt;br /&gt;
=== In light of the fact that energy is conserved, discuss the mechanism of release of the reaction energy. Explain how this could be confirmed experimentally.===&lt;br /&gt;
&lt;br /&gt;
reactive trajectory:&lt;br /&gt;
&lt;br /&gt;
r(AB):1.6, r(BC):0.74, P AB:-0.5, P BC:0&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-07.png]]&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-08.png]]&lt;br /&gt;
&lt;br /&gt;
===Discuss how the distribution of energy between different modes (translation and vibration) affect the efficiency of the reaction, and how this is influenced by the position of the transition state. ===&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-09.png]]&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-10.png]]&lt;br /&gt;
&lt;br /&gt;
==&#039;&#039;&#039;References&#039;&#039;&#039;==&lt;br /&gt;
&amp;lt;references/&amp;gt;:&lt;/div&gt;</summary>
		<author><name>Ql2817</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=File:Ql2817-10.png&amp;diff=781371</id>
		<title>File:Ql2817-10.png</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=File:Ql2817-10.png&amp;diff=781371"/>
		<updated>2019-05-16T15:29:32Z</updated>

		<summary type="html">&lt;p&gt;Ql2817: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;/div&gt;</summary>
		<author><name>Ql2817</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=File:Ql2817-09.png&amp;diff=781368</id>
		<title>File:Ql2817-09.png</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=File:Ql2817-09.png&amp;diff=781368"/>
		<updated>2019-05-16T15:29:18Z</updated>

		<summary type="html">&lt;p&gt;Ql2817: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;/div&gt;</summary>
		<author><name>Ql2817</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=781318</id>
		<title>MRD:ql2817</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=781318"/>
		<updated>2019-05-16T15:21:22Z</updated>

		<summary type="html">&lt;p&gt;Ql2817: /* In light of the fact that energy is conserved, discuss the mechanism of release of the reaction energy. Explain how this could be confirmed experimentally. */&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;br /&gt;
== &#039;&#039;&#039;Question 1&#039;&#039;&#039; ==&lt;br /&gt;
&lt;br /&gt;
=== On a potential energy surface diagram, how is the transition state mathematically defined? How can the transition state be identified, and how can it be distinguished from a local minimum of the potential energy surface?===&lt;br /&gt;
&lt;br /&gt;
The transition state is defined as the maximum on the minimum energy path linking reactants and the products.It is located at the saddle point in the potential energy surface diagram, which defined as : ∂V(ri)/∂ri=0 and H &amp;lt; 0, where H = frr(r0​,V0​)fVV(r0​,V0​)−f2rV​(r0​,V0​) .&lt;br /&gt;
&lt;br /&gt;
The transition state is the specific combination of internuclear distances AB and BC at which the trajectory is a point on the contour plot.&lt;br /&gt;
&lt;br /&gt;
=== Report your best estimate of the transition state position (rts) and explain your reasoning illustrating it with a “Internuclear Distances vs Time” plot for a relevant trajectory. ===&lt;br /&gt;
When r(AB)=r(BC)=0.907 Å, p1 = p2 = 0.0, the transition state occurs. The internuclear distance vs time graph gives a relatively straight line which indicates a constant distance.&lt;br /&gt;
&lt;br /&gt;
=== Comment on how the mep and the trajectory you just calculated differ. ===&lt;br /&gt;
The mep trajectory keeps the potential energy at the minimum in a straight line, whereas the dynamic trajectory is wavy.&lt;br /&gt;
&lt;br /&gt;
r1 = 0.907, r2 = 0.917&lt;br /&gt;
&lt;br /&gt;
Molecules and atome moving away from each other.&lt;br /&gt;
&lt;br /&gt;
Setup a calculation where the initial positions correspond to the final positions of the trajectory you calculated above, the same final momenta values but with their signs reversed.&lt;br /&gt;
&lt;br /&gt;
r1 = rts+δ, r2 = rts&lt;br /&gt;
&lt;br /&gt;
final values of the positions r1(t) = 3.45, r2(t) = 0.72 and the average momenta  p1(t) = -1.45, p2(t) = -2.48 at large t.&lt;br /&gt;
&lt;br /&gt;
The molecule and the atom moving close together instead of moving apart.&lt;br /&gt;
&lt;br /&gt;
=== Complete the table above by adding the total energy, whether the trajectory is reactive or unreactive, and provide a plot of the trajectory and a small description for what happens along the trajectory. What can you conclude from the table? ===&lt;br /&gt;
&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot; border=&amp;quot;5&amp;quot;&lt;br /&gt;
! P1!!P2 !! Etot!! Reactive?!!Description of the dyanmics!!Illustration of the trajectory&lt;br /&gt;
|-&lt;br /&gt;
| -1.25 || -2.5|| -99.08|| yes||The trajectory goes through the transition state and also go into the products. ||[[File:Surface01_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -1.5|| -2.0|| -100.22|| no||The trajectory falls back down into the reactants because there was not enough energy for reactants to pass over the transition state. || [[File:Surface02_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -1.5||  -2.5|| -98.91|| yes||The trajectory goes through the transition state and also go into the products with enough energy. || [[File:Surface03_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -2.5|| -5.0|| -84.62|| no||The trajectory was carrying enough energy towards products but then it shifts back into the reactants. || [[File:Surface04_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -2.5||  -5.2|| -83.40|| yes||The trajectory goes through the transition state and also go into the products with enough energy. || [[File:Surface05_ql2817.png]]&lt;br /&gt;
|}&lt;br /&gt;
&lt;br /&gt;
=== State what are the main assumptions of Transition State Theory. Given the results you have obtained, how will Transition State Theory predictions for reaction rate values compare with experimental values? ===&lt;br /&gt;
Assumptions &amp;lt;ref name=&amp;quot;main&amp;quot;&amp;gt;https://en.wikibooks.org/wiki/Statistical_Thermodynamics_and_Rate_Theories/Eyring_Transition_State_Theory#Assumptions_of_Transition_State_Theory&lt;br /&gt;
&amp;lt;/ref&amp;gt;&lt;br /&gt;
&lt;br /&gt;
*Reactants are in constant equilibrium with the transition state structure.&lt;br /&gt;
*The energy of the particles follow a Boltzmann distribution.&lt;br /&gt;
*Once reactants become the transition state, the transition state structure does not collapse back to the reactants.&lt;br /&gt;
&lt;br /&gt;
Transition state theory will predict a higher reaction rate than experimental one.&lt;br /&gt;
&lt;br /&gt;
== &#039;&#039;&#039;Exercise 2: F-H-H system&#039;&#039;&#039; ==&lt;br /&gt;
&lt;br /&gt;
===By inspecting the potential energy surfaces, classify the F + H2 and H + HF reactions according to their energetics (endothermic or exothermic). How does this relate to the bond strength of the chemical species involved? ===&lt;br /&gt;
&#039;&#039;&#039;F+H2:&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
r(AB)=1.5,r(BC)=0.74, AB,BC m=0&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-01.png]]&lt;br /&gt;
&lt;br /&gt;
exothermic, because the trajectory goes from a higher PE to a lower PE.&lt;br /&gt;
&lt;br /&gt;
&#039;&#039;&#039;H+F2:&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
r(AB)=1.5,r(BC)=0.74, AB,BC m=0&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-02.png]]&lt;br /&gt;
&lt;br /&gt;
endothermic, because the trajectory goes from a lower PE to a higher PE.&lt;br /&gt;
&lt;br /&gt;
===Locate the approximate position of the transition state. ===&lt;br /&gt;
&#039;&#039;&#039;F+H2:&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
r(AB): 1.8108&lt;br /&gt;
r(BC): 0.744877&lt;br /&gt;
AB BC m: 0&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-03.png]]&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&#039;&#039;&#039;H+HF:&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
r(AB): 0.744877&lt;br /&gt;
r(BC): 1.8108&lt;br /&gt;
AB BC m: 0&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-04.png]]&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
===Report the activation energy for both reactions. ===&lt;br /&gt;
&#039;&#039;&#039;F+H2:&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
activation energy: 30 kcal/mol&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-05.png]]&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&#039;&#039;&#039;H+FH::&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
activation energy: 0.44kcal/mol&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-06.png]]&lt;br /&gt;
&lt;br /&gt;
=== In light of the fact that energy is conserved, discuss the mechanism of release of the reaction energy. Explain how this could be confirmed experimentally.===&lt;br /&gt;
&lt;br /&gt;
reactive trajectory:&lt;br /&gt;
&lt;br /&gt;
r(AB):1.6, r(BC):0.74, P AB:-0.5, P BC:0&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-07.png]]&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-08.png]]&lt;br /&gt;
&lt;br /&gt;
===Discuss how the distribution of energy between different modes (translation and vibration) affect the efficiency of the reaction, and how this is influenced by the position of the transition state. ===&lt;br /&gt;
&lt;br /&gt;
==&#039;&#039;&#039;References&#039;&#039;&#039;==&lt;br /&gt;
&amp;lt;references/&amp;gt;:&lt;/div&gt;</summary>
		<author><name>Ql2817</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=File:Ql2817-08.png&amp;diff=781291</id>
		<title>File:Ql2817-08.png</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=File:Ql2817-08.png&amp;diff=781291"/>
		<updated>2019-05-16T15:18:21Z</updated>

		<summary type="html">&lt;p&gt;Ql2817: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;/div&gt;</summary>
		<author><name>Ql2817</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=File:Ql2817-07.png&amp;diff=781289</id>
		<title>File:Ql2817-07.png</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=File:Ql2817-07.png&amp;diff=781289"/>
		<updated>2019-05-16T15:18:07Z</updated>

		<summary type="html">&lt;p&gt;Ql2817: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;/div&gt;</summary>
		<author><name>Ql2817</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=781072</id>
		<title>MRD:ql2817</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=781072"/>
		<updated>2019-05-16T14:50:17Z</updated>

		<summary type="html">&lt;p&gt;Ql2817: /* Report the activation energy for both reactions. */&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;br /&gt;
== &#039;&#039;&#039;Question 1&#039;&#039;&#039; ==&lt;br /&gt;
&lt;br /&gt;
=== On a potential energy surface diagram, how is the transition state mathematically defined? How can the transition state be identified, and how can it be distinguished from a local minimum of the potential energy surface?===&lt;br /&gt;
&lt;br /&gt;
The transition state is defined as the maximum on the minimum energy path linking reactants and the products.It is located at the saddle point in the potential energy surface diagram, which defined as : ∂V(ri)/∂ri=0 and H &amp;lt; 0, where H = frr(r0​,V0​)fVV(r0​,V0​)−f2rV​(r0​,V0​) .&lt;br /&gt;
&lt;br /&gt;
The transition state is the specific combination of internuclear distances AB and BC at which the trajectory is a point on the contour plot.&lt;br /&gt;
&lt;br /&gt;
=== Report your best estimate of the transition state position (rts) and explain your reasoning illustrating it with a “Internuclear Distances vs Time” plot for a relevant trajectory. ===&lt;br /&gt;
When r(AB)=r(BC)=0.907 Å, p1 = p2 = 0.0, the transition state occurs. The internuclear distance vs time graph gives a relatively straight line which indicates a constant distance.&lt;br /&gt;
&lt;br /&gt;
=== Comment on how the mep and the trajectory you just calculated differ. ===&lt;br /&gt;
The mep trajectory keeps the potential energy at the minimum in a straight line, whereas the dynamic trajectory is wavy.&lt;br /&gt;
&lt;br /&gt;
r1 = 0.907, r2 = 0.917&lt;br /&gt;
&lt;br /&gt;
Molecules and atome moving away from each other.&lt;br /&gt;
&lt;br /&gt;
Setup a calculation where the initial positions correspond to the final positions of the trajectory you calculated above, the same final momenta values but with their signs reversed.&lt;br /&gt;
&lt;br /&gt;
r1 = rts+δ, r2 = rts&lt;br /&gt;
&lt;br /&gt;
final values of the positions r1(t) = 3.45, r2(t) = 0.72 and the average momenta  p1(t) = -1.45, p2(t) = -2.48 at large t.&lt;br /&gt;
&lt;br /&gt;
The molecule and the atom moving close together instead of moving apart.&lt;br /&gt;
&lt;br /&gt;
=== Complete the table above by adding the total energy, whether the trajectory is reactive or unreactive, and provide a plot of the trajectory and a small description for what happens along the trajectory. What can you conclude from the table? ===&lt;br /&gt;
&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot; border=&amp;quot;5&amp;quot;&lt;br /&gt;
! P1!!P2 !! Etot!! Reactive?!!Description of the dyanmics!!Illustration of the trajectory&lt;br /&gt;
|-&lt;br /&gt;
| -1.25 || -2.5|| -99.08|| yes||The trajectory goes through the transition state and also go into the products. ||[[File:Surface01_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -1.5|| -2.0|| -100.22|| no||The trajectory falls back down into the reactants because there was not enough energy for reactants to pass over the transition state. || [[File:Surface02_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -1.5||  -2.5|| -98.91|| yes||The trajectory goes through the transition state and also go into the products with enough energy. || [[File:Surface03_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -2.5|| -5.0|| -84.62|| no||The trajectory was carrying enough energy towards products but then it shifts back into the reactants. || [[File:Surface04_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -2.5||  -5.2|| -83.40|| yes||The trajectory goes through the transition state and also go into the products with enough energy. || [[File:Surface05_ql2817.png]]&lt;br /&gt;
|}&lt;br /&gt;
&lt;br /&gt;
=== State what are the main assumptions of Transition State Theory. Given the results you have obtained, how will Transition State Theory predictions for reaction rate values compare with experimental values? ===&lt;br /&gt;
Assumptions &amp;lt;ref name=&amp;quot;main&amp;quot;&amp;gt;https://en.wikibooks.org/wiki/Statistical_Thermodynamics_and_Rate_Theories/Eyring_Transition_State_Theory#Assumptions_of_Transition_State_Theory&lt;br /&gt;
&amp;lt;/ref&amp;gt;&lt;br /&gt;
&lt;br /&gt;
*Reactants are in constant equilibrium with the transition state structure.&lt;br /&gt;
*The energy of the particles follow a Boltzmann distribution.&lt;br /&gt;
*Once reactants become the transition state, the transition state structure does not collapse back to the reactants.&lt;br /&gt;
&lt;br /&gt;
Transition state theory will predict a higher reaction rate than experimental one.&lt;br /&gt;
&lt;br /&gt;
== &#039;&#039;&#039;Exercise 2: F-H-H system&#039;&#039;&#039; ==&lt;br /&gt;
&lt;br /&gt;
===By inspecting the potential energy surfaces, classify the F + H2 and H + HF reactions according to their energetics (endothermic or exothermic). How does this relate to the bond strength of the chemical species involved? ===&lt;br /&gt;
&#039;&#039;&#039;F+H2:&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
r(AB)=1.5,r(BC)=0.74, AB,BC m=0&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-01.png]]&lt;br /&gt;
&lt;br /&gt;
exothermic, because the trajectory goes from a higher PE to a lower PE.&lt;br /&gt;
&lt;br /&gt;
&#039;&#039;&#039;H+F2:&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
r(AB)=1.5,r(BC)=0.74, AB,BC m=0&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-02.png]]&lt;br /&gt;
&lt;br /&gt;
endothermic, because the trajectory goes from a lower PE to a higher PE.&lt;br /&gt;
&lt;br /&gt;
===Locate the approximate position of the transition state. ===&lt;br /&gt;
&#039;&#039;&#039;F+H2:&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
r(AB): 1.8108&lt;br /&gt;
r(BC): 0.744877&lt;br /&gt;
AB BC m: 0&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-03.png]]&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&#039;&#039;&#039;H+HF:&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
r(AB): 0.744877&lt;br /&gt;
r(BC): 1.8108&lt;br /&gt;
AB BC m: 0&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-04.png]]&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
===Report the activation energy for both reactions. ===&lt;br /&gt;
&#039;&#039;&#039;F+H2:&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
activation energy: 30 kcal/mol&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-05.png]]&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&#039;&#039;&#039;H+FH::&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
activation energy: 0.44kcal/mol&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-06.png]]&lt;br /&gt;
&lt;br /&gt;
=== In light of the fact that energy is conserved, discuss the mechanism of release of the reaction energy. Explain how this could be confirmed experimentally.===&lt;br /&gt;
&lt;br /&gt;
===Discuss how the distribution of energy between different modes (translation and vibration) affect the efficiency of the reaction, and how this is influenced by the position of the transition state. ===&lt;br /&gt;
&lt;br /&gt;
==&#039;&#039;&#039;References&#039;&#039;&#039;==&lt;br /&gt;
&amp;lt;references/&amp;gt;:&lt;/div&gt;</summary>
		<author><name>Ql2817</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=File:Ql2817-06.png&amp;diff=781065</id>
		<title>File:Ql2817-06.png</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=File:Ql2817-06.png&amp;diff=781065"/>
		<updated>2019-05-16T14:49:34Z</updated>

		<summary type="html">&lt;p&gt;Ql2817: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;/div&gt;</summary>
		<author><name>Ql2817</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=File:Ql2817-05.png&amp;diff=781062</id>
		<title>File:Ql2817-05.png</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=File:Ql2817-05.png&amp;diff=781062"/>
		<updated>2019-05-16T14:49:18Z</updated>

		<summary type="html">&lt;p&gt;Ql2817: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;/div&gt;</summary>
		<author><name>Ql2817</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=780712</id>
		<title>MRD:ql2817</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=780712"/>
		<updated>2019-05-16T14:05:05Z</updated>

		<summary type="html">&lt;p&gt;Ql2817: /* By inspecting the potential energy surfaces, classify the F + H2 and H + HF reactions according to their energetics (endothermic or exothermic). How does this relate to the bond strength of the chemical species involved? */&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;br /&gt;
== &#039;&#039;&#039;Question 1&#039;&#039;&#039; ==&lt;br /&gt;
&lt;br /&gt;
=== On a potential energy surface diagram, how is the transition state mathematically defined? How can the transition state be identified, and how can it be distinguished from a local minimum of the potential energy surface?===&lt;br /&gt;
&lt;br /&gt;
The transition state is defined as the maximum on the minimum energy path linking reactants and the products.It is located at the saddle point in the potential energy surface diagram, which defined as : ∂V(ri)/∂ri=0 and H &amp;lt; 0, where H = frr(r0​,V0​)fVV(r0​,V0​)−f2rV​(r0​,V0​) .&lt;br /&gt;
&lt;br /&gt;
The transition state is the specific combination of internuclear distances AB and BC at which the trajectory is a point on the contour plot.&lt;br /&gt;
&lt;br /&gt;
=== Report your best estimate of the transition state position (rts) and explain your reasoning illustrating it with a “Internuclear Distances vs Time” plot for a relevant trajectory. ===&lt;br /&gt;
When r(AB)=r(BC)=0.907 Å, p1 = p2 = 0.0, the transition state occurs. The internuclear distance vs time graph gives a relatively straight line which indicates a constant distance.&lt;br /&gt;
&lt;br /&gt;
=== Comment on how the mep and the trajectory you just calculated differ. ===&lt;br /&gt;
The mep trajectory keeps the potential energy at the minimum in a straight line, whereas the dynamic trajectory is wavy.&lt;br /&gt;
&lt;br /&gt;
r1 = 0.907, r2 = 0.917&lt;br /&gt;
&lt;br /&gt;
Molecules and atome moving away from each other.&lt;br /&gt;
&lt;br /&gt;
Setup a calculation where the initial positions correspond to the final positions of the trajectory you calculated above, the same final momenta values but with their signs reversed.&lt;br /&gt;
&lt;br /&gt;
r1 = rts+δ, r2 = rts&lt;br /&gt;
&lt;br /&gt;
final values of the positions r1(t) = 3.45, r2(t) = 0.72 and the average momenta  p1(t) = -1.45, p2(t) = -2.48 at large t.&lt;br /&gt;
&lt;br /&gt;
The molecule and the atom moving close together instead of moving apart.&lt;br /&gt;
&lt;br /&gt;
=== Complete the table above by adding the total energy, whether the trajectory is reactive or unreactive, and provide a plot of the trajectory and a small description for what happens along the trajectory. What can you conclude from the table? ===&lt;br /&gt;
&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot; border=&amp;quot;5&amp;quot;&lt;br /&gt;
! P1!!P2 !! Etot!! Reactive?!!Description of the dyanmics!!Illustration of the trajectory&lt;br /&gt;
|-&lt;br /&gt;
| -1.25 || -2.5|| -99.08|| yes||The trajectory goes through the transition state and also go into the products. ||[[File:Surface01_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -1.5|| -2.0|| -100.22|| no||The trajectory falls back down into the reactants because there was not enough energy for reactants to pass over the transition state. || [[File:Surface02_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -1.5||  -2.5|| -98.91|| yes||The trajectory goes through the transition state and also go into the products with enough energy. || [[File:Surface03_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -2.5|| -5.0|| -84.62|| no||The trajectory was carrying enough energy towards products but then it shifts back into the reactants. || [[File:Surface04_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -2.5||  -5.2|| -83.40|| yes||The trajectory goes through the transition state and also go into the products with enough energy. || [[File:Surface05_ql2817.png]]&lt;br /&gt;
|}&lt;br /&gt;
&lt;br /&gt;
=== State what are the main assumptions of Transition State Theory. Given the results you have obtained, how will Transition State Theory predictions for reaction rate values compare with experimental values? ===&lt;br /&gt;
Assumptions &amp;lt;ref name=&amp;quot;main&amp;quot;&amp;gt;https://en.wikibooks.org/wiki/Statistical_Thermodynamics_and_Rate_Theories/Eyring_Transition_State_Theory#Assumptions_of_Transition_State_Theory&lt;br /&gt;
&amp;lt;/ref&amp;gt;&lt;br /&gt;
&lt;br /&gt;
*Reactants are in constant equilibrium with the transition state structure.&lt;br /&gt;
*The energy of the particles follow a Boltzmann distribution.&lt;br /&gt;
*Once reactants become the transition state, the transition state structure does not collapse back to the reactants.&lt;br /&gt;
&lt;br /&gt;
Transition state theory will predict a higher reaction rate than experimental one.&lt;br /&gt;
&lt;br /&gt;
== &#039;&#039;&#039;Exercise 2: F-H-H system&#039;&#039;&#039; ==&lt;br /&gt;
&lt;br /&gt;
===By inspecting the potential energy surfaces, classify the F + H2 and H + HF reactions according to their energetics (endothermic or exothermic). How does this relate to the bond strength of the chemical species involved? ===&lt;br /&gt;
&#039;&#039;&#039;F+H2:&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
r(AB)=1.5,r(BC)=0.74, AB,BC m=0&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-01.png]]&lt;br /&gt;
&lt;br /&gt;
exothermic, because the trajectory goes from a higher PE to a lower PE.&lt;br /&gt;
&lt;br /&gt;
&#039;&#039;&#039;H+F2:&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
r(AB)=1.5,r(BC)=0.74, AB,BC m=0&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-02.png]]&lt;br /&gt;
&lt;br /&gt;
endothermic, because the trajectory goes from a lower PE to a higher PE.&lt;br /&gt;
&lt;br /&gt;
===Locate the approximate position of the transition state. ===&lt;br /&gt;
&#039;&#039;&#039;F+H2:&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
r(AB): 1.8108&lt;br /&gt;
r(BC): 0.744877&lt;br /&gt;
AB BC m: 0&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-03.png]]&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&#039;&#039;&#039;H+HF:&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
r(AB): 0.744877&lt;br /&gt;
r(BC): 1.8108&lt;br /&gt;
AB BC m: 0&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-04.png]]&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
===Report the activation energy for both reactions. ===&lt;br /&gt;
&lt;br /&gt;
=== In light of the fact that energy is conserved, discuss the mechanism of release of the reaction energy. Explain how this could be confirmed experimentally.===&lt;br /&gt;
&lt;br /&gt;
===Discuss how the distribution of energy between different modes (translation and vibration) affect the efficiency of the reaction, and how this is influenced by the position of the transition state. ===&lt;br /&gt;
&lt;br /&gt;
==&#039;&#039;&#039;References&#039;&#039;&#039;==&lt;br /&gt;
&amp;lt;references/&amp;gt;:&lt;/div&gt;</summary>
		<author><name>Ql2817</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=780705</id>
		<title>MRD:ql2817</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=780705"/>
		<updated>2019-05-16T14:04:18Z</updated>

		<summary type="html">&lt;p&gt;Ql2817: /* Exercise 2: F-H-H system */&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;br /&gt;
== &#039;&#039;&#039;Question 1&#039;&#039;&#039; ==&lt;br /&gt;
&lt;br /&gt;
=== On a potential energy surface diagram, how is the transition state mathematically defined? How can the transition state be identified, and how can it be distinguished from a local minimum of the potential energy surface?===&lt;br /&gt;
&lt;br /&gt;
The transition state is defined as the maximum on the minimum energy path linking reactants and the products.It is located at the saddle point in the potential energy surface diagram, which defined as : ∂V(ri)/∂ri=0 and H &amp;lt; 0, where H = frr(r0​,V0​)fVV(r0​,V0​)−f2rV​(r0​,V0​) .&lt;br /&gt;
&lt;br /&gt;
The transition state is the specific combination of internuclear distances AB and BC at which the trajectory is a point on the contour plot.&lt;br /&gt;
&lt;br /&gt;
=== Report your best estimate of the transition state position (rts) and explain your reasoning illustrating it with a “Internuclear Distances vs Time” plot for a relevant trajectory. ===&lt;br /&gt;
When r(AB)=r(BC)=0.907 Å, p1 = p2 = 0.0, the transition state occurs. The internuclear distance vs time graph gives a relatively straight line which indicates a constant distance.&lt;br /&gt;
&lt;br /&gt;
=== Comment on how the mep and the trajectory you just calculated differ. ===&lt;br /&gt;
The mep trajectory keeps the potential energy at the minimum in a straight line, whereas the dynamic trajectory is wavy.&lt;br /&gt;
&lt;br /&gt;
r1 = 0.907, r2 = 0.917&lt;br /&gt;
&lt;br /&gt;
Molecules and atome moving away from each other.&lt;br /&gt;
&lt;br /&gt;
Setup a calculation where the initial positions correspond to the final positions of the trajectory you calculated above, the same final momenta values but with their signs reversed.&lt;br /&gt;
&lt;br /&gt;
r1 = rts+δ, r2 = rts&lt;br /&gt;
&lt;br /&gt;
final values of the positions r1(t) = 3.45, r2(t) = 0.72 and the average momenta  p1(t) = -1.45, p2(t) = -2.48 at large t.&lt;br /&gt;
&lt;br /&gt;
The molecule and the atom moving close together instead of moving apart.&lt;br /&gt;
&lt;br /&gt;
=== Complete the table above by adding the total energy, whether the trajectory is reactive or unreactive, and provide a plot of the trajectory and a small description for what happens along the trajectory. What can you conclude from the table? ===&lt;br /&gt;
&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot; border=&amp;quot;5&amp;quot;&lt;br /&gt;
! P1!!P2 !! Etot!! Reactive?!!Description of the dyanmics!!Illustration of the trajectory&lt;br /&gt;
|-&lt;br /&gt;
| -1.25 || -2.5|| -99.08|| yes||The trajectory goes through the transition state and also go into the products. ||[[File:Surface01_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -1.5|| -2.0|| -100.22|| no||The trajectory falls back down into the reactants because there was not enough energy for reactants to pass over the transition state. || [[File:Surface02_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -1.5||  -2.5|| -98.91|| yes||The trajectory goes through the transition state and also go into the products with enough energy. || [[File:Surface03_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -2.5|| -5.0|| -84.62|| no||The trajectory was carrying enough energy towards products but then it shifts back into the reactants. || [[File:Surface04_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -2.5||  -5.2|| -83.40|| yes||The trajectory goes through the transition state and also go into the products with enough energy. || [[File:Surface05_ql2817.png]]&lt;br /&gt;
|}&lt;br /&gt;
&lt;br /&gt;
=== State what are the main assumptions of Transition State Theory. Given the results you have obtained, how will Transition State Theory predictions for reaction rate values compare with experimental values? ===&lt;br /&gt;
Assumptions &amp;lt;ref name=&amp;quot;main&amp;quot;&amp;gt;https://en.wikibooks.org/wiki/Statistical_Thermodynamics_and_Rate_Theories/Eyring_Transition_State_Theory#Assumptions_of_Transition_State_Theory&lt;br /&gt;
&amp;lt;/ref&amp;gt;&lt;br /&gt;
&lt;br /&gt;
*Reactants are in constant equilibrium with the transition state structure.&lt;br /&gt;
*The energy of the particles follow a Boltzmann distribution.&lt;br /&gt;
*Once reactants become the transition state, the transition state structure does not collapse back to the reactants.&lt;br /&gt;
&lt;br /&gt;
Transition state theory will predict a higher reaction rate than experimental one.&lt;br /&gt;
&lt;br /&gt;
== &#039;&#039;&#039;Exercise 2: F-H-H system&#039;&#039;&#039; ==&lt;br /&gt;
&lt;br /&gt;
===By inspecting the potential energy surfaces, classify the F + H2 and H + HF reactions according to their energetics (endothermic or exothermic). How does this relate to the bond strength of the chemical species involved? ===&lt;br /&gt;
&#039;&#039;&#039;F+H2:&lt;br /&gt;
&#039;&#039;&#039;r(AB)=1.5,r(BC)=0.74, AB,BC m=0&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-01.png]]&lt;br /&gt;
&lt;br /&gt;
exothermic, because the trajectory goes from a higher PE to a lower PE.&lt;br /&gt;
&lt;br /&gt;
&#039;&#039;&#039;H+F2:&lt;br /&gt;
&#039;&#039;&#039;r(AB)=1.5,r(BC)=0.74, AB,BC m=0&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-02.png]]&lt;br /&gt;
&lt;br /&gt;
endothermic, because the trajectory goes from a lower PE to a higher PE.&lt;br /&gt;
&lt;br /&gt;
===Locate the approximate position of the transition state. ===&lt;br /&gt;
&#039;&#039;&#039;F+H2:&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
r(AB): 1.8108&lt;br /&gt;
r(BC): 0.744877&lt;br /&gt;
AB BC m: 0&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-03.png]]&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&#039;&#039;&#039;H+HF:&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
r(AB): 0.744877&lt;br /&gt;
r(BC): 1.8108&lt;br /&gt;
AB BC m: 0&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-04.png]]&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
===Report the activation energy for both reactions. ===&lt;br /&gt;
&lt;br /&gt;
=== In light of the fact that energy is conserved, discuss the mechanism of release of the reaction energy. Explain how this could be confirmed experimentally.===&lt;br /&gt;
&lt;br /&gt;
===Discuss how the distribution of energy between different modes (translation and vibration) affect the efficiency of the reaction, and how this is influenced by the position of the transition state. ===&lt;br /&gt;
&lt;br /&gt;
==&#039;&#039;&#039;References&#039;&#039;&#039;==&lt;br /&gt;
&amp;lt;references/&amp;gt;:&lt;/div&gt;</summary>
		<author><name>Ql2817</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=File:Ql2817-04.png&amp;diff=780703</id>
		<title>File:Ql2817-04.png</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=File:Ql2817-04.png&amp;diff=780703"/>
		<updated>2019-05-16T14:04:11Z</updated>

		<summary type="html">&lt;p&gt;Ql2817: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;/div&gt;</summary>
		<author><name>Ql2817</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=780682</id>
		<title>MRD:ql2817</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=780682"/>
		<updated>2019-05-16T14:01:22Z</updated>

		<summary type="html">&lt;p&gt;Ql2817: /* Locate the approximate position of the transition state. */&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;br /&gt;
== &#039;&#039;&#039;Question 1&#039;&#039;&#039; ==&lt;br /&gt;
&lt;br /&gt;
=== On a potential energy surface diagram, how is the transition state mathematically defined? How can the transition state be identified, and how can it be distinguished from a local minimum of the potential energy surface?===&lt;br /&gt;
&lt;br /&gt;
The transition state is defined as the maximum on the minimum energy path linking reactants and the products.It is located at the saddle point in the potential energy surface diagram, which defined as : ∂V(ri)/∂ri=0 and H &amp;lt; 0, where H = frr(r0​,V0​)fVV(r0​,V0​)−f2rV​(r0​,V0​) .&lt;br /&gt;
&lt;br /&gt;
The transition state is the specific combination of internuclear distances AB and BC at which the trajectory is a point on the contour plot.&lt;br /&gt;
&lt;br /&gt;
=== Report your best estimate of the transition state position (rts) and explain your reasoning illustrating it with a “Internuclear Distances vs Time” plot for a relevant trajectory. ===&lt;br /&gt;
When r(AB)=r(BC)=0.907 Å, p1 = p2 = 0.0, the transition state occurs. The internuclear distance vs time graph gives a relatively straight line which indicates a constant distance.&lt;br /&gt;
&lt;br /&gt;
=== Comment on how the mep and the trajectory you just calculated differ. ===&lt;br /&gt;
The mep trajectory keeps the potential energy at the minimum in a straight line, whereas the dynamic trajectory is wavy.&lt;br /&gt;
&lt;br /&gt;
r1 = 0.907, r2 = 0.917&lt;br /&gt;
&lt;br /&gt;
Molecules and atome moving away from each other.&lt;br /&gt;
&lt;br /&gt;
Setup a calculation where the initial positions correspond to the final positions of the trajectory you calculated above, the same final momenta values but with their signs reversed.&lt;br /&gt;
&lt;br /&gt;
r1 = rts+δ, r2 = rts&lt;br /&gt;
&lt;br /&gt;
final values of the positions r1(t) = 3.45, r2(t) = 0.72 and the average momenta  p1(t) = -1.45, p2(t) = -2.48 at large t.&lt;br /&gt;
&lt;br /&gt;
The molecule and the atom moving close together instead of moving apart.&lt;br /&gt;
&lt;br /&gt;
=== Complete the table above by adding the total energy, whether the trajectory is reactive or unreactive, and provide a plot of the trajectory and a small description for what happens along the trajectory. What can you conclude from the table? ===&lt;br /&gt;
&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot; border=&amp;quot;5&amp;quot;&lt;br /&gt;
! P1!!P2 !! Etot!! Reactive?!!Description of the dyanmics!!Illustration of the trajectory&lt;br /&gt;
|-&lt;br /&gt;
| -1.25 || -2.5|| -99.08|| yes||The trajectory goes through the transition state and also go into the products. ||[[File:Surface01_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -1.5|| -2.0|| -100.22|| no||The trajectory falls back down into the reactants because there was not enough energy for reactants to pass over the transition state. || [[File:Surface02_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -1.5||  -2.5|| -98.91|| yes||The trajectory goes through the transition state and also go into the products with enough energy. || [[File:Surface03_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -2.5|| -5.0|| -84.62|| no||The trajectory was carrying enough energy towards products but then it shifts back into the reactants. || [[File:Surface04_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -2.5||  -5.2|| -83.40|| yes||The trajectory goes through the transition state and also go into the products with enough energy. || [[File:Surface05_ql2817.png]]&lt;br /&gt;
|}&lt;br /&gt;
&lt;br /&gt;
=== State what are the main assumptions of Transition State Theory. Given the results you have obtained, how will Transition State Theory predictions for reaction rate values compare with experimental values? ===&lt;br /&gt;
Assumptions &amp;lt;ref name=&amp;quot;main&amp;quot;&amp;gt;https://en.wikibooks.org/wiki/Statistical_Thermodynamics_and_Rate_Theories/Eyring_Transition_State_Theory#Assumptions_of_Transition_State_Theory&lt;br /&gt;
&amp;lt;/ref&amp;gt;&lt;br /&gt;
&lt;br /&gt;
*Reactants are in constant equilibrium with the transition state structure.&lt;br /&gt;
*The energy of the particles follow a Boltzmann distribution.&lt;br /&gt;
*Once reactants become the transition state, the transition state structure does not collapse back to the reactants.&lt;br /&gt;
&lt;br /&gt;
Transition state theory will predict a higher reaction rate than experimental one.&lt;br /&gt;
&lt;br /&gt;
== &#039;&#039;&#039;Exercise 2: F-H-H system&#039;&#039;&#039; ==&lt;br /&gt;
&lt;br /&gt;
===By inspecting the potential energy surfaces, classify the F + H2 and H + HF reactions according to their energetics (endothermic or exothermic). How does this relate to the bond strength of the chemical species involved? ===&lt;br /&gt;
&#039;&#039;&#039;F+H2:&lt;br /&gt;
&#039;&#039;&#039;r(AB)=1.5,r(BC)=0.74, AB,BC m=0&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-01.png]]&lt;br /&gt;
&lt;br /&gt;
exothermic, because the trajectory goes from a higher PE to a lower PE.&lt;br /&gt;
&lt;br /&gt;
&#039;&#039;&#039;H+F2:&lt;br /&gt;
&#039;&#039;&#039;r(AB)=1.5,r(BC)=0.74, AB,BC m=0&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-02.png]]&lt;br /&gt;
&lt;br /&gt;
endothermic, because the trajectory goes from a lower PE to a higher PE.&lt;br /&gt;
&lt;br /&gt;
===Locate the approximate position of the transition state. ===&lt;br /&gt;
&#039;&#039;&#039;F+H2:&#039;&#039;&#039;&lt;br /&gt;
&lt;br /&gt;
r(AB): 1.8108&lt;br /&gt;
r(BC): 0.744877&lt;br /&gt;
AB BC m: 0&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-03.png]]&lt;br /&gt;
&lt;br /&gt;
===Report the activation energy for both reactions. ===&lt;br /&gt;
&lt;br /&gt;
=== In light of the fact that energy is conserved, discuss the mechanism of release of the reaction energy. Explain how this could be confirmed experimentally.===&lt;br /&gt;
&lt;br /&gt;
===Discuss how the distribution of energy between different modes (translation and vibration) affect the efficiency of the reaction, and how this is influenced by the position of the transition state. ===&lt;br /&gt;
&lt;br /&gt;
==&#039;&#039;&#039;References&#039;&#039;&#039;==&lt;br /&gt;
&amp;lt;references/&amp;gt;:&lt;/div&gt;</summary>
		<author><name>Ql2817</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=File:Ql2817-03.png&amp;diff=780680</id>
		<title>File:Ql2817-03.png</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=File:Ql2817-03.png&amp;diff=780680"/>
		<updated>2019-05-16T14:01:08Z</updated>

		<summary type="html">&lt;p&gt;Ql2817: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;/div&gt;</summary>
		<author><name>Ql2817</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=780618</id>
		<title>MRD:ql2817</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=780618"/>
		<updated>2019-05-16T13:53:06Z</updated>

		<summary type="html">&lt;p&gt;Ql2817: /* Exercise 2: F-H-H system */&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;br /&gt;
== &#039;&#039;&#039;Question 1&#039;&#039;&#039; ==&lt;br /&gt;
&lt;br /&gt;
=== On a potential energy surface diagram, how is the transition state mathematically defined? How can the transition state be identified, and how can it be distinguished from a local minimum of the potential energy surface?===&lt;br /&gt;
&lt;br /&gt;
The transition state is defined as the maximum on the minimum energy path linking reactants and the products.It is located at the saddle point in the potential energy surface diagram, which defined as : ∂V(ri)/∂ri=0 and H &amp;lt; 0, where H = frr(r0​,V0​)fVV(r0​,V0​)−f2rV​(r0​,V0​) .&lt;br /&gt;
&lt;br /&gt;
The transition state is the specific combination of internuclear distances AB and BC at which the trajectory is a point on the contour plot.&lt;br /&gt;
&lt;br /&gt;
=== Report your best estimate of the transition state position (rts) and explain your reasoning illustrating it with a “Internuclear Distances vs Time” plot for a relevant trajectory. ===&lt;br /&gt;
When r(AB)=r(BC)=0.907 Å, p1 = p2 = 0.0, the transition state occurs. The internuclear distance vs time graph gives a relatively straight line which indicates a constant distance.&lt;br /&gt;
&lt;br /&gt;
=== Comment on how the mep and the trajectory you just calculated differ. ===&lt;br /&gt;
The mep trajectory keeps the potential energy at the minimum in a straight line, whereas the dynamic trajectory is wavy.&lt;br /&gt;
&lt;br /&gt;
r1 = 0.907, r2 = 0.917&lt;br /&gt;
&lt;br /&gt;
Molecules and atome moving away from each other.&lt;br /&gt;
&lt;br /&gt;
Setup a calculation where the initial positions correspond to the final positions of the trajectory you calculated above, the same final momenta values but with their signs reversed.&lt;br /&gt;
&lt;br /&gt;
r1 = rts+δ, r2 = rts&lt;br /&gt;
&lt;br /&gt;
final values of the positions r1(t) = 3.45, r2(t) = 0.72 and the average momenta  p1(t) = -1.45, p2(t) = -2.48 at large t.&lt;br /&gt;
&lt;br /&gt;
The molecule and the atom moving close together instead of moving apart.&lt;br /&gt;
&lt;br /&gt;
=== Complete the table above by adding the total energy, whether the trajectory is reactive or unreactive, and provide a plot of the trajectory and a small description for what happens along the trajectory. What can you conclude from the table? ===&lt;br /&gt;
&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot; border=&amp;quot;5&amp;quot;&lt;br /&gt;
! P1!!P2 !! Etot!! Reactive?!!Description of the dyanmics!!Illustration of the trajectory&lt;br /&gt;
|-&lt;br /&gt;
| -1.25 || -2.5|| -99.08|| yes||The trajectory goes through the transition state and also go into the products. ||[[File:Surface01_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -1.5|| -2.0|| -100.22|| no||The trajectory falls back down into the reactants because there was not enough energy for reactants to pass over the transition state. || [[File:Surface02_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -1.5||  -2.5|| -98.91|| yes||The trajectory goes through the transition state and also go into the products with enough energy. || [[File:Surface03_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -2.5|| -5.0|| -84.62|| no||The trajectory was carrying enough energy towards products but then it shifts back into the reactants. || [[File:Surface04_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -2.5||  -5.2|| -83.40|| yes||The trajectory goes through the transition state and also go into the products with enough energy. || [[File:Surface05_ql2817.png]]&lt;br /&gt;
|}&lt;br /&gt;
&lt;br /&gt;
=== State what are the main assumptions of Transition State Theory. Given the results you have obtained, how will Transition State Theory predictions for reaction rate values compare with experimental values? ===&lt;br /&gt;
Assumptions &amp;lt;ref name=&amp;quot;main&amp;quot;&amp;gt;https://en.wikibooks.org/wiki/Statistical_Thermodynamics_and_Rate_Theories/Eyring_Transition_State_Theory#Assumptions_of_Transition_State_Theory&lt;br /&gt;
&amp;lt;/ref&amp;gt;&lt;br /&gt;
&lt;br /&gt;
*Reactants are in constant equilibrium with the transition state structure.&lt;br /&gt;
*The energy of the particles follow a Boltzmann distribution.&lt;br /&gt;
*Once reactants become the transition state, the transition state structure does not collapse back to the reactants.&lt;br /&gt;
&lt;br /&gt;
Transition state theory will predict a higher reaction rate than experimental one.&lt;br /&gt;
&lt;br /&gt;
== &#039;&#039;&#039;Exercise 2: F-H-H system&#039;&#039;&#039; ==&lt;br /&gt;
&lt;br /&gt;
===By inspecting the potential energy surfaces, classify the F + H2 and H + HF reactions according to their energetics (endothermic or exothermic). How does this relate to the bond strength of the chemical species involved? ===&lt;br /&gt;
&#039;&#039;&#039;F+H2:&lt;br /&gt;
&#039;&#039;&#039;r(AB)=1.5,r(BC)=0.74, AB,BC m=0&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-01.png]]&lt;br /&gt;
&lt;br /&gt;
exothermic, because the trajectory goes from a higher PE to a lower PE.&lt;br /&gt;
&lt;br /&gt;
&#039;&#039;&#039;H+F2:&lt;br /&gt;
&#039;&#039;&#039;r(AB)=1.5,r(BC)=0.74, AB,BC m=0&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-02.png]]&lt;br /&gt;
&lt;br /&gt;
endothermic, because the trajectory goes from a lower PE to a higher PE.&lt;br /&gt;
&lt;br /&gt;
===Locate the approximate position of the transition state. ===&lt;br /&gt;
&lt;br /&gt;
===Report the activation energy for both reactions. ===&lt;br /&gt;
&lt;br /&gt;
=== In light of the fact that energy is conserved, discuss the mechanism of release of the reaction energy. Explain how this could be confirmed experimentally.===&lt;br /&gt;
&lt;br /&gt;
===Discuss how the distribution of energy between different modes (translation and vibration) affect the efficiency of the reaction, and how this is influenced by the position of the transition state. ===&lt;br /&gt;
&lt;br /&gt;
==&#039;&#039;&#039;References&#039;&#039;&#039;==&lt;br /&gt;
&amp;lt;references/&amp;gt;:&lt;/div&gt;</summary>
		<author><name>Ql2817</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=780611</id>
		<title>MRD:ql2817</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=780611"/>
		<updated>2019-05-16T13:52:31Z</updated>

		<summary type="html">&lt;p&gt;Ql2817: /* By inspecting the potential energy surfaces, classify the F + H2 and H + HF reactions according to their energetics (endothermic or exothermic). How does this relate to the bond strength of the chemical species involved? */&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;br /&gt;
== &#039;&#039;&#039;Question 1&#039;&#039;&#039; ==&lt;br /&gt;
&lt;br /&gt;
=== On a potential energy surface diagram, how is the transition state mathematically defined? How can the transition state be identified, and how can it be distinguished from a local minimum of the potential energy surface?===&lt;br /&gt;
&lt;br /&gt;
The transition state is defined as the maximum on the minimum energy path linking reactants and the products.It is located at the saddle point in the potential energy surface diagram, which defined as : ∂V(ri)/∂ri=0 and H &amp;lt; 0, where H = frr(r0​,V0​)fVV(r0​,V0​)−f2rV​(r0​,V0​) .&lt;br /&gt;
&lt;br /&gt;
The transition state is the specific combination of internuclear distances AB and BC at which the trajectory is a point on the contour plot.&lt;br /&gt;
&lt;br /&gt;
=== Report your best estimate of the transition state position (rts) and explain your reasoning illustrating it with a “Internuclear Distances vs Time” plot for a relevant trajectory. ===&lt;br /&gt;
When r(AB)=r(BC)=0.907 Å, p1 = p2 = 0.0, the transition state occurs. The internuclear distance vs time graph gives a relatively straight line which indicates a constant distance.&lt;br /&gt;
&lt;br /&gt;
=== Comment on how the mep and the trajectory you just calculated differ. ===&lt;br /&gt;
The mep trajectory keeps the potential energy at the minimum in a straight line, whereas the dynamic trajectory is wavy.&lt;br /&gt;
&lt;br /&gt;
r1 = 0.907, r2 = 0.917&lt;br /&gt;
&lt;br /&gt;
Molecules and atome moving away from each other.&lt;br /&gt;
&lt;br /&gt;
Setup a calculation where the initial positions correspond to the final positions of the trajectory you calculated above, the same final momenta values but with their signs reversed.&lt;br /&gt;
&lt;br /&gt;
r1 = rts+δ, r2 = rts&lt;br /&gt;
&lt;br /&gt;
final values of the positions r1(t) = 3.45, r2(t) = 0.72 and the average momenta  p1(t) = -1.45, p2(t) = -2.48 at large t.&lt;br /&gt;
&lt;br /&gt;
The molecule and the atom moving close together instead of moving apart.&lt;br /&gt;
&lt;br /&gt;
=== Complete the table above by adding the total energy, whether the trajectory is reactive or unreactive, and provide a plot of the trajectory and a small description for what happens along the trajectory. What can you conclude from the table? ===&lt;br /&gt;
&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot; border=&amp;quot;5&amp;quot;&lt;br /&gt;
! P1!!P2 !! Etot!! Reactive?!!Description of the dyanmics!!Illustration of the trajectory&lt;br /&gt;
|-&lt;br /&gt;
| -1.25 || -2.5|| -99.08|| yes||The trajectory goes through the transition state and also go into the products. ||[[File:Surface01_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -1.5|| -2.0|| -100.22|| no||The trajectory falls back down into the reactants because there was not enough energy for reactants to pass over the transition state. || [[File:Surface02_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -1.5||  -2.5|| -98.91|| yes||The trajectory goes through the transition state and also go into the products with enough energy. || [[File:Surface03_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -2.5|| -5.0|| -84.62|| no||The trajectory was carrying enough energy towards products but then it shifts back into the reactants. || [[File:Surface04_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -2.5||  -5.2|| -83.40|| yes||The trajectory goes through the transition state and also go into the products with enough energy. || [[File:Surface05_ql2817.png]]&lt;br /&gt;
|}&lt;br /&gt;
&lt;br /&gt;
=== State what are the main assumptions of Transition State Theory. Given the results you have obtained, how will Transition State Theory predictions for reaction rate values compare with experimental values? ===&lt;br /&gt;
Assumptions &amp;lt;ref name=&amp;quot;main&amp;quot;&amp;gt;https://en.wikibooks.org/wiki/Statistical_Thermodynamics_and_Rate_Theories/Eyring_Transition_State_Theory#Assumptions_of_Transition_State_Theory&lt;br /&gt;
&amp;lt;/ref&amp;gt;&lt;br /&gt;
&lt;br /&gt;
*Reactants are in constant equilibrium with the transition state structure.&lt;br /&gt;
*The energy of the particles follow a Boltzmann distribution.&lt;br /&gt;
*Once reactants become the transition state, the transition state structure does not collapse back to the reactants.&lt;br /&gt;
&lt;br /&gt;
Transition state theory will predict a higher reaction rate than experimental one.&lt;br /&gt;
&lt;br /&gt;
== &#039;&#039;&#039;Exercise 2: F-H-H system&#039;&#039;&#039; ==&lt;br /&gt;
&lt;br /&gt;
===By inspecting the potential energy surfaces, classify the F + H2 and H + HF reactions according to their energetics (endothermic or exothermic). How does this relate to the bond strength of the chemical species involved? ===&lt;br /&gt;
F+H2:&lt;br /&gt;
r(AB)=1.5,r(BC)=0.74, AB,BC m=0&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-01.png]]&lt;br /&gt;
&lt;br /&gt;
exothermic, because the trajectory goes from a higher PE to a lower PE.&lt;br /&gt;
H+F2:&lt;br /&gt;
&lt;br /&gt;
r(AB)=1.5,r(BC)=0.74, AB,BC m=0&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-02.png]]&lt;br /&gt;
&lt;br /&gt;
endothermic, because the trajectory goes from a lower PE to a higher PE.&lt;br /&gt;
&lt;br /&gt;
===Locate the approximate position of the transition state. ===&lt;br /&gt;
&lt;br /&gt;
===Report the activation energy for both reactions. ===&lt;br /&gt;
&lt;br /&gt;
=== In light of the fact that energy is conserved, discuss the mechanism of release of the reaction energy. Explain how this could be confirmed experimentally.===&lt;br /&gt;
&lt;br /&gt;
===Discuss how the distribution of energy between different modes (translation and vibration) affect the efficiency of the reaction, and how this is influenced by the position of the transition state. ===&lt;br /&gt;
&lt;br /&gt;
==&#039;&#039;&#039;References&#039;&#039;&#039;==&lt;br /&gt;
&amp;lt;references/&amp;gt;:&lt;/div&gt;</summary>
		<author><name>Ql2817</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=780605</id>
		<title>MRD:ql2817</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=780605"/>
		<updated>2019-05-16T13:52:07Z</updated>

		<summary type="html">&lt;p&gt;Ql2817: /* By inspecting the potential energy surfaces, classify the F + H2 and H + HF reactions according to their energetics (endothermic or exothermic). How does this relate to the bond strength of the chemical species involved? */&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;br /&gt;
== &#039;&#039;&#039;Question 1&#039;&#039;&#039; ==&lt;br /&gt;
&lt;br /&gt;
=== On a potential energy surface diagram, how is the transition state mathematically defined? How can the transition state be identified, and how can it be distinguished from a local minimum of the potential energy surface?===&lt;br /&gt;
&lt;br /&gt;
The transition state is defined as the maximum on the minimum energy path linking reactants and the products.It is located at the saddle point in the potential energy surface diagram, which defined as : ∂V(ri)/∂ri=0 and H &amp;lt; 0, where H = frr(r0​,V0​)fVV(r0​,V0​)−f2rV​(r0​,V0​) .&lt;br /&gt;
&lt;br /&gt;
The transition state is the specific combination of internuclear distances AB and BC at which the trajectory is a point on the contour plot.&lt;br /&gt;
&lt;br /&gt;
=== Report your best estimate of the transition state position (rts) and explain your reasoning illustrating it with a “Internuclear Distances vs Time” plot for a relevant trajectory. ===&lt;br /&gt;
When r(AB)=r(BC)=0.907 Å, p1 = p2 = 0.0, the transition state occurs. The internuclear distance vs time graph gives a relatively straight line which indicates a constant distance.&lt;br /&gt;
&lt;br /&gt;
=== Comment on how the mep and the trajectory you just calculated differ. ===&lt;br /&gt;
The mep trajectory keeps the potential energy at the minimum in a straight line, whereas the dynamic trajectory is wavy.&lt;br /&gt;
&lt;br /&gt;
r1 = 0.907, r2 = 0.917&lt;br /&gt;
&lt;br /&gt;
Molecules and atome moving away from each other.&lt;br /&gt;
&lt;br /&gt;
Setup a calculation where the initial positions correspond to the final positions of the trajectory you calculated above, the same final momenta values but with their signs reversed.&lt;br /&gt;
&lt;br /&gt;
r1 = rts+δ, r2 = rts&lt;br /&gt;
&lt;br /&gt;
final values of the positions r1(t) = 3.45, r2(t) = 0.72 and the average momenta  p1(t) = -1.45, p2(t) = -2.48 at large t.&lt;br /&gt;
&lt;br /&gt;
The molecule and the atom moving close together instead of moving apart.&lt;br /&gt;
&lt;br /&gt;
=== Complete the table above by adding the total energy, whether the trajectory is reactive or unreactive, and provide a plot of the trajectory and a small description for what happens along the trajectory. What can you conclude from the table? ===&lt;br /&gt;
&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot; border=&amp;quot;5&amp;quot;&lt;br /&gt;
! P1!!P2 !! Etot!! Reactive?!!Description of the dyanmics!!Illustration of the trajectory&lt;br /&gt;
|-&lt;br /&gt;
| -1.25 || -2.5|| -99.08|| yes||The trajectory goes through the transition state and also go into the products. ||[[File:Surface01_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -1.5|| -2.0|| -100.22|| no||The trajectory falls back down into the reactants because there was not enough energy for reactants to pass over the transition state. || [[File:Surface02_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -1.5||  -2.5|| -98.91|| yes||The trajectory goes through the transition state and also go into the products with enough energy. || [[File:Surface03_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -2.5|| -5.0|| -84.62|| no||The trajectory was carrying enough energy towards products but then it shifts back into the reactants. || [[File:Surface04_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -2.5||  -5.2|| -83.40|| yes||The trajectory goes through the transition state and also go into the products with enough energy. || [[File:Surface05_ql2817.png]]&lt;br /&gt;
|}&lt;br /&gt;
&lt;br /&gt;
=== State what are the main assumptions of Transition State Theory. Given the results you have obtained, how will Transition State Theory predictions for reaction rate values compare with experimental values? ===&lt;br /&gt;
Assumptions &amp;lt;ref name=&amp;quot;main&amp;quot;&amp;gt;https://en.wikibooks.org/wiki/Statistical_Thermodynamics_and_Rate_Theories/Eyring_Transition_State_Theory#Assumptions_of_Transition_State_Theory&lt;br /&gt;
&amp;lt;/ref&amp;gt;&lt;br /&gt;
&lt;br /&gt;
*Reactants are in constant equilibrium with the transition state structure.&lt;br /&gt;
*The energy of the particles follow a Boltzmann distribution.&lt;br /&gt;
*Once reactants become the transition state, the transition state structure does not collapse back to the reactants.&lt;br /&gt;
&lt;br /&gt;
Transition state theory will predict a higher reaction rate than experimental one.&lt;br /&gt;
&lt;br /&gt;
== &#039;&#039;&#039;Exercise 2: F-H-H system&#039;&#039;&#039; ==&lt;br /&gt;
&lt;br /&gt;
===By inspecting the potential energy surfaces, classify the F + H2 and H + HF reactions according to their energetics (endothermic or exothermic). How does this relate to the bond strength of the chemical species involved? ===&lt;br /&gt;
F+H2:&lt;br /&gt;
r(AB)=1.5,r(BC)=0.74, AB,BC m=0&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-01.png]]&lt;br /&gt;
&lt;br /&gt;
exothermic, because the trajectory goes from a higher PE to a lower PE.&lt;br /&gt;
H+F2:&lt;br /&gt;
r(AB)=1.5,r(BC)=0.74, AB,BC m=0&lt;br /&gt;
&lt;br /&gt;
[[File:ql2817-02.png]]&lt;br /&gt;
&lt;br /&gt;
endothermic, because the trajectory goes from a lower PE to a higher PE.&lt;br /&gt;
&lt;br /&gt;
===Locate the approximate position of the transition state. ===&lt;br /&gt;
&lt;br /&gt;
===Report the activation energy for both reactions. ===&lt;br /&gt;
&lt;br /&gt;
=== In light of the fact that energy is conserved, discuss the mechanism of release of the reaction energy. Explain how this could be confirmed experimentally.===&lt;br /&gt;
&lt;br /&gt;
===Discuss how the distribution of energy between different modes (translation and vibration) affect the efficiency of the reaction, and how this is influenced by the position of the transition state. ===&lt;br /&gt;
&lt;br /&gt;
==&#039;&#039;&#039;References&#039;&#039;&#039;==&lt;br /&gt;
&amp;lt;references/&amp;gt;:&lt;/div&gt;</summary>
		<author><name>Ql2817</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=780598</id>
		<title>MRD:ql2817</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=780598"/>
		<updated>2019-05-16T13:51:35Z</updated>

		<summary type="html">&lt;p&gt;Ql2817: /* Exercise 2: F-H-H system */&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;br /&gt;
== &#039;&#039;&#039;Question 1&#039;&#039;&#039; ==&lt;br /&gt;
&lt;br /&gt;
=== On a potential energy surface diagram, how is the transition state mathematically defined? How can the transition state be identified, and how can it be distinguished from a local minimum of the potential energy surface?===&lt;br /&gt;
&lt;br /&gt;
The transition state is defined as the maximum on the minimum energy path linking reactants and the products.It is located at the saddle point in the potential energy surface diagram, which defined as : ∂V(ri)/∂ri=0 and H &amp;lt; 0, where H = frr(r0​,V0​)fVV(r0​,V0​)−f2rV​(r0​,V0​) .&lt;br /&gt;
&lt;br /&gt;
The transition state is the specific combination of internuclear distances AB and BC at which the trajectory is a point on the contour plot.&lt;br /&gt;
&lt;br /&gt;
=== Report your best estimate of the transition state position (rts) and explain your reasoning illustrating it with a “Internuclear Distances vs Time” plot for a relevant trajectory. ===&lt;br /&gt;
When r(AB)=r(BC)=0.907 Å, p1 = p2 = 0.0, the transition state occurs. The internuclear distance vs time graph gives a relatively straight line which indicates a constant distance.&lt;br /&gt;
&lt;br /&gt;
=== Comment on how the mep and the trajectory you just calculated differ. ===&lt;br /&gt;
The mep trajectory keeps the potential energy at the minimum in a straight line, whereas the dynamic trajectory is wavy.&lt;br /&gt;
&lt;br /&gt;
r1 = 0.907, r2 = 0.917&lt;br /&gt;
&lt;br /&gt;
Molecules and atome moving away from each other.&lt;br /&gt;
&lt;br /&gt;
Setup a calculation where the initial positions correspond to the final positions of the trajectory you calculated above, the same final momenta values but with their signs reversed.&lt;br /&gt;
&lt;br /&gt;
r1 = rts+δ, r2 = rts&lt;br /&gt;
&lt;br /&gt;
final values of the positions r1(t) = 3.45, r2(t) = 0.72 and the average momenta  p1(t) = -1.45, p2(t) = -2.48 at large t.&lt;br /&gt;
&lt;br /&gt;
The molecule and the atom moving close together instead of moving apart.&lt;br /&gt;
&lt;br /&gt;
=== Complete the table above by adding the total energy, whether the trajectory is reactive or unreactive, and provide a plot of the trajectory and a small description for what happens along the trajectory. What can you conclude from the table? ===&lt;br /&gt;
&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot; border=&amp;quot;5&amp;quot;&lt;br /&gt;
! P1!!P2 !! Etot!! Reactive?!!Description of the dyanmics!!Illustration of the trajectory&lt;br /&gt;
|-&lt;br /&gt;
| -1.25 || -2.5|| -99.08|| yes||The trajectory goes through the transition state and also go into the products. ||[[File:Surface01_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -1.5|| -2.0|| -100.22|| no||The trajectory falls back down into the reactants because there was not enough energy for reactants to pass over the transition state. || [[File:Surface02_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -1.5||  -2.5|| -98.91|| yes||The trajectory goes through the transition state and also go into the products with enough energy. || [[File:Surface03_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -2.5|| -5.0|| -84.62|| no||The trajectory was carrying enough energy towards products but then it shifts back into the reactants. || [[File:Surface04_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -2.5||  -5.2|| -83.40|| yes||The trajectory goes through the transition state and also go into the products with enough energy. || [[File:Surface05_ql2817.png]]&lt;br /&gt;
|}&lt;br /&gt;
&lt;br /&gt;
=== State what are the main assumptions of Transition State Theory. Given the results you have obtained, how will Transition State Theory predictions for reaction rate values compare with experimental values? ===&lt;br /&gt;
Assumptions &amp;lt;ref name=&amp;quot;main&amp;quot;&amp;gt;https://en.wikibooks.org/wiki/Statistical_Thermodynamics_and_Rate_Theories/Eyring_Transition_State_Theory#Assumptions_of_Transition_State_Theory&lt;br /&gt;
&amp;lt;/ref&amp;gt;&lt;br /&gt;
&lt;br /&gt;
*Reactants are in constant equilibrium with the transition state structure.&lt;br /&gt;
*The energy of the particles follow a Boltzmann distribution.&lt;br /&gt;
*Once reactants become the transition state, the transition state structure does not collapse back to the reactants.&lt;br /&gt;
&lt;br /&gt;
Transition state theory will predict a higher reaction rate than experimental one.&lt;br /&gt;
&lt;br /&gt;
== &#039;&#039;&#039;Exercise 2: F-H-H system&#039;&#039;&#039; ==&lt;br /&gt;
&lt;br /&gt;
===By inspecting the potential energy surfaces, classify the F + H2 and H + HF reactions according to their energetics (endothermic or exothermic). How does this relate to the bond strength of the chemical species involved? ===&lt;br /&gt;
F+H2:&lt;br /&gt;
r(AB)=1.5,r(BC)=0.74, AB,BC m=0&lt;br /&gt;
[[File:ql2817-01.png]]&lt;br /&gt;
exothermic, because the trajectory goes from a higher PE to a lower PE.&lt;br /&gt;
H+F2:&lt;br /&gt;
r(AB)=1.5,r(BC)=0.74, AB,BC m=0&lt;br /&gt;
[[File:ql2817-02.png]]&lt;br /&gt;
endothermic, because the trajectory goes from a lower PE to a higher PE.&lt;br /&gt;
&lt;br /&gt;
===Locate the approximate position of the transition state. ===&lt;br /&gt;
&lt;br /&gt;
===Report the activation energy for both reactions. ===&lt;br /&gt;
&lt;br /&gt;
=== In light of the fact that energy is conserved, discuss the mechanism of release of the reaction energy. Explain how this could be confirmed experimentally.===&lt;br /&gt;
&lt;br /&gt;
===Discuss how the distribution of energy between different modes (translation and vibration) affect the efficiency of the reaction, and how this is influenced by the position of the transition state. ===&lt;br /&gt;
&lt;br /&gt;
==&#039;&#039;&#039;References&#039;&#039;&#039;==&lt;br /&gt;
&amp;lt;references/&amp;gt;:&lt;/div&gt;</summary>
		<author><name>Ql2817</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=File:Ql2817-02.png&amp;diff=780578</id>
		<title>File:Ql2817-02.png</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=File:Ql2817-02.png&amp;diff=780578"/>
		<updated>2019-05-16T13:49:52Z</updated>

		<summary type="html">&lt;p&gt;Ql2817: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;/div&gt;</summary>
		<author><name>Ql2817</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=File:Ql2817-01.png&amp;diff=780573</id>
		<title>File:Ql2817-01.png</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=File:Ql2817-01.png&amp;diff=780573"/>
		<updated>2019-05-16T13:49:27Z</updated>

		<summary type="html">&lt;p&gt;Ql2817: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;/div&gt;</summary>
		<author><name>Ql2817</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=780395</id>
		<title>MRD:ql2817</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=780395"/>
		<updated>2019-05-16T13:30:35Z</updated>

		<summary type="html">&lt;p&gt;Ql2817: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;br /&gt;
== &#039;&#039;&#039;Question 1&#039;&#039;&#039; ==&lt;br /&gt;
&lt;br /&gt;
=== On a potential energy surface diagram, how is the transition state mathematically defined? How can the transition state be identified, and how can it be distinguished from a local minimum of the potential energy surface?===&lt;br /&gt;
&lt;br /&gt;
The transition state is defined as the maximum on the minimum energy path linking reactants and the products.It is located at the saddle point in the potential energy surface diagram, which defined as : ∂V(ri)/∂ri=0 and H &amp;lt; 0, where H = frr(r0​,V0​)fVV(r0​,V0​)−f2rV​(r0​,V0​) .&lt;br /&gt;
&lt;br /&gt;
The transition state is the specific combination of internuclear distances AB and BC at which the trajectory is a point on the contour plot.&lt;br /&gt;
&lt;br /&gt;
=== Report your best estimate of the transition state position (rts) and explain your reasoning illustrating it with a “Internuclear Distances vs Time” plot for a relevant trajectory. ===&lt;br /&gt;
When r(AB)=r(BC)=0.907 Å, p1 = p2 = 0.0, the transition state occurs. The internuclear distance vs time graph gives a relatively straight line which indicates a constant distance.&lt;br /&gt;
&lt;br /&gt;
=== Comment on how the mep and the trajectory you just calculated differ. ===&lt;br /&gt;
The mep trajectory keeps the potential energy at the minimum in a straight line, whereas the dynamic trajectory is wavy.&lt;br /&gt;
&lt;br /&gt;
r1 = 0.907, r2 = 0.917&lt;br /&gt;
&lt;br /&gt;
Molecules and atome moving away from each other.&lt;br /&gt;
&lt;br /&gt;
Setup a calculation where the initial positions correspond to the final positions of the trajectory you calculated above, the same final momenta values but with their signs reversed.&lt;br /&gt;
&lt;br /&gt;
r1 = rts+δ, r2 = rts&lt;br /&gt;
&lt;br /&gt;
final values of the positions r1(t) = 3.45, r2(t) = 0.72 and the average momenta  p1(t) = -1.45, p2(t) = -2.48 at large t.&lt;br /&gt;
&lt;br /&gt;
The molecule and the atom moving close together instead of moving apart.&lt;br /&gt;
&lt;br /&gt;
=== Complete the table above by adding the total energy, whether the trajectory is reactive or unreactive, and provide a plot of the trajectory and a small description for what happens along the trajectory. What can you conclude from the table? ===&lt;br /&gt;
&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot; border=&amp;quot;5&amp;quot;&lt;br /&gt;
! P1!!P2 !! Etot!! Reactive?!!Description of the dyanmics!!Illustration of the trajectory&lt;br /&gt;
|-&lt;br /&gt;
| -1.25 || -2.5|| -99.08|| yes||The trajectory goes through the transition state and also go into the products. ||[[File:Surface01_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -1.5|| -2.0|| -100.22|| no||The trajectory falls back down into the reactants because there was not enough energy for reactants to pass over the transition state. || [[File:Surface02_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -1.5||  -2.5|| -98.91|| yes||The trajectory goes through the transition state and also go into the products with enough energy. || [[File:Surface03_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -2.5|| -5.0|| -84.62|| no||The trajectory was carrying enough energy towards products but then it shifts back into the reactants. || [[File:Surface04_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -2.5||  -5.2|| -83.40|| yes||The trajectory goes through the transition state and also go into the products with enough energy. || [[File:Surface05_ql2817.png]]&lt;br /&gt;
|}&lt;br /&gt;
&lt;br /&gt;
=== State what are the main assumptions of Transition State Theory. Given the results you have obtained, how will Transition State Theory predictions for reaction rate values compare with experimental values? ===&lt;br /&gt;
Assumptions &amp;lt;ref name=&amp;quot;main&amp;quot;&amp;gt;https://en.wikibooks.org/wiki/Statistical_Thermodynamics_and_Rate_Theories/Eyring_Transition_State_Theory#Assumptions_of_Transition_State_Theory&lt;br /&gt;
&amp;lt;/ref&amp;gt;&lt;br /&gt;
&lt;br /&gt;
*Reactants are in constant equilibrium with the transition state structure.&lt;br /&gt;
*The energy of the particles follow a Boltzmann distribution.&lt;br /&gt;
*Once reactants become the transition state, the transition state structure does not collapse back to the reactants.&lt;br /&gt;
&lt;br /&gt;
Transition state theory will predict a higher reaction rate than experimental one.&lt;br /&gt;
&lt;br /&gt;
== &#039;&#039;&#039;Exercise 2: F-H-H system&#039;&#039;&#039; ==&lt;br /&gt;
&lt;br /&gt;
===By inspecting the potential energy surfaces, classify the F + H2 and H + HF reactions according to their energetics (endothermic or exothermic). How does this relate to the bond strength of the chemical species involved? ===&lt;br /&gt;
&lt;br /&gt;
===Locate the approximate position of the transition state. ===&lt;br /&gt;
&lt;br /&gt;
===Report the activation energy for both reactions. ===&lt;br /&gt;
&lt;br /&gt;
=== In light of the fact that energy is conserved, discuss the mechanism of release of the reaction energy. Explain how this could be confirmed experimentally.===&lt;br /&gt;
&lt;br /&gt;
===Discuss how the distribution of energy between different modes (translation and vibration) affect the efficiency of the reaction, and how this is influenced by the position of the transition state. ===&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
==&#039;&#039;&#039;References&#039;&#039;&#039;==&lt;br /&gt;
&amp;lt;references/&amp;gt;:&lt;/div&gt;</summary>
		<author><name>Ql2817</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=780313</id>
		<title>MRD:ql2817</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=780313"/>
		<updated>2019-05-16T13:19:23Z</updated>

		<summary type="html">&lt;p&gt;Ql2817: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;br /&gt;
== &#039;&#039;&#039;Question 1&#039;&#039;&#039; ==&lt;br /&gt;
&lt;br /&gt;
=== On a potential energy surface diagram, how is the transition state mathematically defined? How can the transition state be identified, and how can it be distinguished from a local minimum of the potential energy surface?===&lt;br /&gt;
&lt;br /&gt;
The transition state is defined as the maximum on the minimum energy path linking reactants and the products.It is located at the saddle point in the potential energy surface diagram, which defined as : ∂V(ri)/∂ri=0 and H &amp;lt; 0, where H = frr(r0​,V0​)fVV(r0​,V0​)−f2rV​(r0​,V0​) .&lt;br /&gt;
&lt;br /&gt;
The transition state is the specific combination of internuclear distances AB and BC at which the trajectory is a point on the contour plot.&lt;br /&gt;
&lt;br /&gt;
=== Report your best estimate of the transition state position (rts) and explain your reasoning illustrating it with a “Internuclear Distances vs Time” plot for a relevant trajectory. ===&lt;br /&gt;
When r(AB)=r(BC)=0.907 Å, p1 = p2 = 0.0, the transition state occurs. The internuclear distance vs time graph gives a relatively straight line which indicates a constant distance.&lt;br /&gt;
&lt;br /&gt;
=== Comment on how the mep and the trajectory you just calculated differ. ===&lt;br /&gt;
The mep trajectory keeps the potential energy at the minimum in a straight line, whereas the dynamic trajectory is wavy.&lt;br /&gt;
&lt;br /&gt;
r1 = 0.907, r2 = 0.917&lt;br /&gt;
&lt;br /&gt;
Molecules and atome moving away from each other.&lt;br /&gt;
&lt;br /&gt;
Setup a calculation where the initial positions correspond to the final positions of the trajectory you calculated above, the same final momenta values but with their signs reversed.&lt;br /&gt;
&lt;br /&gt;
r1 = rts+δ, r2 = rts&lt;br /&gt;
&lt;br /&gt;
final values of the positions r1(t) = 3.45, r2(t) = 0.72 and the average momenta  p1(t) = -1.45, p2(t) = -2.48 at large t.&lt;br /&gt;
&lt;br /&gt;
The molecule and the atom moving close together instead of moving apart.&lt;br /&gt;
&lt;br /&gt;
=== Complete the table above by adding the total energy, whether the trajectory is reactive or unreactive, and provide a plot of the trajectory and a small description for what happens along the trajectory. What can you conclude from the table? ===&lt;br /&gt;
&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot; border=&amp;quot;5&amp;quot;&lt;br /&gt;
! P1!!P2 !! Etot!! Reactive?!!Description of the dyanmics!!Illustration of the trajectory&lt;br /&gt;
|-&lt;br /&gt;
| -1.25 || -2.5|| -99.08|| yes||The trajectory goes through the transition state and also go into the products. ||[[File:Surface01_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -1.5|| -2.0|| -100.22|| no||The trajectory falls back down into the reactants because there was not enough energy for reactants to pass over the transition state. || [[File:Surface02_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -1.5||  -2.5|| -98.91|| yes||The trajectory goes through the transition state and also go into the products with enough energy. || [[File:Surface03_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -2.5|| -5.0|| -84.62|| no||The trajectory was carrying enough energy towards products but then it shifts back into the reactants. || [[File:Surface04_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -2.5||  -5.2|| -83.40|| yes||The trajectory goes through the transition state and also go into the products with enough energy. || [[File:Surface05_ql2817.png]]&lt;br /&gt;
|}&lt;br /&gt;
&lt;br /&gt;
=== State what are the main assumptions of Transition State Theory. Given the results you have obtained, how will Transition State Theory predictions for reaction rate values compare with experimental values? ===&lt;br /&gt;
Assumptions &amp;lt;ref name=&amp;quot;main&amp;quot;&amp;gt;https://en.wikibooks.org/wiki/Statistical_Thermodynamics_and_Rate_Theories/Eyring_Transition_State_Theory#Assumptions_of_Transition_State_Theory&lt;br /&gt;
&amp;lt;/ref&amp;gt;&lt;br /&gt;
&lt;br /&gt;
*Reactants are in constant equilibrium with the transition state structure.&lt;br /&gt;
*The energy of the particles follow a Boltzmann distribution.&lt;br /&gt;
*Once reactants become the transition state, the transition state structure does not collapse back to the reactants.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
==&#039;&#039;&#039;References&#039;&#039;&#039;==&lt;br /&gt;
&amp;lt;references/&amp;gt;:&lt;/div&gt;</summary>
		<author><name>Ql2817</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=778348</id>
		<title>MRD:ql2817</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=778348"/>
		<updated>2019-05-14T16:13:21Z</updated>

		<summary type="html">&lt;p&gt;Ql2817: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;br /&gt;
== &#039;&#039;&#039;Question 1&#039;&#039;&#039; ==&lt;br /&gt;
&lt;br /&gt;
=== On a potential energy surface diagram, how is the transition state mathematically defined? How can the transition state be identified, and how can it be distinguished from a local minimum of the potential energy surface?===&lt;br /&gt;
&lt;br /&gt;
The transition state is defined as the maximum on the minimum energy path linking reactants and the products.It is located at the saddle point in the potential energy surface diagram, which defined as : ∂V(ri)/∂ri=0 and H &amp;lt; 0, where H = frr(r0​,V0​)fVV(r0​,V0​)−f2rV​(r0​,V0​) .&lt;br /&gt;
&lt;br /&gt;
The transition state is the specific combination of internuclear distances AB and BC at which the trajectory is a point on the contour plot.&lt;br /&gt;
&lt;br /&gt;
=== Report your best estimate of the transition state position (rts) and explain your reasoning illustrating it with a “Internuclear Distances vs Time” plot for a relevant trajectory. ===&lt;br /&gt;
When r(AB)=r(BC)=0.907 Å, p1 = p2 = 0.0, the transition state occurs. The internuclear distance vs time graph gives a relatively straight line which indicates a constant distance.&lt;br /&gt;
&lt;br /&gt;
=== Comment on how the mep and the trajectory you just calculated differ. ===&lt;br /&gt;
The mep trajectory keeps the potential energy at the minimum in a straight line, whereas the dynamic trajectory is wavy.&lt;br /&gt;
&lt;br /&gt;
r1 = 0.907, r2 = 0.917&lt;br /&gt;
&lt;br /&gt;
Molecules and atome moving away from each other.&lt;br /&gt;
&lt;br /&gt;
Setup a calculation where the initial positions correspond to the final positions of the trajectory you calculated above, the same final momenta values but with their signs reversed.&lt;br /&gt;
&lt;br /&gt;
r1 = rts+δ, r2 = rts&lt;br /&gt;
&lt;br /&gt;
final values of the positions r1(t) = 3.45, r2(t) = 0.72 and the average momenta  p1(t) = -1.45, p2(t) = -2.48 at large t.&lt;br /&gt;
&lt;br /&gt;
The molecule and the atom moving close together instead of moving apart.&lt;br /&gt;
&lt;br /&gt;
=== Complete the table above by adding the total energy, whether the trajectory is reactive or unreactive, and provide a plot of the trajectory and a small description for what happens along the trajectory. What can you conclude from the table? ===&lt;br /&gt;
&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot; border=&amp;quot;5&amp;quot;&lt;br /&gt;
! P1!!P2 !! Etot!! Reactive?!!Description of the dyanmics!!Illustration of the trajectory&lt;br /&gt;
|-&lt;br /&gt;
| -1.25 || -2.5|| -99.08|| yes||The trajectory goes through the transition state and also go into the products. ||[[File:Surface01_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -1.5|| -2.0|| -100.22|| no||The trajectory falls back down into the reactants because there was not enough energy for reactants to pass over the transition state. || [[File:Surface02_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -1.5||  -2.5|| -98.91|| yes||The trajectory goes through the transition state and also go into the products with enough energy. || [[File:Surface03_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -2.5|| -5.0|| -84.62|| no||The trajectory was carrying enough energy towards products but then it shifts back into the reactants. || [[File:Surface04_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -2.5||  -5.2|| -83.40|| yes||The trajectory goes through the transition state and also go into the products with enough energy. || [[File:Surface05_ql2817.png]]&lt;br /&gt;
|}&lt;br /&gt;
&lt;br /&gt;
=== State what are the main assumptions of Transition State Theory. Given the results you have obtained, how will Transition State Theory predictions for reaction rate values compare with experimental values? ===&lt;br /&gt;
Assumptions &amp;lt;ref name=&amp;quot;main&amp;quot;&amp;gt;https://en.wikibooks.org/wiki/Statistical_Thermodynamics_and_Rate_Theories/Eyring_Transition_State_Theory#Assumptions_of_Transition_State_Theory&lt;br /&gt;
&amp;lt;/ref&amp;gt;&lt;br /&gt;
&lt;br /&gt;
*Reactants are in constant equilibrium with the transition state structure.&lt;br /&gt;
*The energy of the particles follow a Boltzmann distribution.&lt;br /&gt;
*Once reactants become the transition state, the transition state structure does not collapse back to the reactants.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
==&#039;&#039;&#039;References&#039;&#039;&#039;==&lt;br /&gt;
&amp;lt;references/&amp;gt;:&lt;br /&gt;
&lt;br /&gt;
*Reactants are in constant equilibrium with the transition state structure.&lt;br /&gt;
*The energy of the particles follow a Boltzmann distribution.&lt;br /&gt;
*Once reactants become the transition state, the transition state structure does not collapse back to the reactants.&lt;/div&gt;</summary>
		<author><name>Ql2817</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=778334</id>
		<title>MRD:ql2817</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=778334"/>
		<updated>2019-05-14T16:10:00Z</updated>

		<summary type="html">&lt;p&gt;Ql2817: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;br /&gt;
== &#039;&#039;&#039;Question 1&#039;&#039;&#039; ==&lt;br /&gt;
&lt;br /&gt;
=== On a potential energy surface diagram, how is the transition state mathematically defined? How can the transition state be identified, and how can it be distinguished from a local minimum of the potential energy surface?===&lt;br /&gt;
&lt;br /&gt;
The transition state is defined as the maximum on the minimum energy path linking reactants and the products.It is located at the saddle point in the potential energy surface diagram, which defined as : ∂V(ri)/∂ri=0 and H &amp;lt; 0, where H = frr(r0​,V0​)fVV(r0​,V0​)−f2rV​(r0​,V0​) .&lt;br /&gt;
&lt;br /&gt;
The transition state is the specific combination of internuclear distances AB and BC at which the trajectory is a point on the contour plot.&lt;br /&gt;
&lt;br /&gt;
=== Report your best estimate of the transition state position (rts) and explain your reasoning illustrating it with a “Internuclear Distances vs Time” plot for a relevant trajectory. ===&lt;br /&gt;
When r(AB)=r(BC)=0.907 Å, p1 = p2 = 0.0, the transition state occurs. The internuclear distance vs time graph gives a relatively straight line which indicates a constant distance.&lt;br /&gt;
&lt;br /&gt;
=== Comment on how the mep and the trajectory you just calculated differ. ===&lt;br /&gt;
The mep trajectory keeps the potential energy at the minimum in a straight line, whereas the dynamic trajectory is wavy.&lt;br /&gt;
&lt;br /&gt;
r1 = 0.907, r2 = 0.917&lt;br /&gt;
&lt;br /&gt;
Molecules and atome moving away from each other.&lt;br /&gt;
&lt;br /&gt;
Setup a calculation where the initial positions correspond to the final positions of the trajectory you calculated above, the same final momenta values but with their signs reversed.&lt;br /&gt;
&lt;br /&gt;
r1 = rts+δ, r2 = rts&lt;br /&gt;
&lt;br /&gt;
final values of the positions r1(t) = 3.45, r2(t) = 0.72 and the average momenta  p1(t) = -1.45, p2(t) = -2.48 at large t.&lt;br /&gt;
&lt;br /&gt;
The molecule and the atom moving close together instead of moving apart.&lt;br /&gt;
&lt;br /&gt;
=== Complete the table above by adding the total energy, whether the trajectory is reactive or unreactive, and provide a plot of the trajectory and a small description for what happens along the trajectory. What can you conclude from the table? ===&lt;br /&gt;
&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot; border=&amp;quot;5&amp;quot;&lt;br /&gt;
! P1!!P2 !! Etot!! Reactive?!!Description of the dyanmics!!Illustration of the trajectory&lt;br /&gt;
|-&lt;br /&gt;
| -1.25 || -2.5|| -99.08|| yes||The trajectory goes through the transition state and also go into the products. ||[[File:Surface01_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -1.5|| -2.0|| -100.22|| no||The trajectory falls back down into the reactants because there was not enough energy for reactants to pass over the transition state. || [[File:Surface02_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -1.5||  -2.5|| -98.91|| yes||The trajectory goes through the transition state and also go into the products with enough energy. || [[File:Surface03_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -2.5|| -5.0|| -84.62|| no||The trajectory was carrying enough energy towards products but then it shifts back into the reactants. || [[File:Surface04_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -2.5||  -5.2|| -83.40|| yes||The trajectory goes through the transition state and also go into the products with enough energy. || [[File:Surface05_ql2817.png]]&lt;br /&gt;
|}&lt;br /&gt;
&lt;br /&gt;
=== State what are the main assumptions of Transition State Theory. Given the results you have obtained, how will Transition State Theory predictions for reaction rate values compare with experimental values? ===&lt;br /&gt;
Assumptions &amp;lt;ref&amp;gt;&lt;br /&gt;
&lt;br /&gt;
*Reactants are in constant equilibrium with the transition state structure.&lt;br /&gt;
*The energy of the particles follow a Boltzmann distribution.&lt;br /&gt;
*Once reactants become the transition state, the transition state structure does not collapse back to the reactants.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
== &#039;&#039;&#039;Reference&#039;&#039;&#039; ==&lt;br /&gt;
1.https://en.wikibooks.org/wiki/Statistical_Thermodynamics_and_Rate_Theories/Eyring_Transition_State_Theory#Assumptions_of_Transition_State_Theory&lt;/div&gt;</summary>
		<author><name>Ql2817</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=778332</id>
		<title>MRD:ql2817</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=778332"/>
		<updated>2019-05-14T16:09:36Z</updated>

		<summary type="html">&lt;p&gt;Ql2817: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;br /&gt;
== &#039;&#039;&#039;Question 1&#039;&#039;&#039; ==&lt;br /&gt;
&lt;br /&gt;
=== On a potential energy surface diagram, how is the transition state mathematically defined? How can the transition state be identified, and how can it be distinguished from a local minimum of the potential energy surface?===&lt;br /&gt;
&lt;br /&gt;
The transition state is defined as the maximum on the minimum energy path linking reactants and the products.It is located at the saddle point in the potential energy surface diagram, which defined as : ∂V(ri)/∂ri=0 and H &amp;lt; 0, where H = frr(r0​,V0​)fVV(r0​,V0​)−f2rV​(r0​,V0​) .&lt;br /&gt;
&lt;br /&gt;
The transition state is the specific combination of internuclear distances AB and BC at which the trajectory is a point on the contour plot.&lt;br /&gt;
&lt;br /&gt;
=== Report your best estimate of the transition state position (rts) and explain your reasoning illustrating it with a “Internuclear Distances vs Time” plot for a relevant trajectory. ===&lt;br /&gt;
When r(AB)=r(BC)=0.907 Å, p1 = p2 = 0.0, the transition state occurs. The internuclear distance vs time graph gives a relatively straight line which indicates a constant distance.&lt;br /&gt;
&lt;br /&gt;
=== Comment on how the mep and the trajectory you just calculated differ. ===&lt;br /&gt;
The mep trajectory keeps the potential energy at the minimum in a straight line, whereas the dynamic trajectory is wavy.&lt;br /&gt;
&lt;br /&gt;
r1 = 0.907, r2 = 0.917&lt;br /&gt;
&lt;br /&gt;
Molecules and atome moving away from each other.&lt;br /&gt;
&lt;br /&gt;
Setup a calculation where the initial positions correspond to the final positions of the trajectory you calculated above, the same final momenta values but with their signs reversed.&lt;br /&gt;
&lt;br /&gt;
r1 = rts+δ, r2 = rts&lt;br /&gt;
&lt;br /&gt;
final values of the positions r1(t) = 3.45, r2(t) = 0.72 and the average momenta  p1(t) = -1.45, p2(t) = -2.48 at large t.&lt;br /&gt;
&lt;br /&gt;
The molecule and the atom moving close together instead of moving apart.&lt;br /&gt;
&lt;br /&gt;
=== Complete the table above by adding the total energy, whether the trajectory is reactive or unreactive, and provide a plot of the trajectory and a small description for what happens along the trajectory. What can you conclude from the table? ===&lt;br /&gt;
&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot; border=&amp;quot;5&amp;quot;&lt;br /&gt;
! P1!!P2 !! Etot!! Reactive?!!Description of the dyanmics!!Illustration of the trajectory&lt;br /&gt;
|-&lt;br /&gt;
| -1.25 || -2.5|| -99.08|| yes||The trajectory goes through the transition state and also go into the products. ||[[File:Surface01_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -1.5|| -2.0|| -100.22|| no||The trajectory falls back down into the reactants because there was not enough energy for reactants to pass over the transition state. || [[File:Surface02_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -1.5||  -2.5|| -98.91|| yes||The trajectory goes through the transition state and also go into the products with enough energy. || [[File:Surface03_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -2.5|| -5.0|| -84.62|| no||The trajectory was carrying enough energy towards products but then it shifts back into the reactants. || [[File:Surface04_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -2.5||  -5.2|| -83.40|| yes||The trajectory goes through the transition state and also go into the products with enough energy. || [[File:Surface05_ql2817.png]]&lt;br /&gt;
|}&lt;br /&gt;
&lt;br /&gt;
=== State what are the main assumptions of Transition State Theory. Given the results you have obtained, how will Transition State Theory predictions for reaction rate values compare with experimental values? ===&lt;br /&gt;
Assumptions&amp;lt;ref&amp;gt;https://en.wikibooks.org/wiki/Statistical_Thermodynamics_and_Rate_Theories/Eyring_Transition_State_Theory#Assumptions_of_Transition_State_Theory:&lt;br /&gt;
&lt;br /&gt;
*Reactants are in constant equilibrium with the transition state structure.&lt;br /&gt;
*The energy of the particles follow a Boltzmann distribution.&lt;br /&gt;
*Once reactants become the transition state, the transition state structure does not collapse back to the reactants.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
== &#039;&#039;&#039;Reference&#039;&#039;&#039; ==&lt;br /&gt;
1.https://en.wikibooks.org/wiki/Statistical_Thermodynamics_and_Rate_Theories/Eyring_Transition_State_Theory#Assumptions_of_Transition_State_Theory&lt;/div&gt;</summary>
		<author><name>Ql2817</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=778321</id>
		<title>MRD:ql2817</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=778321"/>
		<updated>2019-05-14T16:07:34Z</updated>

		<summary type="html">&lt;p&gt;Ql2817: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;br /&gt;
== &#039;&#039;&#039;Question 1&#039;&#039;&#039; ==&lt;br /&gt;
&lt;br /&gt;
=== On a potential energy surface diagram, how is the transition state mathematically defined? How can the transition state be identified, and how can it be distinguished from a local minimum of the potential energy surface?===&lt;br /&gt;
&lt;br /&gt;
The transition state is defined as the maximum on the minimum energy path linking reactants and the products.It is located at the saddle point in the potential energy surface diagram, which defined as : ∂V(ri)/∂ri=0 and H &amp;lt; 0, where H = frr(r0​,V0​)fVV(r0​,V0​)−f2rV​(r0​,V0​) .&lt;br /&gt;
&lt;br /&gt;
The transition state is the specific combination of internuclear distances AB and BC at which the trajectory is a point on the contour plot.&lt;br /&gt;
&lt;br /&gt;
=== Report your best estimate of the transition state position (rts) and explain your reasoning illustrating it with a “Internuclear Distances vs Time” plot for a relevant trajectory. ===&lt;br /&gt;
When r(AB)=r(BC)=0.907 Å, p1 = p2 = 0.0, the transition state occurs. The internuclear distance vs time graph gives a relatively straight line which indicates a constant distance.&lt;br /&gt;
&lt;br /&gt;
=== Comment on how the mep and the trajectory you just calculated differ. ===&lt;br /&gt;
The mep trajectory keeps the potential energy at the minimum in a straight line, whereas the dynamic trajectory is wavy.&lt;br /&gt;
&lt;br /&gt;
r1 = 0.907, r2 = 0.917&lt;br /&gt;
&lt;br /&gt;
Molecules and atome moving away from each other.&lt;br /&gt;
&lt;br /&gt;
Setup a calculation where the initial positions correspond to the final positions of the trajectory you calculated above, the same final momenta values but with their signs reversed.&lt;br /&gt;
&lt;br /&gt;
r1 = rts+δ, r2 = rts&lt;br /&gt;
&lt;br /&gt;
final values of the positions r1(t) = 3.45, r2(t) = 0.72 and the average momenta  p1(t) = -1.45, p2(t) = -2.48 at large t.&lt;br /&gt;
&lt;br /&gt;
The molecule and the atom moving close together instead of moving apart.&lt;br /&gt;
&lt;br /&gt;
=== Complete the table above by adding the total energy, whether the trajectory is reactive or unreactive, and provide a plot of the trajectory and a small description for what happens along the trajectory. What can you conclude from the table? ===&lt;br /&gt;
&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot; border=&amp;quot;5&amp;quot;&lt;br /&gt;
! P1!!P2 !! Etot!! Reactive?!!Description of the dyanmics!!Illustration of the trajectory&lt;br /&gt;
|-&lt;br /&gt;
| -1.25 || -2.5|| -99.08|| yes||The trajectory goes through the transition state and also go into the products. ||[[File:Surface01_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -1.5|| -2.0|| -100.22|| no||The trajectory falls back down into the reactants because there was not enough energy for reactants to pass over the transition state. || [[File:Surface02_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -1.5||  -2.5|| -98.91|| yes||The trajectory goes through the transition state and also go into the products with enough energy. || [[File:Surface03_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -2.5|| -5.0|| -84.62|| no||The trajectory was carrying enough energy towards products but then it shifts back into the reactants. || [[File:Surface04_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -2.5||  -5.2|| -83.40|| yes||The trajectory goes through the transition state and also go into the products with enough energy. || [[File:Surface05_ql2817.png]]&lt;br /&gt;
|}&lt;br /&gt;
&lt;br /&gt;
=== State what are the main assumptions of Transition State Theory. Given the results you have obtained, how will Transition State Theory predictions for reaction rate values compare with experimental values? ===&lt;br /&gt;
Assumptions[1]:&lt;br /&gt;
&lt;br /&gt;
*Reactants are in constant equilibrium with the transition state structure.&lt;br /&gt;
*The energy of the particles follow a Boltzmann distribution.&lt;br /&gt;
*Once reactants become the transition state, the transition state structure does not collapse back to the reactants.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
== &#039;&#039;&#039;Reference&#039;&#039;&#039; ==&lt;br /&gt;
1.https://en.wikibooks.org/wiki/Statistical_Thermodynamics_and_Rate_Theories/Eyring_Transition_State_Theory#Assumptions_of_Transition_State_Theory&lt;/div&gt;</summary>
		<author><name>Ql2817</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=778186</id>
		<title>MRD:ql2817</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=778186"/>
		<updated>2019-05-14T15:49:34Z</updated>

		<summary type="html">&lt;p&gt;Ql2817: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;br /&gt;
== &#039;&#039;&#039;Question 1&#039;&#039;&#039; ==&lt;br /&gt;
&lt;br /&gt;
=== On a potential energy surface diagram, how is the transition state mathematically defined? How can the transition state be identified, and how can it be distinguished from a local minimum of the potential energy surface?===&lt;br /&gt;
&lt;br /&gt;
The transition state is defined as the maximum on the minimum energy path linking reactants and the products.It is located at the saddle point in the potential energy surface diagram, which defined as : ∂V(ri)/∂ri=0 and H &amp;lt; 0, where H = frr(r0​,V0​)fVV(r0​,V0​)−f2rV​(r0​,V0​) .&lt;br /&gt;
&lt;br /&gt;
The transition state is the specific combination of internuclear distances AB and BC at which the trajectory is a point on the contour plot.&lt;br /&gt;
&lt;br /&gt;
=== Report your best estimate of the transition state position (rts) and explain your reasoning illustrating it with a “Internuclear Distances vs Time” plot for a relevant trajectory. ===&lt;br /&gt;
When r(AB)=r(BC)=0.907 Å, p1 = p2 = 0.0, the transition state occurs. The internuclear distance vs time graph gives a relatively straight line which indicates a constant distance.&lt;br /&gt;
&lt;br /&gt;
=== Comment on how the mep and the trajectory you just calculated differ. ===&lt;br /&gt;
The mep trajectory keeps the potential energy at the minimum in a straight line, whereas the dynamic trajectory is wavy.&lt;br /&gt;
&lt;br /&gt;
r1 = 0.907, r2 = 0.917&lt;br /&gt;
&lt;br /&gt;
Molecules and atome moving away from each other.&lt;br /&gt;
&lt;br /&gt;
Setup a calculation where the initial positions correspond to the final positions of the trajectory you calculated above, the same final momenta values but with their signs reversed.&lt;br /&gt;
&lt;br /&gt;
r1 = rts+δ, r2 = rts&lt;br /&gt;
&lt;br /&gt;
final values of the positions r1(t) = 3.45, r2(t) = 0.72 and the average momenta  p1(t) = -1.45, p2(t) = -2.48 at large t.&lt;br /&gt;
&lt;br /&gt;
The molecule and the atom moving close together instead of moving apart.&lt;br /&gt;
&lt;br /&gt;
=== Complete the table above by adding the total energy, whether the trajectory is reactive or unreactive, and provide a plot of the trajectory and a small description for what happens along the trajectory. What can you conclude from the table? ===&lt;br /&gt;
&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot; border=&amp;quot;5&amp;quot;&lt;br /&gt;
! P1!!P2 !! Etot!! Reactive?!!Description of the dyanmics!!Illustration of the trajectory&lt;br /&gt;
|-&lt;br /&gt;
| -1.25 || -2.5|| -99.08|| yes||The trajectory goes through the transition state and also go into the products. ||[[File:Surface01_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -1.5|| -2.0|| -100.22|| no||The trajectory falls back down into the reactants because there was not enough energy for reactants to pass over the transition state. || [[File:Surface02_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -1.5||  -2.5|| -98.91|| yes||The trajectory goes through the transition state and also go into the products with enough energy. || [[File:Surface03_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -2.5|| -5.0|| -84.62|| no||The trajectory was carrying enough energy towards products but then it shifts back into the reactants. || [[File:Surface04_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -2.5||  -5.2|| -83.40|| yes||The trajectory goes through the transition state and also go into the products with enough energy. || [[File:Surface05_ql2817.png]]&lt;br /&gt;
|}&lt;br /&gt;
&lt;br /&gt;
=== State what are the main assumptions of Transition State Theory. Given the results you have obtained, how will Transition State Theory predictions for reaction rate values compare with experimental values? ===&lt;/div&gt;</summary>
		<author><name>Ql2817</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=778170</id>
		<title>MRD:ql2817</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=778170"/>
		<updated>2019-05-14T15:48:20Z</updated>

		<summary type="html">&lt;p&gt;Ql2817: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;br /&gt;
== &#039;&#039;&#039;Question 1&#039;&#039;&#039; ==&lt;br /&gt;
&lt;br /&gt;
=== On a potential energy surface diagram, how is the transition state mathematically defined? How can the transition state be identified, and how can it be distinguished from a local minimum of the potential energy surface?===&lt;br /&gt;
&lt;br /&gt;
The transition state is defined as the maximum on the minimum energy path linking reactants and the products.It is located at the saddle point in the potential energy surface diagram, which defined as : ∂V(ri)/∂ri=0 and H &amp;lt; 0, where H = frr(r0​,V0​)fVV(r0​,V0​)−f2rV​(r0​,V0​) .&lt;br /&gt;
&lt;br /&gt;
The transition state is the specific combination of internuclear distances AB and BC at which the trajectory is a point on the contour plot.&lt;br /&gt;
&lt;br /&gt;
=== Report your best estimate of the transition state position (rts) and explain your reasoning illustrating it with a “Internuclear Distances vs Time” plot for a relevant trajectory. ===&lt;br /&gt;
When r(AB)=r(BC)=0.907 Å, p1 = p2 = 0.0, the transition state occurs. The internuclear distance vs time graph gives a relatively straight line which indicates a constant distance.&lt;br /&gt;
&lt;br /&gt;
=== Comment on how the mep and the trajectory you just calculated differ. ===&lt;br /&gt;
The mep trajectory keeps the potential energy at the minimum in a straight line, whereas the dynamic trajectory is wavy.&lt;br /&gt;
&lt;br /&gt;
r1 = 0.907, r2 = 0.917&lt;br /&gt;
&lt;br /&gt;
Molecules and atome moving away from each other.&lt;br /&gt;
&lt;br /&gt;
Setup a calculation where the initial positions correspond to the final positions of the trajectory you calculated above, the same final momenta values but with their signs reversed.&lt;br /&gt;
&lt;br /&gt;
r1 = rts+δ, r2 = rts&lt;br /&gt;
&lt;br /&gt;
final values of the positions r1(t) = 3.45, r2(t) = 0.72 and the average momenta  p1(t) = -1.45, p2(t) = -2.48 at large t.&lt;br /&gt;
&lt;br /&gt;
The molecule and the atom moving close together instead of moving apart.&lt;br /&gt;
&lt;br /&gt;
=== Complete the table above by adding the total energy, whether the trajectory is reactive or unreactive, and provide a plot of the trajectory and a small description for what happens along the trajectory. What can you conclude from the table? ===&lt;br /&gt;
&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot; border=&amp;quot;5&amp;quot;&lt;br /&gt;
! P1!!P2 !! Etot!! Reactive?!!Description of the dyanmics!!Illustration of the trajectory&lt;br /&gt;
|-&lt;br /&gt;
| -1.25 || -2.5|| -99.08|| yes||The trajectory goes through the transition state and also go into the products. ||[[File:Surface01_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -1.5|| -2.0|| -100.22|| no||The trajectory falls back down into the reactants because there was not enough energy for reactants to pass over the transition state. || [[File:Surface02_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -1.5||  -2.5|| -98.91|| yes||The trajectory goes through the transition state and also go into the products with enough energy. || [[File:Surface03_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -2.5|| -5.0|| -84.62|| no|| || [[File:Surface04_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -2.5||  -5.2|| -83.40|| yes|| || [[File:Surface05_ql2817.png]]&lt;br /&gt;
|}&lt;br /&gt;
&lt;br /&gt;
=== State what are the main assumptions of Transition State Theory. Given the results you have obtained, how will Transition State Theory predictions for reaction rate values compare with experimental values? ===&lt;/div&gt;</summary>
		<author><name>Ql2817</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=778129</id>
		<title>MRD:ql2817</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=778129"/>
		<updated>2019-05-14T15:43:27Z</updated>

		<summary type="html">&lt;p&gt;Ql2817: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;br /&gt;
== &#039;&#039;&#039;Question 1&#039;&#039;&#039; ==&lt;br /&gt;
&lt;br /&gt;
=== On a potential energy surface diagram, how is the transition state mathematically defined? How can the transition state be identified, and how can it be distinguished from a local minimum of the potential energy surface?===&lt;br /&gt;
&lt;br /&gt;
The transition state is defined as the maximum on the minimum energy path linking reactants and the products.It is located at the saddle point in the potential energy surface diagram, which defined as : ∂V(ri)/∂ri=0 and H &amp;lt; 0, where H = frr(r0​,V0​)fVV(r0​,V0​)−f2rV​(r0​,V0​) .&lt;br /&gt;
&lt;br /&gt;
The transition state is the specific combination of internuclear distances AB and BC at which the trajectory is a point on the contour plot.&lt;br /&gt;
&lt;br /&gt;
=== Report your best estimate of the transition state position (rts) and explain your reasoning illustrating it with a “Internuclear Distances vs Time” plot for a relevant trajectory. ===&lt;br /&gt;
When r(AB)=r(BC)=0.907 Å, p1 = p2 = 0.0, the transition state occurs. The internuclear distance vs time graph gives a relatively straight line which indicates a constant distance.&lt;br /&gt;
&lt;br /&gt;
=== Comment on how the mep and the trajectory you just calculated differ. ===&lt;br /&gt;
The mep trajectory keeps the potential energy at the minimum in a straight line, whereas the dynamic trajectory is wavy.&lt;br /&gt;
&lt;br /&gt;
r1 = 0.907, r2 = 0.917&lt;br /&gt;
&lt;br /&gt;
Molecules and atome moving away from each other.&lt;br /&gt;
&lt;br /&gt;
Setup a calculation where the initial positions correspond to the final positions of the trajectory you calculated above, the same final momenta values but with their signs reversed.&lt;br /&gt;
&lt;br /&gt;
r1 = rts+δ, r2 = rts&lt;br /&gt;
&lt;br /&gt;
final values of the positions r1(t) = 3.45, r2(t) = 0.72 and the average momenta  p1(t) = -1.45, p2(t) = -2.48 at large t.&lt;br /&gt;
&lt;br /&gt;
The molecule and the atom moving close together instead of moving apart.&lt;br /&gt;
&lt;br /&gt;
=== Complete the table above by adding the total energy, whether the trajectory is reactive or unreactive, and provide a plot of the trajectory and a small description for what happens along the trajectory. What can you conclude from the table? ===&lt;br /&gt;
&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot; border=&amp;quot;5&amp;quot;&lt;br /&gt;
! P1!!P2 !! Etot!! Reactive?!!Description of the dyanmics!!Illustration of the trajectory&lt;br /&gt;
|-&lt;br /&gt;
| -1.25 || -2.5|| -99.08|| yes|| ||[[File:Surface01_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -1.5|| -2.0|| -100.22|| no|| cell|| [[File:Surface02_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -1.5||  -2.5|| -98.91|| yes|| cell|| [[File:Surface03_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -2.5|| -5.0|| -84.62|| no|| cell|| [[File:Surface04_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -2.5||  -5.2|| -83.40|| no|| cell|| [[File:Surface05_ql2817.png]]&lt;br /&gt;
|}&lt;br /&gt;
&lt;br /&gt;
=== State what are the main assumptions of Transition State Theory. Given the results you have obtained, how will Transition State Theory predictions for reaction rate values compare with experimental values? ===&lt;/div&gt;</summary>
		<author><name>Ql2817</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=File:Surface05_ql2817.png&amp;diff=778128</id>
		<title>File:Surface05 ql2817.png</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=File:Surface05_ql2817.png&amp;diff=778128"/>
		<updated>2019-05-14T15:43:20Z</updated>

		<summary type="html">&lt;p&gt;Ql2817: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;/div&gt;</summary>
		<author><name>Ql2817</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=File:Surface04_ql2817.png&amp;diff=778122</id>
		<title>File:Surface04 ql2817.png</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=File:Surface04_ql2817.png&amp;diff=778122"/>
		<updated>2019-05-14T15:43:02Z</updated>

		<summary type="html">&lt;p&gt;Ql2817: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;/div&gt;</summary>
		<author><name>Ql2817</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=File:Surface03_ql2817.png&amp;diff=778121</id>
		<title>File:Surface03 ql2817.png</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=File:Surface03_ql2817.png&amp;diff=778121"/>
		<updated>2019-05-14T15:42:51Z</updated>

		<summary type="html">&lt;p&gt;Ql2817: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;/div&gt;</summary>
		<author><name>Ql2817</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=File:Surface02_ql2817.png&amp;diff=778113</id>
		<title>File:Surface02 ql2817.png</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=File:Surface02_ql2817.png&amp;diff=778113"/>
		<updated>2019-05-14T15:42:03Z</updated>

		<summary type="html">&lt;p&gt;Ql2817: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;/div&gt;</summary>
		<author><name>Ql2817</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=778109</id>
		<title>MRD:ql2817</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=778109"/>
		<updated>2019-05-14T15:41:34Z</updated>

		<summary type="html">&lt;p&gt;Ql2817: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;br /&gt;
== &#039;&#039;&#039;Question 1&#039;&#039;&#039; ==&lt;br /&gt;
&lt;br /&gt;
=== On a potential energy surface diagram, how is the transition state mathematically defined? How can the transition state be identified, and how can it be distinguished from a local minimum of the potential energy surface?===&lt;br /&gt;
&lt;br /&gt;
The transition state is defined as the maximum on the minimum energy path linking reactants and the products.It is located at the saddle point in the potential energy surface diagram, which defined as : ∂V(ri)/∂ri=0 and H &amp;lt; 0, where H = frr(r0​,V0​)fVV(r0​,V0​)−f2rV​(r0​,V0​) .&lt;br /&gt;
&lt;br /&gt;
The transition state is the specific combination of internuclear distances AB and BC at which the trajectory is a point on the contour plot.&lt;br /&gt;
&lt;br /&gt;
=== Report your best estimate of the transition state position (rts) and explain your reasoning illustrating it with a “Internuclear Distances vs Time” plot for a relevant trajectory. ===&lt;br /&gt;
When r(AB)=r(BC)=0.907 Å, p1 = p2 = 0.0, the transition state occurs. The internuclear distance vs time graph gives a relatively straight line which indicates a constant distance.&lt;br /&gt;
&lt;br /&gt;
=== Comment on how the mep and the trajectory you just calculated differ. ===&lt;br /&gt;
The mep trajectory keeps the potential energy at the minimum in a straight line, whereas the dynamic trajectory is wavy.&lt;br /&gt;
&lt;br /&gt;
r1 = 0.907, r2 = 0.917&lt;br /&gt;
&lt;br /&gt;
Molecules and atome moving away from each other.&lt;br /&gt;
&lt;br /&gt;
Setup a calculation where the initial positions correspond to the final positions of the trajectory you calculated above, the same final momenta values but with their signs reversed.&lt;br /&gt;
&lt;br /&gt;
r1 = rts+δ, r2 = rts&lt;br /&gt;
&lt;br /&gt;
final values of the positions r1(t) = 3.45, r2(t) = 0.72 and the average momenta  p1(t) = -1.45, p2(t) = -2.48 at large t.&lt;br /&gt;
&lt;br /&gt;
The molecule and the atom moving close together instead of moving apart.&lt;br /&gt;
&lt;br /&gt;
=== Complete the table above by adding the total energy, whether the trajectory is reactive or unreactive, and provide a plot of the trajectory and a small description for what happens along the trajectory. What can you conclude from the table? ===&lt;br /&gt;
&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot; border=&amp;quot;5&amp;quot;&lt;br /&gt;
! P1!!P2 !! Etot!! Reactive?!!Description of the dyanmics!!Illustration of the trajectory&lt;br /&gt;
|-&lt;br /&gt;
| -1.25 || -2.5|| -99.08|| yes|| ||[[File:Surface01_ql2817.png]]&lt;br /&gt;
|-&lt;br /&gt;
| -1.5|| -2.0|| -100.22|| no|| cell|| &lt;br /&gt;
|-&lt;br /&gt;
| -1.5||  -2.5|| -98.91|| yes|| cell|| &lt;br /&gt;
|-&lt;br /&gt;
| -2.5|| -5.0|| -84.62|| no|| cell|| &lt;br /&gt;
|-&lt;br /&gt;
| -2.5||  -5.2|| -83.40|| no|| cell|| &lt;br /&gt;
|}&lt;br /&gt;
&lt;br /&gt;
=== State what are the main assumptions of Transition State Theory. Given the results you have obtained, how will Transition State Theory predictions for reaction rate values compare with experimental values? ===&lt;/div&gt;</summary>
		<author><name>Ql2817</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=File:Surface01_ql2817.png&amp;diff=778091</id>
		<title>File:Surface01 ql2817.png</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=File:Surface01_ql2817.png&amp;diff=778091"/>
		<updated>2019-05-14T15:40:25Z</updated>

		<summary type="html">&lt;p&gt;Ql2817: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;/div&gt;</summary>
		<author><name>Ql2817</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=778061</id>
		<title>MRD:ql2817</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=778061"/>
		<updated>2019-05-14T15:37:14Z</updated>

		<summary type="html">&lt;p&gt;Ql2817: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;br /&gt;
== &#039;&#039;&#039;Question 1&#039;&#039;&#039; ==&lt;br /&gt;
&lt;br /&gt;
=== On a potential energy surface diagram, how is the transition state mathematically defined? How can the transition state be identified, and how can it be distinguished from a local minimum of the potential energy surface?===&lt;br /&gt;
&lt;br /&gt;
The transition state is defined as the maximum on the minimum energy path linking reactants and the products.It is located at the saddle point in the potential energy surface diagram, which defined as : ∂V(ri)/∂ri=0 and H &amp;lt; 0, where H = frr(r0​,V0​)fVV(r0​,V0​)−f2rV​(r0​,V0​) .&lt;br /&gt;
&lt;br /&gt;
The transition state is the specific combination of internuclear distances AB and BC at which the trajectory is a point on the contour plot.&lt;br /&gt;
&lt;br /&gt;
=== Report your best estimate of the transition state position (rts) and explain your reasoning illustrating it with a “Internuclear Distances vs Time” plot for a relevant trajectory. ===&lt;br /&gt;
When r(AB)=r(BC)=0.907 Å, p1 = p2 = 0.0, the transition state occurs. The internuclear distance vs time graph gives a relatively straight line which indicates a constant distance.&lt;br /&gt;
&lt;br /&gt;
=== Comment on how the mep and the trajectory you just calculated differ. ===&lt;br /&gt;
The mep trajectory keeps the potential energy at the minimum in a straight line, whereas the dynamic trajectory is wavy.&lt;br /&gt;
&lt;br /&gt;
r1 = 0.907, r2 = 0.917&lt;br /&gt;
&lt;br /&gt;
Molecules and atome moving away from each other.&lt;br /&gt;
&lt;br /&gt;
Setup a calculation where the initial positions correspond to the final positions of the trajectory you calculated above, the same final momenta values but with their signs reversed.&lt;br /&gt;
&lt;br /&gt;
r1 = rts+δ, r2 = rts&lt;br /&gt;
&lt;br /&gt;
final values of the positions r1(t) = 3.45, r2(t) = 0.72 and the average momenta  p1(t) = -1.45, p2(t) = -2.48 at large t.&lt;br /&gt;
&lt;br /&gt;
The molecule and the atom moving close together instead of moving apart.&lt;br /&gt;
&lt;br /&gt;
=== Complete the table above by adding the total energy, whether the trajectory is reactive or unreactive, and provide a plot of the trajectory and a small description for what happens along the trajectory. What can you conclude from the table? ===&lt;br /&gt;
&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot; border=&amp;quot;5&amp;quot;&lt;br /&gt;
! P1!!P2 !! Etot!! Reactive?!!Description of the dyanmics!!Illustration of the trajectory&lt;br /&gt;
|-&lt;br /&gt;
| -1.25 || -2.5|| -99.08|| yes|| ||&lt;br /&gt;
|-&lt;br /&gt;
| -1.5|| -2.0|| -100.22|| no|| cell|| &lt;br /&gt;
|-&lt;br /&gt;
| -1.5||  -2.5|| -98.91|| yes|| cell|| &lt;br /&gt;
|-&lt;br /&gt;
| -2.5|| -5.0|| -84.62|| no|| cell|| &lt;br /&gt;
|-&lt;br /&gt;
| -2.5||  -5.2|| -83.40|| no|| cell|| &lt;br /&gt;
|}&lt;br /&gt;
&lt;br /&gt;
=== State what are the main assumptions of Transition State Theory. Given the results you have obtained, how will Transition State Theory predictions for reaction rate values compare with experimental values? ===&lt;/div&gt;</summary>
		<author><name>Ql2817</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=778002</id>
		<title>MRD:ql2817</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=778002"/>
		<updated>2019-05-14T15:32:08Z</updated>

		<summary type="html">&lt;p&gt;Ql2817: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;br /&gt;
== &#039;&#039;&#039;Question 1&#039;&#039;&#039; ==&lt;br /&gt;
&lt;br /&gt;
=== On a potential energy surface diagram, how is the transition state mathematically defined? How can the transition state be identified, and how can it be distinguished from a local minimum of the potential energy surface?===&lt;br /&gt;
&lt;br /&gt;
The transition state is defined as the maximum on the minimum energy path linking reactants and the products.It is located at the saddle point in the potential energy surface diagram, which defined as : ∂V(ri)/∂ri=0 and H &amp;lt; 0, where H = frr(r0​,V0​)fVV(r0​,V0​)−f2rV​(r0​,V0​) .&lt;br /&gt;
&lt;br /&gt;
The transition state is the specific combination of internuclear distances AB and BC at which the trajectory is a point on the contour plot.&lt;br /&gt;
&lt;br /&gt;
=== Report your best estimate of the transition state position (rts) and explain your reasoning illustrating it with a “Internuclear Distances vs Time” plot for a relevant trajectory. ===&lt;br /&gt;
When r(AB)=r(BC)=0.907 Å, p1 = p2 = 0.0, the transition state occurs. The internuclear distance vs time graph gives a relatively straight line which indicates a constant distance.&lt;br /&gt;
&lt;br /&gt;
=== Comment on how the mep and the trajectory you just calculated differ. ===&lt;br /&gt;
The mep trajectory keeps the potential energy at the minimum in a straight line, whereas the dynamic trajectory is wavy.&lt;br /&gt;
&lt;br /&gt;
r1 = 0.907, r2 = 0.917&lt;br /&gt;
&lt;br /&gt;
Molecules and atome moving away from each other.&lt;br /&gt;
&lt;br /&gt;
Setup a calculation where the initial positions correspond to the final positions of the trajectory you calculated above, the same final momenta values but with their signs reversed.&lt;br /&gt;
&lt;br /&gt;
r1 = rts+δ, r2 = rts&lt;br /&gt;
&lt;br /&gt;
final values of the positions r1(t) = 3.45, r2(t) = 0.72 and the average momenta  p1(t) = -1.45, p2(t) = -2.48 at large t.&lt;br /&gt;
&lt;br /&gt;
The molecule and the atom moving close together instead of moving apart.&lt;br /&gt;
&lt;br /&gt;
=== Complete the table above by adding the total energy, whether the trajectory is reactive or unreactive, and provide a plot of the trajectory and a small description for what happens along the trajectory. What can you conclude from the table? ===&lt;br /&gt;
&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot; border=&amp;quot;5&amp;quot;&lt;br /&gt;
! P1!!P2 !! Etot!! Reactive?!!Description of the dyanmics!!Illustration of the trajectory&lt;br /&gt;
|-&lt;br /&gt;
| -1.25 || -2.5|| -99.076|| yes|| || [[File:surface01_ql2817]]&lt;br /&gt;
|-&lt;br /&gt;
| -1.5|| -2.0|| cell|| cell|| cell|| cell&lt;br /&gt;
|-&lt;br /&gt;
| -1.5||  -2.5|| cell|| cell|| cell|| cell&lt;br /&gt;
|-&lt;br /&gt;
| -2.5|| -5.0|| cell|| cell|| cell|| cell&lt;br /&gt;
|-&lt;br /&gt;
| -2.5||  -5.2|| cell|| cell|| cell|| cell&lt;br /&gt;
|}&lt;br /&gt;
&lt;br /&gt;
=== State what are the main assumptions of Transition State Theory. Given the results you have obtained, how will Transition State Theory predictions for reaction rate values compare with experimental values? ===&lt;/div&gt;</summary>
		<author><name>Ql2817</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=777958</id>
		<title>MRD:ql2817</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=777958"/>
		<updated>2019-05-14T15:27:37Z</updated>

		<summary type="html">&lt;p&gt;Ql2817: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;br /&gt;
== &#039;&#039;&#039;Question 1&#039;&#039;&#039; ==&lt;br /&gt;
&lt;br /&gt;
=== On a potential energy surface diagram, how is the transition state mathematically defined? How can the transition state be identified, and how can it be distinguished from a local minimum of the potential energy surface?===&lt;br /&gt;
&lt;br /&gt;
The transition state is defined as the maximum on the minimum energy path linking reactants and the products.It is located at the saddle point in the potential energy surface diagram, which defined as : ∂V(ri)/∂ri=0 and H &amp;lt; 0, where H = frr(r0​,V0​)fVV(r0​,V0​)−f2rV​(r0​,V0​) .&lt;br /&gt;
&lt;br /&gt;
The transition state is the specific combination of internuclear distances AB and BC at which the trajectory is a point on the contour plot.&lt;br /&gt;
&lt;br /&gt;
=== Report your best estimate of the transition state position (rts) and explain your reasoning illustrating it with a “Internuclear Distances vs Time” plot for a relevant trajectory. ===&lt;br /&gt;
When r(AB)=r(BC)=0.907 Å, p1 = p2 = 0.0, the transition state occurs. The internuclear distance vs time graph gives a relatively straight line which indicates a constant distance.&lt;br /&gt;
&lt;br /&gt;
=== Comment on how the mep and the trajectory you just calculated differ. ===&lt;br /&gt;
The mep trajectory keeps the potential energy at the minimum in a straight line, whereas the dynamic trajectory is wavy.&lt;br /&gt;
&lt;br /&gt;
r1 = 0.907, r2 = 0.917&lt;br /&gt;
&lt;br /&gt;
Molecules and atome moving away from each other.&lt;br /&gt;
&lt;br /&gt;
Setup a calculation where the initial positions correspond to the final positions of the trajectory you calculated above, the same final momenta values but with their signs reversed.&lt;br /&gt;
&lt;br /&gt;
r1 = rts+δ, r2 = rts&lt;br /&gt;
&lt;br /&gt;
final values of the positions r1(t) = 3.45, r2(t) = 0.72 and the average momenta  p1(t) = -1.45, p2(t) = -2.48 at large t.&lt;br /&gt;
&lt;br /&gt;
The molecule and the atom moving close together instead of moving apart.&lt;br /&gt;
&lt;br /&gt;
=== Complete the table above by adding the total energy, whether the trajectory is reactive or unreactive, and provide a plot of the trajectory and a small description for what happens along the trajectory. What can you conclude from the table? ===&lt;br /&gt;
&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot; border=&amp;quot;5&amp;quot;&lt;br /&gt;
! P1!!P2 !! Etot!! Reactive?!!Description of the dyanmics!!Illustration of the trajectory&lt;br /&gt;
|-&lt;br /&gt;
| -1.25 || -2.5|| cell|| cell|| cell|| cell&lt;br /&gt;
|-&lt;br /&gt;
| -1.5|| -2.0|| cell|| cell|| cell|| cell&lt;br /&gt;
|-&lt;br /&gt;
| -1.5||  -2.5|| cell|| cell|| cell|| cell&lt;br /&gt;
|-&lt;br /&gt;
| -2.5|| -5.0|| cell|| cell|| cell|| cell&lt;br /&gt;
|-&lt;br /&gt;
| -2.5||  -5.2|| cell|| cell|| cell|| cell&lt;br /&gt;
|}&lt;br /&gt;
&lt;br /&gt;
=== State what are the main assumptions of Transition State Theory. Given the results you have obtained, how will Transition State Theory predictions for reaction rate values compare with experimental values? ===&lt;/div&gt;</summary>
		<author><name>Ql2817</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=777805</id>
		<title>MRD:ql2817</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=777805"/>
		<updated>2019-05-14T15:10:55Z</updated>

		<summary type="html">&lt;p&gt;Ql2817: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;br /&gt;
== &#039;&#039;&#039;Question 1&#039;&#039;&#039; ==&lt;br /&gt;
&lt;br /&gt;
=== On a potential energy surface diagram, how is the transition state mathematically defined? How can the transition state be identified, and how can it be distinguished from a local minimum of the potential energy surface?===&lt;br /&gt;
&lt;br /&gt;
The transition state is defined as the maximum on the minimum energy path linking reactants and the products.It is located at the saddle point in the potential energy surface diagram, which defined as : ∂V(ri)/∂ri=0 and H &amp;lt; 0, where H = frr(r0​,V0​)fVV(r0​,V0​)−f2rV​(r0​,V0​) .&lt;br /&gt;
&lt;br /&gt;
The transition state is the specific combination of internuclear distances AB and BC at which the trajectory is a point on the contour plot.&lt;br /&gt;
&lt;br /&gt;
=== Report your best estimate of the transition state position (rts) and explain your reasoning illustrating it with a “Internuclear Distances vs Time” plot for a relevant trajectory. ===&lt;br /&gt;
When r(AB)=r(BC)=0.907 Å, p1 = p2 = 0.0, the transition state occurs. The internuclear distance vs time graph gives a relatively straight line which indicates a constant distance.&lt;br /&gt;
&lt;br /&gt;
=== Comment on how the mep and the trajectory you just calculated differ. ===&lt;br /&gt;
The mep trajectory keeps the potential energy at the minimum in a straight line, whereas the dynamic trajectory is wavy.&lt;br /&gt;
&lt;br /&gt;
r1 = 0.907, r2 = 0.917&lt;br /&gt;
&lt;br /&gt;
Molecules and atome moving away from each other.&lt;br /&gt;
&lt;br /&gt;
Setup a calculation where the initial positions correspond to the final positions of the trajectory you calculated above, the same final momenta values but with their signs reversed.&lt;br /&gt;
&lt;br /&gt;
r1 = rts+δ, r2 = rts&lt;br /&gt;
&lt;br /&gt;
final values of the positions r1(t) = 3.45, r2(t) = 0.72 and the average momenta  p1(t) = -1.45, p2(t) = -2.48 at large t.&lt;br /&gt;
&lt;br /&gt;
The molecule and the atom moving close together instead of moving apart.&lt;br /&gt;
&lt;br /&gt;
=== Complete the table above by adding the total energy, whether the trajectory is reactive or unreactive, and provide a plot of the trajectory and a small description for what happens along the trajectory. What can you conclude from the table? ===&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
=== State what are the main assumptions of Transition State Theory. Given the results you have obtained, how will Transition State Theory predictions for reaction rate values compare with experimental values? ===&lt;/div&gt;</summary>
		<author><name>Ql2817</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=777666</id>
		<title>MRD:ql2817</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=777666"/>
		<updated>2019-05-14T14:53:22Z</updated>

		<summary type="html">&lt;p&gt;Ql2817: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;br /&gt;
== &#039;&#039;&#039;Question 1&#039;&#039;&#039; ==&lt;br /&gt;
&lt;br /&gt;
=== On a potential energy surface diagram, how is the transition state mathematically defined? How can the transition state be identified, and how can it be distinguished from a local minimum of the potential energy surface?===&lt;br /&gt;
&lt;br /&gt;
The transition state is defined as the maximum on the minimum energy path linking reactants and the products.It is located at the saddle point in the potential energy surface diagram, which defined as : ∂V(ri)/∂ri=0 and H &amp;lt; 0, where H = frr(r0​,V0​)fVV(r0​,V0​)−f2rV​(r0​,V0​) .&lt;br /&gt;
&lt;br /&gt;
The transition state is the specific combination of internuclear distances AB and BC at which the trajectory is a point on the contour plot.&lt;br /&gt;
&lt;br /&gt;
=== Report your best estimate of the transition state position (rts) and explain your reasoning illustrating it with a “Internuclear Distances vs Time” plot for a relevant trajectory. ===&lt;br /&gt;
When r(AB)=r(BC)=0.907 Å, p1 = p2 = 0.0, the transition state occurs. The internuclear distance vs time graph gives a relatively straight line which indicates a constant distance.&lt;br /&gt;
&lt;br /&gt;
=== Comment on how the mep and the trajectory you just calculated differ. ===&lt;br /&gt;
The mep trajectory keeps the potential energy at the minimum in a straight line, whereas the dynamic trajectory is wavy.&lt;br /&gt;
&lt;br /&gt;
r1 = rts+δ, r2 = rts&lt;br /&gt;
&lt;br /&gt;
final values of the positions r1(t) = 3.5, r2(t) = 0.74 and the average momenta  p1(t) = 2.48, p2(t) = 1.24 at large t.&lt;br /&gt;
&lt;br /&gt;
r1 = rts+δ, r2 = rts&lt;br /&gt;
&lt;br /&gt;
final values of the positions r1(t) = 0.74, r2(t) = 3.5 and the average momenta  p1(t) = 1.24, p2(t) = 2.48 at large t.&lt;br /&gt;
&lt;br /&gt;
Setup a calculation where the initial positions correspond to the final positions of the trajectory you calculated above, the same final momenta values but with their signs reversed. - the molecule and the atom coming together instead of moving apart.&lt;br /&gt;
&lt;br /&gt;
=== Complete the table above by adding the total energy, whether the trajectory is reactive or unreactive, and provide a plot of the trajectory and a small description for what happens along the trajectory. What can you conclude from the table? ===&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
=== State what are the main assumptions of Transition State Theory. Given the results you have obtained, how will Transition State Theory predictions for reaction rate values compare with experimental values? ===&lt;/div&gt;</summary>
		<author><name>Ql2817</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=777617</id>
		<title>MRD:ql2817</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=777617"/>
		<updated>2019-05-14T14:46:33Z</updated>

		<summary type="html">&lt;p&gt;Ql2817: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;br /&gt;
== &#039;&#039;&#039;Question 1&#039;&#039;&#039; ==&lt;br /&gt;
&lt;br /&gt;
=== On a potential energy surface diagram, how is the transition state mathematically defined? How can the transition state be identified, and how can it be distinguished from a local minimum of the potential energy surface?===&lt;br /&gt;
&lt;br /&gt;
The transition state is defined as the maximum on the minimum energy path linking reactants and the products.It is located at the saddle point in the potential energy surface diagram, which defined as : ∂V(ri)/∂ri=0 and H &amp;lt; 0, where H = frr(r0​,V0​)fVV(r0​,V0​)−f2rV​(r0​,V0​) .&lt;br /&gt;
&lt;br /&gt;
The transition state is the specific combination of internuclear distances AB and BC at which the trajectory is a point on the contour plot.&lt;br /&gt;
&lt;br /&gt;
=== Report your best estimate of the transition state position (rts) and explain your reasoning illustrating it with a “Internuclear Distances vs Time” plot for a relevant trajectory. ===&lt;br /&gt;
When r(AB)=r(BC)=0.91 Å, p1 = p2 = 0.0, the transition state occurs. The internuclear distance vs time graph gives a relatively straight line whihc indicates a constant distance.&lt;br /&gt;
&lt;br /&gt;
=== Comment on how the mep and the trajectory you just calculated differ. ===&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
=== Complete the table above by adding the total energy, whether the trajectory is reactive or unreactive, and provide a plot of the trajectory and a small description for what happens along the trajectory. What can you conclude from the table? ===&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
=== State what are the main assumptions of Transition State Theory. Given the results you have obtained, how will Transition State Theory predictions for reaction rate values compare with experimental values? ===&lt;/div&gt;</summary>
		<author><name>Ql2817</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=777610</id>
		<title>MRD:ql2817</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=777610"/>
		<updated>2019-05-14T14:45:50Z</updated>

		<summary type="html">&lt;p&gt;Ql2817: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;br /&gt;
== &#039;&#039;&#039;Question 1&#039;&#039;&#039; ==&lt;br /&gt;
&lt;br /&gt;
=== On a potential energy surface diagram, how is the transition state mathematically defined? How can the transition state be identified, and how can it be distinguished from a local minimum of the potential energy surface?===&lt;br /&gt;
&lt;br /&gt;
The transition state is defined as the maximum on the minimum energy path linking reactants and the products.It is located at the saddle point in the potential energy surface diagram, which defined as : ∂V(ri)/∂ri=0 and H &amp;lt; 0, where H = frr(r0​,V0​)fVV(r0​,V0​)−f2rV​(r0​,V0​) .&lt;br /&gt;
&lt;br /&gt;
The transition state is the specific combination of internuclear distances AB and BC at which the trajectory is a point on the contour plot.&lt;br /&gt;
&lt;br /&gt;
=== Report your best estimate of the transition state position (rts) and explain your reasoning illustrating it with a “Internuclear Distances vs Time” plot for a relevant trajectory. ===&lt;br /&gt;
When r(AB)=r(BC)=0.91 Å, p1 = p2 = 0.0, the transition state occurs. The internuclear distance vs time graph gives a relatively straight line whihc indicates a constant distance.&lt;br /&gt;
&lt;br /&gt;
=== Comment on how the mep and the trajectory you just calculated differ. ===&lt;br /&gt;
&lt;br /&gt;
=== Complete the table above by adding the total energy, whether the trajectory is reactive or unreactive, and provide a plot of the trajectory and a small description for what happens along the trajectory. What can you conclude from the table? ===&lt;br /&gt;
&lt;br /&gt;
=== State what are the main assumptions of Transition State Theory. Given the results you have obtained, how will Transition State Theory predictions for reaction rate values compare with experimental values? ===&lt;/div&gt;</summary>
		<author><name>Ql2817</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=777602</id>
		<title>MRD:ql2817</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=777602"/>
		<updated>2019-05-14T14:44:52Z</updated>

		<summary type="html">&lt;p&gt;Ql2817: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;br /&gt;
== &#039;&#039;&#039;Question 1&#039;&#039;&#039; ==&lt;br /&gt;
&lt;br /&gt;
=== On a potential energy surface diagram, how is the transition state mathematically defined? How can the transition state be identified, and how can it be distinguished from a local minimum of the potential energy surface?===&lt;br /&gt;
&lt;br /&gt;
The transition state is defined as the maximum on the minimum energy path linking reactants and the products.It is located at the saddle point in the potential energy surface diagram, which defined as : ∂V(ri)/∂ri=0 and H &amp;lt; 0, where H = frr(r0​,V0​)fVV(r0​,V0​)−f2rV​(r0​,V0​) .&lt;br /&gt;
&lt;br /&gt;
The transition state is the specific combination of internuclear distances AB and BC at which the trajectory is a point on the contour plot.&lt;br /&gt;
&lt;br /&gt;
=== Report your best estimate of the transition state position (rts) and explain your reasoning illustrating it with a “Internuclear Distances vs Time” plot for a relevant trajectory. ===&lt;br /&gt;
When r(AB)=r(BC)=0.91 Å, p1 = p2 = 0.0, the transition state occurs. The internuclear distance vs time graph gives a relatively straight line whihc indicates a constant distance.&lt;br /&gt;
&lt;br /&gt;
=== Comment on how the mep and the trajectory you just calculated differ. ===&lt;/div&gt;</summary>
		<author><name>Ql2817</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=777594</id>
		<title>MRD:ql2817</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=777594"/>
		<updated>2019-05-14T14:43:06Z</updated>

		<summary type="html">&lt;p&gt;Ql2817: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;br /&gt;
== &#039;&#039;&#039;Question 1&#039;&#039;&#039; ==&lt;br /&gt;
&lt;br /&gt;
=== On a potential energy surface diagram, how is the transition state mathematically defined? How can the transition state be identified, and how can it be distinguished from a local minimum of the potential energy surface?===&lt;br /&gt;
&lt;br /&gt;
The transition state is defined as the maximum on the minimum energy path linking reactants and the products.It is located at the saddle point in the potential energy surface diagram, which defined as : ∂V(ri)/∂ri=0 and H &amp;lt; 0, where H = frr(r0​,V0​)fVV(r0​,V0​)−f2rV​(r0​,V0​) .&lt;br /&gt;
&lt;br /&gt;
The transition state is the specific combination of internuclear distances AB and BC at which the trajectory is a point on the contour plot.&lt;br /&gt;
&lt;br /&gt;
=== Report your best estimate of the transition state position (rts) and explain your reasoning illustrating it with a “Internuclear Distances vs Time” plot for a relevant trajectory. ===&lt;br /&gt;
When r(AB)=r(BC)=0.91 Å, p1 = p2 = 0.0, the transition state occurs. The internuclear distance vs time graph gives a relatively straight line.&lt;/div&gt;</summary>
		<author><name>Ql2817</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=777574</id>
		<title>MRD:ql2817</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=MRD:ql2817&amp;diff=777574"/>
		<updated>2019-05-14T14:39:59Z</updated>

		<summary type="html">&lt;p&gt;Ql2817: Created page with &amp;quot; == &amp;#039;&amp;#039;&amp;#039;Question 1&amp;#039;&amp;#039;&amp;#039; ==  === On a potential energy surface diagram, how is the transition state mathematically defined? How can the transition state be identified, and how can...&amp;quot;&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;br /&gt;
== &#039;&#039;&#039;Question 1&#039;&#039;&#039; ==&lt;br /&gt;
&lt;br /&gt;
=== On a potential energy surface diagram, how is the transition state mathematically defined? How can the transition state be identified, and how can it be distinguished from a local minimum of the potential energy surface?===&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
=== Report your best estimate of the transition state position (rts) and explain your reasoning illustrating it with a “Internuclear Distances vs Time” plot for a relevant trajectory. ===&lt;br /&gt;
When r(AB)=r(BC)=0.91 Å, p1 = p2 = 0.0, the transition state occurs. The internuclear distance vs time graph gives a relatively straight line.&lt;/div&gt;</summary>
		<author><name>Ql2817</name></author>
	</entry>
	<entry>
		<id>https://chemwiki.ch.ic.ac.uk/index.php?title=Year1ql&amp;diff=681092</id>
		<title>Year1ql</title>
		<link rel="alternate" type="text/html" href="https://chemwiki.ch.ic.ac.uk/index.php?title=Year1ql&amp;diff=681092"/>
		<updated>2018-03-08T22:07:59Z</updated>

		<summary type="html">&lt;p&gt;Ql2817: &lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;&lt;br /&gt;
== &#039;&#039;&#039;NH3 molecule&#039;&#039;&#039; ==&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
===&#039;&#039;&#039;General Information&#039;&#039;&#039; ===&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
calculation method: RB3LYP&lt;br /&gt;
&lt;br /&gt;
basis set: 6-31G(d.p)&lt;br /&gt;
&lt;br /&gt;
final energy E(RB3LYP) in atomic units (au): -56.55776873&lt;br /&gt;
&lt;br /&gt;
RMS gradient: 0.00000485&lt;br /&gt;
&lt;br /&gt;
point group of your molecule: C3V&lt;br /&gt;
&lt;br /&gt;
N-H bond distance=1.01798&lt;br /&gt;
&lt;br /&gt;
N-H-N bond angle= 109.471&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
=== &#039;&#039;&#039;Item Table&#039;&#039;&#039; ===&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&amp;lt;pre&amp;gt;&lt;br /&gt;
&lt;br /&gt;
         Item               Value     Threshold  Converged?&lt;br /&gt;
 Maximum Force            0.000004     0.000450     YES&lt;br /&gt;
 RMS     Force            0.000004     0.000300     YES&lt;br /&gt;
 Maximum Displacement     0.000072     0.001800     YES&lt;br /&gt;
 RMS     Displacement     0.000035     0.001200     YES&lt;br /&gt;
&amp;lt;/pre&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
=== &#039;&#039;&#039;Jmol 3D Model&#039;&#039;&#039; ===&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&amp;lt;jmol&amp;gt;&amp;lt;jmolApplet&amp;gt;&lt;br /&gt;
  &amp;lt;title&amp;gt;test molecule&amp;lt;/title&amp;gt;&lt;br /&gt;
  &amp;lt;color&amp;gt;black&amp;lt;/color&amp;gt;&lt;br /&gt;
  &amp;lt;size&amp;gt;200&amp;lt;/size&amp;gt;&lt;br /&gt;
  &amp;lt;uploadedFileContents&amp;gt;QINGLI_PHUNT_NH3_OPTF_POP.LOG&amp;lt;/uploadedFileContents&amp;gt;&lt;br /&gt;
  &amp;lt;script&amp;gt;frame 1.16&amp;lt;/script&amp;gt;&lt;br /&gt;
&amp;lt;/jmolApplet&amp;gt;&amp;lt;/jmol&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
The optimisation file is liked to [[Media:QINGLI_PHUNT_NH3_OPTF_POP.LOG| here]]&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
=== &#039;&#039;&#039;Display Vibrations&#039;&#039;&#039; ===&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
[[File:Qingli_display_model.png]]&lt;br /&gt;
=== &#039;&#039;&#039;Questions about Display Vibrations&#039;&#039;&#039; ===&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
how many modes do you expect from the 3N-6 rule? 6&lt;br /&gt;
&lt;br /&gt;
which modes are degenerate (ie have the same energy)? 5  6&lt;br /&gt;
&lt;br /&gt;
which modes are &amp;quot;bending&amp;quot; vibrations and which are &amp;quot;bond stretch&amp;quot; vibrations? 1 2 3,  4 5 6&lt;br /&gt;
&lt;br /&gt;
which mode is highly symmetric? 4&lt;br /&gt;
&lt;br /&gt;
one mode is known as the &amp;quot;umbrella&amp;quot; mode, which one is this? 1&lt;br /&gt;
&lt;br /&gt;
how many bands would you expect to see in an experimental spectrum of gaseous ammonia? 4&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
=== &#039;&#039;&#039;charge&#039;&#039;&#039; ===&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
charge on the N-atom: -1.125&lt;br /&gt;
charge on the H-atoms: 0.375&lt;br /&gt;
Since N atom is more electronegative than H atom, the charge on N atom is negative while that on H is positive. &lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
== &#039;&#039;&#039;H2 molecule&#039;&#039;&#039; ==&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
=== &#039;&#039;&#039;General Information&#039;&#039;&#039; ===&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
H-H bond distance = 0.74309&lt;br /&gt;
&lt;br /&gt;
H-H bond angle = 180°&lt;br /&gt;
&lt;br /&gt;
Calculation Method: RB3LYP&lt;br /&gt;
&lt;br /&gt;
Basis Set: 6-31G(d,p)&lt;br /&gt;
&lt;br /&gt;
final energy E(RB3LYP) in atomic units (au): -1.17853930&lt;br /&gt;
&lt;br /&gt;
RMS gradient: 0.00012170&lt;br /&gt;
&lt;br /&gt;
Point Group: D*H&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
=== &#039;&#039;&#039;Item Table&#039;&#039;&#039; ===&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&amp;lt;pre&amp;gt;&lt;br /&gt;
&lt;br /&gt;
         Item               Value     Threshold  Converged?&lt;br /&gt;
 Maximum Force            0.000211     0.000450     YES&lt;br /&gt;
 RMS     Force            0.000211     0.000300     YES&lt;br /&gt;
 Maximum Displacement     0.000278     0.001800     YES&lt;br /&gt;
 RMS     Displacement     0.000393     0.001200     YES&lt;br /&gt;
&lt;br /&gt;
&amp;lt;/pre&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
=== &#039;&#039;&#039;Jmol 3D Model&#039;&#039;&#039; ===&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&amp;lt;jmol&amp;gt;&amp;lt;jmolApplet&amp;gt;&lt;br /&gt;
  &amp;lt;title&amp;gt;test molecule&amp;lt;/title&amp;gt;&lt;br /&gt;
  &amp;lt;color&amp;gt;black&amp;lt;/color&amp;gt;&lt;br /&gt;
  &amp;lt;size&amp;gt;200&amp;lt;/size&amp;gt;&lt;br /&gt;
  &amp;lt;uploadedFileContents&amp;gt;QINGLI_PHUNT_H2_OPTF_POP.LOG&amp;lt;/uploadedFileContents&amp;gt;&lt;br /&gt;
&amp;lt;script&amp;gt;frame 1.14&amp;lt;/script&amp;gt;&lt;br /&gt;
&amp;lt;/jmolApplet&amp;gt;&amp;lt;/jmol&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The optimisation file is liked to [[Media:QINGLI_PHUNT_H2_OPTF_POP.LOG| here]]&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
=== &#039;&#039;&#039;Display Vibrations&#039;&#039;&#039; ===&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
[[File:Qingli_display_model_h2.png]]&lt;br /&gt;
== &#039;&#039;&#039;N2 molecule&#039;&#039;&#039; ==&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
=== &#039;&#039;&#039;General Information&#039;&#039;&#039; ===&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
H-H bond distance = 1.10550&lt;br /&gt;
&lt;br /&gt;
H-H bond angle = 180°&lt;br /&gt;
&lt;br /&gt;
Calculation Method: RB3LYP&lt;br /&gt;
&lt;br /&gt;
Basis Set: 6-31G(d,p)&lt;br /&gt;
&lt;br /&gt;
final energy E(RB3LYP) in atomic units (au): -109.52412868&lt;br /&gt;
&lt;br /&gt;
RMS gradient: 0.00000365&lt;br /&gt;
&lt;br /&gt;
Point Group: D*H&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
=== &#039;&#039;&#039;Item Table&#039;&#039;&#039; ===&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&amp;lt;pre&amp;gt;&lt;br /&gt;
&lt;br /&gt;
         Item               Value     Threshold  Converged?&lt;br /&gt;
 Maximum Force            0.000006     0.000450     YES&lt;br /&gt;
 RMS     Force            0.000006     0.000300     YES&lt;br /&gt;
 Maximum Displacement     0.000002     0.001800     YES&lt;br /&gt;
 RMS     Displacement     0.000003     0.001200     YES&lt;br /&gt;
&amp;lt;/pre&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
=== &#039;&#039;&#039;Jmol 3D Model&#039;&#039;&#039; ===&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&amp;lt;jmol&amp;gt;&amp;lt;jmolApplet&amp;gt;&lt;br /&gt;
  &amp;lt;title&amp;gt;test molecule&amp;lt;/title&amp;gt;&lt;br /&gt;
  &amp;lt;color&amp;gt;black&amp;lt;/color&amp;gt;&lt;br /&gt;
  &amp;lt;size&amp;gt;200&amp;lt;/size&amp;gt;&lt;br /&gt;
  &amp;lt;uploadedFileContents&amp;gt;QINGLI_PHUNT_N2_OPTF_POP.LOG&amp;lt;/uploadedFileContents&amp;gt;&lt;br /&gt;
&amp;lt;script&amp;gt;frame 1.12&amp;lt;/script&amp;gt;&lt;br /&gt;
&amp;lt;/jmolApplet&amp;gt;&amp;lt;/jmol&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The optimisation file is liked to [[Media:QINGLI_PHUNT_N2_OPTF_POP.LOG| here]]&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
=== &#039;&#039;&#039;Display Vibrations&#039;&#039;&#039; ===&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
[[File:Qingli_display_model_n2.png]]&lt;br /&gt;
== &#039;&#039;&#039;Reaction Energies&#039;&#039;&#039; ==&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
E(NH3)= -56.55776873 a.u&lt;br /&gt;
&lt;br /&gt;
2*E(NH3)= -113.11553746 a.u&lt;br /&gt;
&lt;br /&gt;
E(N2)= -109.52412298 a.u&lt;br /&gt;
&lt;br /&gt;
E(H2)= -1.17853930 a.u&lt;br /&gt;
&lt;br /&gt;
3*E(H2)= -3.5356179 a.u&lt;br /&gt;
&lt;br /&gt;
ΔE=2*E(NH3)-[E(N2)+3*E(H2)]= -113.11553746-(-109.52412298-3.5356179)=-0.05579658 a.u= -146.50 kJ/mol&lt;br /&gt;
&lt;br /&gt;
Since the energy difference is negative, the ammonia product is more stable.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
== &#039;&#039;&#039;F2 molecule&#039;&#039;&#039; ==&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
===&#039;&#039;&#039;General Information&#039;&#039;&#039; ===&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
F-F bond distance = 1.16000 Å&lt;br /&gt;
&lt;br /&gt;
F-F bond angle = 180°&lt;br /&gt;
&lt;br /&gt;
Calculation Method: RB3LYP&lt;br /&gt;
&lt;br /&gt;
Basis Set: 6-31G(d,p)&lt;br /&gt;
&lt;br /&gt;
Total Energy: -199.42620785 a.u.&lt;br /&gt;
&lt;br /&gt;
RMS Gradient Norm: 0.23253407 a.u.&lt;br /&gt;
&lt;br /&gt;
Point Group: D*H &lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
===&#039;&#039;&#039;Item Table&#039;&#039;&#039; ===&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&amp;lt;pre&amp;gt;&lt;br /&gt;
&lt;br /&gt;
         Item               Value     Threshold  Converged?&lt;br /&gt;
 Maximum Force            0.000128     0.000450     YES &lt;br /&gt;
 RMS     Force            0.000128     0.000300     YES &lt;br /&gt;
 Maximum Displacement     0.000156     0.001800     YES&lt;br /&gt;
 RMS     Displacement     0.000221     0.001200     YES &lt;br /&gt;
&lt;br /&gt;
&amp;lt;/pre&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
=== &#039;&#039;&#039;Jmol 3D Model&#039;&#039;&#039; ===&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&amp;lt;jmol&amp;gt;&amp;lt;jmolApplet&amp;gt;&lt;br /&gt;
  &amp;lt;title&amp;gt;test molecule&amp;lt;/title&amp;gt;&lt;br /&gt;
  &amp;lt;color&amp;gt;black&amp;lt;/color&amp;gt;&lt;br /&gt;
  &amp;lt;size&amp;gt;200&amp;lt;/size&amp;gt;&lt;br /&gt;
  &amp;lt;uploadedFileContents&amp;gt;QINGLI_PHUNT_F2_OPTF_POP.LOG&amp;lt;/uploadedFileContents&amp;gt;&lt;br /&gt;
&amp;lt;script&amp;gt;frame 1.12&amp;lt;/script&amp;gt;&lt;br /&gt;
&amp;lt;/jmolApplet&amp;gt;&amp;lt;/jmol&amp;gt;&lt;br /&gt;
&lt;br /&gt;
The optimisation file is liked to [[Media:QINGLI_PHUNT_F2_OPTF_POP.LOG| here]]&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
===&#039;&#039;&#039;Display Vibrations&#039;&#039;&#039; ===&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
[[File:Qingli_display_model_f2.png]]&lt;br /&gt;
=== &#039;&#039;&#039;charge&#039;&#039;&#039;===&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
There is the same charge on 2 F atoms and F2 molecule does not carry on a overall charge.&lt;br /&gt;
&lt;br /&gt;
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===&#039;&#039;&#039;Molecular Orbital&#039;&#039;&#039;===&lt;br /&gt;
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MO1&lt;br /&gt;
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[[File:Ql_MO_F2_1.png|600px]]&lt;br /&gt;
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MO2&lt;br /&gt;
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[[File:Ql_MO_F2_2.png|600px]]&lt;br /&gt;
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MO3&lt;br /&gt;
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[[File:Ql_MO_F2_3.png|600px]]&lt;br /&gt;
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MO4&lt;br /&gt;
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[[File:Ql_MO_F2_4.png|600px]]&lt;br /&gt;
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MO5&lt;br /&gt;
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[[File:Ql_MO_F2_5.png|600px]]&lt;br /&gt;
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&#039;&#039;&#039;Summary&#039;&#039;&#039;&lt;br /&gt;
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MO1 and MO2 are bonding and anti-bonding orbitals respectively formed by 2s AOs of each F atom. Both of them are sigma bonds.&lt;br /&gt;
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2p AOs of F atom contribute to the formation of MO3, MO4 and MO5. MO3 and MO4 are occupied and bonding while MO5 is anti-bonding orbital. MO3 and MO5 are sigma MOs formed by 2 pz AOs and, MO4 is pi MOs which is formed by 2 Px AOs.&lt;br /&gt;
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MO3 and MO4 are bonding orbitals, they have relatively lower energy in HOMO region, at -0.58753 a.u. and -0.52332 a.u.&lt;br /&gt;
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Also, MO5 is the LUMO with energy (-0.12679 a.u.)&lt;/div&gt;</summary>
		<author><name>Ql2817</name></author>
	</entry>
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